ocw skaa1213 10 work and energy 2

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  • 7/30/2019 OCW SKAA1213 10 Work and Energy 2

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    SKAA1213 EngineeringMechanics

    TOPIC10

    Lecturers:

    Rosli AnanDr. Mohd Yunus IshakDr. Tan Cher Siang

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    TheWorkofaForce

    Princip eo Wor an Energy

    ConservativeForcesandPotentialEnergy ConservationofEnergy

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    itundergoes

    adisplacement

    (dr)

    in

    the

    .

    drFU

    Fsin Fsin

    rr

    Fcos Fcos

    dr

    r r'

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    displacementalong

    its

    path

    from

    r1 to

    r2 (or

    1 2 ,

    integration.

    ,

    F(s),

    11

    cos.21sr

    dsFdrFU

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    Consideraparticle

    which

    moves

    up

    along

    the

    path

    kdzjdyidxjWdrFU

    r

    r 21 )

    ~~~

    ).(

    ~

    (.

    2

    1

    yyWWdyy

    y 12 )(

    2

    1s2

    y

    y21 drs1 y2

    F=-Wjx

    y1

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    Magnitudeof

    force

    in

    alinear

    elastic

    spring

    positionisFs =ks

    The work is ne ative since F acts in the

    oppositesensetods.

    22 ssUnstretched

    22

    21

    11

    11 sss ss s

    s

    ds

    22 kF

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    Work: )(cos 1221 ssFU

    Workof

    aweight: yWU 21

    22

    11

    22

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    moves2m to

    the

    right.

    Determine

    the

    work

    .2 m

    P

    100 N

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    Looking at the right pulley:

    m

    P

    NP 50

    2

    100

    100 N

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    Looking at the bottom pulley,because there are 2 cables, the

    m

    P

    distance moved by the 100 N is:

    m2

    100 NJFsU 100)1)(100(

    2

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    inertialcoordinate

    system

    Forthe articleinthetan entialdirection2

    1

    2

    1

    dvmvdsFv

    v

    s

    s

    t tt maF

    21

    22

    22

    2

    1

    mvmvdsFs

    st

    21

    2221

    11mvmvU

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    2211 TUT 2

    112

    1mvT 222

    2

    1mvT

    Definition:

    alltheforcesactingontheparticle asitmovesfrom

    initialtoitsfinalpositionisequaltotheparticlesfinal

    kineticenergy

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    .

    Whenan

    applied

    force

    P just

    balances

    the

    ,

    aconstantvelocityv ismaintained:

    22 1122

    k

    v v

    P PW

    dr

    s1 s2N

    F=kN

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    Principleof

    Work

    and

    Energy: 2211 TUT

    Kineticenergy: 2 mv

    Workoffriction: 2222mvsNPsmv k

    Workofspring:

    2

    1

    2

    2212

    1

    2

    1ksksU

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    inclinedroad

    at

    aspeed

    of

    6m/s.

    if

    the

    driver

    jams

    onthebrakes,causinghiswheelstolock,determine

    howfars histiresskidontheroad.Thecoefficientof

    thekinetic

    friction

    between

    the

    wheels

    and

    the

    road

    sk = .

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    Work(FreeBodyDiagram)NA doesnoworkasandtheweight1500kg,isdisplaceds

    sin15.Applyingequationofequilibriumnormaltothe

    road,

    NN

    NF

    A

    An

    6.14213

    015cos)81.9(1500;;0

    NNF Akk 1.4264)6.14213(3.0

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    PrincipleofWorkandEnergy

    TUT

    222111mvUUmv kW

    01.426415sin14715615001 2 ss

    m27.592

    s

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    ConservativeForcesandPotential

    Energy

    Definedby

    the

    work

    done

    in

    moving

    aparticle

    thepath followedbytheparticle

    Energyisdefinedasthecapacityfordoingwork

    particle

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    ConservativeForcesandPotential

    Energy

    Whenaparticle

    is

    located

    adistance

    yabove a

    datum,

    the

    weightW haspositivegravitationalpotentialenergyV

    Ifyispositiveupward,gravitationalpotentialenergyofthe

    particle

    of

    weight

    W

    is: Vg =+Wy

    WyVg y

    +yW

    Datum-y Vg =0

    W

    g =- y

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    ConservativeForcesandPotential

