project calculation

CKT NO AREA LIGHTS FANSR1 BR1 2 1

Y1 BR2 2 1

B1 TOILET1 1 0

R2 TOILET2 1 0

Y2 DINING HALL 2 0

B2 HALL 4 2

R3 KITCHEN+UTILITY 5 0

Y3 BALCONY 2 0

19 4

FOR 1 PLOT POWER=25785 THEN FOR 4 PLOTS 103140

FOR CURRENTI=P/√3VCOSф

P= 103140V= 415

I= ?

COSф= 0.8

I= 179.3664264448

ADDING 25% FOR FUTURE USE

I= 224.208033056

SINCE I<200 AMPS

We need 3.5C x 25MM2 Alum/PVC/AWA/PVC CABLE

SINCE I=56 AMPS WE ARE SELECTING 4 POLE 63 AMPS MCB

TRANSFORMER SELCTION

KVA = KW/PF

KW= 103.14PF= 0.8

KVA= 128.925with a design margin of 25% 161.1562525% more for future loads. 201.4453125

B48

Transformer is a critical part of the power system which cant be upgraded/changed frequently. A minimum of 25% design margin has to be taken for transformer sizing. i.e. 130 x 1.25 = 163 Kva. If iam the designer, I will use 200 KVA transformer.

EX-FAN6A DB 15A GYSER AC R Y B0 3 0 1 0 1 4000

0 3 0 1 0 1 4000

1 1 0 0 1 0 1760

1 1 0 0 1 0 1760

0 1 0 1 0 1 3720

0 2 1 2 0 2 7625

1 4 0 2 0 0 2800

0 0 0 0 0 0 120

3 15 1 7 2 5 8560 7840 9385

25785

We need 3.5C x 25MM2 Alum/PVC/AWA/PVC CABLE

F1

The load for this 6A socket has been taken only 100Watts in the calculation. Whereas it shall be 6x240v = 1440 watts

H1

The load for this 15A socket has been taken only 1000Watts in the calculation. Whereas it shall be 15x240v = 3600 watts

A34

1. AWA should be used for single core cables to minimize the magnetizing current in the armouring. Its recommended to use SWA instead of AWA in multicore cables. 2. A cable size cannot be reached without considering the voltage drops. In a good power system, the voltage drop shall be limited to 3% (As per NEC standard). I have given below a sample voltage drop calculation considering a length of 300 meters. 3. Before selecting a cable size, we need to check the exact current carrying capacity of the cable. Then it should be derated as per the site conditions. the derating factors are mentioned in the manufacturers catalogue. The current carrying capacity of PVC insulated 25 Sq.mm Aluminium cable is 83 Amps. as per the catalogue of Riyadh Cables Ltd. since our load current is 225 Amps, this cable is not suitable.


Calculation for the voltage drops in the cable.System Voltage 415Cable Length 300Resistance of the cable 0.102Current 180

%Vd = ((2xIxRxL/1000)/V)x100

%Vd = 2.654458 %

A38

since the current is 180 Amps, it is recommended to use MCCB of 180x1.25 = 225 Amps Ampere trip.

M43

Measure the actual length of the cable required. Here I have considered 300 Meters.

Calculation for the voltage drops in the cable.VoltsMetersOhms/Km For Aluminium cable size of 400 Sq.mm Amps

((2xIxRxL/1000)/V)x100

The voltage drop is less than 3%. Hence this cable can be used.

AREA 12LUX 300LUMENS OF LAMP 2425CO-EFFICIENT OF UTILITY 0.47MAINTANANCE FACTOR 0.8

NO.OF FIXTURES 3.94823426189954

CKT NO PHASE

LCKT 4 R2LCKT 1 R1LCKT 3 B1LCKT 2 Y1LCKT 6 Y2

POWER CIRCUITCKT NO PHASE

PCKT 1 B2PCKT 2 R3PCKT 3 Y3PCKT 4 B3PCKT 5 R4PCKT 6 B4

PCKT 7 R5

TOTAL LOAD/FLATTHEN FOR 4 PLOTS FOR CURRENTP=V=I=COSф=

I=


I=

SINCE I<200 AMPS

We need 4C x 25MM2 Alum/PVC/AWA/PVC CABLE


CAPACITOR BANK SELCTION

K

Power(KW)

KVAR


KVA = KW/PF

KW=PF=

KVA=

Adding25 % Future load (KVA)

