pcb3013 hw#5 solution

Upload: chai-cws

Post on 04-Jun-2018

235 views

Category:

Documents


1 download

TRANSCRIPT

  • 8/13/2019 PCB3013 HW#5 Solution

    1/5

    PCB3013-Well Test Analysis

    HW# 5

    Prof. Dr. Mustafa Onur, UTP, September 2013

    SOLUTIONS

    Given Date: October 29, 2013Due Data: November 07, 2013

    Subject: Analysis of a buildup test with wellbore storage and skin effects by using type-curve

    matching and semi-log techniques.

    Table 1 gives reservoir/well/fluid data for a vertical well known to be producing at the center

    of a closed reservoir. Table 2 presents the pressure data obtained from a buildup testconducted in that well.

    (a) (10 pts)Estimate producing time using total production and rate prior to shut-in.

    (b) (20 pts)Make a log-log diagnostic plot of delta shut-in pressure change and its derivative

    versus elapsed time, and identify flow regimes exhibited by the buildup data and their timeintervals. Also calculate wellbore storage coefficient from unit-slope line if it exists and kh

    from radial flow derivative (i.e., from zero-slope line) if it exists.

    (c) (30 pts) Perform Horner Analysis to determine permeability, skin, and initial staticpressure. Note that to determine which time interval you will fit your radial flow straight lineon Horner graph, you should look at log-log diagnostic plots of delta pressure and its

    derivative.

    (d) (40 pts) Analyze the same data using type curve matching to estimate k, s, wellborestorage coefficient. Please tabulate your results for comparison.

    Table 1. Reservoir/well/fluid property data.

    Reservoir Thickness, h, 30 ft

    Well radius, rw,, 0.3 ft

    Viscosity, , 1.0 cp

    Formation Volume Factor,Bo, 1.0 RB/STB

    Porosity 0.1Total compressibility, ct 1x10

    -51/psi

    Flow rate before shut-in 300 STB/D

    Total production prior to shut-in 150000 STB

  • 8/13/2019 PCB3013 HW#5 Solution

    2/5

    Table 2. Buildup Test Pressure Data

    Shut-in Time

    t, h.

    Shut-in

    Pressures

    pws, psi

    Delta Pressure

    p=pwf,s-pws

    psi

    Delta

    pressure-

    derivative

    (based on

    Equivalent

    time)psi

    0.0 3961.98 0.0 -

    0.01 3965.16 2.40 2.27

    0.06 3977.23 15.25 15.84

    0.14 3997.14 35.16 33.79

    0.2 4011.03 49.05 48.55

    0.32 4037.89 75.91 74.83

    0.57 4091.54 129.56 113.62

    1.01 4175.46 213.48 174.77

    1.43 4244.22 282.24 222.47

    2.01 4326.49 364.51 253.54

    4.02 4515.62 553.64 271.05

    6.37 4631.6 669.62 217.87

    8.02 4678.39 716.41 182.83

    10.1 4715.24 753.26 142.92

    12.71 4743.4 781.42 105.56

    16 4764.25 802.27 77.89

    20.15 4780.28 818.3 58.99

    25.37 4792 830.02 46.92

    31.93 4801.62 839.64 39.37

    35.83 4806.51 844.53 39.64

    40.2 4810.72 848.74 36.25

    50.61 4819.51 857.53 36.63

    56.79 4823.23 861.25 35.65

    71.49 4831.93 869.95 33.68

    80.21 4835.39 873.41 34.1

    127.13 4851.33 889.35 33.45

    a-) The total production is given as 150000STB and the flow rate prior to shut in is

    given as 300STB/D. From the above we can approximate the production time as:

    Total Production 150000500 12000

    300p p pt t Days t hrs

    q= = = =

    b-) The log-log plot is given below:

  • 8/13/2019 PCB3013 HW#5 Solution

    3/5

    It is clear from the points that fall on the unit slope line that a wellbore storage

    dominated flow period exists. Using the point at t=0.14 hrs.

    05.016.3524

    14.01300

    24=

    =

    =

    p

    tBqC osc bbl/psi

    From the radial flow period we have:

    70.6 70.6

    ln

    ln

    sc o sc od p q B q Bkhd pd t kh

    d t

    = =

    If we use the point at t=71.49 hrs. Then we have:

    9.62868.33

    10.13006.70

    ln/

    6.70=

    =

    =

    tdpd

    Bqkh osc

    md-ft

    c-) Since we have taken tpas 12000hrs, we can say tp>>t. The horner plot of the data

    is given below:

    0.01 0.1 1 10 100 1000t, hrs

    1

    10

    100

    1000

    pwf,s

    -pws,psi

    Unit slope line

    Flat line

  • 8/13/2019 PCB3013 HW#5 Solution

    4/5

    The equation for the semi-log straight line of the Horner plot is given as follows:

    81.7log 5013.48pt t

    pt

    + = +

    Hence from the slope of the semilog straightline we can estimate the kh product:

    1.5977.81

    10.13006.162ln/

    6.162 ==

    =tdpd

    Bqkh osc md-ft

    From the semilog equation we can compute the pressure at t =1hr.

    ( )12000 1

    ( 1) 81.7log 5013.48 1 4680.21

    p t p t psi+

    = = + = =

    We can solve for skin using the below equation

    23.4

    23.33.011011.0

    9.19log

    7.81

    98.39612.4680151.1

    23.3log151.1

    25

    2

    ,1

    =

    +

    =

    +

    =

    s

    s

    rc

    k

    m

    pps

    wt

    swfhr

    Estimate of initial static pressure can be found from extrapolation of the straight line

    to Horner ratio of 1 aspi= 5013 psia.

    1 10 100 1000 10000 100000 1000000 10000000

    (tp+t)/t

    3800

    4000

    4200

    4400

    4600

    4800

    5000

    Shutin

    pressure,psi

    p=-81.7log((tp+t)/t)+5013.48

  • 8/13/2019 PCB3013 HW#5 Solution

    5/5

    d-) Data have been analyzed using type curve matching. The following values of kh,

    C and S are obtained.

    kh, md-ft 661

    s 5.55

    C, bbl/psi 0.0495

    All values determined from all analysis methods are given below:

    Unit Slope line

    and log-log

    derivative plot,

    part-b

    Horner part-c Type-Curve Matching

    kh, md-ft 628.9 597.1 661

    S 4.23 5.55

    C, bbl/psi 0.05 0.0495

    pi, psi 5013 -