quantum numbers (2)
TRANSCRIPT
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Atomic structure
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Thomson model of the
atom
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Rutherford experiment (withGeiger and Marsden)
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Rutherfords model of the
atom (planetary)
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Bohr model of the atom
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Werner Heisenberg
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Particle in a Box
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Particle in a box
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ndescribes the size of the orbital
1, 2, 3, and so on
nucleus
electron
The principal qunatum number n describes the energy of an orbital
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Orbital Quantum Number
l describes the shape of the orbital
any integer between 0 and n - 1
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Magnetic Quantum Numbers
ms is the spin quantum number. It describes theorientation of the electron spin
ms = +1/2 or ms=-1/2
ml the magnetic quantum number. It describes the
orientation in space
-l to +l
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Quantum NumbersDefinitions n principal quantum # 1,2,3 determines energy
l angular momentum q. # 0,1,..,n-1 angular dependence ml magnetic quantum # 0,1,.. ,l orientation in space
s spin q. # 1/2 spin magnetic moment ms magnetic spin q. # 1/2 orientation of spin
magnetic moment in spaceOrbital nodesAngular nodes: lRadial nodes: n-l-1Examples1. The 14 wave functions for 14 electrons that can be accommodated in 5f
orbitals have the following quantum numbers:
n = 5l = 3ml = -3, -2, -1, 0, 1, 2, 3s = 1/2mS = +1/2, -1/2
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Angular and Radial Part of the Wave
Function
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All nodes
n-1
Angular nodes
l
Radial nodes
n-l-1
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Orbital symbol
n,,m = n (-symbol)directionExamples:
1,0,0 = 1s2,1,0 = 2pzLimits on quantum #s
for energy level n0, 1, 2, (n-1);
s, p, d,
m 0, 1, , Example:n = 2, = ?, m = ?
= 0, m = 0 = 1, m = 1, 0, -1
What we now have:
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What we now have:
1) Energy levels for electron in an atom
depends only on n!!!
2) Each level has n2
orbitals with that energyDegeneracy
all ,m with same n have same energy
(e.g., n = 2, degeneracy = 4: 2s, 2px, 2py,
2pz)
3) Orbital: mathematical function that
gives wave-like properties:
phase, direction
4) Square Orbital:
Probability distribution ofelectron position in that orbital
We will use plots of orbitals to show these
properties
and to determine properties of the atom
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Radial wave/probability functions
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Size of Hydrogen1s orbital
e- is found 90% of
the time from
r = 0 2.6 ao (.14 nm)
90% of probability
contour line
No angular dependence!!
ao
= 5.29 x 10-11 m
e(-r/ao)
2.6 ao
Radial function
Figure 16 19: 1 2 3 orbitals
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Figure 12.18:
1s, 2s, 3s orbitals
Figure 16.19: 1s, 2s, 3s orbitals
(no angular dependence!!)
(idea of relative size)
+-+
90% Probability contours showing relative
size of orbitals
phases of
wave function ()
radial probability distribution (r22) = probability of findingelectron at a distance r from the center of the nucleus
+-+
++ -
++-
Understanding radial distribution
http://localhost/var/www/apps/conversion/AppData/Local/Temp/Atom3secondpartraddistfunc2009Lec7.ppt -
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Angular representation of the porbitals
= 1 ; now there IS angular dependence
m = 1, 0, -1 : 3 orbitals in 3 different directions
Phases given as + and - signs
r
e-
+
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Exercises:
1. Consider an atom which has the
following electron configuration on the
4th shell: 4d10. Find the quantum numbersthat describe this orbital.
2. How many radial nodes, angular nodes
are there in a 3pz, 4s, 5d orbitals?
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