name: chapter 5: polynomials and polynomial functions
TRANSCRIPT
Name: Chapter 5: Polynomials and Polynomial Functions
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Lesson 5-1: Solving Polynomial Equations Date:
*Note: A monomial is a number, variable, or an expression that is the product of one or more variables
with nonnegative integer exponents.
*Note: A polynomial is the addition or subtraction of monomials.
* The degree of a polynomial is the degree of the monomial with the highest degree.
Name: Chapter 5: Polynomials and Polynomial Functions
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Example 1: Simplify each expression. Assume that no variable equals 0.
A. (πβ3)(π2π4)(πβ1). B. π2
π10
C. (3π3
π4)
2
D. (π₯β2π¦β3)(π₯β3π¦5)(π§2)
Example 2: Determine whether each expression is a polynomial. If it is a polynomial, state the degree of the
polynomial.
A. π4 β 4βπ + 18 B. β16π5 +3
4π2π7
C. π₯2 β 3π₯β1 + 7 D. 1
2π2π3 + 3π5
Example 3: Simplify each expression.
A. (2π3 + 5π β 7) β (π3 β 3π + 2) B. (4π₯2 β 9π₯ + 3) + (β2π₯2 β 5π₯ β 6)
Name: Chapter 5: Polynomials and Polynomial Functions
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Example 4: Simplify βπ¦(4π¦2 + 2π¦ β 3)
Example 5: A small online retailer estimates that the cost, in dollars, associated with selling π₯ units of a
particular product is given by the expression 0.001π₯2 + 5π₯ + 500. The revenue from selling π₯ units is
given by 10π₯. Write a polynomial to represent the profits generated by the product if profit = revenue β
cost.
Example 6: Simplify (π2 + 3π β 4)(π + 2)
Name: Chapter 5: Polynomials and Polynomial Functions
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Lesson 5-2: Dividing Polynomials Date:
Example 1: Simplify 5π2πβ15ππ3+10π3π4
5ππ.
Example 2: Use long division to find (π₯2 β 2π₯ β 15) Γ· (π₯ β 5)
Example 3: MULTIPLE CHOICE Which expression is equal to (π2 β 5π + 3)(2 β π)β1?
A. π + 3
B. βπ + 3 +3
2βπ
C. βπ β 3 +3
2βπ
D. βπ + 3 β3
2βπ
Name: Chapter 5: Polynomials and Polynomial Functions
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Synthetic division is a simpler process for dividing a polynomial by a binomial.
Example 4: Use synthetic division to find
A. (π₯3 β 4π₯2 + 6π₯ β 4) Γ· (π₯ β 2) B. (π₯2 + 8π₯ + 7) Γ· (π₯ + 1)
Example 5: Use synthetic division to find
A. (4π¦3 β 6π¦2 + 4π¦ β 1) Γ· (2π¦ β 1) B. (8π¦3 β 12π¦2 + 4π¦ + 10) Γ· (2π¦ + 1)
Name: Chapter 5: Polynomials and Polynomial Functions
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Lesson 5-3: Polynomial Functions Date:
A polynomial is written in standard form when the values of the exponents are in descending order.
The coefficient of the first term of a polynomial in standard form is called the leading coefficient.
Polynomial Expression Degree Leading Coefficient
Constant
Linear
Quadratic
Cubic
General
Example 1: State the degree and leading coefficient of each polynomial in one variable. If it is not a
polynomial in one variable, explain why.
A. 7π§3 β 4π§2 + π§ B. 6π3 β 4π2 + ππ2
C. 3π₯5 + 2π₯2 β 4 β 8π₯6 D. 9π¦3 + 4π¦6 β 45 β 8π¦2 β 5π¦7
A polynomial function is a continuous function that can be described by a polynomial equation in one
variable. The simplest polynomial functions of the form π(π₯) = ππ₯π are called power functions.
Example 2: The volume of air in the lungs during a 5-second respiratory cycle can be modeled by π£(π‘) =
β 0.037π‘3 + 0.152π‘2 + 0.173π‘, where π£ is the volume in liters and π‘ is the time in seconds. This model is
an example of a polynomial function. Find the volume of air in the lungs 1.5 seconds into the respiratory
cycle.
Name: Chapter 5: Polynomials and Polynomial Functions
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Example 3: Find π(2π₯ β 1) β 3π(π₯) if π(π) = 2π2 + π β 1.
Name: Chapter 5: Polynomials and Polynomial Functions
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Constant
Linear
Quadratic
Cubic
Quartic
Quintic
Name: Chapter 5: Polynomials and Polynomial Functions
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Example 4: For each graph describe the end behavior, determine whether it represents an odd-degree or an
even-degree function, and state the number of real zeros.
A. B.
C. D.
Name: Chapter 5: Polynomials and Polynomial Functions
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Lesson 5-4: Analyzing Graphs of Polynomial Functions Date:
Example 1: Graph π(π₯) = βπ₯3 β 4π₯2 + 5 by making a table of values.
