· presentation of the context . organization of ideas . style and choice of words . questions 22...

ANSWER KEY

First Year Higher Secondary Examination March 2020

Communicative English Code No: FY – 22

Qn No Value Points Split Score Total Score

1

2

3

4 a

b

5

6

7

8

9

Questions 1 to 6 (answer all)

from, to, of, with

tall / green

feedback

to go back

to illustrate

What do you like for breakfast?

listen

Questions 7 to 11 (answer any three)

king, prince

Two meaningful sentences with words or phrases expressing

advice like

you must, you should. you ought to, you have to,

If I were you, you had better, why don’t you etc

Radio Text

Meaningful sentences conveying the idea like the following

• The opposition leader said that the government had

created the problem.

• The opposition leader said, the government had created

the problem.

• The government had created the problem, said the

1+1+1+1

1

1

1

1

1

1

1+1

1+1

4

1

1

2

1

1

2

2

10

11 a

b

12

13

14

15

16

opposition leader.

News headline

Any short relevant news headline

Example

• Artificial intelligence makes computer a human being.

• Artificial intelligence gives a human touch to computer.

True

False

Questions 12 to 17 (answer any four)

Recipe

Name of the dish

Ingredients

Method of preparation

Cookery diction and sequencing

Four relevant arguments supporting the motion with proper

expressions

Possible expressions suitable for the context

In my opinion

In my view

I agree with

I support the topic

Notice

Format

Content with relevant details

Framing questions

Relevant questions

structure of questions

Expressing views

1 x 2

1 x 2

1

1

1

1

1

1

1+1+1+1

2

2

1+1+1+1

2

2

2

4

4

4

4

17

18

19

20

21

22

Meaningful sentences with words or phrases expressing views

like

In my opinion, In my view, I think , As far as I am concerned etc

Name of the profession

Reasons for the choice and how to accomplish

Apt expressions and language

Questions 18 to 21 (answer any two)

Content relevant to the topic

Logical sequencing of ideas

Style and choice of words

Report

Title

Logical presentation of the matter

Details of special attraction

Language and style

Complaint letter

Format and formal language expressing complaint

Organization of ideas

Introducing the topic

Presentation of the context

Organization of ideas

Style and choice of words

Questions 22 to 26 (answer any three)

Application letter with CV

Application letter

CV

1 x 4

2

2

2

2

1

1

2

1

1

3

2

1

2

1

1

3

3

4

4

5

5

5

5

6

23

24

25

26

Brochure

Title

Catchy and brief introduction

Content and subtitles

Choice of words

Details of services, facilities, destination

Catchy caption

Speech

Salutation and conclusion

Introducing the topic

Logical presentation of ideas

Appropriate language or choice of words

Telephonic conversation

Telephone etiquette

Relevant exchanges

Meaningful questions and sentences

Logical presentation of the matter

Content with relevant details

Choice of words and style of language

1

1

1

1

1

1

1

2

2

1

2

2

2

2

2

2

6

6

6

6

Reeson K A

9496169094

ANSWER KEY

FIRST YEAR HIGHER SECONDARY EXAMINATION MARCH-2020

SUBJECT: BOTANY SCORE :30

Qn. No.

Sub. Qns

Answer key/ Value points Score Total Score

I 1 (c) / Mitochondria 1 1 2 (a)/Dicot root 1 1

3 Euglena 1 1

4 Anaphase 1 1

5 2 1 1

II 6 a. b.

Facilitated diffusion/Facilitated transport Diffusion in which hydrophilic substances move across a membrane along the concentration gradient through certain transport molecules in the membrane/ Diffusion facilitated by the protein/ movement of particles through transport protein without using ATP

1 1

2

7 a. b. c. d.

Synapsis/ chromosome start pairing/ formation of synaptonemal complex/ formation of bivalent or tetrad Pachytene Diplotene Terminalisation of chiasmata/ Nucleolus disappears/ Nuclear envelope breaks/ Chromosomes fully condensed

½

½ ½ ½

2

8. Growing plants in nutrient solution/ Soil less culture . essential elements were identified/ Deficiency symptoms discovered / commercial production of vegetables/ To make kitchen gardens/ production of seedless cucumber, tomato, lettuce/ relevant such other response (any One response)

1 1

2

9.

Lysosome Golgi apparatus Ribosome

. Rich in hydrolytic enzymes / (d)

. Made up of many flat, disc shaped sacs or cisternae / (b)

. Involved in protein synthesis . Membrane is absent / (a), (e)

½ x4

2

10 a. b.

Non-cyclic / Z scheme manner / Zig Zag manner 1 / PS I / P 700

1+1

2

c. d.

2 / PS II / P700 and P680

Absent (any Two correct responses give full score)

11 a. b.

The breakdown of glucose in to pyruvic acid Cytoplasm / cytosol

1 1

2

12 a. b. c.

A. Mesophyll Cell B. Bundle sheath cell OAA/ Malic acid / Aspartic acid PEP carboxylase / PEP case

1 ½ ½

2

13 a. b.

Respiration takes place in the absence of oxygen/ Incomplete oxidation of glucose in anaerobic condition/ fermentation Converted to ethanol (ethyl alcohol, C2H5OH) and CO2

1 1

2

14 a. b.

