phys122a-lecture 2 electric field - university of...
TRANSCRIPT
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Phys122A-Lecture 2 Electric Field
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Physics 122 Labs Sections begin on next week
Before your section meets – Get a copy of the lab manual at the UW Bookstore! – Read the information on page iii as it has a lot of information related
to the course, the course website, WebAssign, etc. – Get a WebAssign account (Pay by credit card only)
There are 3 components to the labs:
– Pre-Labs: Needs to be completed before each of your lab sessions begin. Pre-labs will be completed in WebAssign
– In-class Experiment: This is your lab section in which you will need your lab manual.
– Post-Labs: Completed after your lab session also on WebAssign
(Lab) Course website: – http://courses.washington.edu/phys122z/index.php – Please check the Frequently Asked Questions (FAQs) link before you email the
Instructor!
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“Reading”
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From FlipIt Physics For the collection of charges shown in the above
problem, which of the following statements best
describes FY, the y component of the net force on the
charge at the origin
FY > 0
FY = 0
FY < 0
“In Force from Four Charges
it is unclear whether the
angle matters.”
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From FlipIt Physics• “What is charge?” • “Electric charge is the physical property of matter that
causes it to experience a force when placed in an electromagnetic field.”
• “Conserved” • Units: [Q] = Coulomb (C)
e p n
Q -e +e 0
e = 1.60217662⇥ 10�19 C
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From FlipIt Physics
• “Where are you from?” Born in UK but lived here since I was 0.5 years old.
• “Don’t assign two units!” Sorry.
• Explain why force on electrons and nucleus is equal magnitude. (Newton 3rd Law.)
• Line integral wasn’t explained.
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Introduction to the Electric Field…
• Coulomb Law:
• Superposition for an collection of discrete charges:
~F1,2 =k q1q2r21,2
r1,2
~FNet,i =X
j 6=i
k qiqjr2j,i
rj,i
q1
q1
q1q1
q1
q1
q1
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• Superposition for an collection of discrete charges:
• Define the Electric Field (q0 is a test charge):
Introduction to the Electric Field…
q1q2
q0
q3q4
q5q6
~E ⌘~FNet,0
q0
~FNet,0 =X
j 6=0
k q0qjr2j,0
rj,0 = q0X
j 6=0
k qjr2j,0
rj,i
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Electric field from a point charge
• Electric Field from a point charge (at the origin):
• Electric Field from a collection of charges:
~E ⌘~F1,0
q0=
k q1r2
r
~E(~r0) =X
j 6=0
k qjr2j,0
rj,0
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What is a field?
• Scalar, vector (or tensor…) valued function of space (and time).
• Electric Field (vector)
• Magnetic Field (vector)
• Electric Potential (scalar)
~E(~r, t)
~B(~r, t)
�(~r, t)
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Fields of all kinds...
77
82
8368
5566
83
75 80
9091
7571
80
72
84
73
82
8892
77
8888
7364
These isolated Temperatures make up a Scalar Field (you learn only the temperature at a place you choose)
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Fields of all kinds...
77
82
8368
5566
83
75 80
9091
7571
80
72
84
73
57
8892
77
5688
7364
That would require a VECTOR field. (you learn how fast the wind is blowing,
AND in what direction)
It may be more interesting to know which way the wind is blowing …
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Does the E field really exist?
• Computation tool or physical entity?
• Two unattractive alternatives:
• Assume E field exists at all locations in space ✔
• Assume action at a distance ✘
• Useful heuristic for understanding physics: There is no instantaneous action at a distance.
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Visualizing the E field
• Direction:
• Radial
• Direction of the force on a positive charge
• Amplitude:
• Decreases with distance
~E(~r ) =k q1r2
r
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Visualizing the E field
• “quiver” or Velocity Plot
• You almost never see the E field drawn this way!
• General tool for visualizing a vector field.
-6 -4 -2 0 2 4 6-6
-4
-2
0
2
4
6
+Q
Y (m
)
X (m)
~E(~r ) =k q1r2
r
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Visualizing the E field
Field lines … next time.
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Visualizing the E field
• “quiver” or Velocity Plot
• You almost never see the E field drawn this way!
• General tool for visualizing a vector field.
-6 -4 -2 0 2 4 6-6
-4
-2
0
2
4
6
+Q
Y (m
)
X (m)
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Visualizing the E field
x (m)-5 0 5
Ex (A
U)
-10-8-6-4-202468
10
~
E(x, y)���y=0
= k q1xi
|x|3
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Clicker 2-1
Two equal mass balls are suspended from the ceiling with equal length nonconducting threads as shown. Ball 1 has charge Q1 = +3q and Ball 2 has charge Q2 = +q.
– Which of the following pictures best represents the equilibrium position?
Q2 Q1
(a)
+3q +q Q2 Q1
(b) +3q
+q Q2 Q1
(c) +3q +q
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Clicker 2-2 What happens to the Force on q1 if its sign is changed?
A) |F1| increases B) |F1| remains the same C) |F1| decreases D) Need more information to determine
q1
q2
q3
q4
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• Two charges, Q1 and Q2 , fixed along the x-axis as shown, produce an electric field E at a point (x,y) = (0,d) which is directed along the negative y-axis.
– Which is true?
(a) Both charges Q1 and Q2 must be positive.
(b) Both charges Q1 and Q2 must be negative.
(c) The charges Q1 and Q2 must have opposite signs.
Q2 Q1 x
y
E d
Clicker 2-3
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• Q1 has charge +Q • Q2 has charge +2Q • They are separated by d. • Charge q is a distance a away from Q1 Is there a place – the value for a -- between Q1 and Q2 where the force on ANY charge (positive or negative) is zero?
(a) NO (b) Yes, but I can’t find it with all this time pressure. (c) Yes and my answer is _______ from Q1. I will volunteer to
specify if you ask me Clicker 2-4
d a
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Electric field from a point charge
• Electric Field from a point charge (at the origin):
• Electric Field from a collection of charges:
~E ⌘~F1,0
q0=
k q1r2
r
~E(~r0) =X
j 6=0
k qjr2j,0
rj,0
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E field from a line charge• Electric Field from a collection of charges:
• Electric Field from a continuous charge distribution:
~E(~r0) =X
j 6=0
k qjr2j,0
rj,0
origin
observer
E(r )
r
r ′
dqr ′
r − r ′~E(~r ) = k
Zdq~r 0
~r � ~r 0
|~r � ~r 0 |3
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E field from a charge distribution
• Electric Field from a 1D source: [λ] = C/m1
• Electric Field from a 2D source: [σ] = C/m2
• Electric Field from a 3D source: [ρ] = C/m3
origin
observer
E(r )
r
r ′
dqr ′
r − r ′~E(~r ) = k
Zdq~r 0
~r � ~r 0
|~r � ~r 0 |3
dq~r 0 ! d` �(~r 0)
dq~r 0 ! d
2x�(~r 0)
dq~r 0 ! d
3x ⇢(~r 0)
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E field from a line charge[a] = m
[�] = C/m
�
a
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Clicker
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Work the integral…