mth 10905 algebra
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MTH 10905 Algebra. formulas CHAPTER 2 Section 6. Simple Interest Formula. Formula is an equation commonly used to express a specific relationship mathematically. Evaluate a formula is to substitute the appropriate numerical values for the variables and perform the operations. - PowerPoint PPT PresentationTRANSCRIPT
MTH 10905Algebra
FORMULAS
CHAPTER 2 SECTION 6
Simple Interest Formula
Formula is an equation commonly used to express a specific relationship mathematically.
Evaluate a formula is to substitute the appropriate numerical values for the variables and perform the operations.
Simple Interest Formula is used in banking
interest = (principal)(rate)(time)
i = prt
r and t are related in that r is given as annual interest rate and t is given in years
Use the Simple Interest Formula
EXP: How much simple interest would be owed on a $12,000 4-year loan at 6% simple interest?
i = prt i = (12,000)(0.06)(4)i = (720)(4)i = 2,880
The interest will be $2,880
Ask yourself is $2,880 realistic. $720 a year for 4 years
What is the total you will pay for the loan?
$12,000 + $2,880 = $14,880
Use the Simple Interest Formula
EXP: What was the principal on a 3-year, 5% loan is the simple interest was $300.00?
i = prt
300 = (p)(0.05)(3)300 = (0.15)(p)300 / 0.15 = p2000 = p
The Principal amount is $2,000
Use the Distance Formula
Distance Formula:
distance = (rate)(time)d = rt
EXP: Find the distance traveled if a car travels 3 hours at 62.5 mph.
d = rt
d = (62.5)(3)d = 187.5
The car traveled 187.5 miles.
Use the Distance Formula
EXP: How fast is a car traveling if it travels 84 miles in 1.5 hours?
d = rt
84 = (r)(1.5)84 / 1.5 = r56 = r
The car is traveling 56 mph.
Use Geometric Formulas
Perimeter is the sum of the lengths of the sides of a figure.Measured in centimeters, inches, or feet
Area is the total surface within the figures boundaries.Measured in square units, square centimeter, square inches, or square feet.
Quadrilateral is the general name for a four-sided figure.
Square s Area = s2 and Perimeter = 4s A = s2 P = 4s
Use Geometric Formulas – page 142
h
Rectangle Area = lw and Perimeter = 2l + 2w w A = lw P = 2l + 2w
l l = length and w = width
Triangle a c Area = ½ bh and Perimeter = a + b + c A = ½ bh P = a + b + c
b b = base and h = height
Circle Area = П r2 and Circumference = 2 П r r A= П r2 C = 2 П r
r = radius and П ≈ 3.14diameter is a line segment through the center of the circle and endpoints lie on the circle and the Circumference is the length of the curve
Use Geometric Formulas
EXP:A rectangle garden is 60 ft long by 15 ft wide.Find the perimeter and area.
w = 15
l = 60
Area = lw Perimeter = 2l + 2wA = (15)(60) P = 2(60) + 2(15)A = 900 ft2 P = 120 + 30
P = 150 ft
The area is in square feet because the formula involves multiplication of 2 linear dimensions. Example: (2ft)(3ft) = (2)(3)(ft)(ft) = 6 ft2
Use Geometric Formulas
EXP:A rectangle table has a perimeter of 216 inches. If the length is 72 inches find the width.
w = ?
l = 72
Perimeter = 2l + 2w 216 = 2(72) + 2(w) 216 = 144 + 2w216 – 144 = 2w 72 = 2w 36 = w
The width is 36 inches.
Use Geometric Formulas
h
A Triangular sign has an area of 6 ft2 Find the base of the sign if its height is 4 ft. a c
b
Area = ½ bh 6 = (½)(b)(4)6 = 2b3 = b The base is 3 ft.
b = base and h = height
Use Geometric Formulas
EXP:
Find the area and circumference of a pizza with a 10 inch diameter.
r ½ (d) = r½ (10) = r5 = r
A= П r2 C = 2 П rA = П (52) C = (2)(П )(5)A = П (25) C = П (10) A ≈ 78.5 C ≈ 31.4
r = radius and П ≈ 3.14
radius is ½ of the diameter.
Use Geometric Formulas – page 145
Volume is considered the space occupied by a figure. Measured in cubic units, cubic centimeter, cubic feet, and cubic inches. Used with three-dimensional figures. Volume is in cubic units because the formula involves multiplication of 3 linear dimensions. Exp: (2ft)(3ft)(4ft) = (2)(3)(4)(ft)(ft)(ft) = 24 ft3
Rectangular Solid: V = l w h Exp: Safe
Right Circular Cylinder: V = П r2 h Exp: Barrel
Right Circular Cone: V = 1/3 П r2 h Exp: Ice cream cone
Sphere: V = 4/3 П r3 Exp: ball
Use Geometric Formulas – page 145
Sphere: Find the volume of a ball with a diameter of 6 inches.
½ (d) = r½ (6) = r3 = r
V = 4/3 П r3 V = (4/3)( П ) ( 33 )V = (4/3)(27)( П ) V = 36 П V ≈ 113.10 in3
Volume is in cubic units because the formula involves multiplication of 3 linear dimensions. Exp: (2inches)(3inches)(4 inches) = (2)(3)(4)(inches)(inches)(inches) = 24 in3
Solving for a Variable in a Formula
To solve for a variable in a formula you treat each variable as it was a constant except for the one that you are solving.
Solve by isolating the variable you are solving to one side of the equation.
Exp: Simple Interest Formula
i = prt solve for p
ip
rt
Solving for a Variable in a Formula
Exp: Solve A = 2b + c for b
Exp: Solve for b
2
2
2
A b c
A c b
a cb
1
3R ab 1
3
33
3
R ab
abR
R ab
Rb
a
Solving for a Variable in a Formula
Slope intercept formy = mx + b
Write the equation 12x – 4y = 20 in slope intercept form
12 4 20
4 12 20
12 20
43 5
x y
y x
xy
y x
Solving for a Variable in a Formula
Write the equation in slope intercept form
1 1( 3)
2 3y x
1 11
2 3
1 11
3 2
1 1
3 2
y x
y x
y x
Remember
Pay attention to the units. Sometimes a unit conversion will be necessary before using a formula
When working with a formula, start with the general form and then substitute in known quantities.
Sometimes drawing a picture, when appropriate, may be helpful. Label all the known and unknown quantities.
HOMEWORK 2.6
Page 148 - 150
#11, 13, 14, 19, 24, 28, 47, 49, 51, 52, 57, 60, 64, 67, 73, 85, 99