principles of semiconductor devices-l11

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  • 8/8/2019 Principles of Semiconductor Devices-L11

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    Alam ECE-606 S09 1

    www.nanohub.org

    NCN

    EE-606: Solid State DevicesLecture 11: Equilibrium Statistics

    Muhammad Ashraful [email protected]

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    Outline

    Alam ECE-606 S09 2

    1) Law of mass-action & intrinsic concentration

    2) Statistics of donors and acceptor levels

    3) Conclusion

    Reference: Vol. 6, Ch. 4 (pages 110-120)

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    Fermi-Level for Intrinsic Semiconductors

    Alam ECE-606 S09 3

    2

    =

    gE

    i

    F

    V

    i

    Cn eE

    NE

    N

    FE

    ( ) ( )

    1

    2 2

    +

    = =

    = +

    c i v i E E E E

    Gi

    V

    C

    VCn p e e

    E E ln

    N

    N

    N

    N

    E

    k

    3

    2

    2

    = =

    = gV

    i

    E

    i CN

    p nn eNn

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    However

    Alam ECE-606 S09 4

    Intrinsic concentration too small ..

    We need to do something toincrease carrier concentration or

    conductivity of semiconductors

    This is done by doping.

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    Looking ahead: Carrier-Density w/Doping

    Alam ECE-606 S09 5

    0+ + = D AN p n dV N

    0+ + =ADp n NN

    1 10

    42

    ++ =

    +

    F D

    F

    A B

    C

    F

    B F B

    B

    V D

    ( E E )

    A( E E ) / k T ( E E )

    ( E

    / k T

    E ) / k T C / k TVN

    NN

    eee

    Ne

    A bulk material must be charge neutral over all

    Further if the material is spatially homogenous

    Let us see how the formula come about

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    Outline

    Alam ECE-606 S09 6

    1) Law of mass-action and intrinsic concentration

    2) Statistics of donor and acceptor levels

    3) Conclusion

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    Characteristics of Donor Atoms

    Alam ECE-606 S09 7

    (D)

    r0

    ET

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    Localized vs. Delocalized States

    Alam ECE-606 S09 8

    2N states/per-band (with spin)

    2N-2 states/per-band (with spin)

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    Statistics of Donor Levels

    Alam ECE-606 S09 9

    0 0 0 0 1

    1 0 1 1

    0 1 1 1

    i F

    B

    i F

    B

    i i i

    ( E E )

    k T

    ( E E )

    k T

    u / d E N P

    / / Z

    / e Z

    / e Z

    1/1 x x x

    =

    i i F B F B

    i i F

    ii

    B

    ( E N E ) / k T ( E ) / k T

    i ( E N E ) /

    N

    k T

    i

    Ee eP

    e Z

    Coulomb interactionforbids this configuration

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    Statistics of Donor Levels

    Alam ECE-606 S09 10

    0 0 0 0 1

    0 1 1 1

    1 0 1 1

    i F

    B

    i F

    B

    i i i

    ( E E )

    k T

    ( E E )

    k T

    u / d E N P

    / / Z

    / e Z

    / e Z

    00

    00

    00 01 102

    1 1

    1 2 1

    = = =+ + + +i F B F i B( E E ) / k T ( E E ) / k T

    P / Zf

    P P P / Z e / Z e

    00

    1 11 1

    1 11

    2

    2

    = =+

    +F i B

    i F B

    ( E E )/ k T ( E E ) / k T

    fe

    e

    Prob. that the donor

    is empty (charged)

    Prob. that the donor

    is filled with at least

    one electron (neutral)

    Note the extra factor .

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    Coulomb Exclusion for Band Electrons?

    Alam ECE-606 S09 11

    0 0 0 1

    1 1 1

    i F

    B

    ( E E

    i

    )

    i

    T

    i

    k

    state E N P

    / Z

    e Z

    i i F B i i F B

    i i F B

    ( E N E ) / k T ( E N E ) / k T

    i ( E N E ) / k T

    i

    e eP

    e Z

    =

    Ei

    E=0

    E=2

    E=4

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    Localized vs. Band Electrons

    12

    E1 2/Lx

    E2 4/Lx

    E3 6/Lx

    E4 8/Lx

    E5 10/Lx

    E6 12/Lx

    E1 2p/(Lx/2)

    E2 4/(Lx/2)

    E3 6/(Lx/2)

    Lx

    Lx/2 Lx/2

    Two electrons (even withopposite spin) can notbe at the same positionand same energy becauseof electrostatic repulsion

    Band electrons (withopposite spin) need not

    be at the same position,so they can share occupysame energy level.

