noise in modulation
TRANSCRIPT
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Noise in Modulation
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The primary figure of merit for signals in analog
systems is signal-to-noise rat io. The signal-to-noise ratio is the ratio of the signal power to the
noise power.
While the amount of external ambient noise is not
always within the control of a communicationsengineer, the way in which we can distinguish
between the signal an the noise is.
The demodulation process for any modulationsystem seeks to recreate the original modulating
signal with as little attenuation of the signal and as
much attenuation of the noise as possible.
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The signal-to-noise ratio changes as the modulated
signal goes through the demodulation process. Wewish the signal-to-noise ratio to increaseas a result
of the demodulation process.
The extent to which the signal-to-noise ratio
increases is called the signal-to-noise improvement,
or SNRI. This signal-to-noise improvement is equal
to the ratio of the demodulated signal-to-noise ratioto the input signal-to-noise ratio.
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The calculation of the signal-to-noise improvement
(SNRI) is shown in the following diagram.
Demodulator
si(t)so(t)
ni(t) no(t)
22
22
onoini
osoisi
nPnP
sPsP
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..
no
soo
ni
sii
P
PSNR
P
PSNR
.no
ni
si
so
si
ni
no
so
i
o
P
P
P
P
P
P
P
P
SNR
SNRSNRI
The notation < >means t ime average.
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In determining the ability of a demodulator to
discriminate signal from noise, we calculate Psi, Pso,Pniand Pnoand plug these values (or expressions)
into the expression
.
no
ni
si
so
P
P
P
PSNRI
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Noise in Amplitude
Modulated Systems The SNRI will be calculated for DSB-SC
and DSB-LC.
A DSB-SC demodulator is linear: thesignal and the noise components canbe considered separately.
A DSB-LC demodulator is non-linear:the signal and the noise componentscannot be treated separately.
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X so(t)
cosct
si(t) = xc(t)
.cos)()( ttmtx cc w
The expression for the modulated carrier for DSB-
SC is
Demodulation of this signal is performed by
multiplying xc(t) by cos wct and low-pass filtering theresult.
LPFd(t)
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The result of this demodulation can be seen by
analysis:
].2cos1[)(
cos)(
cos)()(
21
2
ttm
ttm
ttxtd
c
c
cc
w
w
w
Low-pass filtering the result eliminates the cos 2wct
component.
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).()( 21 tmtso
Based upon these relationships, we can find theratio of the signal input power and the signal output
power.
21222 )(cos)( tmttmP csi w
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4122
212
)()( tmtmPso
.2
1
)(
)(
212
412
tm
tm
P
P
si
so
So, it seems, half of our SNRIcalculation is done.
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The other half of the calculation deals with the
noise.
Let us use the quadrature decompositionto
represent the noise:
.sin)(cos)()( ttnttntn cscc ww
It is this signal which will represent ni(t).
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The noise input to the demodulator (in the above
form) is demodulated along with the signal.Because the demodulator is linear, we can treat the
noise separately from the signal.
X no(t)
cosct
ni(t) = nccosctnss inct
LPFdn(t)
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tntnttntn
ttntnttntd
cscc
ccscc
ccscc
cn
wwwww
wwww
2sin]2cos1[cossincos
cossincoscos)()(
21
21
2
After dn(t )passes through the low-pass filter, all we
have left is
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).()( 21
tntn co
Now, we calculate the power in the noise.
.)()()( 241
4122
212 tntntnP ccno
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The ratio of the noise powers becomes
.4)(
)(
2
41
2
tn
tn
P
P
no
ni
Finally, our signal-to-noise improvement becomes
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.2421
no
ni
si
so
PP
PPSNRI
Thus, the DSB-SC demodulation process improves
the signal-to-noise ratio by a factor of two.
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.cos)(1)( ttmtx cc w
The expression for the modulated carrier for DSB-
LC is
(This is a simplified versionof the more accurate
expression which takes into account the modulation
index. In this simplified version, the modulation
index is equal to one.)
The demodulation process extracts m(t)from xc(t).
