physics electrics problems(solved

1
1. Un rezistor cu R= 5 ohmi ro = 1,75 x 10^-8 ohm x m s= 0,35 mm^2 = 0,35 x 10^-6 m^2 L conductor R= ro x l/s => l = Rx s / l = 100 2. E= 16 v r=3 ohmi R = 5 I= E/ R+r = 16/8 = 2A Ub= R x I = 5x2=10 E=Ub+u u = E-Ub = 16-6 =10 Isc = E/R = 16/5 =3,2 A 3. R1=89,5 I1= 50 mA R2=179,5 I2= 25 ma I1(R1+r)=I2(R2+r) 50(89,5+3)=25(179,5+r) r = 0,5 E= 50x 10^-3 (89,5+0,5) = 4,5 V 4. I=3A E=12 Ub= 9 R= U/I= 9/3 = 3 u=E-Ub = 3 r=u/I = 3/3= 1

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1. Un rezistor cu R= 5 ohmi ro = 1,75 x 10^-8 ohm x m s= 0,35 mm^2 = 0,35 x 10^-6 m^2L conductor

R= ro x l/s => l = Rx s / l = 100

2. E= 16 v r=3 ohmi R = 5I= E/ R+r = 16/8 = 2AUb= R x I = 5x2=10E=Ub+u u = E-Ub = 16-6 =10Isc = E/R = 16/5 =3,2 A

3.R1=89,5 I1= 50 mAR2=179,5I2= 25 maI1(R1+r)=I2(R2+r)50(89,5+3)=25(179,5+r) r = 0,5E= 50x 10^-3 (89,5+0,5) = 4,5 V

4.I=3A E=12 Ub= 9 R= U/I= 9/3 = 3u=E-Ub = 3r=u/I = 3/3= 1