According to the results obtained the rating of the transformed should be

B91

Author: The standard rating of transformers are (25,40,63,100,125,160,250,315,350,400,500,630,750,800,1000)kva (1,1.25,1.5,2,2.5,3,4,6,8,10)MVA

AREA LIGHTS FANS EX-FANS 6A DB 15ALIVING HALL+BAL 5 1 0 2 1 0

BR1 2 1 0 3 0 0

DINING HALL+KIT+UTILITY 4 2 1 2 0 0

BR2 2 1 0 3 0 0

T1+T2 4 0 2 2 0 0

CONNECTED LOAD 17 5 3 12 1 0

MAXIMUM DEMAND 14 4 2 10 1 0

DEMAND FACTOR 0.82352941 0.8 0.6666666667 0.833333 1 0

AREA LIGHTS FANS EX-FANS 6A DB 15ABR1+BR2+HALL 0 0 0 0 0 1

DINING HALL 2

T1+T2

BED ROOM1

BED ROOM2

HALL

DRAWING HALL

2

20420 W

81680 WI=P/√3VCOSф81680 W

415?0.8

142.046245026295

177.557806282868



0.265677895

81.68

21.7005704636

81.680.9

90.7555555555556 KVA

113.444444444444 KVA

125 KVA

C85

Author: power factor has been improved from 0.8to 0.9 by using capacitor bank of rating 21.700 kvar

GYSER AC R Y B0 0 9 625 625

0 0 6 520 520

0 0 9 740 740

0 0 6 520 520

0 0 8 640 640

0 0 0

0 0

0 0

GYSER AC1000 1000

2000 2000

2 3000 3000

1 2500 2500

1 2500 2500

1 2500 2500

1 2500 2500

2000 2000

6500 7180 6740


ROOM AREA

AREA LENGTH (M)BREADTH (M)AREA in MNO OF FIXTURES

BED ROOM 1 3.26 3.7 12.062 4 2 RUNS OF 2.5 SQMM+1 RUN OF 1.5 SQMM

HALL 5.31 3.7 19.647 7 2 RUNS OF 2.5 SQMM+1 RUN OF 1.5 SQMM

BED ROOM-2 3.76 3.34 12.5584 5 2 RUNS OF 2.5 SQMM+1 RUN OF 1.5 SQMM

DINING HALL 2.69 3.45 9.2805 2 2 RUNS OF 2.5 SQMM+1 RUN OF 1.5 SQMM

KITHCHEN 2.51 3.34 8.3834 3 2 RUNS OF 2.5 SQMM+1 RUN OF 1.5 SQMM

TOILET-1 1.78 1.67 2.9726 1 2 RUNS OF 2.5 SQMM+1 RUN OF 1.5 SQMM

TOILET-2 1.29 2.32 2.9928 1 2 RUNS OF 2.5 SQMM+1 RUN OF 1.5 SQMM

BALCONY 1.79 1.92 3.4368 1 2 RUNS OF 2.5 SQMM+1 RUN OF 1.5 SQMM

AREA LIGHT POINTS TV DB A.C 15A

BED ROOM -1 4 1 1 1 3 1 1 1 13 895 1 1

HALL 2 2 1 1 1 1 1 1 1 11 560 2 1 3

BED ROOM-2 1 1 1 3 1 1 1 9 655 1 1

DINING HALL 2 1 1 4 300 0

KITHCHEN 3 3 2 1 9 780 3 3

TOILET-1 1 1 1 3 260 1 1 2

TOILET-2 1 1 1 3 260 1 1 2

BALCONY 1 1 2 160 0

UTILITY 1 1 2 160 0

GATE 1 1 60 0TOTAL 13 5 2 9 12 3 3 3 2 1 1 1 1 1 57 4090 4 2 6WATTAGE/UNIT 60 80 60 100 100 100 100 15 60 25 700 2500 1500 1000 5000INDIVIDUAL POWER CONSUMED BY EACH 780 400 120 900 1200 300 0 300 30 60 0 0 0 25 4115 10000 3000 6000 19000

BALANCING THE LIGHTING LOADCIRCUIT NO PHASE AREA POINTS LOAD MAX POMAX LOAD AS PAR NEC (WATTS)

1 R1,R2 BED ROOM 1 +T1+BALCONY 18 1315 10 800 8 5152 Y1,Y2 BED ROOM 2+ T2 12 915 10 800 2 1153 Y3 KITCHEN 9 780 10 800 1.00 20.004 R3,R4 DINING HALL, UTILITY 6 460 10 800 4.00 340.005 Y4,Y5 HALL 11 560 10 800 1.00 240.00