Carboxylation, Reduction, Regeneration / Schematic representation of Calvin cycle First stable product is a 3 C compound/ 3-PGA/ 3-Phosphoglyceric acid ( If a or b is correct give full score)

2

2

15

A B a. Double fertilisation angiosperm/ v

b. Heterospory pteridophyte/ gymnosperm/angiosperm/iv/iii/v

c. Protonema Bryophyte/ i

d. Naked seeds Gymnosperm/ iii

½ ½ ½ ½

2

16 a. b.

Schleiden and Schwann . all living organisms are composed of cells and product of cells . all cells arise from pre-existing cells

1 ½ x2

2

III

17 a. b. c.

A. Twisted B. Vexillary/ Papilionaceous One margin of each member overlap that of the next one and so on/ regular overlapping Standard petal, wing (lateral) petals, keel petal (anterior small petal)

1 ½ ½ x3

3

18 a. b. c.

Auxin, Cytokinin, Gibberellin ABA/Abscisic acid . inhibit seed germination/stimulate the closure of stomata/helps to withstand desiccation/antagonist to Gibberellin/seed dormancy/ seed maturation/seed development (any Two responses)

½ x3 ½ ½ x2

19 a. b.

Reticulate, Parallel (regardless of mentioning A and B) Arrangement of veins and veinlets in the leaf lamina

2 1

3

20

. present between upper and lower epidermis . made up of parenchyma cells . divided in to palisade and spongy parenchyma . adaxially placed cells are palisade . palisade cells are elongated . palisade cells are arranged vertically and parallel to each other . spongy parenchyma cells are oval or round . spongy parenchyma cells are situated below palisade and extends to the lower epidermis . spongy parenchyma is loosely packed with air cavities . palisade parenchyma contains more chloroplast . spongy parenchyma contains less chloroplast . perform photosynthesis (any Three responses)

1x3

3

BINOY V M - 9605866895

FIRST YEAR HIGHER SECONDARY EXAMINATION, MARCH 2020

PART-III ZOOLOGY (Max Score :30)

I-Answer any 3 questions from 1 to 5.Each question carries 1 Score

Qn Answer key Score

1 c) / Carbonic anhydrase 1

2 Amino acids 1

3 b) / Sarcomere 1

4 b) / Comb plates, Bio luminescence 1

5 (a) / Taxon / ( b) / Species 1 II-Answer any 9 questions from 6 to 16.Each question carries 2 Score

6 Amoeboid movement- with the help of Pseudopodia/WBC movements/Cytoskeltel elements Ciliary Movement- with the help of Cilia/Fallopian tubes / trachea. etc

Muscular movement- with the help of Muscles/ intestine/peristalsis. etc (any two movements and its parts) 1 + 1 =2

7 a) Uremia ½ b)Renal Calculi/Kidney Stone ½ c)Kidney Transplantation ½

d)Glomerulonephritis ½

8 Class Amphibia (i) & (iv) OR Skin is moist without scales & Can live in aquatic as well as terrestrial habitat. Class Reptilia (ii) & (iii) OR

Body is covered by dry and cornified skin. & Shed the scales as skin cast

1

1

9 Enzyme molecules are fewer than substrate molecules and after saturation of 2 substrate molecules; there are no free enzyme molecules to bind with additional substrate

molecules.

10 Active transport- against the concentration gradient/ Energy required. Simple diffusion- depends on concentration gradient/ from higher concentration to lower concentration/ Energy not required.

1

1

11 a)IRV(Inspiratory Reserve Volume) / ½ Additional volume of air a person can inspire by a forcible inspiration/

2500 ml to 3000ml

ERV(Expiratory Reserve volume ) /

Additional volume of air a person can Expire by a forcible Expiration/ ½

1000 ml to 1100ml

b) Tidal Volume / ½

Volume of air inspired or expired during a normal respiration./

500ml

Residual Volume /

Volume of air remaining in the lungs even after a forcible expiration/ ½

1100ml to 1200ml

12 Gastric juice : Pepsin/ Rennin/ Lipase (any one) Intestinal juice: Lipase Pepsin : Proteolytic enzyme /Protein Digesting/ Proteins to Peptones

Rennin : Proteolytic enzyme / Protein Digesting/ of infants Lipase: Lipolytic enzyme / Lipid or Fat digesting. ( function of any two enzymes)

½ ½

½ + ½

13 a) Renin ½

b)Angiotensin-I c) Aldosterone d) Rise in GFR/ Increased GFR/Increases

½ ½ ½

Page: 1/2

1.Manoj Kumar P (11041) , Malappuram – MOB: 9847554332

2. Dr.Archana Devi T , Alappuzha

3. Sabu K, Kasaragod

4. Dileep K , Kozhikode

5. K R Unnikrishnan , Thrissur

6. Shanto Mathew ,wayanad

Page:2/2

14 Adrenal Cortex Adrenal Medulla

Secrete corticoids/ carbohydrate metabolism/

regulation of water-electrolyte balance/ metabolism of minerals /

development of sex characters like growth of hairs ,etc

(Any 2 points= 1 score)

They secrete Epinephrine/ Adrenaline and Nor epinephrine/Noradrenaline (Catacholamine)/ emergency hormone/ fight or flight hormones/any one function( increase alertness, sweating, increase heart beat etc) (Any 2 points= 1 score)

2

15 a)Uric acid 1 b)Malpighian tubules, Fat body, Urecose gland, Nephrocytes (Any two) 1