Example 2: Determine consecutive values of π₯ between which each real zero of the function π(π₯) = π₯4 β
π₯3 β 4π₯2 + 1 is located. Then draw the graph.
x
y
x
y
Name: Chapter 5: Polynomials and Polynomial Functions
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If no other points nearby have a greater y-coordinate, it is a relative maximum.
If no other points nearby have a lesser y-coordinate, it is a relative minimum.
The maximum and minimum values of a function are called the extrema or turning points.
Example 3: Graph π(π₯) = π₯3 β 3π₯2 + 5. Estimate the x-coordinates at which the relative maxima and
relative minima occur.
Example 4: The weight π€, in pounds, of a patient during a 7-week illness is modeled by the function
π€(π) = 0.1π3β 0.6π2 + 110, where π is the number of weeks since the patient became ill.
A. Graph the equation.
B. Describe the turning points of the graph and its end behavior.
C. What trends in the patientβs weight does the graph suggest?
D. Is it reasonable to assume the trend will continue indefinitely?
x
y
x
y
Name: Chapter 5: Polynomials and Polynomial Functions
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Lesson 5-5: Solving Polynomial Equations Date:
Polynomials that cannot be factored are called prime polynomials.
Example 1: Factor each polynomial. If the polynomial cannot be factored, write prime.
A. π₯3 β 400 B. 25π₯5 + 3π₯2π¦3
Name: Chapter 5: Polynomials and Polynomial Functions
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Example 2: Factor each polynomial. If the polynomial cannot be factored, write prime.
A. π₯3 + 5π₯2 β 2π₯ β 10 B. π2 + 3ππ¦ + 2ππ¦2 + 6π¦3
Example 3: Factor each polynomial. If the polynomial cannot be factored, write prime.
A. π₯2π¦3 β 3π₯π¦3 + 2π¦3 + π₯2π§3 β 3π₯π§3 + 2π§3 B. 64π₯6 β π¦6
Example 4: Determine the dimensions of the cubes below if the length of the smaller cube is one half the
length of the larger cube, and the volume of the shaded figure is 23,625 cubic centimeters.
Name: Chapter 5: Polynomials and Polynomial Functions
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Example 5: Write each expression in quadratic form, if possible.
A. 2π₯6 β π₯3 + 9 B. π₯4 β 2π₯3 β 1
Example 6: Solve π₯4 β 29π₯2 + 100 = 0.
Name: Chapter 5: Polynomials and Polynomial Functions
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Lesson 5-6: The Remainder and Factor Theorems Date:
The value of π(π) is the same as the remainder when the polynomial is divided by π₯ β π.
Applying the Remainder Theorem using synthetic division to evaluate a function is called synthetic
substitution.
Example 1: If π(π₯) = 2π₯4 β 5π₯2 + 8π₯ β 7, find π(6).
Example 2: The number of college students from the United States who study abroad can be modeled by
the function π(π₯) = 0.02π₯4 β 0.52π₯3 + 4.03π₯2 + 0.09π₯ + 77.54, where π₯ is the number of years since
1993 and π(π₯) is the number of students in thousands. How many U.S. college students will study abroad in
2011?
Name: Chapter 5: Polynomials and Polynomial Functions
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When you divide a polynomial by one of its binomial factors, the quotient is called a depressed
polynomial, which has a degree that is one less than the original polynomial.
Example 3:
A. Determine whether π₯ β 3 is a factor of π₯3 + 4π₯2 β 15π₯ β 18. If so, find the remaining factors of the
polynomial.
B. Determine whether π₯ + 2 is a factor of π₯3 + 8π₯2 + 17π₯ + 10. If so, find the remaining factors of the
polynomial.
Name: Chapter 5: Polynomials and Polynomial Functions
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Lesson 5-7: Roots and Zeros Date:
Example 1: Solve each equation. State the number and type of roots.
A. π₯2 + 2π₯ β 48 = 0 B. π¦4 β 256 = 0
Name: Chapter 5: Polynomials and Polynomial Functions
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Example 2: State the possible number of positive real zeros, negative real zeros, and imaginary zeros of
π(π₯) = βπ₯6 + 4π₯3 β 2π₯2 β π₯ β 1.
Example 3: Find all of the zeros of π(π₯) = π₯3 β π₯2 + 2π₯ + 4.
Name: Chapter 5: Polynomials and Polynomial Functions
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Example 4: Write a polynomial function of least degree with integral coefficients, the zeros of which include
4 and 4 β π.
Name: Chapter 5: Polynomials and Polynomial Functions
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Lesson 5-8: Rational Zero Theorem Date:
Example 1: List all of the possible rational zeros of each function.
A. π(π₯) = 3π₯4 β π₯3 + 4 B. π(π₯) = π₯4 + 7π₯3 β 15
Example 2: The volume of a rectangular solid is 1120 cubic feet. The width is 2 feet less than the height, and
the length is 4 feet more than the height. Find the dimensions of the solid.
Example 3: Find all of the zeros of π(π₯) = π₯4 + π₯3 β 19π₯2 + 11π₯ + 30.