160 10 800 10.00 640.00

FAN POINT

2-WAY LIGHT POINT

5 AMPS SOCKET INDEP

5 AMPS SOCKET DEPEND

ENT

TELEPHONE

EXHAUST FAN

FOOT LAMP

GATE LIGHT

TV JUNCTI

ON BOX

TELEPHONE

JUNCTION BOX

BELL POINT

TOTAL POINTS

CONNECTED LOAD

GYSER

TOTAL POINTS

P13

Author: (DISTRIBUTION BOARD)

J30

Author: TOTAL POINTS OF BOTH CIRCUITS (R1,R2)

K30

Author: TOTAL WATTAGE OF CIRCUIT R1 AND R2

L30

Author: POINTS IN CIRCUIT R1

M30

Author: WATTAGE OF CIRCUIT R1

N30

Author: POINTS OF CIRCUIT R2 (TOTAL POINTS-POINTS OF CURCUIT R1)

O30

Author: WATTAGE OF CIRCUIT R2 (TOTAL WATTAGE-WATTAGE OF R1)

BALANCING THE POWER LOADCIRCUIT NO PHASE AREA POINTS LOAD MAX LOAD AS PAR NEC (WATTS)

1 B3 KITCHEN 3 3000 3 30002 R5,R6,R7 HALL 3 6000 3 30003 Y6 BED ROOM 1 1 2500 3 30004 Y7 BED ROOM 2 1 2500 3 3000

MAX POINTS AS PER

J39

2 CIRCUITS FOR AC 2(Nos)*2500W=5000W 1(NO)*1000W=1000W TOTAL LOAD=6000W :-)

5 B4 TOILET1+TOILET2 2 3000 3 30006 B5 TOILET1+TOILET2 2 2000 3 3000

R 7775 R 660875Y 7255 Y 616675B 8000 B 680000TOTAL CONNECTED LOAD(W) 23030 TOTAL CONNECTED L 1957550DEMAND FACTOR 0.65 DEMAND FACTOR 55.25MAXIMUM DEAMAND(W) 14969.5 MAXIMUM DEAMAND 1272407.5 1.272MAXIMUM DEAMAND(KW) 14.9695 MAXIMUM DEAMAND1272.41

FOR CURRENT I=P/√3VCOSфP= 14969.5 W

V= 415I= ?COSф= 0.8 0.69671 1.43532

I= 26.0328265


I= 32.5410331



CAPACITOR BANK SELCTION

K 0.2656779

Power(KW) 14.9695

KVAR 3.97706525

POWER CONSUPTION PER FLAT POWER CONSUPTION FOR EIGHTY FIVE FLATS

J42

Author: 2 GYSERS CAN BE CLUBBED IN A SINGLE CIRCUIT EACH OF 1500W 2*1500W=3000 :-)

J43

Author: THIS CIRCUIT CONSISTS OF TWO 15A SOCKET OF 1000W EACH 2*1000W=2000W :-(

F46

Author: THE DIFFRENCE BETWEEN ANY TWO PHASES SHOULD NOT EXCEED 10% OF THE TOTAL WATTAGE ;-)

J46

Author: THE DIFFRENCE BETWEEN ANY TWO PHASES SHOULD NOT EXCEED 10% OF THE TOTAL WATTAGE ;-)

E69

Author: IF I<200 AMPS WE NEED 4C x 25MM2 AL/PVC CABLE IF I>200 AMPS WE NEED 3.5C x 25MM2 AL/PVC CABLE :-)


KVA = KW/PF

KW= 14.9695PF= 0.9

KVA= 16.6327778 KVA

Adding25 % Future load (KVA) 20.7909722 KVA

125 KVA

According to the results obtained the rating of the transformed should be

F91

Author: power factor has been improved from 0.8to 0.9 by using capacitor bank of rating 21.700 kvar

E97

Author: The standard rating of transformers are (25,40,63,100,125,160,250,315,350,400,500,630,750,800,1000)kva (1,1.25,1.5,2,2.5,3,4,6,8,10)MVA

WATTS/ UNIT LOAD/CIRCUIT (WATT)

2500

6000

2500

0

3000

2500

2500

0

0

0

CONNECTED LOAD

project calculation

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