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    Analysis of a Complex KindWeek 1

    Lecture 2: Algebra and Geometry in the Complex Plane

    Petra Bonfert-Taylor

    Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind

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    The Complex Plane

    Complex numbers: expressions of the form z=x+iy, where

    x is called thereal partof z;x=Re z, andy is called theimaginary partof z;y=Im z.

    Set of complex numbers: C (thecomplex plane).

    Real numbers: subset of the complex numbers (those whose ima

    is zero).

    The complex plane can be identified with R2.

    Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind

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    The Modulus of a Complex Number

    Definition

    Themodulusof the complex number z=x+iyis the length of the ve

    |z|=

    x2 +y2.

    Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind

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    Multiplication of Complex Numbers

    Motivation: (x+iy) (u+iv) =xu+ixv+iyu+i2yv

    So we define:

    Definition

    (x+iy) (u+iv) = (xu yv) +i(xv+yu) C.

    Example:

    (3 + 4i)(1 + 7i) = (3 28) +i(21 4) =31 + 17

    The usual properties hold:

    (z1z2)z3 =z1(z2z3)(associative)z1z2 =z2z1 (commutative)z1(z2+z3) =z1z2+z1z3 (distributive)

    Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind

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    So What isi?

    i=0 + 1i,

    so

    i2 = (0 + 1i)(0 + 1i) = (0 0 1 1) +i(0 1 + 1 0) =1

    i3 =i2 i=1 i=i

    i4 =i2 i2 = (1)(1) =1i5 =i4 i=i

    i6 =1 . . .

    Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind

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    How Do You Divide Complex Numbers?

    Suppose thatz=x+iyandw=u+iv. What is z

    w (forw=0)?

    z

    w =

    x+iy

    u+iv

    = (x+iy)(u iv)

    (u+iv)(u iv)

    = (xu+yv) +i(xv+yu)

    u2 +v2 +i(uv+vu)

    = xu+yv

    u2 +v2 +iyu xv

    u2 +v2 .

    In particular:1

    z =

    1

    x+iy =

    x iy

    x2 +y2, as long asz=0.

    Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind

    Th C l C j

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    The Complex Conjugate

    Note the importance of the quantityx iyin the previous calculation!

    Definition

    Ifz=x+iy thenz=x iy is thecomplex conjugateof z.

    Properties:

    z=z

    z+w=z+ w

    |z|= |z|zz= (x+iy)(x iy) =x2 +y2 =|z|2

    1

    z =

    z

    zz =

    z

    |z|2

    Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind

    M P i f h C l C j

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    More Properties of the Complex Conjugate

    When isz=z?

    z+z= (x+iy) + (x iy) =2x, so

    Re z=z+ z

    2 , similarly Im z=

    z z

    2i .

    |z w|= |z| |w|zw

    =

    z

    w, (w=0)

    |z|= 0 if and only ifz=0.

    Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind

    S I liti

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    Some Inequalities

    |z| Re z |z|

    |z| Im z |z|

    |z+ w| |z| + |w|(triangle inequality)

    |z w| |z| |w|(reverse triangle inequality)

    Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind

    Th F d t l Th f Al b

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    The Fundamental Theorem of Algebra

    Theorem

    If a0,

    a1, . . . ,

    anare complex numbers with an=0, then the polynomia

    p(z) =anzn +an1z

    n1 + +a1z+ a0

    has n roots z1, z2, . . . zn inC. It can be factored as

    p(z) =an(z z1)(z z2) (z zn).

    We will be able to prove this theorem later in this course!

    Consider the polynomialp(x) =x2 + 1 in R. It has no real roots!But in C it can be factored: z2 + 1= (z+ i)(z i)!

    Lecture 2: Algebra and Geometry in C Analysis of a Complex Kind