16 • Cartilage cells are called Chondrocytes 1 • Intercalated discs are seen in Cardiac muscle / Heart muscle 1

III-Answer any 3 questions from 17 to 20. Each question carries 3 Score

17

a)ECG/Electrical activity of heart/Polarisation and Depolarisation /flow of cardiac impulse. ½

b)P-Wave: Electrical Excitation/Contraction/ systole/Depolarisation of atria ½

QRS-Wave-Depolarisation / contraction / systole of ventricle ½

T-Wave- Return to normal state / relaxation/dlastole/ Repolarisation of ventricle ½

c)Deviation indicates abnormality / Heart attack/ any other heart disease 1

18 A-Testis ½ B-Thymosin ½

C-Provide immunity/ differentiation of T lymphocytes/development of immune system ½

D-Pancreas ½

E-Melatonin ½

F-Regulate 24 hour cycle/ Diurnal rhythm / Biological clock/ Any other function (metabolism,pigmentation,defence etc). ½

19 A-Balanoglossus-Phylum Hemichordata ½ + ½ B-Nereis-Phylum Annelida ½ + ½ C-Liver Fluke /Fasciola-Phylum Platy helminthes (Flat worms) ½ + ½

20 a)A-lens B-Optic nerve 1 b)Fovea/Macula Lutea/Yellow spot -Thinned out part of retina/with more cones/maximum vision 1

c)Cornea Aqueous chamber Lens Vitreous chamber Retina 1

ANSWER KEY FIRST YEAR HIGHER SECONDARY EXAMINATION MARCH 2020 MATHEMATICS (SCIENCE)

Qn.No

Sub Qn

ANSWER KEY VALUE POINT

Score Total score

1) i) ii) iii)

(B) n(A)=0 ------------------ -------------------------→ (B) {x/x€R,6<x<12} ---------------------------------→ (C) B, ---------------------------------------------------→

1 1 1

3

2) n(u)=600 Tea=A, n(A)=150 Coffee=B, n(B)=225 n(A∩B)=100 n(AUB)=n(A)+n(B)-n(A∩B) ----------------------→ =150+225-100 =275 ---------------------------------------→ n(neither tea nor coffee)=n(A'∩B') ---------→ =n(U)-n(AUB) =600-275 =325---------------→ Remarks ii)n(A'∩B')=n(AUB)'=n(U)-n(AUB)-------→(1/2) iii) Correct answer using Venn diagram, score(3) Type equation here.

1 1/2 1/2 1

3

3)

Cosec(x)=-2 Sin(x)=-1/2 X is in the third or fourth quadrant

X= π+𝜋

6 =

7𝜋

6 ---------------------------------→

X= 2π - 𝜋

6 =

11𝜋

6 -------------------------------→

Principal solutions are 7𝜋

6 and

11𝜋

6

Sin(x)=-1/2

Sin(x)=Sin(7𝜋

6)

1 1/2

3


4)

i) ii)

General solution x=nπ+(−1)𝑛y -----------------→

X=nπ+(−1)𝑛 7𝜋

6 ----------------→

Remarks One of the principal solutions is correct, Score(1) (C) 0 --------------- ----------------------------------→ a=-3/4

r=(

3

16)

(−3

4)=

−1

4 ----------------------------------→

𝑆𝛼=𝑎

(1−𝑟) --------------------------------------→

=−(

3

4)

(1−(−1

4))

= (

−3

4)

(5

4)

=-3/5 ----------------→

1 1/2 1 1/2 1 1/2

3

5) 7+77+777+-----------nterms =7[1+11+111+-----n terms]-----------→ =7/9[9+99+999+---n terms]-------→ =7/9[10-1+100-1+1000-1+---n terms] =7/9[(10+100+1000+--)-(1+1+1+--)-------→

=7/9[10(10𝑛−1)

10−1− 𝑛]

=7/9[10(10𝑛−1)

9− 𝑛]-------------→

Remarks

i) 𝑆𝑛 =𝑎(𝑟𝑛−1)

(𝑟−1), 𝑠𝑐𝑜𝑟𝑒(1)

1/2 1/2 1 1

3

6) i)

P=(3,4,5) Q=(0,4,0)


ii)

PQ=√(𝑥2 − 𝑥1)2 + (𝑦2 − 𝑦1)2 + (𝑧2 − 𝑧1)2

=√9 + 0 + 25

= √34---------------------------------→ 𝑥1=3 𝑥2=0 m=2 𝑦1=4 𝑦2=4 n=3 ----------------------→ 𝑧1=5 𝑧2=0

(x,y,z)=[𝑚𝑥2+𝑛𝑥1

𝑚+𝑛,

𝑚𝑦2+𝑛𝑦1

𝑚+𝑛,

𝑚𝑧2+𝑛𝑧1

𝑚+𝑛] -----→

= (9/5,4,3) ----------------------------------→ Remarks i)Distance formulae, score (1/2) ii)Section formulae ,score (1)

1/2 1/2 1/2 1 1/2

3

7)

𝑑𝑦

𝑑𝑥= lim

ℎ→0

𝑓(𝑥+ℎ)−𝑓(𝑥)

ℎ ----------------→

𝑓(𝑥)=cos(x)

𝑓(𝑥+ℎ)=Cos(x+h)

