problem 5.6b

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Problem 5.6b Ammonia Process - Energy Balance for Mixer into R3 Using average molar heat capacities 7.42 7.02 Tref (K) 273.15 11.86 14.57 S 3 4.97 323.15 Temp (K) Feed 2507.98 N(N2) Feed 7522.93 N(H2) Feed 735.76 Temp (K) R2 out 0.00 N(NH3) Feed 4647.56 N(N2) R2 out 96.54 N(CH4) Feed 12201.88 N(H2) R2 out 34.55 N(Ar) Feed 3602.98 N(NH3) R2 out 3649923.65 Feed 2202.26 N(CH4) R2 out 477.80 N(Ar) R2 out Use Goal Seek to vary T R2 In ### R2 out Energy Balance = 0 (out - in) 50% of Feed S 5 0 S 3b Mixer S 6 671.36 Temp (K) R3 In 748.77 Temp (F) 5901.55 N(N2) R3 In 15963.34 N(H2) R3 In 3602.98 N(NH3) R3 In 2250.53 N(CH4) R3 In 495.07 N(Ar) R3 In ### R3 In CpN2 CpH2 CpNH3 CpCH4 CpAr ΣNshs (Cal) ΣNshs (Cal ΣNshs (Cal

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ex5.6b

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Problem 5.6b Ammonia Process - Energy Balance for Mixer into R3 Using average molar heat capacities 7.427.02Tref (K) 273.15 11.8614.57S 3 4.97323.15 Temp (K) Feed2507.98 N(N2) Feed7522.93 N(H2) Feed 735.76 Temp (K) R2 out0.00 N(NH3) Feed 4647.56 N(N2) R2 out96.54 N(CH4) Feed 12201.88 N(H2) R2 out34.55 N(Ar) Feed 3602.98 N(NH3) R2 out3649923.65 Feed 2202.26 N(CH4) R2 out477.80 N(Ar) R2 out Use Goal See to !ar" T R2 #$%%% R2 out &$er'" (ala$)e * 0 (out + ,$)50% of Feed S 5 0S 3- MixerS 6671.36 Temp (K) R3 #$ 748.77 Temp (.)5901.55 N(N2) R3 #$15963.34 N(H2) R3 #$3602.98 N(NH3) R3 #$2250.53 N(CH4) R3 #$495.07 N(Ar) R3 #$%%% R3 #$/p02/p12/p013/p/14/p2rNshs (C!)Nshs (C!)Nshs (C!)