physics 1202: lecture 7 today’s agenda announcements: –lectures posted on: rcote/ rcote/ –hw...

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Physics 1202: Lecture 7 Today’s Agenda Announcements: Lectures posted on: www.phys.uconn.edu/~rcote/ HW assignments, solutions etc. Homework #2: Homework #2: On Masterphysics today: due Friday On Masterphysics today: due Friday week week Go to masteringphysics.com Labs: Begin THIS week

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Page 1: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Physics 1202: Lecture 7Today’s Agenda

• Announcements:– Lectures posted on:

www.phys.uconn.edu/~rcote/

– HW assignments, solutions etc.

• Homework #2:Homework #2:– On Masterphysics today: due Friday weekOn Masterphysics today: due Friday week

– Go to masteringphysics.com

• Labs: Begin THIS week

Page 2: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Today’s Topic :• Electric current (Chap.17)

• Review of– Electric current– Resistance

• New concepts– Temperature dependence– Electromotive force (battery)– Power– Circuits

» Devices» Resistance in series & in parallel

Page 3: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

R

I

= R I

Page 4: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Current Idea

Current is the flow of charged particles through a path, at circuit.

Along a simple path current is conserved, cannot create or destroy the charged particles

Closely analogous to fluid flow through a pipe. Charged particles = particles of fluid

Circuit = pipes

Resistance = friction of fluid against pipe walls, with itself.

E

Page 5: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Ohm's Law

• Vary applied voltage V.

• Measure current I

• Does ratio ( V/I ) remain constant??

V

I

slope = R = constant

V

I IR

Page 6: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Resistivity

LA

E

j

e.g, for a copper wire,

~ 10-8 -m, 1mm radius, 1 m long, then R .01

So, in fact, we can compute the resistance if we know a bit about the device, and YES, the property belongs only to the device !

Page 7: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Make sense?

LA

E

j

• Increase the Length, flow of electrons impeded

• Increase the cross sectional Area, flow facilitated

• The structure of this relation is identical to heat flow through materials … think of a window for an intuitive example

How thick?

How big?

What’s it made of?

or

Page 8: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions
Page 9: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Lecture 7, ACT 1• Two cylindrical resistors, R1 and R2, are made of identical material.

R2 has twice the length of R1 but half the radius of R1. – These resistors are then connected to a battery V as shown:

VI1 I2

– What is the relation between I1, the current flowing in R1 , and I2 , the current flowing in R2?

(a) I1 < I2 (b) I1 = I2 (c) I1 > I2

Page 10: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Lecture 7, ACT 2

R

I

1

2 3

4

+

-

x

1 2 3 4

+-

1 2 3 4

+-

1 2 3 4

+-

Consider a circuit consisting of a single loop containing a

battery and a resistor.

Which of the graphs represents

the current I around the loop?

Page 11: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Conductivity versus Temperature• In lab you measure the resistance of a light bulb

filament versus temperature.

• You find RT.

• This is generally (but not always) true for metals around room temperature.

• For insulators R1/T.

• At very low temperatures atom vibrations stop. Then what does R vs T look like??

• This was a major area of research 100 years ago – and still is today.

temperature coefficient of resistivity

Page 12: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions
Page 13: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Electromotive force• Provides a constant potential difference between

2 points : “electromotive force” (emf)

R

I I

rV

+ -

• May have an internal resistance– Not “ideal” (or perfect: small loss of V)

– Parameterized with “internal resistance” r in series with

• Potential change in a circuit

- Ir - IR = 0

Page 14: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Power• Battery:

Stores energy chemically. When attached to a circuit, the energy is transferred to the motion of electrons. This happens at a constant potential.» Battery delivers energy to a circuit.

» Other elements, like resistors, dissipate energy. (light, heat, etc.)

• Total energy delivered not always useful.– How much energy does it take to light your house

… well for how long?

– Remember definition of Power (Phys. 1201).

Page 15: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Power• Recall that

• In a circuit, where the potential remains constant.– Only q varies with time

where

Page 16: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

PowerBatteries & Resistors Energy expended

What’s happening?

Assert:

chemical to electrical

to heat

Charges per time

Energy “drop” per charge

Units okay?

For Resistors:

Rate is:

Page 17: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Power

• What does power mean?– Power delivered by a battery is the amount of

work per time that can be done. i.e. drive an electric motor etc.

– Power dissipated by a resistor, is amount of energy per time that goes into heat, light, etc.

• A light bulb is basically a resistor that heats up. The brightness (intensity) of the bulb is basically the power dissipated in the resistor.– A 200 W bulb is brighter than a 75 W bulb, all

other things equal.

Page 18: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Batteries (non-ideal)• Parameterized with

“internal resistance” r in series with

• : “electromotive force” (emf)

R

I I

rV

Power delivered to the resistor R:

Pmax when R/r =1 !

= V(I=0)

- Ir - IR = 0

- Ir = V

Page 19: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions
Page 20: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

R

I

= R I

Page 21: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Devices• Conductors:

Purpose is to provide zero potential difference between 2 points. » Electric field is never exactly zero.. All conductors

have some resistivity.

» In ordinary circuits the conductors are chosen so that their resistance is negligible.

• Batteries (Voltage sources, seats of emf):

Purpose is to provide a constant potential difference between 2 points. » Cannot calculate the potential difference

from first principles.. electrical chemical energy conversion. Non-ideal batteries will be dealt with in terms of an "internal resistance".

+ -

V+ -

OR

Page 22: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Devices

• Resistors:

Purpose is to limit current drawn in a circuit.» Resistance can be calculated from knowledge of the

geometry of the resistor AND the “resistivity” of the material out of which it is made.

» The effective resistance of series and parallel combinations of resistors will be calculated using the concepts of potential difference and current conservation (Kirchoff’s Laws).

• Resistance

Resistance is defined to be the ratio of the applied voltage to the current passing through. V

I IR

UNIT: OHM =

Page 23: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

How resistance is calculated

• Resistance – property of an object– depends on resistivity of its material and its geometry

• Resistivity – property of all materials– measures how much current density j results from a

given electric field E in that material

– units are Ohm x m (m)

• Conductivity– sometimes used instead of resistivity– measures the same thing as

• Conductance– sometimes used instead of resistance– measures the same thing as R

Page 24: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Resistors

in SeriesThe Voltage “drops”:

Whenever devices are in SERIES, the current is the same through both !

This reduces the circuit to:

a

c

Reffective

a

b

c

R1

R2

I

Hence:

Page 25: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Another (intuitive) way...

Consider two cylindrical resistors with lengths L1 and L2

V

R1

R2

L2

L1

Put them together, end to end to make a longer one...

Page 26: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Resistors in Parallel • What to do?

• But current through R1 is not I ! Call it I1. Similarly, R2 I2.

• How is I related to I 1 & I 2 ?? Current is conserved!

a

d

a

d

I

I

I

I

R1 R2

I1 I2

R

V

V

• Very generally, devices in parallel have the same voltage drop

Page 27: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

Another (intuitive) way...

Consider two cylindrical resistors with cross-sectional areas A1 and A2

Put them together, side by side … to make a “fatter” one with A=A1+A2 ,

V R1

R2

A1A2

Page 28: Physics 1202: Lecture 7 Today’s Agenda Announcements: –Lectures posted on: rcote/ rcote/ –HW assignments, solutions

V R1

R2

V

R1

R2

Summary

• Resistors in series– the current is the same in

both R1 and R2

– the voltage drops add

• Resistors in parallel– the voltage drop is the same

in both R1 and R2

– the currents add