28. (a) Computing torques about the hinge, we find the tension in the wire:

TL sin θ − Wx = 0 =⇒ T =Wx

L sin θ.

(b) The horizontal component of the tension is T cos θ, so equilibrium of horizontal forces requires thatthe horizontal component of the hinge force is

Fx =(

Wx

L sin θ

)cos θ =

Wx

L tan θ.

(c) The vertical component of the tension is T sin θ, so equilibrium of vertical forces requires that thevertical component of the hinge force is

Fy = W −(

Wx

L sin θ

)sin θ = W

(1 − x

L

).