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Kelompok 09 Adinda Sofura Azhariyah Afdhal Hanafi Andrea Rizky Harahab Manggala Pasca Pangiastika Putri Wulandari

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PPT PP Peristiwa PerpindahanPPT PPPPT PPPPT PPPPT PPPPT PPPPT PP

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Page 1: PPT PP.pptx

Kelompok 09

Adinda Sofura AzhariyahAfdhal Hanafi

Andrea Rizky HarahabManggala Pasca

Pangiastika Putri Wulandari

Page 2: PPT PP.pptx

Soal 1Saturated steam at 0.276 MPa (0.276x106 Pascal) flows inside a steel pipe having inside diameter (I.D.) 2.09 cm and outside diameter (O.D.) 2.67 cm. k of the steel is 42.9 W/(m.K). The convective heat transfer coefficients on the inner and outer surfaces of the pipe are 5680 W/(m2.K) and 22.7 W/(m2.K), respectively. The surrounding air is at 294 K.

a. Find the heat loss per meter of the bare pipe (Watt/m).

b. Find the heat loss per meter (Watt/m) of the same pipe but insulated with 85% magnesia of 38 mm thickness (k value for 85% magnesia is 0.0675 W/(m.K))

Page 3: PPT PP.pptx

a

r1

r2

ho

k1

h1

Page 4: PPT PP.pptx

z

r

𝑞𝜃∨𝜃=360 °

𝑞𝜃∨𝜃=0 °

𝑞𝑧∨𝑧=𝐿𝑞𝑧∨𝑧=0 °

𝑞𝑟∨𝑟=𝑟+Δ 𝑟

𝑞𝑧 𝑟∨𝑟=𝑟

Page 5: PPT PP.pptx

I. Konduksi

• Neraca Kesetimbangan

+ =0

• Penjabaran

Page 6: PPT PP.pptx

• Maka + =0

.............x .............x

.......(1) Jadi:

Page 7: PPT PP.pptx

.................(2)

Page 8: PPT PP.pptx

• Boundary Condition

o MencariSaat

To

T1

T2Tu

r1

r2

ho

k1

h1

Page 9: PPT PP.pptx

Maka

Konduksi dari

To

T1

T2Tu

Page 10: PPT PP.pptx

DEA

Page 11: PPT PP.pptx
Page 12: PPT PP.pptx

There is a fluid between 2 long parallel vertical plates. The right plate is at rest, while the left is moving upward or downward at a constant velocity, vs. Therefore, the system generates shear-driven flow. Assume flow is laminar and the fluid is affected by gravity force. No pressure difference is imposed. The distance between 2 plates is B, the width of the plates is W and the length is very long. The fluid is a glycerine solution 30% with density 1000 kg/m3 and viscosity 3 cPoise. B is 0.01 m. Obtain velocity distribution equations for 2 cases, vs = +0.1 m/s and -0.1 m/s,. Plot v against x and shear stress vs x.

SOAL 2

Page 13: PPT PP.pptx

KONDISI 1

SLIDE MANGGALA

Page 14: PPT PP.pptx

Plot Vy vs xx Vy

0 1

1 1613571

2 6487141

3 14620711

4 26014281

5 40667851

0 1 2 3 4 5 60

5000000

10000000

15000000

20000000

25000000

30000000

35000000

40000000

45000000

Vy vs x

Vy

Page 15: PPT PP.pptx

Plot τxy vs x

x τxy

0 49.3

1 -9750.7

2 -19550.7

3 -29350.7

4 -39150.7

5 -48950.7

0 1 2 3 4 5 6

-60000

-50000

-40000

-30000

-20000

-10000

0

10000

τxy vs x

τxy

Page 16: PPT PP.pptx

KONDISI 2

Page 17: PPT PP.pptx

B)

fluid

-vs

x

y

B

-vs

Page 18: PPT PP.pptx

Shell

x

y

Φ𝑥𝑦∨𝑥=𝑥+∆𝑥

Φ 𝑦𝑦∨𝑦=𝐿

Φ 𝑦𝑦∨𝑦=0

Φ𝑧𝑦∨𝑧=0

Φ𝑧𝑦∨𝑧=𝑊

Φ𝑥𝑦∨𝑥=𝑥

z

L

W

Page 19: PPT PP.pptx

Neraca :

+ ()(W. )+ ) = 0

)(W.L)+ )(

Page 20: PPT PP.pptx

Penjabaran

Maka

Page 21: PPT PP.pptx

Sehingga neracanya menjadi :)(W.L) ) = 0)(W.L) = - )

=

Page 22: PPT PP.pptx

= =

=

Page 23: PPT PP.pptx

Boundary condition

X = 0

X = B 0

Page 24: PPT PP.pptx

= 0 = =

Page 25: PPT PP.pptx

Maka : = = =

Page 26: PPT PP.pptx

Plot Vy vs xx Vy

0 -1

1 -1613601

2 -6487201

3 -14620801

4 -26014401

5 -40668001

0 1 2 3 4 5 6

-45000000

-40000000

-35000000

-30000000

-25000000

-20000000

-15000000

-10000000

-5000000

0

Vy vs x

Vy

Page 27: PPT PP.pptx

Plot τxy vs x

x Vy

0 -1

1 -1613601

2 -6487201

3 -14620801

4 -26014401

5 -40668001

0 1 2 3 4 5 6-10000

0

10000

20000

30000

40000

50000

60000

τxy vs x

τxy