𝑓(𝑥+ℎ) − 𝑓(𝑥) = 𝐶𝑜𝑠(𝑥 + ℎ) − 𝐶𝑜𝑠(𝑥)

= -2Sin(2𝑥+ℎ

2)𝑆𝑖𝑛(

ℎ

2)------→

𝑓(𝑥+ℎ)−𝑓(𝑥)

ℎ=

−2𝑆𝑖𝑛(2𝑥+ℎ

2)𝑆𝑖𝑛(

ℎ

2)

ℎ

𝑑𝑦

𝑑𝑥= =lim

ℎ→0


2)𝑆𝑖𝑛(

ℎ

2)

ℎ

=limℎ→0


2)𝑆𝑖𝑛(

ℎ

2)ℎ

2.2

=-Sin(x) ----------------------→

1 1 1/2 1/2

3


8)

i) ii)

Remarks

i) Cos(x)-Cos(y) = −2𝑆𝑖𝑛 (𝑥+𝑦

2) 𝑆𝑖𝑛(

𝑥−𝑦

2) --→(1)

iii) 𝐷𝑖𝑟𝑒𝑐𝑡 𝑑𝑦

𝑑𝑥 =-sinx, score (1)

(c) 1275-----------------------------→ 𝑓(0)=lim

𝑥→ō𝑓(𝑥)

= lim(𝑥→ō)

|𝑥|

𝑥

=lim𝑥→0

−𝑥

𝑥

=-1 ---------------------------------------------→

𝑓(0+)= lim𝑥→0+

|𝑥|

𝑥

=lim𝑥→0

𝑥

𝑥

=1 --------------------------------------------→

𝑓(ō)≠𝑓0+) Limit does not exist ------------------------------→ Remark

i) Concept of left hand or right hand limit ,score (1)

ii) Definition of |𝑥|, 𝑠𝑐𝑜𝑟𝑒 (1)

1 1 1 1/2 1/2

3

9) (a) (b) (c) (d)

(ii) f:R→R given by f(x)=𝑥3 ----------------------

(iv) f:R→R given by f(x) = {1, 𝑥 > 00, 𝑥 = 0

−1, 𝑥 < 0}……

(iii) f:R→R given by f(x)= 𝑥 …………→

(i) f:R→R given by f(x)= 1

𝑥 --------→

1 1 1 1

4


Remark i) any answer for part( b) , score (1)

10)

P(n)=7𝑛 − 3𝑛 P(1)= 71 − 31 =4 →P(1) is true ------------------------------→ Assume that P(k) is divisible by 4

P(k) =7𝑘 − 3𝑘 is divisible by 4

7𝑘 − 3𝑘=4 𝑥

7𝑘 = 3𝑘 +4 𝑥 ------------------------→

P(k+1)= 7𝑘+1 − 3𝑘+1 --------------------------→

=7𝑘.7-3𝑘.3

=(3𝑘 +4 𝑥).7- 3𝑘.3

=7. 3𝑘 +28 𝑥-3𝑘.3

=4. 3𝑘+28 𝑥

=4(3𝑘 + 7 𝑥) ----------------------------→ Hence P(k+1) is true

𝑝(𝑛)𝑖𝑠 𝑡𝑟𝑢𝑒 𝑓𝑜𝑟 𝑎𝑙𝑙 𝑛ɛ𝑧

Remark Idea of principle of mathematical induction, score(1)

1 1 1 1

4

11) i)

|𝑧|=r=2

arg(z)=𝜋

3


ii)

Z=r(Cosθ+iSinθ) --------------------------------→

=2(Cos 𝜋

3+iSin

𝜋

3)

=2(1

2+i

√3

2)

=1+i√3 -----------------------------------------→

√1 + √3i=x+iy

𝑥2-𝑦2=1, 2xy=√3 ----------------------------→ 𝑥2+𝑦2=2 ( solve these equations) 2𝑥2=3 𝑥2=3/2

X=±√3

2 ------------------------------------------→

Y=±√1

2 ----------------------------------------------→

√1 + √3𝑖 ==√3

2+ √

1

2i OR −√

3

2− √

1

2i ---→

Remarks i)part (ii) is correct using the complex number in part(i) , score (3)

(ii) Full score for correct x,y using equations ,score(3)

½ ½ 1 1/2 1/2 1

4

12)

2x+y≥4 points are (0,4) and (2,0)---------→ X+y≤3 points are (0,3) and (3,0)-----------→ 2x-3y≤6 points are (0,-2) and (3,0)---------→

1/2 1/2 1/2


13)

i)

Remarks

i) Incorrect shaded region with correct

lines, score(3𝟏

𝟐)

ii) Correct graph using any other points ,score (4)

(𝒙 +𝟏

𝒙)𝟔=6 𝒄𝟎𝒙𝟔+6 𝒄𝟏𝒙𝟓 𝟏

𝒙+6 𝒄𝟐𝒙𝟒 𝟏

𝒙𝟐+

6 𝒄𝟑𝒙𝟑 𝟏

𝒙𝟑 +6 𝒄𝟒𝒙𝟐 𝟏

𝒙𝟒 +6 𝒄𝟓𝒙𝟏 𝟏

𝒙𝟓+6 𝒄𝟔𝟏

𝒙𝟔

=𝒙𝟔 + 𝟔𝒙𝟒 + 𝟏𝟓𝒙𝟐 + 𝟐𝟎 +𝟏𝟓

𝒙𝟐 +𝟔

𝒙𝟒 +𝟏

𝒙𝟔

2𝟏

𝟐

1 1

4 4


ii)

