*Transmission Lines and WaveguidesWaveguide and other transmission lines for the low-loss transmission of microwave power.Early microwave systems relied on waveguide and coaxial lines for transmission line media.Waveguide: high power-handling capability, low loss, but bulky and expensiveCoaxial line: high bandwidth, convenient for test applications, difficult medium in which to fabricate complex microwave components.Planar transmission lines: stripline, microstrip, slotline, coplanar waveguide compact, low cost, easily integrated with active devices

*3.1 General Solutions for TEM, TE and TM wavesGeneral solutions to Maxwells equations for the specific cases of TEM, TE and TM wave propagation in cylindrical transmission lines or waveguides.Uniform in z direction and infinitely long

Figure 3.1 (p. 92) (a) General two-conductor transmission line and (b) closed waveguide.

*Assume ejt dependence

where e(x,y) and h(x,y): transverse (x,y) E & H field components, ez and hz: longitudinal E & H field components.Assume source free,

*

*where kc: cutoff wavenumber, : the wavenumber of the material filling with the transmission line or waveguide region.TEM WavesTEM waves are characterized by Ez = Hz = 0.From (3.3a) and (3.4b)

the cutoff wavenumber kc = 0 for TEM waves.Helmholtz equation for Ex from (1.42)

*For e-jz dependence,

Similar result also applies to Ey ( )

Transverse fields e(x,y) of a TEM wave satisfy Laplaces equation.Similarly, In the electrostatic case, E field can be expressed as

*In order for (3.13) to be valid, the curl of e must vanish:

The voltage between 2 conductors and current flow on a conductor:

TEM waves can exist when 2 or more conductors are present. (ex: Plane waves)

*The wave impedance of a TEM mode

*The procedure for analyzing a TEM line:Solve Laplace equation, (3.14) for (x,y)Find these constants by applying the B.C. for the known voltages on the conductorsCompute e and E form (3.13) & (3.1a). Compute h and H from (3.18) and (3.1b).Compute V from (3.15), I from (3.16).The propagation constant is given by (3.8), Z0 is given by Z0 = V/I.

*TE WavesCharacterized by Ez = 0, Hz 0.

In this case, kc 0, and the propagation constant is generally a function of frequency and the geometry of the line or guide.

*The Helmholtz equation

Since Hz(x,y,z) = hz(x,y)e-jz, and kc2 = k2 2

TE wave impedance can be

*TM WavesCharacterized by Hz = 0, Ez 0.

*The procedure for analyzing TE and TM waveguidesSolve the reduced Helmholtz equation, (3.21) or (3.25) for hz or ez. The solution will contain several unknown constants, and the unknown cutoff wavenumber, kc.Use (3.19) or (3.23) to find the transverse fields from hz or ez.Apply the B.C. to the appropriate field components to find the unknown constants and kc.The propagation constant is given by (3.6) and the wave impedance by (3.22) or (3.26).

*Attenuation due to Dielectric LossUsing the complex dielectric constant

In practice, most dielectric materials have a very small loss (tan

*(3.27) reduces to

For TE or TM wave

For TEM line, kc = 0, k =

*3.2 Parallel Plate WaveguideFigure 3.2 (p. 98) Geometry of a parallel plate waveguide.

*The simplest type of guide that can support TM and TE modes; can also support a TEM mode.TEM ModesTEM mode solution can be obtained by solving Laplaces equation.

AssumeSince there is no variation in x,

The transverse E-field from (3.13),

*The voltage of the top plate with respect to the bottom plate The total current on the top plate

*TM ModesHz = 0, Ez satisfies (3.25) with

B.C.

*TM0 mode = TEM modeThe cutoff frequency fcTM1 mode is the lowest TM mode with a cutoff frequency

*At frequencies below the cutoff frequency of a given mode, the propagation constant is purely imaginary, corresponding to a rapid exponential decay of the fields. cutoff or evanescent modes.TMn mode propagation is analogous to a high-pass filter response.The wave impedance

pure real for f > fc, pure imaginary for f < fc.The guide wavelength is defined the distance between equiphase planes along the z-axis.

*g > = 2/k, the wavelength of a plane wave in the material.The phase velocity and guide wavelength are defined only for a propagation mode, for which is real.A cutoff wavelength for the TMn mode may be defined as

Poynting vector

*Consider the dominant TM1 mode, which has a propagation constant,2 plane waves traveling obliquely in the y, +z and +y, +z directions.

*Figure 3.3 (p. 102)Bouncing plane wave interpretation of the TM1 parallel plate waveguide mode.f fc: 1 0: 2 plane waves up and down, no real power flow.

*Conductor loss can be treated using the perturbation method.

where Po: the power flow down the guide in the absence of conductor loss given by (3.54), Pl: the power dissipated per unit length in the 2 lossy conductors

*TE ModesEz = 0, Hz satisfies (3.21) with

B.C.

*The cutoff frequency fcThe wave impedance

*If n = 0, Ex = Hy = 0, P0 = 0 no TE0 mode.