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The input signal power is
212
2
12
212
22
)(1
)()(21
)(1
cos)(1
tm
tmtm
tm
ttmP csi
w
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.)(1 212
tm
The modulating signal m(t)is assumed here to have
zero mean.
If m(t) = coswmt, then
.1 43
21
21 siP
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The output power is simply
)(2 tmPso
which is equal to if m(t) = coswmt.
.32
43
21 si
so
PP
Thus, when m(t)is a sinewave, our signal power
ratio is
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Now, we deal with the noise.
As mentioned previously, since the demodulation
process is non-linear, we cannot treat the signal and
the noise separately. To deal with the noise, we
retain the carrier, but set the modulat ing s ignal tozero. Thus, the signal that we demodulate is
).(cos1 tntc w
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The resultant output from demodulating this signal
will be the output noise power.
To demodulate this signal (analytically), we use the
quadrature decomposition for n(t). The input to our
demodulator becomes
.sin)(cos)(cos ttnttnt csccc www
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We then work with this expression:
.sin)(cos)(1
sin)(cos)(cos
ttnttn
ttnttnt
cscc
csccc
ww
www
At this point we make an assumpt ion(which turns
out to be quite reasonable in many cases):
.)(1)( tntn cs
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In words, the noise (either the in-phase or
quadrature component) is much smaller inmagnitude that that of the signal coswct.
With this assumption the input to the demodulator
becomes
.cos)(1 ttn cc w
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We recall that when the input
is applied, the output is
ttm cwcos)(1
).(tm
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Similarly, when the input is
is applied, the output is
ttn cc wcos)(1
).(tnc
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Thus, the noise output is
).()( tntn co
The output noise power is
.)()( 22 nicno PtntnP
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.132
32
no
ni
si
so
PP
PPSNRI
,1no
ni
P
P
Thus,
and
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We see that the signal-to-noise improvement for
DSB-LC is not as good as that of DSB-SC. The
reason for using DSB-LC is that it is relatively easy
to demodulate. (Standard broadcast AM [530-1640
kHz], uses DSB-LC.)
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Noise in Frequency
Modulated Systems The frequency modulation and demodulation process
is non-l inear.
As with DSB-LC, we cannot treat the signal and the
noise separately.
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].)(cos[)( tmkttx fcc w
The expression for the modulated carrier for FM
As with DSB-LC AM, he demodulation process
extracts m(t)from xc(t). This extraction process
consists of three steps:
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1. Extract argument from cos().
2. Subtract wct.
3. Differentiate what is left to get kfm(t).
Based upon these three steps we can quickly get
the input signal power and the output signal power.
).somethingcos()()( txts ci
.)something(cos212 siP
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).()( tmkts fo
.)()( 2222 tmktmkP ffso
Without much loss of generality, we can assume that
m(t) = cosmt.
.2
21
fso kP
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.
2
21
2
21
f
f
si
so
k
k
P
P
We now have the signal power ratio:
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As with the DSB-LC AM, the effective noise input
comes along with an unmodulated carrier:
).(])(0cos[ tntmtc w
If use the quadrature decomposition of the noise, we
have, as the effective noise input
,sin)(cos)(cos ttnttnt csccc www
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.sin)(cos)(1 ttnttn cscc ww
or,
This expression can be combined into a single
sinewave
),cos( w tR c
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where
.)(1
)(tan
).()](1[
1
222
tn
tn
tntnR
c
s
sc
At this point we make a simliar assumption to what
we made with DSB-LC AM:
.1)(1)( tntn cs
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(The new part is the 1.)
Using this assumption we have
).()(tan 1 tntn ss
(This last is true because tan-1x xfor small values
ofx.)
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))(cos( tntR sc w
With the assumptions given, our effective noise input
becomes
We may now apply our three demodulation steps:
1. Extract argument from cos().2. Subtract wct.
3. Differentiate what is left to get kfm(t).
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1.
2.
3.
)(tntsc
w
)(tns
)(tns
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Thus, the output noise is
).()( tntn so
All that remains to be done is to find the noise power
from the noise signals [ni(t) and no(t)].
The noise power will be found from the powerspectral densities of the input noise and the output
noise.