(𝒙

𝟑+ 𝟗𝒚)𝟏𝟎

n=10 is even only one middle term -------→

term is (𝒏

𝟐+1) =6 th term ---------→

𝒕𝟔=10𝒄𝟓(𝒙

𝟑)𝟓(𝟗𝒚)𝟓

=252×𝒙𝟓

𝟑𝟓 ×𝟗𝟓 ×𝒚𝟓

= 61236 𝒙𝟓𝒚𝟓 --------→ Remark

i)𝒄𝒐𝒓𝒓𝒆𝒄𝒕 𝒆𝒙𝒑𝒂𝒏𝒔𝒊𝒐𝒏 𝒐𝒇 (𝒂 + 𝒃)𝟔 ,score (1)

ii)𝒕𝒓+𝟏 = 𝒏𝑪𝒓𝒂(𝒏−𝒓)𝒃𝒓 ,score (1)

iii)𝒄𝒐𝒓𝒓𝒆𝒄𝒕 𝒆𝒙𝒑𝒂𝒏𝒔𝒊𝒐𝒏 𝒐𝒇(𝒂 + 𝒃),𝒏 , 𝒔𝒄𝒐𝒓𝒆(𝟏

𝟐)

1/2 1/2 1

14 i)

Path traced by P is a circle Centre =(1,2)

Radius =√(𝑥2 − 𝑥1)2 + (𝑦2 − 𝑦1)2 --------→

=√(3 − 1)2 + (5 − 2)2

=√(2)2 + (3)2

=√4 + 9

=√13 --------→

Equation of circle (𝑥 − 𝑥1)2 + (𝑦 − 𝑦1)2=𝒓𝟐 --------→

(𝑥 − 1)2 + (𝑦 − 2)2=(√13)𝟐

(𝑥 − 1)2 + (𝑦 − 2)2=𝟏𝟑 --------→

1/2 1/2 1/2 1/2


ii) (a) b)

a=3 b=2

Equation of ellipse 𝒙𝟐

𝒃𝟐 +𝒚𝟐

𝒂𝟐 = 1 --------------→

𝒙𝟐

𝟐𝟐 +𝒚𝟐

𝟑𝟐 = 1

𝒙𝟐

𝟒+

𝒚𝟐

𝟗 = 1 ----------------------------→

𝒄𝟐 = 𝒂𝟐 - 𝒃𝟐 ------------------------→

=𝟑𝟐 - 𝟐𝟐=5

C =√𝟓 Foci =(0, ±𝒄)

=(𝟎, ± √𝟓) ------------------------→ Remark ii)If a=2 and b=3, score (1/2)

1/2 1/2 1/2 1/2

4


15 16

i) ii) i)(a)

Contra positive If a number is not divisible by 3 ,then it is not divisible by 9 ------------------------→

Let √5 is rational,

√5= 𝒂

𝒃 ,a and b have no common

factors ------------------------------→

√5b =a 5𝒃𝟐 =𝒂𝟐

a is divisible by 5 --------------→ a = 5c 𝒂𝟐=25𝒄𝟐 5𝒃𝟐=25𝒄𝟐 𝒃𝟐 =5𝒄𝟐 𝒃 𝒊𝒔 𝒅𝒊𝒗𝒊𝒔𝒃𝒍𝒆 𝒃𝒚 𝟓 ---------------→ 𝒂 𝒂𝒏𝒅 𝒃 𝒉𝒂𝒗𝒆 𝒄𝒐𝒎𝒎𝒐𝒏 𝒇𝒂𝒄𝒕𝒐𝒓𝒔 It contadicts our assumption

√5 is irrational

P(E orF)=P(EUF) =P(E)+P(F)-P(E∩F) -------------------→

1 1 1/2 1/2 1 1/2

4


17

(b) ii)(a) b) i)

= 𝟏

𝟒+

𝟏

𝟐−

𝟏

𝟖=

𝟓

𝟖 -----------------------------→

P(not E and not F) =P(E'∩ F') =P(EU F)ˡ =1-P(EUF) ---------------→

=1 - 𝟓

𝟖=

𝟑

𝟖 ----------→

n(s) = 4 𝒄𝟐=6 -------------------------------→ A = one man = one man and one woman = 2 𝒄𝟏x 2 𝒄𝟏=4

P(A) = 𝒏(𝑨)

𝒏(𝑺) =

𝟒

𝟔 =

𝟐

𝟑 --------------→

B= two men n(B) = 2 𝑪𝟐=1 -------------------------------→

P(B) = 𝒏(𝐵)

𝒏(𝑺)=

𝟏

𝟔 -----------------------→

Remarks i)P(EUF) =P(E)+P(F)-P(E∩F), score (½) ii)P(not E and not F) = P(E'∩ F'), score(1/2)

iii)P(A) =𝒏(𝑨)

𝒏(𝑺) score (1/2)

𝐭𝐚𝐧 𝐱 =-5/12 cot x = -12/5 Sin x= 5/13 cosec x =13/5 ------→ Cos x= -12/13 sec x = -13/12

1/2 1/2 1/2 1/2 1/2 1/2 1/2 2

4


18

ii) iii) i) ii)(a)

