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  • 8/2/2019 (NeymanPearson lemma - Wikipedia, the free encyclopedia)

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    NeymanPearson lemmaFrom Wikipedia, the free encyclopedia

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    In statistics, the Neyman-Pearson lemma, named after Jerzy Neyman and Egon Pearson, states that when performing a

    hypothesis test between two point hypothesesH0: = 0 andH1: = 1, then the likelihood-ratio test which rejectsH0in favour ofH1 when

    where

    is the most powerful test of size for a threshold . If the test is most powerful for all , it is said to be

    uniformly most powerful (UMP) for alternatives in the set .

    In practice, the likelihood ratio is often used directly to construct tests see Likelihood-ratio test. However it can also

    be used to suggest particular test-statistics that might be of interest or to suggest simplified tests for this one

    considers algebraic manipulation of the ratio to see if there are key statistics in it related to the size of the ratio (i.e.

    whether a large statistic corresponds to a small ratio or to a large one).

    Contents

    1 Proof

    2 Example

    3 See also

    4 References

    5 External links

    Proof

    Define the rejection region of the null hypothesis for the NP test as

    Any other test will have a different rejection region that we define as . Furthermore, define the probability of the

    data falling in region R, given parameter as

    For both tests to have size , it must be true that

    It will be useful to break these down into integrals over distinct regions:

    and

    Setting and equating the above two expression yields that

    Comparing the powers of the two tests, and , one can see that

    NeymanPearson lemma - Wikipedia, the free encyclopedia http://en.wikipedia.org/wiki/NeymanPearson_lemma

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    Now by the definition of ,

    Hence the inequality holds.

    Example

    Let be a random sample from the distribution where the mean is known, and suppose that

    we wish to test for against . The likelihood for this set of normally distributed data is

    We can compute the likelihood ratio to find the key statistic in this test and its effect on the test's outcome:

    This ratio only depends on the data through . Therefore, by the Neyman-Pearson lemma, the most

    powerful test of this type of hypothesis for this data will depend only on . Also, by inspection, we can

    see that if , then is an increasing function of . So we should reject if

    is sufficiently large. The rejection threshold depends on the size of the test. In this example, the test

    statistic can be shown to be a scaled Chi-square distributed random variable and an exact critical value can be obtained.

    See also

    Statistical power

    References

    Jerzy Neyman, Egon Pearson (1933). "On the Problem of the Most Efficient Tests of Statistical Hypotheses".

    Philosophical Transactions of the Royal Society of London. Series A, Containing Papers of a Mathematical or

    Physical Character231: 289337. doi:10.1098/rsta.1933.0009 (http://dx.doi.org/10.1098%2Frsta.1933.0009) .

    JSTOR 91247 (http://www.jstor.org/stable/91247) .

    cnx.org: Neyman-Pearson criterion (http://cnx.org/content/m11548/latest/)

    External links

    Cosma Shalizi, a professor of statistics at Carnegie Mellon University, gives an intuitive derivation of the

    Neyman-Pearson Lemma using ideas from economics (http://cscs.umich.edu/~crshalizi/weblog/630.html)

    Retrieved from "http://en.wikipedia.org/w/index.php?title=Neyman%E2%80%93Pearson_lemma&oldid=479307028"

    Categories: Statistical theorems Statistical tests

    This page was last modified on 28 February 2012 at 15:11.

    Text is available under the Creative Commons Attribution-ShareAlike License; additional terms may apply. See

    Terms of use for details.

    Wikipedia is a registered trademark of the Wikimedia Foundation, Inc., a non-profit organization.

    NeymanPearson lemma - Wikipedia, the free encyclopedia http://en.wikipedia.org/wiki/NeymanPearson_lemma

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