pelebaran jalan bangko revisi akhir model (1)
TRANSCRIPT
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8/17/2019 Pelebaran Jalan Bangko Revisi Akhir Model (1)
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B A N GA S A L
K A Y U
B A N GA S A L
K A Y U
0 + 0 0 0
0 + 0 5 0
0 + 1
0 0
0 + 1 5 0
0 + 2
0 0
0
+ 2 5 0
0 + 3 0 0
0 + 3 5 0
T S = 0 + 0 3 5 . 6 7 8
S C = 0 + 0 7 9 . 6 7 8
C S = 0 + 2 4 9 . 7 4 1
S T = 0 + 2 9 3 . 7 4 1
R U M A H
N O N
P E R M A N
E N
K I O
S / W A R U N
G
N O N
P E R M
A N E N
B E N G K E L
K E N A L P O T
N O N
P E R M A N E N
R U K O
R U K O
B E N GK E L
N ON
P E RMA NE N
R U K O
R U K O
K I O S N O N
P E R M A N E N
K I O S /
W A R U N
G
N O N
P E R M A
N E N
R U M A H
P E R M A N E
N
K I O S N O N
P E R M A N E N
K I O S N O N
P E R M A N E N
R U K O
R U K O
R U K O
R U K O
R U K O
R U K O
K I O S N O N
P E R M A N E
N
R U K O
R U K O
K I O S
P E R M A N E N
K I O S N O N
P E R M A N E N
1
Y = 1 9 6 9 0 0
X = 9 7 7 4 2 0 0 Y = 1 9 7 0 0 0
Y = 1 9 6 9 0 0
X = 9 7 7 4 3 0 0 Y = 1 9 7 0 0 0
Y = 1 9 6 9 0 0
X = 9 7 7 4 4 0 0 Y = 1 9 7 0 0 0
Y = 1 9 6 9 0 0
X = 9 7 7 4 5 0 0 Y = 1 9 7 0 0 0
P T
. B U M
I
G ARIS HIM P IT : 0 + 35 0
J A L A N K E . . . .
X =
1 9 6 9 5 7 . 0 0 0
Y =
9 7 7 4 2 0 5 . 0 0 0
Z
=
5 5 .7 6 4
D el t a
RE L S L C T e
T C / T S
C T / S T
P
1
0 . 0 2 6
DA T A L E N GK UN G
V
0 + 2 2 1 . 8 8 6
0 + 2 8 4 .1 4 4
-
0 . 8 0 7
3 0 .7 3 1
7 0 0
6 0
1 3 - 5 5 -1 2
3 1 .1 2 9