operating systems cse 411 cpu management sept. 18 2006 - lecture 6 instructor: bhuvan urgaonkar

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Operating Systems Operating Systems CSE 411 CSE 411 CPU Management CPU Management Sept. 18 2006 - Lecture 6 Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Instructor: Bhuvan Urgaonkar Urgaonkar

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Page 1: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Operating SystemsOperating SystemsCSE 411CSE 411

CPU ManagementCPU Management

Sept. 18 2006 - Lecture 6Sept. 18 2006 - Lecture 6

Instructor: Bhuvan UrgaonkarInstructor: Bhuvan Urgaonkar

Page 2: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Ready

Waiting

Running

Disk

Lock

OS (scheduler)

Hmm .. Who shouldI pick to run?

Page 3: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

First-Come, First-Served Scheduling

(FCFS) Process Run Time

P1 24

P2 3

P3 3

• Suppose that the processes arrive in the order: P1 , P2 , P3

The Gantt Chart for the schedule is:

• Waiting time for P1 = 0; P2 = 24; P3 = 27• Average waiting time: (0 + 24 + 27)/3 = 17

P1 P2 P3

24 27 300

Page 4: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

FCFS Scheduling (Cont.)

Suppose that the processes arrive in the order P2 , P3 , P1

• The Gantt chart for the schedule is:

• Waiting time for P1 = 6; P2 = 0; P3 = 3• Average waiting time: (6 + 0 + 3)/3 = 3• Much better than previous case• Convoy effect short process behind long process

P1P3P2

63 300

Page 5: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Shortest-Job-First (SJF) Scheduling

• Associate with each process the length of its next CPU burst. Use these lengths to schedule the process with the shortest time

• SJF is optimal for avg. waiting time – gives minimum average waiting time for a given set of processes– In class: Compute average waiting time for the

previous example with SJF– Prove it (Homework 1, Will be handed out next

Friday)

Page 6: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Architecture-dependent part of the Scheduler: Dispatcher• Dispatcher module gives control of the CPU

to the process selected by the scheduler; this involves:– switching context– switching to user mode– jumping to the proper location in the

user program to restart that program• Dispatch latency – time it takes for the

dispatcher to stop one process and start another running– Also called the Context Switch time.

Page 7: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Costs/Overheads of a Context Switch

• Direct/apparent– Time spent doing the switch described in the

last slide– Fixed (more or less)

• Indirect/hidden costs– Cache pollution– Effect of TLB pollution (will study this when we

get to Virtual Memory Management)– Workload dependent

Page 8: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Example from Linux 2.6.xasmlinkage void __sched schedule(void){

[ . . . ]prepare_arch_switch(rq, next);prev = context_switch(rq, prev, next);barrier();

finish_task_switch(prev);[ . . . ]

}

task_t * context_switch(runqueue_t *rq, task_t *prev, task_t *next){

struct mm_struct *mm = next->mm;struct mm_struct *oldmm = prev->active_mm;

/* Here we just switch the register state and the stack. */ switch_to(prev, next, prev);

return prev;}

#define switch_to(prev,next,last) \

asm volatile(SAVE_CONTEXT \

"movq %%rsp,%P[threadrsp](%[prev])\n\t" /* saveRSP */ \

"movq %P[threadrsp](%[next]),%%rsp\n\t" /* restore RSP */ \

"call __switch_to\n\t" \

".globl thread_return\n" \

"thread_return:\n\t" \

"movq %%gs:%P[pda_pcurrent],%%rsi\n\t" \

"movq %P[thread_info](%%rsi),%%r8\n\t" \

LOCK "btr %[tif_fork],%P[ti_flags](%%r8)\n\t" \

"movq %%rax,%%rdi\n\t" \

"jc ret_from_fork\n\t" \

RESTORE_CONTEXT \: "=a" (last) \

: [next] "S" (next), [prev] "D" (prev), \

[threadrsp] "i" (offsetof(struct task_struct, thread.rsp)), \[ti_flags] "i" (offsetof(struct thread_info, flags)),\

[tif_fork] "i" (TIF_FORK), \

[thread_info] "i" (offsetof(struct task_struct, thread_info)), \

[pda_pcurrent] "i" (offsetof(struct x8664_pda, pcurrent)) \

: "memory", "cc" __EXTRA_CLOBBER)

Page 9: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

When is the scheduler invoked?