Remark Four correct values, score (2)

tan x= ¾ 𝐬𝐢𝐧 𝐱+𝐜𝐨𝐬 𝐱

𝐬𝐢𝐧 𝐱−𝐜𝐨𝐬 𝐱 =

𝐭𝐚𝐧 𝐱+𝟏

𝐭𝐚𝐧 𝐱−𝟏 (dividing by cos x)

= 𝟑

𝟒 +𝟏

𝟑

𝟒 −𝟏

= 𝟕

𝟒

−𝟏

𝟒 =-7----------→

𝐬𝐢𝐧 𝟓𝐱+𝐬𝐢𝐧𝟑𝐱

𝐜𝐨𝐬𝟓 𝐱+𝐜𝐨𝐬 𝟑𝐱 =

𝟐𝐬𝐢𝐧𝟒𝐱𝐜𝐨𝐬𝐱

𝟐𝐜𝐨𝐬𝟒𝐱 𝐜𝐨𝐬𝐱 =

𝒔𝒊𝒏𝟒𝒙

𝒄𝒐𝒔𝟒𝒙=tan4x

Remarks

i) sinx+siny=2sin(𝒙+𝒚

𝟐)𝒄𝒐𝒔 (

𝒙−𝒚

𝟐), score(1/2)

ii) cosx+cosy=2cos(𝒙+𝒚

𝟐) 𝒄𝒐𝒔 (

𝒙−𝒚

𝟐),

score(1/2) D=1 ,A=1 ,U=1 ,G=1 ,H=1, T=1, E=1, R=1 Vowels=A,E,U Vowels=3 Consonants = 5 Vowels together No of words = 6! X 3! = 4320 -----→ Remarks Any method with correct answer, score (2) No of ways of choosing 4 cards from 52 cards = 52 𝑪𝟒 ------------------------------------→ = 270725

1 1 2 2 1

6


19

(b) (c) (d) i)

4 cards are same suite = 13 𝑪𝟒 + 13 𝑪𝟒 + 13 𝑪𝟒 + 13 𝑪𝟒 --------→ = 2860 4 cards are different suite =13 𝑪𝟏x 13 𝑪𝟏x13 𝑪𝟏x13 𝑪𝟏 ----------→

=𝟏𝟑𝟒 2 red and 2 black =26 𝑪𝟐 x26 𝑪𝟐 ----------→ = 105625 Remarks i)correct expansion of n 𝑷𝒓, score(1/2) ii) correct expansion of n 𝑪𝒓, score (1/2)

iii)expansion of 52 𝑪𝟒, 13 𝑪𝟒 etc are not necessary Midpoint of AB =(3,2) ---------------------→ Slope of AB = -1 -------------------------------→ Slope of perpendicular line to AB = 1 Equation of perpendicular line is y-2=1(x-3) → x-y-1=0 or x-y=1 -------------------------→ Remarks

i)midpoint =( 𝒙𝟏+𝒙𝟐

𝟐 ,

𝒚𝟏+𝒚𝟐

𝟐), score(1/2)

ii) slope = 𝒚𝟐−𝒚𝟏

𝒙𝟐−𝒙𝟏 ,score(1/2)

iii) 𝒎𝟏 𝑿 𝒎𝟐 = -1, score (1/2)

1 1 1 1/2 1/2 1

6


ii) iii)

iv) 𝒚 − 𝒚𝟏 =m (𝒙 − 𝒙𝟏) ,score (1/2) C = (x,0) -----------------------------------→ Given AC =BC

√(𝒙 − 𝟐)𝟐 + (𝟎 − 𝟑)𝟐 = √(𝒙 − 𝟒)𝟐 + (𝟎 − 𝟏)𝟐

𝒙𝟐 -4x+4+9 =𝒙𝟐-8x+16+1 4x =4 X = 1 Point C =(1,0) -------------------→ Remarks Distance formula, score (1/2) 𝒙𝟏 = 2, 𝒚𝟏 = 3, 𝒙𝟐 = 4, 𝒚𝟐 = 1 𝒙𝟑 =1, 𝒚𝟑 = 0 Area =1/2[𝒙𝟏(𝒚𝟐 − 𝒚𝟑 ) +𝒙𝟐(𝒚𝟑 − 𝒚𝟏)+ 𝒙𝟑(𝒚𝟏 − 𝒚𝟐]

=1/2[2(1-0)+4(0-3)+1(3-1)] = ½[2-12+2] = ½[-8] =-4----------------------------------→ Area =4 sq.unit ----------------------------→ Remarks Any method area =4 ,score (2)

1/2 1/2 1 1 1/2 ½

6


20 i) ii) iii)

class f x 𝒙𝟐 f.x f. 𝒙𝟐

30-40 3 35 1225 105 3675

40-50 7 45 2025 315 14175

50-60 12 55 3025 660 36300

60-70 15 65 4225 975 63375

70-80 8 75 5625 600 45000

80-90 3 85 7225 255 21675 90-100 2 95 9025 190 18050

50 3100 202250

Mean= ∑ 𝒇.𝒙

∑ 𝒇 -------------------------------------→

=3100/50 =62 --------------→

Varience = ∑ 𝒇.𝒙𝟐

∑ 𝒇 -(

∑ 𝒇.𝒙

∑ 𝒇)𝟐 -----------------→

= 𝟐𝟎𝟐𝟐𝟓𝟎

𝟓𝟎 - (𝟔𝟐)𝟐

=4045-3844=201 ---------------→

Coefficient of variation = 𝝈𝒙�̅�

x 100 ----→

=√201

𝟔𝟐 x100

=22.85 ---------=-→ Remarks i)correct table ,score(2) ii)correct formula of mean , score (1)

