power supply and thermal issues

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F. Z. Peng: Slide 1 Feb. 15, 2006 How to Select and Use Power Suppl ies and dc/dc Converters for Your Applications Fang Z. Peng Dept. of Electrical and Computer Engineering Michigan State University Phone: 517-336-4687, Fax: 517-353-1980 Email: [email protected] u.edu

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Page 1: Power Supply and Thermal Issues

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F. Z. Peng: Slide 1Feb. 15, 2006

How to Select and Use Power Supplies anddc/dc Converters for Your Applications

Fang Z. PengDept. of Electrical and Computer Engineering

Michigan State University

Phone: 517-336-4687, Fax: 517-353-1980

Email: [email protected]

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F. Z. Peng: Slide 2Feb. 15, 2006

Contents

Introduction to Power Supplies and dc/dc

Converters

Types & Technologies of Power Suppliesand dc/dc Converters

Circuit Selection and Design

Circuit Performance and Protection Features

Thermal Requirements and Design Issues

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F. Z. Peng: Slide 3Feb. 15, 2006

Introduction to Power Supplies and dc/dcConverters

Available/Raw Power Sources ± AC or DC (frequency)

 ± Un-regulated (changes with load, prime source, etc.)

 ±

Voltage (different level, polarity, isolation) ± Non-protected (against over load, fault, temp., etc.)

Load Demand ± Different AC or DC (frequency)

 ±Regulated (against load, prime source, etc.)

 ± Voltage (different level, polarity, isolation)

 ± Protected (against over load, fault, temp., etc.)

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F. Z. Peng: Slide 4Feb. 15, 2006

Power Supply 

Introduction to Power Supplies and dc/dcConverters ±cont.

Power & Electronic

Circuits

Raw power inDesired power out

(V, I, P, F)

To loads:

Electronic cktsMotor

Computer

Equipment

Control

BatteryFuel Cell

AC Outlet

Solar

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F. Z. Peng: Slide 6Feb. 15, 2006

AC-DC Power Supplies-Circuit Selection and Design

Using Linear Regulators

Using LDO Regulator 

http://www.national.com/pf/LM/LM78M05.html 

Step-down Xfmer 

Regulator 120 V  AC 

For low power (several watts or below) applications. Low efficiency, large size and weight (bulky step-down line

transformer)

Low cost

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F. Z. Peng: Slide 7Feb. 15, 2006

AC-DC Power Supplies-Circuit Selection and Design

Using Switching-Mode

High efficiency

Small size and light weight

For high power (density) applications

http://www.linear.com/index.jsp

http://www.linear.com/3770 

http://www.electronicproducts.com/ 

TI Power Supply Technologies Poster 

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F. Z. Peng: Slide 8Feb. 15, 2006

Selecting the Right dc/dc Converter 

The Need for dc/dc Converters ± E.g., a single AA alkaline battery produces 1.5 V when fully charged and its

voltage drops to as low as 0.9 V when becoming depleted.

Dc/dc Converter Types

 ± Buck

 ± Boost

 ± Buck-Boost

Dc/dc Converter Technologies

 ± Linear Regulators

 ±Switching Regulators

 ± Charge Pumps

The MCP170 3 LDO is one type of dc/dc linear regulator 

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F. Z. Peng: Slide 9Feb. 15, 2006

Selecting the Right dc/dc Converter ±cont.

Dc/dc converter technology comparison

Parameter Linear regulator 

Switchingregulator 

Charge pump

Efficiency Low High Medium

EMI Noise Low High Medium

Output current Low to medium Low to High Low

Boost (step-up) No Yes Yes

Buck (step-down)

 Yes Yes Yes

Solution size small Large Medium

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F. Z. Peng: Slide 10Feb. 15, 2006

Selecting the Right dc/dc Converter ±cont.

VBAT = 3.7 V nom, BIN_BB = 1.2 V 

Load Current = 600 m APower delivered to load = 600 m A * 1.2 V = 720 mW Power converted to heat =

720 mW * ((3.7/1.2) 1) = 1,500 mW T otal power consumed =

720 mW + 1,500 mW = 2,200 mW 

32% goes to work, 68% goes to heating user hand and ear w hen using a Linear Regulator for amobile device

VBAT = 3.7 V nom; BIN_BB = 1.2 V Load Current = 600 m AConverter efficiency = 90%

Power delivered to load = 600 m A * 1.2 V = 720 mW Power converted to heat =720 mW * ((1/0.9) 1)=80 mW T otal power consumed = 720 mW + 80 mW = 800 mW 

90% goes to work, 10% goes to heating user hand and ear W hen using a Switc h- mode regulator for a mobile device.

Linear regulators:Inexpensivesmall footprint low part count low noise

high ripple rejection

Switching regulators:a bigger footprint higher part count,more cost  prone to conducted and radiated EMI.

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F. Z. Peng: Slide 11Feb. 15, 2006

Specs, Performance and Protection

Voltage ripple (+-50 mV, or 5%)

Isolation (e.g., 1,500 V ac for 1 min.)

Load regulation (e.g., 3%)

Dynamic response (transients, wake-up time, etc.)

Short circuit protection

OC protection

OV protection

OT protection

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F. Z. Peng: Slide 12Feb. 15, 2006

Power Losses and Thermal Design

For example, a 7815 linear regulator with input voltage of 20 Vand output current of 1 A. The power loss is (20-15)Vx(1 A)=5 W.

From the chip to the ambient, (Ti can be calculated according tothe thermal circuit using Ohm¶s law (R=V/I), where R is thethermal resistance, V is the temperature and I is the power dissipation.

case ambient  Thcase ambient 

dissipation

out dissipation in out out  

op

T T  R

 P 

 P   P P P P  

L

!

! !

W here:T case is case T emp.T ambient is ambient T emp.P 

dissipationis power loss

P in is input power P out is output power Lop is efficiency under 

given operating conditions

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F. Z. Peng: Slide 13Feb. 15, 2006

Power Losses and Thermal Design--A more detailed thermal circuit

W : Device power loss

Tj : Junction temperature of device Tc : Device case temperature

Tf : Temperature of heatsink Ta : Ambient temperature

Rth(j-c) : Thermal resistance between junction andcase, specified in datasheet

Rth(c-f) : Contact thermal resistance between caseand heatsink, specified in datasheet

Rth(f-a) : Thermal resistance between heatsink andambient air, specified by the heatsink manufacturer 

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F. Z. Peng: Slide 14Feb. 15, 2006

Power Losses and Thermal Design

Tc=W×{Rth(c-f) + Rth(f-a)}+Ta

Tj=W×Rth(j-c)+Tc

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