• CPU scheduling decisions may take place when a process:1. Switches from running to waiting state2. Switches from running to ready state3. Switches from waiting to ready4. Terminates

• Scheduling only under 1 and 4: nonpreemptive scheduling– E.g., FCFS and SJF

• All other scheduling is preemptive

Page 10: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Why Pre-emption is Necessary

• To improve CPU utilization– Most processes are not ready at all times during their lifetimes– E.g., think of a text editor waiting for input from the keyboard– Also improves I/O utilization

• To improve responsiveness– Many processes would prefer “slow but steady progress” over

“long wait followed by fast process”

• Most modern CPU schedulers are pre-emptive

Page 11: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

SJF: Variations on the theme

• Non-preemptive: once CPU given to the process it cannot be

preempted until completes its CPU burst - the SJF we already saw

• Preemptive: if a new process arrives with CPU length less

than remaining time of current executing process, preempt. This scheme is know as Shortest-Remaining-Time-First (SRTF) Also called Shortest Remaining Processing Time (SRPT)

• Why SJF/SRTF may not be practical CPU requirement of a process rarely known in advance

Page 12: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Choosing the Right Scheduling

Algorithm/Scheduling Criteria

• CPU utilization – keep the CPU as busy as possible• Throughput – # of processes that complete their

execution per time unit• Turnaround time – amount of time to execute a

particular process• Waiting time – amount of time a process has been

waiting in the ready queue• Response time – amount of time it takes from

when a request was submitted until the first response is produced, not output (for time-sharing environment)

• Fairness

Page 13: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Round Robin (RR)• Each process gets a small unit of CPU time

(time quantum), usually 10-100 milliseconds. After this time has elapsed, the process is preempted and added to the end of the ready queue.

• If there are n processes in the ready queue and the time quantum is q, then each process gets 1/n of the CPU time in chunks of at most q time units at once. No process waits more than (n-1)q time units.

• Performance– q large => FCFS– q small => q must be large with respect to

context switch, otherwise overhead is too high

Page 14: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Example of RR with Time Quantum = 20

Process CPU Time

P1 53

P2 17

P3 68

P4 24

• The Gantt chart is:

• Typically, higher average turnaround than SJF, but better response

P1 P2 P3 P4 P1 P3 P4 P1 P3 P3

0 20 37 57 77 97 117 121 134 154 162

Page 15: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Time Quantum and Context Switch Time

Page 16: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Turnaround Time Varies With Time Quantum

Page 17: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Priority-based Scheduling

• Associate with each process a quantity called its CPU priority• At each scheduling instant

– Pick the ready process with the highest CPU priority– Update (usually decrement) the priority of the process last

running• Priority = Time since arrival => FCFS• Priority = 1/Size => SJF• Priority = 1/Remaining Time => SRPT• Priority = Time since last run => Round-robin (RR)

• UNIX variants– Priority values are positive integers with upper bounds– Decreased every quantum

• Fairness, avoid starvation– Increased if the process was waiting, more wait => larger

increase• To make interactive processes more responsive

– Problems• Hard to analyze theoretically, so hard to give any guarantees• May unfairly reward blocking processes

Page 18: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Multilevel Queue• Ready queue is partitioned into separate queues:

foreground (interactive)background (batch)

• Each queue has its own scheduling algorithm– foreground – RR– background – FCFS

• Scheduling must be done between the queues– Fixed priority scheduling; (i.e., serve all from

foreground then from background). Possibility of starvation.

– Time slice – each queue gets a certain amount of CPU time which it can schedule amongst its processes; i.e., 80% to foreground in RR

– 20% to background in FCFS

Page 19: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Multilevel Queue Scheduling

Page 20: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Multilevel Feedback Queue

• A process can move between the various queues; aging can be implemented this way

• Multilevel-feedback-queue scheduler defined by the following parameters:– number of queues– scheduling algorithms for each queue– method used to determine when to upgrade a

process– method used to determine when to demote a

process– method used to determine which queue a process

will enter when that process needs service

Page 21: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Example of Multilevel Feedback Queue

• Three queues: – Q0 – RR with time quantum 8 milliseconds– Q1 – RR time quantum 16 milliseconds– Q2 – FCFS

• Scheduling– A new job enters queue Q0 which is served FCFS. When

it gains CPU, job receives 8 milliseconds. If it does not finish in 8 milliseconds, job is moved to queue Q1.

– At Q1 job is again served FCFS and receives 16 additional milliseconds. If it still does not complete, it is preempted and moved to queue Q2.

Page 22: Operating Systems CSE 411 CPU Management Sept. 18 2006 - Lecture 6 Instructor: Bhuvan Urgaonkar

Multilevel Feedback Queues