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1
Introduction Free particles Cross section 2 → 2 Decay width
FYSH300, fall 2013
Tuomas [email protected]
Office: FL249. No fixed reception hours.
fall 2013
Part 3: Scattering theory
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Introduction Free particles Cross section 2 → 2 Decay width
Basic idea
Particle physics experiment:Know incoming particle(s) — measure outgoing particle properties:
I Momenta (absolute value and direction)I Charges (electric, other conserved), masses, spins/polarizations
=⇒ identify particle typeI Repeat experiment and measure number/frequency of events
=⇒ collect statistics, form spectra (jakauma) dN/ d3p, correlationsI Compare to theory to test/learn about fundamental interactions.
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Introduction Free particles Cross section 2 → 2 Decay width
Terminology IWhat goes in
Beam I Consists of projectile (ammus) particles a (e.g.e±, µ±, ν, p, π, . . . ).
I ∼ monoenergetic & collimated (|∆p|/|p| 1).I Sufficient (1011 . . . 1013 particles/s) but not too high
intensity: want many scatterings, but no interactionsbetween beam particles
I May be polarized or notI Consists of bunches (LHC: 7.4cm long, 7.5m = 25ns
apart)
Target Macroscopic sample at rest in lab (kohtio)
I Large number of particle b.I Distance between scattering centers db λa = h/pa:
independent scatteringsI Thin, so that each a scatters most once.
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Introduction Free particles Cross section 2 → 2 Decay width
Terminology IIWhere it collides
Collider experiment: two beams collide; LHC, Tevatron, LEP,+ Achieve higher energy/$ (
√s = E∗a + E∗b ,
$ ∼ Ebeam ∼√
s)- Hard to align beams: less events
(Not always symmetric: e.g. HERA 30GeV e− + 920GeV p )
Fixed target experiment: beam+target+ Can make target big enough so every beam particle
scatters =⇒ better statistics- Lower energy/$ (
√s ≈
p2mbETRF
a , $ ∼ Ebeam ∼ s )
An experimentalist cannot boost the lab to v = 0.9999 but a theorist can, sowe can do the following derivations in the TRF (= fixed target lab frame).
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Introduction Free particles Cross section 2 → 2 Decay width
Terminology IIIWhat comes out
Exclusive experiment: measure and identify all final state particles.Examples
I π− + p → π+ + π− + nI e+ + e− → µ+ + µ−
Inclusive experiment: only care about/measure certain particles(rest denoted as “X ”). Completely random examples:
I p + p → XI π− + p → π+ + XI p + p → µ+ + µ− + X
Elastic scattering: a + b → a + b (initial and final particles same).
Inelastic scattering: final state particles 6= initial state particles.Examples:
I e+ + e− → e+ + e−, elasticI e+ + e− → µ+ + µ−, inelasticI e+ + e− → µ+ + µ− + γ, inelasticI p + p → X , with X 6= p + p inelastic (total inelastic cross
section)
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Introduction Free particles Cross section 2 → 2 Decay width
Luminosity and cross section
Number of events in scattering a + b → X depends onI Experimental setup: Intensity of incoming projectile particles a + number
of target particles b encounteredI Properties of fundamental interaction
Number of events per unit time
dNa+b→Xev
dt= σa+b→X
Lz | ΦaNb, where
Φa is the flux of particle a (particles/(time*area))
Nb is the number of target particles b “under” the beam
L is the luminosityσ is the cross section: this encodes everything about the
particle interaction.
Dimensions:»
dNdt
–=
1s
= m2 1sm2 =⇒ Cross section is an area.
(Remember we chose to work in TRF, but you can always boost.)
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Introduction Free particles Cross section 2 → 2 Decay width
Some interpretationCross section
σ can be thought of as size of particle; but “size” depends on interaction . . .σ of billiard ball scattering is π(2R)2, (scatter if centers less than 2R apart.)
— but σ of neutrino-billiard ball scattering is much much less.
Loosely cross section = area × probability to scatterProbability is dimensionless — Billiard balls have P = 1 for distance < 2R.
