PATEL Shubhamkhumar Oral blanc de Physique

PT Lycée Benjamin Franklin 5 juin 2019

Exercice A :

Exercice B :

m l M

!0

xx(t) ✓(t) ✓(0) = ✓0 x(0) = 0 d✓

dt(0) = 0 dx

dt(0) = 0

M >> m M << m !1 = !0

Dd

−θ0

M

m.

✓(0) = �✓0 t0t < t0 t > t0 ✓(t) x(t)

x = D t1t > t1

a bT1 T2 �

T (r) a b � r

L z

I+(z, t) = I0 exp j(!t� kz)

z = L/2

�/2

+Vsat V+ > V� �Vsat V+ < V�E R2 R1 = 10 ⌦

cµ0

M�!f = �↵x�!ex

�

x(t)x(t)

3, 1.107

a = 50�!⌦ = ⌦�!uz

r = a k�!v k = 180�!⌦ �!v

�!v v < a v > a�!⌦

p = p0 p

af 0

1 2 1

2 f 01 f 0

2

1 2 f 01 = 3a f 0

2 = a O1O2 = 2a

µ T xd~F = �Kdsy~ey ds

y

c =q

T

µ!0 =

qK

µ

�

� = 589 nm

L = 2, 9 cm30± 1

n� 1 n

h

↵h = 20 m ↵ = 100 �

L1 L2 M Q0

V0 P1

P0 T0

U µh

V2

T2

V0

h0

T2T0

P0 µ g h �T2T0

P0 µ g h0

� h h0

⇢

• ⇢ = 0 x < �a

• ⇢ = ⇢0. sin�⇡.x

a

�x 2 [�a, a]

• ⇢ = 0 x > a