    Energy

    Whenan

    elastic

    spring

    is

    elongatedorcompressed

    position:s =0

    fromunstretchedposition,

    theelasticpotentialenergyk

    e

    2

    2

    1ksVe

    +s

    k

    2

    2

    1ksVe

    -s

    21ksV

    k2

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    interms

    of

    the

    difference

    in

    their

    potential

    energies

    Ifonl conservative orces area liedtothebod whenmovingfromstatetostate,wehave

    conservationofenergy(orconservationof

    mechanicalenergy)

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    Gravitationalpotential

    energy: WyVg

    Elasticpotential

    energy

    :

    21ksVe

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    floorto

    the

    twelve

    floor,

    with

    the

    height

    for

    .

    potentialenergyofthelift?

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    Usethe

    eight

    floor

    as

    datum:

    WhV

    JV

    mN

    00018

    )12)(1500(

    g

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    .

    up,abox

    is

    left

    at

    each

    floor

    or

    the

    first

    box

    at

    .

    heightforeachstoreyis3.5m andthelift

    .

    liftingtheliftandtheboxes.

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    , ,

    theelevation

    drop

    of

    400

    m.

    Determine

    its

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    platformat

    A.

    The

    initial

    downward

    speed

    is

    2m/s.

    Thestiffnessoftheelasticcordisk=5kN/m.The

    lengthofthecordislo.BytakingB asthedatumand

    neglecting

    the

    size

    of

    Johnson,

    200m

    A

    B

    FIGUREP3

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    a Whatisthe ravitational otentialener V ofJohnson

    atpositionA andB?

    b) Calculatetheelasticpotentialenergy,Ve oftheelastic

    cor w en o nson sa epos on . ve eanswer

    intermoflo.

    c Determinethe

    re uired

    un

    stretched

    len th

    of

    the

    cord

    sothatJohnsonstopsmomentarilyjustabovethesurface

    ofthewater.

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    andis

    connected

    to

    a25

    kg

    mass

    located

    on

    an

    inclinedroughsurfaceatC.Bothmassesare

    connectedbyaninelasticweightlessropepassing

    through

    a

    frictionless

    pulley

    at

    B.

    The

    25

    kg

    mass

    is

    n a y e npos ona an s enre ease o

    slidedowntheinclinedsurface.Thecoefficientof

    ,s

    ,k

    massesand

    the

    rough

    surface

    is

    0.25

    and

    0.20

    respectively.

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    a Showthatbothmasses will move as soon as the 25

    kg mass isreleased.

    b) Determinetheaccelerationofbothmasses.

    c) Usingprincipleofworkandenergy,determinethe

    distancetravelledbythe5kgmassbeforecomingtoa

    sto

    afterthe

    25

    k

    mass

    comes

    to

    asto

    at

    D.

    5kg

    AB

    C

    12 D

    5

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    alongarough

    horizontal

    surface

    AB,

    and

    then

    up

    an

    inclinedroughsurfaceuntiltheblockstopsatCas

    showninFigureP5(a).TheforceFremainshorizontal

    as

    it

    pushes

    the

    block

    up

    the

    inclined

    plane.

    The

    va ueo ecoe c en o ne c r c on k

    betweentheblockandboththehorizontaland

    . .

    showsthe

    atand

    vtgraphs

    of

    the

    block

    as

    it

    is

    in

    motionfromAtoC.

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    A B

    CF

    a(m/s2)

    3

    v(m/s)

    t(s)B C

    1.2

    v

    FIGUREP5(b)

    2

    t(s)tB tC

    FIGUREP5(c)

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    a Determinethean leoftheinclined lane.

    b) Using

    the

    principle

    of

    work

    and

    energy,

    determine:i. thevelocityoftheblockasitpassesbypointB(vB)giventhat

    e s ance rom o s m,

    ii. thedistancefromBtoC.

    c) Validateyour

    answers

    in

    part

    (b)

    by

    using

    rectilinear

    kinematics.

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    TheEnd