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The input noise is additive white Gaussian noise.
The power spectral density of the input noise is
.2)(
0N
fSni
The output noise is the derivative of the quadraturecomponent of the (input) noise [ns(t)].
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We know, from a previous exercise, that
.)( 0NfSns
We need to find the power spectral density of the
derivat ive of the quadrature component. To find this
we multiply Sns(f) by the square of the transfer
function for the differentiation operation.
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The effect of the differentiation operation is shown in
three ways:
d
dt
j f
ns(t) ns(t).
Ns(f) No(f)
| f|2Sns(f) Sno(f)
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Thus, the power spectral density of the output noise
is
.2)( 02
0 NffSn p
Now that we have the power spectral densities of
the input and the output spectra, all that remains to
find thepoweris to integrate the respective powerspectral densitiesover the appropriate frequencies.
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The input noise is a bandpass process. Let BTbe
the bandwidth.
f
Sni(f)
N0/2
BT
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Integrating the power spectral density, we have
.)(2
20
0
TTni BNB
NP
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The input noise is a lowpass process. Let Wbe the
bandwidth.
f
Sno(f)=N04p2f2
W-W
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Integrating the power spectral density, we have
W
W
W
W
no
f
N
dffNP
34
4
32
0
22
0
p
p
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.3
8
342
3
0
2
3
20
WN
WN
p
p
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.8
332
3
80 320 W
BBN
P
PT
WNT
no
ni
pp
Thus, the ratio of the noise powers is
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Finally, the signal-to-noise improvement is
.
8
332
2
W
Bk
P
P
P
PSNRI Tf
no
ni
si
so
p
kf peak frequency deviation
BT modulated carrier bandwidth
W demodulated bandwidth
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Exercise: Suppose that the modulated carrier
bandwidth is given by Carsons rule:
).1(2 mT fB
Further suppose that the demodulated bandwidth isthe bandwidth of the modulating signal:
mfW
Show that the resultant signal-to-noise improvement
is
).1(3 2 SNRI
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Use
.2 m
f
fkp
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Exercise: Suppose that the modulated carrier
bandwidth is simply twice the modulating frequency:
.2 mT fB
Further suppose that the demodulated bandwidth isthe bandwidth of the modulating signal:
mfW
Show that the resultant signal-to-noise improvement
is
.3 2SNRI
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Improvement of FM SNRI
Using De-Emphasis The signal-to-noise improvement for FM, while good,
can be improved by minimizing the noise.
The weakest link where it comes to the noiseamplification is the differentiator: the noise increasesas the cube of the bandwidth.
If the high-pass effect of the differentiator can beoffset by a low-pass filter, the noise will beattenuated, and the SNRI will be improved.
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The weakest link:
f
Sno(f)=N04p2f2
W-W
.3
84
30
222
0
W
W
no
WNdffNP
pp
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Now, let us insert a low-pass filter whose transfer
function is
.1
1
)(1f
jfLP fH
Our output noise power becomes
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.14
2
22
0'
1
W
W f
fno df
fN
P
p
We can integrate this function by letting
.tan1 ff
1tan W
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1
1
1
1
1
1
1
1
1
1
1
tan
tan
22
0
3
1
tan
tan
22
2
20
31
tan
tan
2
2
22
03
1
'
]1[sec4
secsectan4
sec
tan1
tan4
fW
f
W
fW
fW
f
fW
dNf
dNf
dN
fPno
p
p
p
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].tan)[2(411
12
0
3
1 f
W
f
WNf p
We now define a quantity called the signal-to-noise
improvement improvement (no mistake). This is theimprovement in the SNRI as a result of de-
emphasis:
.'
no
no
PP
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The factor becomes
.]tan[3
]tan)[2(4
38
11
11
13
1
3
12
0
3
1
3
0
2
'
fW
fW
fW
fW
no
no
f
W
Nf
WN
P
P
p
p
A plot of this factor is plotted on the following slide.
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10-1
100
101
0
2
4
6
8
10
12
14
16
Increase in SNRI Using De-Emphasis
W / f
(d
B)