pdfs week1lecture2
TRANSCRIPT
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Analysis of a Complex KindWeek 1
Lecture 2: Algebra and Geometry in the Complex Plane
Petra Bonfert-Taylor
Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind
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The Complex Plane
Complex numbers: expressions of the form z=x+iy, where
x is called thereal partof z;x=Re z, andy is called theimaginary partof z;y=Im z.
Set of complex numbers: C (thecomplex plane).
Real numbers: subset of the complex numbers (those whose ima
is zero).
The complex plane can be identified with R2.
Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind
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The Modulus of a Complex Number
Definition
Themodulusof the complex number z=x+iyis the length of the ve
|z|=
x2 +y2.
Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind
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Multiplication of Complex Numbers
Motivation: (x+iy) (u+iv) =xu+ixv+iyu+i2yv
So we define:
Definition
(x+iy) (u+iv) = (xu yv) +i(xv+yu) C.
Example:
(3 + 4i)(1 + 7i) = (3 28) +i(21 4) =31 + 17
The usual properties hold:
(z1z2)z3 =z1(z2z3)(associative)z1z2 =z2z1 (commutative)z1(z2+z3) =z1z2+z1z3 (distributive)
Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind
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So What isi?
i=0 + 1i,
so
i2 = (0 + 1i)(0 + 1i) = (0 0 1 1) +i(0 1 + 1 0) =1
i3 =i2 i=1 i=i
i4 =i2 i2 = (1)(1) =1i5 =i4 i=i
i6 =1 . . .
Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind
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How Do You Divide Complex Numbers?
Suppose thatz=x+iyandw=u+iv. What is z
w (forw=0)?
z
w =
x+iy
u+iv
= (x+iy)(u iv)
(u+iv)(u iv)
= (xu+yv) +i(xv+yu)
u2 +v2 +i(uv+vu)
= xu+yv
u2 +v2 +iyu xv
u2 +v2 .
In particular:1
z =
1
x+iy =
x iy
x2 +y2, as long asz=0.
Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind
Th C l C j
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The Complex Conjugate
Note the importance of the quantityx iyin the previous calculation!
Definition
Ifz=x+iy thenz=x iy is thecomplex conjugateof z.
Properties:
z=z
z+w=z+ w
|z|= |z|zz= (x+iy)(x iy) =x2 +y2 =|z|2
1
z =
z
zz =
z
|z|2
Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind
M P i f h C l C j
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More Properties of the Complex Conjugate
When isz=z?
z+z= (x+iy) + (x iy) =2x, so
Re z=z+ z
2 , similarly Im z=
z z
2i .
|z w|= |z| |w|zw
=
z
w, (w=0)
|z|= 0 if and only ifz=0.
Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind
S I liti
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Some Inequalities
|z| Re z |z|
|z| Im z |z|
|z+ w| |z| + |w|(triangle inequality)
|z w| |z| |w|(reverse triangle inequality)
Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind
Th F d t l Th f Al b
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The Fundamental Theorem of Algebra
Theorem
If a0,
a1, . . . ,
anare complex numbers with an=0, then the polynomia
p(z) =anzn +an1z
n1 + +a1z+ a0
has n roots z1, z2, . . . zn inC. It can be factored as
p(z) =an(z z1)(z z2) (z zn).
We will be able to prove this theorem later in this course!
Consider the polynomialp(x) =x2 + 1 in R. It has no real roots!But in C it can be factored: z2 + 1= (z+ i)(z i)!
Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind