oracle developer les03 arabic

7/27/2019 ORACLE DEVELOPER les03 arabic

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Mohamed_Suez ABU FARIS

10G2011

admin

HIO SUEZ

6/7/2011


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2

-: I) (

Practice 2

1-The HR department wants a query

1: ;DESC EMPLOYEES: HR )

HR : 7.sqllab_01_0\save c: sIsqlpluscriptSAVE

2- The HR department...

2: DISTINCT

3- The HR department has

3: ),( .

4-If you want an extra

4: ),(

5-The HR department needs your assistance

:5

12000.

select Employee_id,last_name,job_id,hire_date asSTARTDATE

from Employees;

Select Distinct ob_idFrom employees;

Select last_name||, ||job_id as EMPLOYEE AND TITLEFrom employees;

Select employee_id||,||last_name||,||first_name||,||>>>>ETC

select last_name,employee_idfrom employees

wheresalary > 12000;


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6-Create a report...

6: ...

7-The HR departments needs to find high-salary

:7

8-Create a report to display the last

... :8

9-Display the last name and department number...

50 20 : 9 .

10-Modify lab_02_03.sql to display the last name and salary

6: 3 .5 35020

11-The HR department needs a report ...

11: 1994 .

select last_name,department_idfrom employees

where employee_id =176;

select last_name,salaryfrom employeeswhere salary not between 5000 and 12000;

select last_name,job_id,hire_date

from employees

where last_name in( 'Matos' , 'Taylor');

select last_name,department_id

from employees

where department_id in( 20,50)

/where department_id =20 ordepartment_id=50

order by last_name;

select last_name,salary "Monthly Salary"

from employeeswhere salary between 5000 and 12000

and department_id in( 20,50) ;___

Select last_name,hire_date

From employees

Where hire_date like'%94';


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12- Create a report to display the last name and job title ...

12: .

)( :-13-Create a report to display the last name, salary

:13 .

14-Display all employee last names in which the third

14: Where

._

select last_name,job_id

from employees

where manager_id is null;

Select last_name,salary,commission_pct

From employees

Where commission_pct is not null

Order by salary desc,commission_pct desc

select last_name

from employees

where last_name like '__a%'


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Case-M

Function

LOWER('SQL CoLOWER: Converts mixed

UPPER('SQL CoUPPER: Converts mixed

INITCAP('SQLINITCAP: Converts t

re

.

.

SELECT'The job id for '||UP

FROM employees;

__anipulation FunctionsRes

sql curse')case or uppercase character stri

SQL Curse')case or lowercase character stri

Sql Course')e first letter of each word to u

aining letters to lowercase

ER(last_name)||' is '||LOWER(job_id) A

ult

ursengs to lowercase

URSEngs to uppercase

urse

percase and

-

-

"EMPLOYEE DETAILS"


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.

..INSTR

Charact FunctionCONCAT('Hello', 'World')

CONCAT: Joins values togeth

SUBSTR('HelloWorld',1,5)SUBSTR: Extracts a string of

LENGTH('HelloWorld')

LENGTH: Shows the length o

INSTR('HelloWorld', 'W')

INSTR: Finds the numeric posLPAD(salary,10,'*')

LPAD: Pads the character val

RPAD(salary, 10, '*')

RPAD: Pads the character val

REPLACE('JACK and JUE','

REPLACE : Replace string wi

TRIM('H' FROM 'HelloWorl

TRIM: Trims any character fr

,CONCAT , a

...

r-Manipulation Functio ResultHelloWorld

r (You are limited to sing two parameters wit

Hellodetermined length

10

a string as a numeric value.

6

ition of a named character.*****24000

e right- ustified.

24000*****

e left-justified.

','BL') BLACK and BL

h another one

') elloWorld

om the string.

-

-: ENGTH

s

h CONCAT)

E


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Number

Function

ROUND(45.926, 2)

ROUND: Rounds value t

TRUNC(45.926, 2)

TRUNC: Truncates va

MOD(1600, 300)

MOD: Returns remai

.

.

16003/=500

SELECT ROUND(4

FROM DUAL;

SELECT TRUNC(45

FROM DUAL

unctionsResul

45.93

o specified decimal 45.92

ue to specified decimal 100

der of division

ROUND

TRUNC

MOD .100

.923,2), ROUND(45.923,0),ROUND(45

.923,2),TRUNC (45.923),TRUNC (45.9

-

.923,-1)

3,-1)


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Wor

-:DD-MON-RR HH:MM:

Element Result

YYYY Full year in numbersYEAR Year spelled out (in

MM Two-digit value forMONTH Full name of the monMON Three-letter abbreviDY Three-letter abbreviDAY Full name of the dayDD Numeric day of the

DUAL

Arithmetic

) ...)