Cross section is Lorentz-invariantIt does not change in boost along the beam axis (or any other) direction(unlike luminosity, because of time dilation!)
Differential σ :dNa+b→c+X
ev
dt d3pc(pc) =
dσa+b→c+X
d3pc(pc)
Lz | ΦaNb
Number of scattering events where final state has particle c in momentumspace cube between pc = (px , py , pz) and (px + ∆px , py + ∆py , pz + ∆pz)— divided by time interval and ∆px ∆py ∆pz .
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Introduction Free particles Cross section 2 → 2 Decay width
Some cross sections
Unit of cross section1barn = 10−28m2
E.g. proton-proton totalinelastic σ at√
s = 200GeV is∼ 40mb = (2fm )2.
Named by Enrico Fermi:( The area corresponding to a
barn is the approximate area of
a typical atomic nucleus which
has a size of 10−12cm. For
most sub-nuclear processes,
this is a very large
cross-section, so Fermi
suggested ”it was as big as a
barn”. )
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Introduction Free particles Cross section 2 → 2 Decay width
More cross sections I
10
-8
10-7
10
-6
10-5
10
-4
10
-3
10-2
1 10 102
σ[m
b]
ω
ρ
φ
ρ′
J/ψ
ψ(2S)Υ
Z
σ(e+e− → hadrons) vs.√
s/GeV
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Introduction Free particles Cross section 2 → 2 Decay width
More cross sections II
10
10 2
10-1
1 10 102
103
104
105
106
107
108
⇓
Plab GeV/c
Cro
ss s
ectio
n (m
b)
10
10 2
10-1
1 10 102
103
104
105
106
107
108
⇓
Plab GeV/c
Cro
ss s
ectio
n (m
b)
√s GeV
1.9 2 10 102 103 104
p p
p−p
total
elastic
total
elastic
pp and pp total and elastic cross sections
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Introduction Free particles Cross section 2 → 2 Decay width
Collider/experiment luminosity
I The luminosity is the “figure of merit” of a particle accelerator/collider.I Bigger luminosity is better, because you can see rarer events.I LHC design luminosity ∼ 1034cm−2s−1 is very big for a collider.
Often quoted is
Integrated luminosity ZdtL
Has units 1/m2: inverse of cross section.
Interpretation:
When LHC has delivered 1fb−1 of integrated lumi, a process with crosssection σ = 1fb should have happened one time (± statistical fluctuations).(LHC design luminosity would give ∼ 300fb−1 in full year of nonstop running.)
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Introduction Free particles Cross section 2 → 2 Decay width
ATLAS measured integrated luminosity at CERN/LHC
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Introduction Free particles Cross section 2 → 2 Decay width
Quantum scattering theory: the S-matrixCross section related to quantum mechanical matrix element, computablefrom the Hamiltonian of a given theory.Consider a scattering process a + b → 1 + 2 + · · ·+ n
Initial state |i〉 is system of two free particles (a + b) at t → −∞.Final state |f 〉 is system of n free particles at t →∞
Time development from |i〉 to |f 〉 described by S-matrix
All information is in matrix elements of S, transition amplitudes
Sfi ≡ 〈f |S|i〉, from which Pfi = |Sfi |2 = 〈i |S†|f 〉〈f |S|i〉
is the transition probability.
Probability is conserved, sum over all final states is 1 (I=identity operator)
1 =X
f
Pfi = 〈i |S†=I,complete setz | X
f
|f 〉〈f | S|i〉 = 〈i |S†S|i〉 = 1∀|i〉, i.e. S unitary
Subtracting trivial |i〉 = |f 〉 we get: “T -matrix” (T like transition) :
S = 1 + i T , i.e. for components Sfi = δfi + iTfi ,
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Introduction Free particles Cross section 2 → 2 Decay width
Quantum mechanical scattering theory
I We need the state vectors |i〉 and |f 〉 corresponding to the initial andfinal particle content.
I These are many particle states created from the vacuum |0〉 by particlecreation operators that should be familiar if you have taken QMII.