*Figure 3.4 (p. 105)Attenuation due to conductor loss for the TEM, TM, and TE1 modes of a parallel plate waveguide.

*Figure 3.5 (p. 106)Field lines for the (a) TEM, (b) TM1, and (c) TE1 modes of a parallel plate waveguide. There is no variation across the width of the waveguide.

*3.3 Rectangular WaveguideTE ModesEz = 0Hz must satisfy the reduced wave equation (3.21)

Can be solved by separation of variables

*Figure 3.6 (p. 107)Photograph of Ka-band (WR-28) rectangular waveguide components. Clockwise from top: a variable attenuator, and E-H (magic) tee junction, a directional coupler, an adaptor to ridge waveguide, an E-plane swept bend, an adjustable short, and a sliding matched load. Courtesy of Agilent Technologies, Santa Rosa, CA

*Figure 3.7 (p. 107)Geometry of a rectangular waveguide.

*We define separation constant kx and ky

Boundary conditions

Using (3.19c) and (3.19d)

*From B.C, D = 0, and ky = n/b, B = 0 , and kx = m/a

The transverse field components of TEmn mode

*is real whenThe mode with the lowest cutoff frequency is called the dominant mode;

*For f < fc, all field components will decay exponentially cutoff or evanescent modesIf more than one mode is propagating, the waveguide is overmoded.The wave impedance

The guide wavelength (: the wavelength of a plane wave in the filling medium)

*For the TE10 mode

*The power flow down the guide for the TE10 mode:

Attenuation can occur because of dielectric loss or conductor loss.

*There are surface currents on all 4 walls.The surface current on the x = 0 wall is

The surface current on the y = 0 wall is

*The attenuation due to conductor loss for TE10 mode

*TM ModesHz = 0

BC: ez(x,y) = 0 @ x = 0, a and y = 0, b

*

*Figure 3.8 (p. 112)Attenuation of various modes in a rectangular brass waveguide with a = 2.0 cm.

*Figure 3.9 (p. 114)Field lines for some of the lower order modes of a rectangular waveguide. Reprinted from Fields and Waves in Communication Electronics, Ramo et al, Wiley, 1965)

*Ex 3.1a = 1.07 cm, b = 0.43 cm, f = 15 GHzSolution: for Teflon r = 2.08, tan = 0.0004

Modemnfc (GHz)TE109.72TE2019.44TE0124.19TE, TM1126.07TE, TM2131.03

*At 15 GHz

*Figure 3.10 (p. 115)Geometry of a partially loaded rectangular waveguide.

*Figure on page 117Reference: Montgomery, et al., Principles of Microwave Circuits, McGraw-Hill, 1948)

*3.4 Circular WaveguideFigure 3.11 (p. 117) Geometry of a circular waveguide.

*TE ModesEz = 0

*The general solution is

*Since

BC: Since Ez = 0, But, D = 0

*If the roots of Jn' (x) are defined as p'nm, so that Jn'(p'nm) = 0, where p'nm is the mth root of Jn', then kc must have the value.

See Table 3.3The Temn modes are defined by the cutoff wavenumber, kcmn = p'nm/a, where n refers to the number of circumferential () variations, and m refers to the number of radial () variations.

*TE11 mode: dominant mode

*The wave impedanceBecause of the azimuthal symmetry of the circular waveguide, both sin n and cos n are terms are valid solutions, and can be present in a specific problem to any degree.The actual amplitudes of these terms will be dependent on the excitation of the waveguide.Consider the dominant TE11 mode with an excitation such that B = 0.

*The power flow down the guide

*

*

*TM Modes

*

*Figure 3.12 (p. 123)Attenuation of various modes in a circular copper waveguide with a = 2.54 cm.

*Figure 3.13 (p. 123)Cutoff frequencies of the first few TE and TM modes of a circular waveguide, relative to the cutoff frequency of the dominant TE11 mode.Ex 3.2

*Figure 3.14 (p. 125)Field lines for some of the lower order modes of a circular waveguide.Reprinted from Fields and Waves in Communication Electronics, Ramo et al, Wiley, 1965)

*3.5 Coaxial LineTEM Mode

Boundary conditions

*Figure 3.15 (p. 126)Coaxial line geometry.

*The general solution to (3.148)

Since the boundary conditions do not vary with , the potential should not vary with . n = 0 k = 0.

*Higher Order ModesThe coaxial line also support TE & TM waveguide modes in addition to a TEM mode.In practice, these modes are usually cutoff (evanescent), only a reactive effect near discontinuities or sources, where they are excited.For TE modes, Ez = 0, and

The general solution (from Sec. 3.4),

*Boundary conditions:

Nontrivial solution for C & D

Characteristic equation for kc

*Figure 3.16 (p. 129)Normalized cutoff frequency of the dominant TE11 waveguide mode for a coaxial line.

*Figure 3.17 (p. 129)Field lines for the (a) TEM and (b) TE11 modes of a coaxial line.

*Ex 3.3a = 0.035, b = 0.116, r = 2.2. What is the highest usable frequency, before the TE11 waveguide mode starts to propagate?

*Photograph on Page 134.

