principles of semiconductor devices-l11
TRANSCRIPT
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Alam ECE-606 S09 1
www.nanohub.org
NCN
EE-606: Solid State DevicesLecture 11: Equilibrium Statistics
Muhammad Ashraful [email protected]
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Outline
Alam ECE-606 S09 2
1) Law of mass-action & intrinsic concentration
2) Statistics of donors and acceptor levels
3) Conclusion
Reference: Vol. 6, Ch. 4 (pages 110-120)
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Fermi-Level for Intrinsic Semiconductors
Alam ECE-606 S09 3
2
=
gE
i
F
V
i
Cn eE
NE
N
FE
( ) ( )
1
2 2
+
= =
= +
c i v i E E E E
Gi
V
C
VCn p e e
E E ln
N
N
N
N
E
k
3
2
2
= =
= gV
i
E
i CN
p nn eNn
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However
Alam ECE-606 S09 4
Intrinsic concentration too small ..
We need to do something toincrease carrier concentration or
conductivity of semiconductors
This is done by doping.
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Looking ahead: Carrier-Density w/Doping
Alam ECE-606 S09 5
0+ + = D AN p n dV N
0+ + =ADp n NN
1 10
42
++ =
+
F D
F
A B
C
F
B F B
B
V D
( E E )
A( E E ) / k T ( E E )
( E
/ k T
E ) / k T C / k TVN
NN
eee
Ne
A bulk material must be charge neutral over all
Further if the material is spatially homogenous
Let us see how the formula come about
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Outline
Alam ECE-606 S09 6
1) Law of mass-action and intrinsic concentration
2) Statistics of donor and acceptor levels
3) Conclusion
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Characteristics of Donor Atoms
Alam ECE-606 S09 7
(D)
r0
ET
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Localized vs. Delocalized States
Alam ECE-606 S09 8
2N states/per-band (with spin)
2N-2 states/per-band (with spin)
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Statistics of Donor Levels
Alam ECE-606 S09 9
0 0 0 0 1
1 0 1 1
0 1 1 1
i F
B
i F
B
i i i
( E E )
k T
( E E )
k T
u / d E N P
/ / Z
/ e Z
/ e Z
1/1 x x x
=
i i F B F B
i i F
ii
B
( E N E ) / k T ( E ) / k T
i ( E N E ) /
N
k T
i
Ee eP
e Z
Coulomb interactionforbids this configuration
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Statistics of Donor Levels
Alam ECE-606 S09 10
0 0 0 0 1
0 1 1 1
1 0 1 1
i F
B
i F
B
i i i
( E E )
k T
( E E )
k T
u / d E N P
/ / Z
/ e Z
/ e Z
00
00
00 01 102
1 1
1 2 1
= = =+ + + +i F B F i B( E E ) / k T ( E E ) / k T
P / Zf
P P P / Z e / Z e
00
1 11 1
1 11
2
2
= =+
+F i B
i F B
( E E )/ k T ( E E ) / k T
fe
e
Prob. that the donor
is empty (charged)
Prob. that the donor
is filled with at least
one electron (neutral)
Note the extra factor .
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Coulomb Exclusion for Band Electrons?
Alam ECE-606 S09 11
0 0 0 1
1 1 1
i F
B
( E E
i
)
i
T
i
k
state E N P
/ Z
e Z
i i F B i i F B
i i F B
( E N E ) / k T ( E N E ) / k T
i ( E N E ) / k T
i
e eP
e Z
=
Ei
E=0
E=2
E=4
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Localized vs. Band Electrons
12
E1 2/Lx
E2 4/Lx
E3 6/Lx
E4 8/Lx
E5 10/Lx
E6 12/Lx
E1 2p/(Lx/2)
E2 4/(Lx/2)
E3 6/(Lx/2)
Lx
Lx/2 Lx/2
Two electrons (even withopposite spin) can notbe at the same positionand same energy becauseof electrostatic repulsion
Band electrons (withopposite spin) need not
be at the same position,so they can share occupysame energy level.
When we divide space by a factor of 2, the
number of states (e.g. 6 here) does not change.
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Acceptor Atoms
Alam ECE-606 S09 13
State [1] . Hole present N-1 charges
State [0] Hole filled . N charges
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Statistics of Acceptor Levels in Si and Ge
14
1. Each atom contributes 2 states (up & down spin)
to a band, therefore a band has 2N states.
2. Every time a host atom is replaced by a impurity
atom, 2 states are disappear per a band and
appear as localized states (sort of).
3. Therefore an acceptor atom close to hh and lh
bands removes four states from those bands.
4. Because of Coulomb interaction only 1 hole can
seat in these 4 states: the states are
0000, 0001, 0010, 0100, 1000.
5. One now uses Pi to compute the occupation of
acceptors.
from lh
from hh
EC
EV
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Number and Energy Considerations
Alam ECE-606 S09 15
4N-4 States
In HH/LH bands0000 1000 0100 0010 0001
1) [0000] is the charged state as it has N electrons, but N-1 protons.
2) Single hole configuration [0001] is uncharged, as we have N-1
electrons, and N-1 protons same is true for [0010], [0100], [1000]
states.
3) Going from [0000] to [0001] states, the number of electrons goesdown by 1 (Ni=-1).
4) Going from [0000] to [0001] states energy goes down by EA,
because one electron is no longer occupying the high energy level at
EA.
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Statistics of Acceptor Levels
Alam ECE-606 S09 16
0000 1000 0100 0010 00010 0
0000
1F B
i i F B
( xE ) / k T
( E N E ) / k T
i
eP
e Z
=
1
0001 0010 0100 1000
A F B A F B
i i F B
( E ( )E ) / k T ( E E ) / k T
( E N E ) / k T
i
e eP P P P
e Z
= = = =
Steps 3 & 4
0000
0000
1000 0100 0010 0001
1
1 4
= =+ + + + A F B( E E ) / k T
Pf
P P P P e
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Filled and empty Donor/Acceptor Levels
Alam ECE-606 S09 17
00
1
1 2
= =+ F i B
D D ( E E )/ k T N f N
e
[ ]0000
=filled
A A A N N N f
2N-2 states
4N-4 States
In HH/LH bands
(Two holes can not seat together)
0000 1000 0100 0010 0001
00 10 01 +emptyD DN N
1
1 4
=
+A F B
A ( E E ) / k T N
e
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Distributions are physical .
Alam ECE-606 S09 18
1
=+ F D B
DD ( E / T
D
E ) k g
Nfe
1 1
= =+ +F D B F
'B D B
D DD ( E E ) / k k T ET ( E ) / k T
N Nf
e e e
Degeneracy factor
Effective donor level
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Summary
Alam ECE-606 S09 19
0ADN p n dV N+ + + =
0AD
Nn Np + + + =
10
12 4
F V B C F B
F D A F BB
( E E ) / k T ( E E ) / k T A
( E E ) / V AD
( E E ) k/ k TT
Ne e
eN N
N
e
+ + + =
A bulk material must be charge neutral over all
Further if the material is spatially homogenous
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Conclusions
Alam ECE-606 S09 20
Intrinsic concentration of electrons in a semiconductor is
relatively small.
The statistics of dopant levels are different because they are
close to the conduction band and because they are localized.
Influenced by pair-wise coulomb repulsion.
The statistics of donor and acceptor atoms are also different,
because donor levels couple with single conduction band,while acceptor levels couple with two valence bands.