I We will, however, not go into the second quantization formalism here;you need it to derive the Feynman rules, but we will in this course not dothat.
Relativistic plane wavesI Contrary to many QM courses we want to have a completely relativistic
normalization (So some things may differ from nonrelativistic treatment QM I/II,
conventions in atomic physics, quantum optics etc.)
I The in and out-states are described by a complete set of orthonormalFock (=multiparticle) states |n〉.
We now need to state our normalization of the wave functions (plane wavestates) that correspond to these multiparticle states.
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Introduction Free particles Cross section 2 → 2 Decay width
Klein-Gordon equation and plane waves
I Remember from nonrelativistic QM: E → i∂0, p→ −i∇.I Nonrelativistic dispersion relation is
E =1
2mp2 =⇒ Schrodinger i∂0ψ(t , x) = − 1
2m∇2ψ(t , x)
I Relativistic dispersion relation
E2 = p2+m2 =⇒ Klein-Gordon eq (i∂0)2ϕ(t , x) =h(−i∇)2 + m2
iϕ(t , x)
I In covariant notation (recall = ∂µ∂µ = ∂2
0 −∇2) relativistic plane wave
( + m2)ϕ(x) = 0, solution Ne−ip·x = Ne−iEpt+ip·x
(E2, not E , because√ of∇ awkward. Physically: antiparticles, E < 0 solutions.)
I Note: Ep =p
p2 + m2, the energy corresponding to momentum p.
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Introduction Free particles Cross section 2 → 2 Decay width
Normalization in a box
Problem: want to work with plane waves (exact) momentumeigenstates.Heisenberg uncertainty relation =⇒ completelydelocalized in space and unnormalizable.
Solution: assume we are in a large box of size V = L3, periodicboundary cond’s.
Normalization choice for plane waves Ne−ip·x
N =1√V
So that ZV
d3x˛Ne−ip·x
˛2= 1
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Introduction Free particles Cross section 2 → 2 Decay width
Box density of states
Periodic boundary allows us to count discrete states:
ϕ(x , y , z) = ϕ(x + L, y , z) = ϕ(x , y + L, z) = ϕ(x , y , z + L)
ei(p1x+p2y+p3z) = ei(p1(x+L)+p2y+p3z) = ei(p1x+p2(y+L)+p3z) = ei(p1x+p2y+p3(z+L))
1 = eip1L = eip2L = eip3L
only true if (p1, p2, p3) = 2πL (n1, n2, n3); ni ∈ Z.
NowXstates
=X
n1,n2,n3
≈V→∞
Zd3n =
ZV
(2π)3 d3p
(P
n f (n) ≈R
dnf (n), when f (n) varies slowly.R n+1/2
n−1/2 dx = 1.
“Slowly varying” requires V →∞ because 2πL (n1, n2, n3) close to 2π
L (n1 + 1, n2, n3).)
Now single particle states are orthonormal
N =1√V
=⇒ 〈p|q〉 =
Zd3x(Ne−ip·x )∗(Ne−iq·x ) = δp,q,
(Discrete Kronecker delta for discrete momenta =⇒ Now well defined matrices S and T . )
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Introduction Free particles Cross section 2 → 2 Decay width
Conserved particle number current, nonrelativistic
In nonrelativistic theory:I Particle density ρNR = ψ∗(t , x)ψ(t , x),
current jNR = − i2m (ψ∗∇ψ − ψ∇ψ∗).
I Probability conservation = continuity equation: ∂tρNR +∇ · jNR = 0.I For a plane wave ψ(t , x) = Ne−iEpt+ip·x these are:
ρNR = |N |2 ; jNR = |N |2p/m.
This does not directly work in relativistic caseI A relativistic current is jµ = (ρ, j)I It should also have a continuity equation ∂µjµ = 0.I But it should be a proper 4-vector;
thus for a plane wave we should have jµ ∼ pµ
I In particular: Density of free particles in a box should beproportional to the energy in a Lorentz-covariant formulation.