1 1 1 1 1 1


iii)Correct formula of varience, score (1) iv)Formula for c.v, score (1)

N.B: Any alternate method is allowed and if the answer is correct ,give full score for that particular question. For more details please contact: 1)LETHA.K (HSST SANTHA HSS AVANOOR THRISSUR, Ph:9447972692) 2) SANALKUMAR.V.P(HSST EVHSS NEDUVATHOOR KOLLAM:Ph:9446852271)

ANSWER KEY

FIRST YEAR HIGHER SECONDARY EXAMINATION 2020-21

HOME SCIENCE

Qn.No Scoring Indicators Split score

Total Score

1 2 3 4 5 6

PART -A c.Anorexia Nervosa a.Babbling c.Educable b.Tetanus a.Gout b.Haemophilia

A B C Measles Rashes spread to the body MMR Polio Crippling disease OPV Pertussis Rapid coughing Pentavalent

1 1 1 1 1 1 1 1 1

1 1 1 1 2 3

7 8 9 10 11 12 13 14

Family and Community Resource Management OR Resource Management a.Hue b.Lightness or darkness Money or Material goods or community facilities (Any one valid point from the above can be scored) PART-B a)Monochromatic color harmony b)Analogous color harmony (With explanation can be scored)

Individuals feels bored because of uninteresting ,monotonous and

undesirable work or working conditions. It often results because of boredom or frustration.

(Any points related to psychological fatigue can also be scored)

a)Changes in size b)Changes in proportion c)Disappearence of old features and acquisition of new features. (Any 2 valid points from the above can be scored) Creative play:Child makes new things with his own ideas. Imaginative play:The child acts as someone else or as an animal (Any other valid points can also be scored) Breast milk contains immunity factors ‘colustrum’ protect the new born

from infections.

1 1 1 1 1 1 1 1 1 1 1 1 1

1 2 1 2 2 2 2

15 16 17 18 19 20 21 22 23 24

It is an ideal food for the infants as it provides the needed nutrients in the right proportions. (Any other valid points can also be scored)

a)Identifying the problem b)Obtaining information and formulating the possible course of action c)Evaluating the consequences of each alternative d)Selecting the best possible course of action. (Any two points from the above can be scored) It serves as a financial guide for the family It serves as a time record for meeting our future needs

(Any other two valid points can also be scored)

Visual acuity: Ability of the eye to see the distant objects clearly Visual efficiency: How well one can use one’s vision. Scale: Relative size of an object Proportion: It is the relationship of the parts of the same object. PART-C a)Authoritarian disciplinary techniques b)Permissive disciplinary techniques c)Democratic disciplinary techniques (With explanation can be scored) This act is applicable for both goods and services Consumer redressal forum There is no fee for lodging a complaint

(Any other valid points can also be scored)

a)Goods and services provided by using money b)Fringe benefits c)Barter system (With explanation can be scored) -Responsibility as a good parent -Responsibility towards other family members -Responsibility towards the living society (With explanation can be scored) It provides attraction to the product It is safe against breakage Easy to carry. (Any other valid points can also be scored) -Ego centrism -Animism

1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1

2 2 2 2 2 3 3 3 3 3

25 26 27 28 29 30

-Irreversibility -Centration -Conservation (Any valid three points with explanation can be scored) -Poverty -Relatively large family size - Ignorance of parents -Orphanage,abandoned or rejected children. (Any three valid points with explanation can be scored) -Sense of identity -Self concept -Self esteem (With explanation can be scored) Test blood for HIV before blood transfusion Ensure the use of disposable needles Sterile instruments in hospitals. (Any other valid points can also be scored) PART-D -Primary colors -Secondary colors -Intermediate colors.(With illustration can be scored) Causes: -curiosity -parental modeling -escape from problems.(Any other valid points with explanation can also be scored) Consequences -academic -physical health -mental health.(Any other valid points with explanation can also be scored) -ISI mark -AGMARK -FPO -Eco Mark -Wool Mark -Silk Mark -100% vegetarian Mark (Any 3 points with explanation or any 6 points can be scored)

1 1 1 1 1 1 1 1 1 1 2 2 2 1 1 1 1 1 1 2 2 2

3 3 3 3 6 6 6

Sangeetha O C, mob:- 9497609835

Pratheetha Pradyoth R S, mob:- 9447863447

Answer KeyFIRST YEAR HIGHER SECONDARY EXAMINATION MARCH 2020

PART III - COMPUTER SCIENCEFY-30 TIME: 2Hrs 15Mins(Including Cool off time)

Qn. No.Sub Qn.

