principles of chemical equilibrium

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Principles of chemical equilibrium Unit1: module 2: kinetics and equilibria: objectives 2.1   2.7.

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Page 1: Principles of Chemical Equilibrium

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Principles of chemical equilibrium

Unit1: module 2: kineticsand equilibria:objectives 2.1 –  2.7.

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• not all reactions proceed to completion.

• some end up with a mixture of reactants and products.

• this is because some reactions are reversible; products can revert back to

reactants.

• As the rate of reaction is dependant on the concentration of reactants:

 the forward reaction starts off fast but slows as the reactants get less

concentrated.

 initially, there is no backward reaction but, as products form, it will get faster.

 provided the temperature remains constant there will come a time when the

backward and forward reactions are equal and opposite ; the reaction has

reached equilibrium.

•Dynamic equilibrium

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• a reversible chemical reaction is a dynamic process.

• everything may appear stationary but the reactions are moving both ways.

• the position of equilibrium can be varied by changing certain conditions.

• Trying to get up a “down” escalator gives an excellent idea of a non-chemical

situation

• involving dynamic equilibrium.

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• It is dynamic: molecules of reactants are continually being converted to

products and molecules of products are continually being converted to

reactants.

• At equilibrium the rate f the forward and backward reactions are equal.

• The concentration of reactants and products at equilibrium do not change.They are constant. This is because the rates of forward and backward reactions

are the same.

• Equilibrium only occurs in closed systems. A closed system is one where none the

reactants or products escapes from the reaction mixture. Many reactions,

however, can take place in open beakers if the reaction takes place in solution

and no gases are involved.

•The characteristics of a system in

dynamic equilibrium

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• There are several forms of the constant; all vary with temperature:

1.  Kc :the equilibrium values are expressed as concentrations of mol dm-3.

2.  Kp :the equilibrium values are expressed as partial pressures.

• Calculating Kc : for a reaction of the form aA + bB cC + dD

then (at constant temperature) Kc  =[C]c.

 [D]d

 [A]a . [B]b 

[ ] denotes the equilibrium concentration in mol dm-3.

Kc is known as the Equilibrium Constant.

The ratio of the molar concentration of the products to reactants is at a constant

temperature, each being raised to a power indicated by their molar amounts in the

balanced equation.

•The terms  

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• Kp :

Mole fraction: for reactions involving mixtures of gases, it is easier to measure

pressures than to measure concentrations . When we are dealing with mixtures of

gases we need to know the fraction of a particular gas present in the mixture in

terms of moles. This is called the mole fraction.

Mole fraction ( )=

 

Example: In a mixture of 0.2 mol H2

 and 0.3 mol O2

 the mol fraction is=.

.+.3= 0.4 

Partial pressure: the pressure exerted by molecules of particular gas in a mixture of

gases is called the partial pressure of that gas. Symbol, P. The partial pressures of all

gases in the mixture add up to the total pressure, PT  = … 

Example: a mixture of gases contains 1.2 mol N2 , 0.5 mol H2 and 0.3 mol of O2 . The

total pressure is 8.0 x 105 kPa. Calculate the partial pressure of hydrogen.

Partial pressure of hydrogen= (8.0 x 105 ) ×.5

.+.3= 2 × 105 

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• The value of Kc for the reaction: 3 5 35  

ethanoic acid ethanol ethyl ethanoate water

can be found using a titration method. The reaction is catalysed by an acid.

• The procedure is:

1. Make up mixtures of known concentration and volumes of the acid reactants and

catalyst, e.g. 2 cm3 water, 2cm3 ethanol, 1cm3 ethanoic acid and 5cm3 of 2 moldm-3 

HCl. (you could also start with known amounts of ethyl ethanoate, water and acid.)

2. Use a burette to deliver each of the liquids into a stopped bottle. Shake the mixture well

and allow it to stand for 1 week at room temperature to reach equilibrium.

3. After 1 week, titrate the whole of the mixture with 1 moldm-3 sodium hydroxide using

phenolphthalein as an indicator. During the time, the amount of acid in the reaction

mixture decreases as the ethanoic acid reacts with the ethanol.

4. Find the exact concentration of hydrochloric acid catalyst you added by a similar

titration.

•Determining a value of Kc by

experiment

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Definition ”When a change is applied to a system in dynamic equilibrium, the  system reacts in such a way as to oppose the effect of the change.” 

• Everyday example :A rose bush grows with increased vigour after it has been

pruned.

• Chemistry example :If you do something to a reaction that is in a state of

equilibrium, the equilibrium position will change to oppose what you have just

done.

•Le Chatelier’s principle

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• Concentration The equilibrium constant is not affected by a change in

concentration at constant temperature. To maintain the constant the

composition of the equilibrium mixture changes.

Example Look at the equilibrium in question Q.4. If the concentration of C is

increased, the position of equilibrium will move to the LHS to oppose the change.

This ensures that the value of the equilibrium constant remains the same.

• Pressure When studying the effect of a change in pressure, we consider thenumber of gaseous molecules only. The more particles you have in a given

volume, the greater the pressure they exert. If you apply a greater pressure they

will become more crowded (i.e. they are under a greater stress). However, if the

system can change it will move to the side with fewer gaseous molecules as they

will now be in a less crowded environment.

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• Temperature: Temperature is the only thing that can change the value of the

equilibrium constant. Altering the temperature affects the rate of both

backward and forward reactions but to different extents. The equilibrium thus

moves producing a new equilibrium constant. The direction of movement

depends on the sign of the enthalpy change.

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• An increase in temperature is used to speed up chemical reactions but it can

have an undesired effect when the reaction is reversible and exothermic. In this

case you get to the equilibrium position quicker but with a reduced yield

because the increased temperature moves the equilibrium to the left. In many

industrial processes a compromise temperature is used (see Haber and Contact

Processes). To reduce the problem one must look for a way of increasing the

rate of a reaction without decreasing the yield i.e. with a catalyst.

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• Catalysts Adding a catalyst DOES NOT AFFECT THE POSITION OF EQUILIBRIUM.

However, it does increase the rate of attainment of equilibrium. This is

especially important in reversible, exothermic industrial reactions such as the

Haber or Contact Processes where economic factors are paramount. Catalysts

work by providing an alternative reaction pathway involving a lower activationenergy.

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C diti E ilib i iti I d Di ti f

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Condition Equilibrium positionaffected

Increase decrease Direction ofshift

Concentration/partial pressure, PP

yes [reactant] - Right

- [product] Right

- [reactant] Left

[product] - Left

Total pressure, P T Yes, but only for gases and

when there is a volumechange.

PT  - Direction of

smallervolume

- PT  Direction ofsmallervolume

Temperature, T yes T - Endothermicdirection

- T exothermicdirection

catalyst no - - -