(Thought experiment: Start from fixed box V , 1 particle in rest, energy m, density 1/V .Boost to another frame, γ = 1/
p1− v2; box size contracted to V/γ,
particle energy now mγ, density γ/V .)
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Introduction Free particles Cross section 2 → 2 Decay width
Conserved current, relativistic case
Definition
jµ ≡ i(ϕ∗∂µϕ− ϕ∂µϕ∗), for plane wave ϕ = Ne−ip·x =⇒ jµ = 2pµ|N |2
In particular, for our choice N = 1√V
the particle density is ρ ≡ j0 = 2EV
I Funny dimensions (of energy density, not number density) , related tonormalization of the (unnormalizable) plane waves.
I Could replace E =⇒ E/m (some books do this) , but then m = 0 difficult.I In the end the normalization cancels along with V
Density of states: now “2E” particles in VThe number of states per particle isX
states
1Npart/state
=
ZV
2Ep(2π)3 d3p = VZ
d4pδ(p2 −m2)
(2π)3 θ(p0)
This is the Lorentz-invariant phase space measure.
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Introduction Free particles Cross section 2 → 2 Decay width
Back to cross section
Cross section is Lorentz-invariant, but we will derive it in TRF.
Recall σa+b→1+···+n =Ns
∆tΦaNb, b at rest
I Nb = nbV = 2ETRFb = 2mb, number of target particles
I Φa = na|vTRFa | = 2ETRF
a |vTRFa |/V flux of particle a (flux = density × velocity)
I 2ETRFa |vTRF
a |/V = 2|pTRFa |/V =
qλ(s,m2
a,m2b)/(mbV )
I Thus (ΦaNb)TRF = 2qλ(s,m2
a,m2b)/V =⇒ Back to Lorentz-invariant form,
up to volume factor V .
I Ns∆t =scattering events per time = probability to go to state |f |; summedover states, divided by ∆t
Ns
∆t=
N(ab → 1 . . . n)
∆t=|Tfi |2
∆t× (number of possible final states),
=
Z nYm=1
V2Ep.(2π)3 d3pm ×
|Tfi |2
∆t
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Introduction Free particles Cross section 2 → 2 Decay width
T -matrix elementThe last, and most important, thing we need
Number of scatterings, T -matrixThe number of scatterings is given by the T -matrix element between finaland initial states. We separate out some factors:
Tfi = −iNaNbN1 . . .Nn(2π)4δ(4)
pa + pb −
nXi=1
pi
!Mfi ,
Why the factors?I Energy, momentum always conserved in amplitude: useful to extractδ(4) to explicitly treat (δ(4))2 in |Tfi |2
I Plane wave normalizations: conventions for N may vary; forMfi not.(Justification: Tfi is matrix element between our box-normalized plane waves
Tfi ∼ 〈f |T |i〉 ∼ (Nae−ipa·xNbe−ipb·x )∗T (N1e−ip1·x . . .Nne−ipn·x )
The “invariant amplitude”Mfi , o.t.o.h. is defined using unnormalized plane waves
Mfi ∼ (e−ipa·x e−ipb·x )∗T (e−ip1·x . . . e−ipn·x )
Why this complication? needed the box to understand delta functions, count particles. . . )
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Introduction Free particles Cross section 2 → 2 Decay width
Putting things together
What is then (δ(k))2? Integral representation of δ:Zdx eikx = (2π)δ(k), thus δ(k = 0) =
12π
Zdx =
L2π
and (2π)4δ(4)(0) = ∆tV
Now we have
σ =1
ΦaNb
Ns
∆t=
V
2qλ(s,m2
a,m2b)
Z nYm=1
»V
2Ep.(2π)3 d3pm
–
|−iNaNbN1 . . .Nn|2h(2π)4δ(4)(pa + pb −
Pni=1 pi )
i2|Mfi |2
∆t
=V
2qλ(s,m2
a,m2b)
Z nYm=1
»V
2Ep.(2π)3 d3pm
–V−n−2(2π)4δ(4)(pa + pb −
Pni=1 pi )[∆tV ]|Mfi |2
∆t
Now volume cancels — time interval cancels
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Introduction Free particles Cross section 2 → 2 Decay width
Final master formula for cross section
The final formulae
Total σ(ab → 1 . . . n) =1
2qλ(s,m2
a,m2b)
"Z nYm=1
d3pm
(2π)32Em
×(2π)4δ(4)“
pa + pb −Xn
i=1pi
”#|Mab→1...n|2 ,
Differentialdσab→1...n
d3p1 . . . d3pn=
1(2(2π)3E1) · · · (2(2π)3En)
1
2qλ(s,m2
a,m2b)
×(2π)4δ(4)“
pa + pb −Xn
i=1pi
”|Mab→1...n|2
I Everything is Lorentz-invariant (Derived in TRF, but now works in any frame.)