Answer Key/ Value PointsSplitScore

TotalScore

Answer any 5 questions from 1 to 6. Each carries 1 score. (5 X 1 = 5)1 11 - 12 hardware - 13 Debugging - 14 Tokens - 15 stdio.h/cstdio - 16 strcat - 1

Answer any 9 questions from 7 to 18. Each carries 2 scores. (9 X 2 = 18)7 Block diagram with all four units Input, Output, Memory, CPU - 2

8

(A+B)’=A’.B’(AB)’=A’+B’ (Statement of Theorms in sentence is also enough)('Break the line change the sign' can be given 1 score)Complement of sum of boolean variables is equal to the product of their individual complementsComplement of products of boolean variables is equal to the sum of their individual complements

1+1 2

9 Accumulator, MAR,MBR, PC,IR(Any 4) ½ X 4 2

10

Any 2 correct points about eachEntry Controlled Loop : Test expression/ Condition is evaluated before the loop execution. If test expression evaluates to false the body will not be executed (Minimum number of execution is zero). Eg. for / while loopExit Controlled Loop : Test expression/ Condition is evaluated after the execution of loop body. Minimum number of execution is one, Eg. do -- while loop

1+1 2

11

Any 2 correct rulesThe rules for constructing identifiers are as follows:→ Arbitrary long sequence of letters digits and underscores→ The first character must be a letter or underscore→ White space and special characters are not allowed→ Keywords cannot be used as identifiers→ Upper and lowercase letters are treated differently.

1+1 2

12AND, OR, NOT (Any 2 with symbols)(Listing of operators can be given 1½ Score).,+,!,&&,||,logic gates can also be considered for symbols

1+1 2

13C++ converts lower sized operands to higher sized operands (Implicit type) /Correct Example(Concept of type conversion or casting can be given 1 score)

- 2

14Correct syntaxOr Initialisation, condition(test expression), updation, body of the loop

½ X 4 2

15 Any 2 correct points about each ½ X 4 2

16 abs(), pow(), trunc(), sqrt(), floor(), sin(),cos(),...(Any 4) ½ X 4 2

17Fibre To The HomeSpeed, Low decay, Less Noise, High Bandwidth(Any 2)

1½ + ½

2

18Search engine websites are special programs that are designed to help peopleto find information available in wwwGoogle, Bing, Yahoo Search, Ask (Any valid One can be considered)

11

2

Answer any 9 questions from 19 to 30. Each carries 3 scores. (9 X 3 = 27)19 2 Correct points about each generation(Any 3 Generations) 1+1+1 3

20

NAND, NOR (gate which can implement any boolean function without using any other gate type can be given full score)Symbol of NAND, NORor Truth Table of NAND, NOR

½ + ½

2

3

21 a (28)10(Give 1/2 Score if method is correct) 1

3b (11101010)2 (Give 1/2 Score if method is correct) 1

c (4D2)16 (Give 1/2 Score if method is correct) 1

22Correct Flowchart(Any 4 different symbols can be given ½ score each)

3 3

23A token which represents data items which never changes its value during program execution. / constants Integer, float character and string (½ score each) or any two with explanation

1

2

3

24

Role of comment-Internal documentation or used to describe about a programSingle Line format- (// .......)Multi line format( /* ... */)

111

3

25Correct Algorithm/Program segment of bubble sort(Explanation with example can be given 1½ Scores)

3 3

26

2 Correct points about eachPut() - to display a character put() accepts only one argumentWrite() accepts 2 argumentswrite() to display a string Both are stream output functions / used along with cout - 1Score

1½

1½ 3

27 Any 3 merits 1+1+1 3

28

Call by value, Call by reference(Address) Any one point about eachCall by value method: Ordinary variables are used as formal parameters. Actual parameters may be constants variables or expressions. The changes made in the formal arguments are not reflected in actual arguments. Exclusive memory allocation is required for the formal arguments.Call by reference method: Reference variables are used as formal parameters. Actual parameters will be variable only. The changes made in the formal arguments are reflected in actual arguments. Memory of actual arguments is shared by formal arguments

½ + ½ 1 + 1

3

29Exact needs (Any 3)(The main advantages of using network computers are Resource sharing, price performance ratio, Communication, Reliability, Scalability)

1+1+1 3

30 Any 3 advantages 1+1+1 3Answer any 2 questions from 31 to 33. Each carries 5 scores. (2 X 5 = 10)

31 a Correct Comparison (Any 2 points each for RAM and ROM) 1+15

b Listing 3 devices (1½ Score) with one point each for a device(1½ Score) ½ X 6

32 a Any 2 difference between 'break' and 'continue' 1+1

5b ?: , its exact use/example 1+1

c Correct example 1

33 a Correct Answer 1

5

b Correct Answer 1

c Correct Answer 1

d Correct Answer 1

e Correct Answer 1

1Bindu Mary Mathews, St. Thomas HSS(03022), Kozhencherry, Pathanamthitta

2 Sreelal R, V V H S S, Thamarakulam, Alappuzha 4042

3NISHANTH N , HSS SREEKRISHNAPURAM(09048), PALAKKAD 9447962552

4THOMAS T PALAKADEN, SJHSS KARIMANNOOR(06019), IDUKKI . 9447523150

5 Binod T P, RVHSS, Chokli ( 13053), Kannur. 9349770595

6MENOUP T, Tharakan HSS Angadippuram(11231), Malappuram 9895141676

7 Roy John, St. Aloysius H S S, Elthuruth (08075), Thrissur, Ph: 88483577388 Vinayachandran C, V G S S Ambikodayam H S S, KollamPh: 9447590544

· presentation of the context . organization of ideas . style and choice of words . questions 22...

Documents