SELECT last_name, hire_datFROM employees

WHERE hire_date < '01-F

SELECT SYSDATEFROM DUAL;

Operation

date + number

date number

date date

date + number/24

king with Dates ___

SS

(nglishonththtion of the monthtion of the day of the weekof the weekonth

)(

ith Dates __

e

B-88';

esult Description

ate Adds a number of days t

ate Subtracts a number of d

umber of days Subtracts one date from

ate Adds a number of hours

3 3

SYSDATE

o a date

ays from a date

another

to a date


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Date Functions ___

.

\

Function Result MONTHS_BETWEEN Number of months between two

dates

MONTHS_BETWEEN ('01-SEP-95','11-JAN-94') 19.6774194

ADD_MONTHS Add calendar months to date ADD_MONTHS('11-JAN-94',6) '11-JUL-94'

NEXT_DAY Next day of the date specified NEXT_DAY ('01-SEP-95','FRIDAY') '08-SEP-95'

LAST_DAY Last day of the month LAST_DAY ('01-FEB-95') '28-FEB-95'

ROUND Round date ROUND(SYSDATE,'MONTH')

ROUND(SYSDATE ,'YEAR')

01-AUG-03

01-JAN-04

TRUNC Truncate date TRUNC(SYSDATE ,'MONTH')

TRUNC(SYSDATE ,'YEAR')

01-JUL-03

01-JAN-03

SELECTemployee_id, hire_date,MONTHS_BETWEEN (SYSDATE, hire_date) TENURE,

ADD_MONTHS (hire_date, 6) REVIEW,NEXT_DAY (hire_date, 'FRIDAY'),

LAST_DAY(hire_date)

FROM employees

HERE MONTHS_BETWEEN (SYSDATE, hire_date) < 36;


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MAN

Operator Meaning

AND Returns TRUE ifconditions are tru

OR Returns TRUE ifcondition is true

NOT Returns TRUE ifis false

SELECT employee_id, hiTRUNC(hire_date, 'MOFROM employees

HERE hire_date LIK

...

-:

10000 .

oth component

ithercomponent .

he following condition .

re_date, ROUND(hire_date, 'MONTH')TH')

'%97';

-:

.

,


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.

.

Rules of

MeaningOperatorArithmetic o1

Concatenatio2Comparison3

IS [NOT] N4

[NOT] BET5Not equal to6

NOT logical7AND logical8OR logical c9

. 3

...recedence

eratorsn operatoronditions

LL, LIKE, [NOT] INEEN

onditionondition

ndition

-:

-:

10000


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-

AD_( ))SA_REP ))AD_REPS

...

...

: )EPS))SA_REP

15 3

:

15000

000


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:-The HR department needs your assistance with creating some queries.

1. Display the last name of all employees who have both an a and an e intheir last name.

2. Display the last name, job, and salary for all employees whose job is salesrepresentative or stock clerk and whose salary is not equal to $2,500,$3,500, or $7,000.

3. Modify lab_02_06.sql to display the last name, salary, and commission forall employees whose commission amount is 20%.

4. Write a query to display the current date. Label the column Date .

5. The HR department needs a report to display the employee number, last

name, salary, and salary increased by 15.5% (expressed as a wholenumber) for each employee. Label the column New Salary.

6. Modify your query lab_03_02.sql to add a column that subtracts the oldsalary from the new salary. Label the column Increase.

7. Write a query that displays the last name (with the first letter uppercaseand all other letters lowercase) and the length of the last name for allemployees whose name starts with the letters J, A, or M. Give eachcolumn an appropriate label. Sort the results by the employees last

names.8. The HR department wants to find the length of employment for each employee. Foreach employee, display the last name and calculate the number of months betweentoday and the date on which the employee was hired. Label the columnMONTHS_WORKED. Order your results by the number of months employed. Round

the number of months up to the closest whole number.


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9. Create a report that produces the following for each employee: earns monthly but wants . Label the column Dream Salaries.

10. Create a query to display the last name and salary for all employees.Format the salary to be 15 characters long, left-padded with the $ symbol.Label the column SALARY.

11. Create a query that displays the first eight characters of the employeeslast names and indicates the amounts of their salaries with asterisks. Eachasterisk signifies a thousand dollars. Sort the data in descending order of

salary. Label the column EMPLOYEES_AND_THEIR_SALARIES.

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