I The invariant amplitudeM(ab → 1 . . . n) from Feynman rules.I Part in [·] is Lorentz-invariant n-particle phase space.
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Introduction Free particles Cross section 2 → 2 Decay width
Special case: 2→ 2 scattering
First work in general frame, start from the general formula
σab→cd =1
2qλ(s,m2
a,m2b)
Zd3pc
2Ec(2π)3
d3pd
2Ed (2π)3 (2π)4δ(4)(pa+pb−pc−pd )|M|2.
I Now δ(4)(p) = δ(E)δ(3)(p) =⇒ integrate d3pd .I Other variable d3pc = |pc |2 d|pc | dΩc
σab→cd =(2π)−2
8qλ(s,m2
a,m2b)
ZdΩc
Z|pc |2 d|pc |
EcEdδ(Ea + Eb − Ec − Ed )|M|2
Get rid of δ(Ea + Eb − Ec − Ed ), usingR
d|pc |.Remember, now Ec =
p|p2
c |+ m2c , Ed =
q|pa + pb − pc |2 + m2
d .=⇒ δ-function has |pc |-dependence in both Ec and Ed .
Complicated in general frame, specialize to CMS.
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Introduction Free particles Cross section 2 → 2 Decay width
Special case: 2→ 2 scattering in CMS
In CMS |pc | = |pd | ≡ p∗f , E∗a + E∗b =√
sGet rid of δ(Ec + Ed −
√s), using
Rd|pc |.
pa
pb
pc
pd
θ∗
θ∗
Remember δ(f (x)) =δ(x − x0)
|f ′(x0)| , where f (x0) = 0
Nowd
dpE(p) =
ddp
pp2 + m2 =
ppp2 + m2
=p
E(p)
So δ(E∗c (p∗f ) + E∗d (p∗f )−√
s) =δ(p∗f − . . . )
p∗fE∗c
+p∗fE∗d
=E∗c E∗dp∗f√
sδ(p∗f − . . . )
and σab→cd =(2π)−2
8qλ(s,m2
a,m2b)
ZdΩc
Z(p∗f )2 dp∗f
E∗c E∗d
E∗c E∗dp∗f√
sδ(p∗f − . . . )|M|2
=(2π)−2
8qλ(s,m2
a,m2b)
p∗f√s
ZdΩ∗c |M|2.
p∗f =
qλ(s,m2
c ,m2d )
(2√
s)(Remember:
qλ(s,m2
a,m2b) came from p∗i .)
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Introduction Free particles Cross section 2 → 2 Decay width
2→ 2 scattering in CMS, final result I
Not integrating over the angle gives differential σ
dσab→cd
dΩ∗c=|Mab→cd |2
64π2s
sλ(s,m2
c ,m2d )
λ(s,m2a,m2
b)=|Mab→cd |2
64π2sp∗fp∗i.