*Figure 3.18 (p. 131)Geometry of a grounded dielectric slab.

*Figure 3.19 (p. 133)Graphical solution of the transcendental equation for the cutoff frequency of a TM surface wave mode of the grounded dielectric slab.

*Figure 3.20 (p. 135)Graphical solution of the transcendental equation for the cutoff frequency of a TE surface wave mode. Figure depicts a mode below cutoff.

*Figure 3.21 (p. 136)Surface wave propagation constants for a grounded dielectric slab with r = 2.55.

*Figure on page 137Reference: R.W. Hornbeck, Numerical Methods, Quantum Publishers, 1975

*3.7 StriplineA planar-type of transmission line that lends itself well to microwave integrated circuitry and photolithographic fabrication.Since stripline has 2 conductors and a homogeneous dielectric, it can support a TEM wave.The stripline can also support higher order TM and TE modes, but these are usually avoided in practice.

*Figure 3.22 (p. 137)Stripline transmission line. (a) Geometry. (b) Electric and magnetic field lines.

*Figure 3.23 (p. 138)Photograph of a stripline circuit assembly, showing four quadrature hybrids, open-circuit tuning stubs, and coaxial transitions. Courtesy of Harlan Howe, Jr. M/A-COM Inc.

*Formulas for Propagation Constant, Characteristic Impedance and AttenuationThe phase velocity of a TEM mode:

The propagation constant of the stripline is

The characteristic impedance of a transmission line is

Laplaces equation can be solved by conformal mapping to find the capacitance per unit length of the stripline. complicated special function

*For practical computations simple formulas have been developed by curve fitting to the exact solution.

where We is the effective width of the center conductor

Given the characteristic impedance, the strip width is

where

*The attenuation due to the dielectric loss is the same as (3.30).The attenuation due to the conductor loss

with

Ex 3.5

*Figure 3.24 (p. 141)Geometry of enclosed stripline.Modified the geometry truncating the plates beyond some distance and placing metal walls on the sides.An Approximate Electrostatic Solution

*3.8 MicrostripMicrostrip line is one of the most popular types of transmission lines, primarily because it can be fabricated by photolithographic process and is easily integrated with other passive and active microwave devices.Microstrip line cannot support a pure TEM wave.In most practical applications, the dielectric substrate is electrically very thin (d

*Figure 3.25 (p. 143)Microstrip transmission line. (a) Geometry. (b) Electric and magnetic field lines.

*Figure 3.26 (p. 145)Equivalent geometry of quasi-TEM microstrip line, where the dielectric slab of thickness I and relative permittivity r has been replaced with a homogeneous medium of effective relative permittivity, e.

*Formulas for Propagation Constant, Characteristic Impedance and AttenuationThe effective dielectric constant of a microstrip line:

The characteristic impedance of a microstrip line is

*Given Z0, and r, the strip width is

where

The attenuation due to dielectric loss

*The attenuation due to the conductor losswhere is the surface resistivity of the conductor. Ex 3.7

*Figure 3.27 (p. 146)Geometry of a microstrip line with conducting sidewalls.An Approximate Electrostatic Solution

*The potential (x,y) satisfying Laplaces equation:

with BC Since there are 2 regions defined by air/dielectric interface, with a charge discontinuity on the strip, we will have separate (x,y).

*Applying BC & even function on x & y,

must be continuous at y = d

*

*The surface current density at y = d,

By a good guess,

Taking the orthogonalization for both sides of s,

*HW2. Use MATLAB to calculate the Z0 with r = 2.2, a = 100d, for W/d = 0 to 10 (step = 0.01) and compare these results with (3.195) & (3.196)C = capacitance per unit length of the microstrip line with r 1C0 = capacitance per unit length of the microstrip line with r = 1

*Figure 3.28 (p. 150)A rectangular waveguide partially filled with dielectric and the transverse resonance equivalent circuit.

*3.10 Wave Velocities and DispersionThe speed of light in a medium is the velocity at which a plane wave would propagate in that medium.The phase velocity is the speed at which a constant phase point travels.The phase velocity is different for different frequencies, then the individual frequency components will not maintain their original phase relationships as they propagate down the transmission line or waveguide, and signal distortion will occur. dispersion

*Group VelocityThe velocity at which a narrow band signal propagates.

*For a lossless, matched transmission line or waveguide,

The time-domain output signal,

Now if |Z()| = A is a constant, and the phase of is a linear function of ( = a),

dispersionless (not distortion for a lossless TEM wave)

*For a lossy TEM line, consider a narrow band input signal of the form representing an AM modulated carrier wave of frequency 0.

*In general, may be a complicated function of . But if F() is narrowband (m

*The velocity of this envelope is the group velocity, vg:

Ex 3.9

*Figure 3.31 (p. 155)Cross section of a ridge waveguide.

*Figure 3.32 (p. 155)Dielectric waveguide geometry.

*Figure 3.33 (p. 156)Geometry of a printed slotline.

*Figure 3.34 (p. 156)Coplanar waveguide geometry.

*Figure 3.35 (p. 157)Covered microstrip line.