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Chapter 7. Newton’s Third Law Chapter 7. Newton’s Third Law The harder one sumo wrestler pushes, the harder the other pushes back. Newton’s third law describes how two objects interact with each other. Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley. with each other. Chapter Goal: To use Newton’s third law to understand interacting objects.

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Page 1: Oef 7.39

Chapter 7. Newton’s Third LawChapter 7. Newton’s Third Law

The harder one sumo

wrestler pushes, the harder

the other pushes back.

Newton’s third law describes

how two objects interact

with each other.

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

with each other.

Chapter Goal: To use

Newton’s third law to

understand interacting

objects.

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Topics:

• Interacting Objects

• Analyzing Interacting Objects

• Newton’s Third Law

Chapter 7. Newton’s Third LawChapter 7. Newton’s Third Law

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

• Ropes and Pulleys

• Examples of Interacting-Object Problems

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Interacting Objects

If object A exerts a force on object B, then object B

exerts a force on object A. The pair of forces, as shown,

is called an action/reaction pair.

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

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Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

The action-reaction pair never occur on the same object !

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Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

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Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

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Newton’s Third Law:

100T N====

1 2100T T N= == == == =

Trrrr

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

7

1Trrrr

2Trrrr

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The Massless String Approximation

Often in physics and engineering problems the mass of the

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

Often in physics and engineering problems the mass of the

string or rope is much less than the masses of the objects

that it connects. In such cases, we can adopt the following

massless string approximation:

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EXAMPLE 7.6 Comparing two tensions

QUESTION:

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

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EXAMPLE 7.6 Comparing two tensions

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

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EXAMPLE 7.6 Comparing two tensions

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

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EXAMPLE 7.6 Comparing two tensions

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

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1100T N====

Find tension of rope 2

1A

m kg====

4B

m kg====

No frictionSystem A:

2,ATrrrr

Anrrrr

arrrr

x

, 2, 1A net A A A AF T n w T m a= + + + == + + + == + + + == + + + =

r r rr r rr r rr r rr r rr r rr r rr r r

2?T ====

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

13

Awrrrr , 2, 1A net A A A A

F T n w T m a= + + + == + + + == + + + == + + + =

1 2,A AT T m a− =− =− =− =

System B:

2,BTrrrr

Bwrrrr

Bnrrrr

arrrr

x

, 2, 1B net B B B BF T n w m a= + + == + + == + + == + + =

r rr rr rr r r r rr r rr r rr r r

2,B BT m a====

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1100T N====

Find tension of rope 2

1A

m kg====

4B

m kg====

No frictionSystem A:

2,ATrrrr

arrrr

1 2,A AT T m a− =− =− =− =

2?T ====

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

14

System B: 2,BTrrrr

arrrr

2,B BT m a====

2, 2, 2B AT T T= == == == =Newton’s Third Law:

1 2 AT T m a− =− =− =− =

2 BT m a====

1

A B

Ta

m m====

++++

1

2

4 10080

5

B

A B

m TT N

m m= = == = == = == = =

++++

����

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Example: The 10.2 kg block is held in place by the massless rope passing over

two massless, frictionless pulleys. Find the tensions to and the

magnitude of force F. 1

T5

T

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15

The same rope:

2 3 5T T T= == == == =

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2 3 5T T T= == == == =

1Trrrr

wrrrr

Equilibrium:

110.2 10 102T w N= ≈ == ≈ == ≈ == ≈ =����

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16

1Trrrr

3Trrrr

2Trrrr

Equilibrium:

1 3 2 22T T T T= + == + == + == + =

1

2 3 551

2

TT N T T= = = == = = == = = == = = =

5Trrrr

Equilibrium:

551F T N= == == == =

Page 17: Oef 7.39

2 3 551T T T N= = == = == = == = =

4Trrrr

1102T N====

51F N====

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

17

2Trrrr

4 2 3 5153T T T T N= + + == + + == + + == + + =

Equilibrium:

5Trrrr

3Trrrr

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EXAMPLE 7.7 Mountain climbing

QUESTION:

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EXAMPLE 7.7 Mountain climbing

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EXAMPLE 7.7 Mountain climbing

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EXAMPLE 7.7 Mountain climbing

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EXAMPLE 7.7 Mountain climbing

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Chapter 7. Summary SlidesChapter 7. Summary Slides

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Chapter 7. Summary SlidesChapter 7. Summary Slides

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General Principles

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General Principles

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Important Concepts

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Important Concepts

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Applications

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Applications

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Chapter 7. Chapter 7. QuestionsQuestions

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Chapter 7. Chapter 7. QuestionsQuestions

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A fishing line of negligible mass lifts a fishupward at constant speed. The line and the fish are the system, the fishing pole is part of the environment. What, if anything, is wrong with the free-body diagrams?