(Differential: scattering events with final particle in angle Ω∗c , divided by angle dΩ∗c )
Special case (ma = mc and mb = md ) or (ma = md and mb = mc)Leads to p∗i = p∗f =⇒
dσab→cd
dΩ∗c=|Mab→cd |2
64π2s
RemarksI Energy-momentum conservation constraints now all implicitly in |M|
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Introduction Free particles Cross section 2 → 2 Decay width
2→ 2 scattering, invariant dσ/dt
Convenient to also express dΩ∗c in a Lorentz-invariant way, via t .In general dΩc = dφc d(cos θc). If scattering is unpolarized (summed, averaged
over spins) , cross sections do not depend on φc =⇒ dσd(cos θc )
= 2π dσdΩc
.
t = (pa − pc)2 = m2a + m2
c − 2E∗a E∗c + 2|p∗a ||p∗c | cos θ∗c=⇒ dt = 2p∗i p∗f d(cos θ∗c )
=⇒ dσdt
=2π
2p∗i p∗f
dσdΩ∗c
pa
pb
pc
pd
θ∗
θ∗
Using the expressions from the previous slide:dσab→cd
dΩ∗c= |Mab→cd |2
64π2sp∗fp∗i
and p∗i =pλ(s,m2
a,m2a)/(2
√s), this leads to
Differential cross section in manifestly Lorentz-invariant form
dσab→cd
dt=
|Mab→cd |2
16πλ(s,m2a,m2
b)
If s m2a,m2
b: λ(s,m2a,m2
b) = s2 + m4a + m4
b − 2sm2a − 2m2
am2b − 2m2
bs ≈ s2
=⇒ this is the easiest version to remember.
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Introduction Free particles Cross section 2 → 2 Decay width
Example: unpolarized e+e− → µ+µ− scatteringA little flavor of things to come
e− µ−, q
e+ µ+, q
γ, Z
I Assume√
s small enough so we can neglectZ0-boson =⇒ only one Feynman diagram at LO(=leading order)
I Use Feynman rules for QuantumElectroDynamics= QED =⇒ get expression for|Me+e−→µ+µ− |2.
I unpolarized = summed over spins of µ±;averaged over the spins of e±, denote |M|2
I Assuming√
s me,mµ
|M|2 ≡ 12
12
Xspins
|M|2 = 2e4 t2 + u2
s2 .
I Origin of Mandelstams: M contains dot productsof pa, pb, pc and pd =⇒ written in terms of s, tand u.
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Introduction Free particles Cross section 2 → 2 Decay width
Example: e+e− → µ+µ− continued
The differential cross section for the above process becomes(p∗i ≈ p∗f in
√s me,mµ limit)
dσdΩ∗c
=α2
4s(1 + cos2 θ∗µ).
From this, the total cross section is
σ(e+e− → µ+µ−) =4πα2
3s.
e− µ−, q
e+ µ+, q
γ, Z I Two interactions vertices ∼ e, soM(e+e− → µ+µ−) ∝ e2, and |M|2 ∝ e4 ∝ α2;α = e2/(4π) ≈ 1/137.
I Check dimensions: [s] = GeV 2
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Introduction Free particles Cross section 2 → 2 Decay width
e+e− → µ+µ−, comments
Angular distribution depends on spin structure
I Angular distribution 1 + cos2 θ∗ characteristic of spin-1 particle (virtualphoton γ∗) decaying into two spin 1/2 particles.
I For spin interpretation, there are two spin states with amplitudes:∼ (1± cos θ). These are different final states =⇒ they do not interfere,each amplitude is squared separately, then added.
I Cross section for γ∗ → 2 spin-0 particles would be ∼ sin2 θ ∼ |Y 11 (θ, φ)|2;
spin has to go into m = 1, ` = 1 angular momentum of the pair.
See Halzen, Martin, sec 6.6.
Squaring and averagingI Sum of diagrams=amplitude with one initial and final state (incl. spin)I Then square each amplitude separatelyI Only then sum/average |M|2’s from different spin states =⇒ this is
denoted by |M|2
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Introduction Free particles Cross section 2 → 2 Decay width
Particle decay
Initial state |i〉 = unstable particle a, decaying to n particle final state |f 〉.I Only natural frame is CMS = rest frame of a.I Momentum conservation p2
a = (p1 + · · ·+ pn)2.In CMS: m2
a = (E1 + · · ·+ En)2 ≥ (m1 + . . .mn)2
=⇒ threshold ma ≥ m1 + · · ·+ mn.(Thus a has ma > 0, there is always a rest frame.)
