Molar volume calculations

Molar volume calculationsa) 3.00 cm b) 0.0143 g/cmc) Mass = g/cm x cm = 0.0143 g/cm x 3.00 cm

= 0.0429 gd) Moles = g x mol/g= 0.0390 g x 1 mol/24.31 g

= 0.001765 mol e) Moles H2 = Moles Mg = 0.001765 mol f) should be higher # than g)h) Class average = 44.1 mLi) 101.6 kPa, j) 22°C, 295 Kk) 2.64 kPa (pg. 464)l) Pgas = Patm - Pvapour = i - k

101.6 kPa - 2.64 kPa = 98.96 kPa

V1 = 44.1 mL, P1 = 98.96 kPa, T1 = 295 KV2 = ?, P2 = 101.325 kPa, T2 = 273 K

P1V1

T1

=P2V2

T2

(98.96 kPa)(44.1 mL)(295 K)

=(101.325 kPa)(V2)

(273 K)(98.96 kPa)(44.1 mL)(273 K)

(295 K)(101.325 kPa)= 39.86 mL

n) 0.001765 mol = 39.86 mL, 1 mol = 22587 mL(divide each side by 0.001765 or cross multiply)o) 22.59 – 22.4

% error = (22.59 - 22.4) / 22.4 x 100%= 0.19/22.4 x 100% = 0.85 %

=V2

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