A. The force of the pole on the fish is missing.

B. The force of gravity on the line is

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

B. The force of gravity on the line is missing.

C. The gravitational force and the tension force are incorrectly identified as an action/reaction pair.

D. There should be only one force on the fish.

E. There is nothing wrong with the free-body diagrams.

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A fishing line of negligible mass lifts a fishupward at constant speed. The line and the fish are the system, the fishing pole is part of the environment. What, if anything, is wrong with the free-body diagrams?

A. The force of the pole on the fish is missing.

B. The force of gravity on the line is

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

B. The force of gravity on the line is missing.

C. The gravitational force and the tension force are incorrectly identified as an action/reaction pair.

D. There should be only one force on the fish.

E. There is nothing wrong with the free-body diagrams.

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Car B is stopped for a red light. Car A, which has the same mass as car B, doesn’t see the red light and runs into the back of B. Which of the following statements is true?

A. A exerts a larger force on B than B exerts on A.

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

A. A exerts a larger force on B than B exerts on A.B. A exerts a force on B but B doesn’t exert a force

on A.C. B exerts a force on A but A doesn’t exert a force

on B.D. B exerts a larger force on A than A exerts on B.E. B exerts the same amount of force on A as A

exerts on B.

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Car B is stopped for a red light. Car A, which has the same mass as car B, doesn’t see the red light and runs into the back of B. Which of the following statements is true?

A. A exerts a larger force on B than B exerts on A.

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

A. A exerts a larger force on B than B exerts on A.B. A exerts a force on B but B doesn’t exert a force

on A.C. B exerts a force on A but A doesn’t exert a force

on B.D. B exerts a larger force on A than A exerts on B.E. B exerts the same amount of force on A as A

exerts on B.

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Boxes A and B are sliding to the right across a frictionless table. The hand H is slowing them down. The mass of A is larger than the mass of B. Rank in order, from largest to smallest, the horizontal forces on A, B, and H.

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

A. FH on B = FH on A > FA on B

B. FB on H = FH on B = FA on B = FB on A

C. FB on H = FH on B < FA on B = FB on A

D. FB on H = FH on B < FA on B = FB on A

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Boxes A and B are sliding to the right across a frictionless table. The hand H is slowing them down. The mass of A is larger than the mass of B. Rank in order, from largest to smallest, the horizontal forces on A, B, and H.

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

A. FH on B = FH on A > FA on B

B. FB on H = FH on B = FA on B = FB on A

C. FB on H = FH on B < FA on B = FB on A

D. FB on H = FH on B < FA on B = FB on A

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A. Equal to

B. Greater than

All three 50 kg blocks are at rest. Is the tension in rope 2 greater than, less than, or equal to the tension in rope 1?

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

B. Greater than

C. Less than

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A. Equal to

B. Greater than

All three 50 kg blocks are at rest. Is the tension in rope 2 greater than, less than, or equal to the tension in rope 1?

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

B. Greater than

C. Less than

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A small car is pushing a larger truck that has a dead battery. The mass of the truck is larger than the mass of thecar. Which of the following statements is true?A. The truck exerts a larger force on the car than the car exerts

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

A. The truck exerts a larger force on the car than the car exerts on the truck.

B. The truck exerts a force on the car but the car doesn’t exert a force on the truck.

C. The car exerts a force on the truck but the truck doesn’t exert a force on the car.

D. The car exerts a larger force on the truck than the truck exerts on the car.

E. The car exerts the same amount of force on the truck as the truck exerts on the car.

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A small car is pushing a larger truck that has a dead battery. The mass of the truck is larger than the mass of thecar. Which of the following statements is true?A. The truck exerts a larger force on the car than the car exerts

Copyright © 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

A. The truck exerts a larger force on the car than the car exerts on the truck.

B. The truck exerts a force on the car but the car doesn’t exert a force on the truck.

C. The car exerts a force on the truck but the truck doesn’t exert a force on the car.

D. The car exerts a larger force on the truck than the truck exerts on the car.

E. The car exerts the same amount of force on the truck as the truck exerts on the car.