TerminologyI In general different possible final states |f 〉: decay channels.I Define the decay width Γf for channel f as
Γf ≡Nf
Na∆Tin a rest frame.
Nf is the number of decays to state fNa is the number of decaying particles a
∆T is the time interval required for Nf decays. All
expe
rimen
tally
acce
ssib
le,
like
def.
ofσ
.
Now want to tie this definition with theoretically calculable quantities, skippingdetails that are similar to the derivation with cross sections.
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Introduction Free particles Cross section 2 → 2 Decay width
Decay width and amplitude
I Recall: for cross section we hadNs∆t = N(ab→1...n)
∆t = |Tfi |2
∆t × (number of possible final states),I Also now
Nf
∆t=|Tfi |2
∆t× (number of possible final states).
I Again transition amplitude Tfi and the invariant amplitudeMfi :
Tfi = −iNaN1 . . .Nn(2π)4δ(4)“
pa −Xn
j=1pj
”Mfi (a→ 1 . . . n).
I |Tfi |2 has a δ(4) squared =⇒ treated similarly as before.I Again the number of final states per particle is 1
2EV
(2π)3 d3p
Result: decay width
Γf =1
2Ea
Z nYm=1
d3pm
(2π)32Em(2π)4δ(4)
“pa −
Xn
i=1pi
”|M(a→ 1 . . . n)|2.
Γa and Ea depend on frame; in CMS Ea = ma. Rest is Lorentz-invariant.
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Introduction Free particles Cross section 2 → 2 Decay width
Branching ratios
I One unstable particle; many possible finals tates |f 〉, each has width Γf .Define total decay width
Γ ≡X
f
Γf ,
I Fraction of each final state is branching ratio
Bf ≡Γf
Γ; often in %.
I mean lifetimeτ ≡ 1
Γ.
34
Introduction Free particles Cross section 2 → 2 Decay width
Branching ratio example
ExampleFor the Z0 boson we have the following branching ratios:
Z0 → e+e− 3.363%µ+µ− 3.366%τ+τ− 3.370%
In addition:I Z0 can decay ”invisibly” to a pair of any of the three neutrino species:
total branching ratio 20.00%.I Hadronic decay modes: remaining 69.91% of the total width
Γ(Z0) = 2.4952± 0.0023GeV τ ' 0.079fm ≈ 3 · 10−25 s.
Hence the Z0 boson is very short-lived.In particle physics “long-lived particles” have lifetime ∼ 10−16s or more=⇒ can be actually seen directly in experiment.
35
Introduction Free particles Cross section 2 → 2 Decay width
Some decay times
I Out of gauge bosons γ is absolutely stable, W± and Z 0 extremelyunbstable, Γ ∼ 2GeV and τ ≈ 3 · 10−25s.
I gluon is confined, stability/unstability not well definedI Neutrinos, e± stableI τ±, µ± decay via weak interaction: τµ ≈ 2 · 10−6s and ττ ≈ 3 · 10−13 s.I Quarks u, d , c, s and b form first a hadron which then decays. Out of all
hadrons only the proton is absolutely stable.I Heaviest t quark decays before it has formed a hadron, τt ≈ 0.02fm ; It
would take a time of the order of 1 fm to make a hadron.
36
Introduction Free particles Cross section 2 → 2 Decay width
1→ 2 decay
Analogous to σ(2→ 2) =⇒ we’ll be brief. Frame is CMS, omit ∗.
Γa→cd =1
2ma
Zd3pc
(2π)32Ec
d3pd
(2π)32Ed(2π)4δ(ma − Ec − Ed )δ(3)(pc + pd )|M|2.
I Use δ(3)(pc + pd ) to doR
d3pd ; sets |pc | = |pd | ≡ pf
I Write d3pc = dΩp2f dpf , want to use δ(ma − Ec − Ed ) to do
Rdpf
I Energy conservation
δ(ma − Ec − Ed ) =EcEd
p0ma|pf =p0δ(pf − p0),
where p0 is obtained by solving ma = Ec + Ed , i.e. explicitly
p0 =
qλ(s,m2
c ,m2d )
2√
s=
qλ(m2
a,m2c ,m2
d )
2ma.
