notes- acids and bases
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Notes- Acids and Bases. Acids and Bases. Arrhenius ACIDS – produces hydrogen ions in aqueous solutions, sour taste, low pH, and the fact that they turn litmus paper red HCl (aq) H + (aq) + Cl - (aq) - PowerPoint PPT PresentationTRANSCRIPT
Notes-Acids and Bases
Acids and Bases
Arrhenius ACIDS – produces hydrogen ions in aqueous solutions, sour taste, low pH, and the fact that they turn litmus paper red
HCl (aq) H+ (aq) + Cl- (aq)
Arrhenius BASES – produces hydroxide ions in aqueous solutions, bitter taste, slippery feel, high pH, and the fact that they turn litmus paper blue
NaOH (aq) Na+ (aq) + OH- (aq)
Arrhenius definition – limits the concept of a base
Bronsted – Lowry definition – gives a broader definition of a base Bronsted – Lowry ACID – a proton (H+) donor Bronsted – Lowry BASE – a proton (H+) acceptor
General Reaction –
HA (aq) + H2O (l) H3O+ (aq) + A- (aq)
Acid Base Conjugate Conjugate Acid Base
Conjugate Base – everything that remains of the acid molecule after a proton is lost
Conjugate Acid – the base with the transferred proton (H+)Conjugate Acid – Base Pair – two substances related to
each other by the donating and accepting of a single proton
proton donor
proton acceptor
Examples: Finish each equation and identify each member of the conjugate acid –base pair.
H2SO4 (aq) + H2O (l) HSO4-1
(aq) + H3O+ (aq)
Acid Base Conjugate Base
Conjugate Acid
CO32- (aq) + H2O (l) HCO3
-1(aq) + OH-
(aq)
Base Acid Conjugate Acid
Conjugate Base
The hydronium ion, H3O+, forms when water behaves as a base. This happens when the two unshared pairs of electrons on O bond covalently with the H+.
Water as an Acid and a Base
Amphoteric – a substance that can behave as either an acid or a base
- water is the most common amphoteric substance
Ionization of Water –
H2O (l) + H2O (l) H3O+ (aq) + OH- (aq)
In the shorthand form:
H2O (l) H+ (aq) + OH- (aq)
Ion-product constant – Kw refers to the ionization of water
Kw = [H+][OH-]At 25C, Kw = [H+][OH-] = [1.0 x 10-7] [1.0 x 10-7]
= 1.0 x 10-14
If [H+] increases, the [OH-] decreases, so the products of the two is still 1.0 x 10-14.
There are three possible situations –1. A neutral solution, where [H+] = [OH-]2. An acidic solution, where [H+] [OH-]3. A basic solution, where [H+] [OH-]
Example: Calculate [H+] or [OH-] as required for each of the following solutions at 25C, for each solution state whether it is neutral, acidic, or basic.
a. 1.0 x 10-5 M OH- b. 10.0 M H+
Kw = [H+][OH-]
1 x 10-14 = [H+][1.0 x 10-5 M]
[H+] = 1.0 x 10-9 M
BASIC
Kw = [H+][OH-]
1 x 10-14 = [10.0 M][OH-]
[OH-] = 1.00 x 10-15 M
ACIDIC
pH scalepH scale – because the [H+] in an aqueous solution is
typically small, logarithms are used to express solution acidity
pH = -log [H+] pOH = -log [OH-]
Graphing calculator Non graphing calculator1. Press the +/- key 1. Enter the [H+]2. Press the log key 2. Press the log key3. Enter the [H+] 3. Press the +/- key
Significant Figure Rule – The number of places to the right of the decimal for a log must be equal to the number of significant figures in the original number.
pH pH ScalScal
ee
Example – Calculate the pH or pOH
a. [H+] = 1.0 x 10-9 M b. [OH-] = 1.0 x 10-6 M
pH = - log [H+]
pH = - log (1.0 x 10-9 M)
pH = 9.00
pOH = - log [OH-]
pOH = - log (1.0 x 10-6 M)
pOH = 6.00
Example – Calculate the pH and pOH
if the concentration of OH-1 is 1.0 x 10-3 M
pOH = - log [OH-]
pOH = - log (1.0 x 10-3 M)
pOH = 3.00
pH = - log [H+]pH = - log (1.0 x 10-11 M)
pH = 11.00
Kw = [H+][OH-]
1 x 10-14 = [H+][1.0 x 10-3 M]
[H+] = 1.0 x 10-11 M
Since Kw = [H+][OH-] = 1.0 x 10-14 ,
pH + pOH = 14.00
Example - The pH of blood is about 7.4. What is the pOH of blood?
pH + pOH =14.00
7.4 + pOH = 14.00
pOH = 6.6
In order to calculate the concentration from the pH or pOH,
[H+] = 10-pH [OH-] = 10-pOH
Graphing calculator Non-graphing calculator1. Press the 2nd 1. Enter the pH
function, then log 2. Press the +/- key2. Press the +/- key 3. Press the
inverse3. Enter the pH log key
Example - The pH of a human blood sample was measured to be 7.41. What is the [H+] in blood?
[H+] = 10-pH
[H+] = 10-7.41
[H+] = 3.9 x 10-8 M
Example – The pOH of the water in a fish tank is found to be 6.59. What is the [H+] for this water?
[OH-] = 10-pOH
[OH-] = 10-6.59
[OH-] = 2.6 x 10-7 M
Kw = [H+][OH-]
1 x 10-14 = [H+][2.6 x 10-7 M]
[H+] = 3.8 x 10-8 M
How Do We Measure pH?
• For less accurate measurements, one can use– Litmus paper
• “Red” paper turns blue above ~pH = 8
• “Blue” paper turns red below ~pH = 5
– An indicator
How Do We Measure pH?
For more accurate measurements, one uses a pH meter, which measures the voltage in the solution.
Strong Acids
• seven strong acids are HCl, HBr, HI, HNO3, H2SO4, HClO3, and HClO4.
• These are, by definition, strong electrolytes and exist totally as ions in aqueous solution.
Strong Bases
• Strong bases are the soluble hydroxides, which are the alkali metal and heavier alkaline earth metal hydroxides (Ca2+, Sr2+, and Ba2+).
• Again, these substances dissociate completely in aqueous solution, strong electrolytes
Titration
A known concentration of base (or acid) is slowly added to a solution of acid (or base).
Titration
A pH meter or indicators are used to determine when the solution has reached the equivalence point, at which the stoichiometric amount of acid equals that of base.
Titration of a Strong Acid with a Strong Base
From the start of the titration to near the equivalence point, the pH goes up slowly.
Titration of a Strong Acid with a Strong Base
Just before and after the equivalence point, the pH increases rapidly.
Titration of a Strong Acid with a Strong Base
At the equivalence point, moles acid = moles base, and the solution contains only water and the salt from the cation of the base and the anion of the acid.
Titration of a Strong Acid with a Strong Base
As more base is added, the increase in pH again levels off.
Neutralization
Neutralization Reaction =
Acid + Base Salt + Water
Salt – ionic compound containing a positive ion other than H+ and a negative ion other than OH-
Buffered solutions – resists a change in its pH even when a strong acid or base is added to it
- A solution is buffered in the presence of a weak acid and its conjugate base
pH and pOH Calculations
H + O H -
pH pO H
[O H -] = 1 x 10 - 1 4
[H + ]
[H + ] = 1 x 10 - 1 4
[O H -]
p O H = 14 - p H
p H = 14 - p O H
pOH
= -l
og[O
H- ]
pH =
-log
[H+
]
[OH
- ] = 1
0-pO
H
[H+
] = 1
0-pH