    When we divide space by a factor of 2, the

    number of states (e.g. 6 here) does not change.

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    Acceptor Atoms

    Alam ECE-606 S09 13

    State [1] . Hole present N-1 charges

    State [0] Hole filled . N charges

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    Statistics of Acceptor Levels in Si and Ge

    14

    1. Each atom contributes 2 states (up & down spin)

    to a band, therefore a band has 2N states.

    2. Every time a host atom is replaced by a impurity

    atom, 2 states are disappear per a band and

    appear as localized states (sort of).

    3. Therefore an acceptor atom close to hh and lh

    bands removes four states from those bands.

    4. Because of Coulomb interaction only 1 hole can

    seat in these 4 states: the states are

    0000, 0001, 0010, 0100, 1000.

    5. One now uses Pi to compute the occupation of

    acceptors.

    from lh

    from hh

    EC

    EV

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    Number and Energy Considerations

    Alam ECE-606 S09 15

    4N-4 States

    In HH/LH bands0000 1000 0100 0010 0001

    1) [0000] is the charged state as it has N electrons, but N-1 protons.

    2) Single hole configuration [0001] is uncharged, as we have N-1

    electrons, and N-1 protons same is true for [0010], [0100], [1000]

    states.

    3) Going from [0000] to [0001] states, the number of electrons goesdown by 1 (Ni=-1).

    4) Going from [0000] to [0001] states energy goes down by EA,

    because one electron is no longer occupying the high energy level at

    EA.

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    Statistics of Acceptor Levels

    Alam ECE-606 S09 16

    0000 1000 0100 0010 00010 0

    0000

    1F B

    i i F B

    ( xE ) / k T

    ( E N E ) / k T

    i

    eP

    e Z

    =

    1

    0001 0010 0100 1000

    A F B A F B

    i i F B

    ( E ( )E ) / k T ( E E ) / k T

    ( E N E ) / k T

    i

    e eP P P P

    e Z

    = = = =

    Steps 3 & 4

    0000

    0000

    1000 0100 0010 0001

    1

    1 4

    = =+ + + + A F B( E E ) / k T

    Pf

    P P P P e

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    Filled and empty Donor/Acceptor Levels

    Alam ECE-606 S09 17

    00

    1

    1 2

    = =+ F i B

    D D ( E E )/ k T N f N

    e

    [ ]0000

    =filled

    A A A N N N f

    2N-2 states

    4N-4 States

    In HH/LH bands

    (Two holes can not seat together)

    0000 1000 0100 0010 0001

    00 10 01 +emptyD DN N

    1

    1 4

    =

    +A F B

    A ( E E ) / k T N

    e

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    Distributions are physical .

    Alam ECE-606 S09 18

    1

    =+ F D B

    DD ( E / T

    D

    E ) k g

    Nfe

    1 1

    = =+ +F D B F

    'B D B

    D DD ( E E ) / k k T ET ( E ) / k T

    N Nf

    e e e

    Degeneracy factor

    Effective donor level

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    Summary

    Alam ECE-606 S09 19

    0ADN p n dV N+ + + =

    0AD

    Nn Np + + + =

    10

    12 4

    F V B C F B

    F D A F BB

    ( E E ) / k T ( E E ) / k T A

    ( E E ) / V AD

    ( E E ) k/ k TT

    Ne e

    eN N

    N

    e

    + + + =

    A bulk material must be charge neutral over all

    Further if the material is spatially homogenous

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    Conclusions

    Alam ECE-606 S09 20

    Intrinsic concentration of electrons in a semiconductor is

    relatively small.

    The statistics of dopant levels are different because they are

    close to the conduction band and because they are localized.

    Influenced by pair-wise coulomb repulsion.

    The statistics of donor and acceptor atoms are also different,

    because donor levels couple with single conduction band,while acceptor levels couple with two valence bands.