Final result Γ(a→ cd) =
qλ(m2
a,m2c ,m2
d )
64π2m3a
ZdΩ|Mfi (a→ cd)|2.
37
Introduction Free particles Cross section 2 → 2 Decay width
Example: π− decay
Two possible final states, µ−νµ and e−νe (threshold,conservation laws).
Experiments:Γ(π− → e−νe)
Γ(π− → µ−νµ)≈ 1.23 · 10−4 very small, why?
π−
u
dW−
νℓ
ℓ
I Annihilate du =⇒ charged weak currentI One W -boson, 2 weak vertices:M∼ g2
Wm2
W∼ GF (“Fermi constant”)
I π− ↔ du: “pion decay constant”M∼ fπ.
Evaluation of the Feynman diagram gives:(Actually Feynman rule for W`ν` vertex + information of pion wavefunction in fπ)
|M(π− → `−ν`)|2 = 4G2F f 2πm2
` (p` · pν) = 2G2F f 2πm2
`m2π
„1− m2
`
m2π
«,
Then (exercise) the decay width is Γ(π− → `−ν`) =1
8πG2
F f 2πmπm2
`
„1− m2
`
m2π
«2
,
which implies the ratioΓ(π− → e−νe)
Γ(π− → µ−νµ)=
„me
mµ
«2„m2π −m2
e
m2π −m2
µ
«2
≈ 1.28·10−4.
38
Introduction Free particles Cross section 2 → 2 Decay width
Example 2: Muon decay µ− → e− + νe + νµ, estimates I1→ 3 decay
µ−νµ
e−
νe
W−
1. Conservation laws determine finalparticles:1.1 Charge conservation: e− (only negative
particle with m < mµ).1.2 µ number conservation: Lµ = 1 =⇒ νµ1.3 e number: Le = 0: νe to compensate e−
2. Only e− detected. 2 others=⇒ continuous distribution of Ee.
As before, we can estimate the decay width asI One W propagator, 2 W -fermion vertices: M∼ g2
W/m2W ∼ GF
I mµ me,mν` =⇒ dimensionally must have Γ ∼ G2F m5
µ
39
Introduction Free particles Cross section 2 → 2 Decay width
Example 2: Muon decay µ− → e− + νe + νµ, calculation
The actual invariant amplitude, from S.M. Feynman rules, is
|M(µ→ e−νeνµ)|2 = 64G2F (k · p′)(k ′ · p).
µ−, p
νµ, k
e−, p′
νe, k′
W−
Denote p = (mµ, 0)
p′ = (E ′,p′)k = (ω, k)
k ′ = (ω′, k′)
Differential width is dΓ =1
2mµM(µ→ e−νeνµ)|2 dQ,
with dQ =d3p′
(2π)32E ′d3k′
(2π)32ω′d3k
(2π)32ω(2π)4δ(4) `p − p′ − k − k ′
´.
This can be simplified usingZ
d3k2ω
=
Z Eats δ(4)z|d4k θ(ω)
1dz | δ(k2) .
40
Introduction Free particles Cross section 2 → 2 Decay width
Example 2: Muon decay µ− → e− + νe + νµ, result
We get dQ =1
(2π)5
d3p′
2E ′d3k′
2ω′θ(mµ − E ′ − ω′)δ((p − p′ − k ′)2)
After intermediate steps (exercise) we get
dΓ =G2
F
2π3 dE ′ dω′mµω′(mµ − 2ω′),
with restrictions12
mµ − E ′ ≤ ω′ ≤ 12
mµ
0 ≤ E ′ ≤ 12
mµ
Integrating, final result is (exercise) Γ =G2
F m5µ
192π3
I Estimate ∼ G2F m5
µ trueI But constant of proportionality is very small!
Details: Halzen-Martin, sec. 12.5. Also in KJE’s notes, after page 87.