module c5
DESCRIPTION
Module C5. Reorder Point/Service Levels. DETERMINING A REORDER POINT, r* (Without Safety Stock). Suppose lead time is 8 working days The company operates 260 days per year r* = LD where L and D are in the same time units L = 8/260 .0308 yrs D = 6240 /year r* = .0308(6240) 192 - PowerPoint PPT PresentationTRANSCRIPT
Module C5
Reorder Point/Service Levels
DETERMINING A REORDER POINT, r* (Without Safety Stock)
• Suppose lead time is 8 working days
• The company operates 260 days per year
• r* = LD where L and D are in the same time units
• L = 8/260 .0308 yrs D = 6240 /year
r* = .0308(6240) 192
OR,
L = 8 days; D/day = 6240/260 = 24
r* = 8(24) = 192
DETERMINING A REORDER POINT, r* (With Safety Stock)
• Suppose lead time is 8 working days
• The company operates 260 days per year
• r* = LD + SS
• Suppose a safety stock of SS = 13 is desired
• L = 8/260 .0308 yrs D = 6240 /year
r* = .0308(6240) +13 192 +13 = 205
Actual Demand Distribution
• Suppose on a short term basis demand actually more closely follows a normal distribution with:– Weekly mean demand W
– Weekly variance 2W, Weekly St’d dev. W,
• Demand over an n-week period:– normal
– Mean nW _
– Variance = n2W, St’d Dev. = (n) W
Calculating Q*
• Over the course of a year, the standard deviation becomes small relative to the mean value -- hence a common practice is to ignore any variability and calculate Q* by the usual EOQ formula
Lead Time Demand• Lead times, however, tend to be short and hence
variability must be considered.
• A cycle service level is supplied to the modeler -- the probability of not running out of stock during the lead time period.
• Suppose lead time is L weeks – Demand during lead time is normal
– Mean demand = L = LW
– St’d dev. = L = L W
Example -- Allen Appliance
• Suppose we can assume that demand follows a normal distribution– This can be checked by a “goodness of fit” test
• From our data, over the course of a week, W, we can approximate W by (105 + … + 130)/10 = 120
W2 sW
2 = ((1052 +…+1302) - 10(120)2)/9 83.33
DEMAND DISTRIBUTION DURING 8 -DAY LEAD TIME
• Normal
• 8 days = 8/5 = 1.6 weeks, so
L = (1.6)(120) = 192
L2 (1.6)(83.33) = 133.33
_____ L 133.33 = 11.55
X
Z
SAFETY STOCK
• Suppose we wish a cycle service level of 99%– WE wish NOT to run out of stock in 99% of our
inventory cycles
0 Z.01 = 2.33
.01
L = 11.55
?192
Calculating r* and Safety Stock Costs
• Reorder point, r* = L + z.01 L =
192 + 2.33(11.55) 219
• Safety stock SS = 2.33(11.55) = 27
• Safety stock cost = ChSS = 1.40(27) = $37.80
This should be added to the TOTAL ANNUAL COST
Using the Template
EnterLead TimeInformation Select
Cycle Service LevelWorksheet
Reorder Point
Module C5 Review• In the short run, demand may seem to follow a
probability distribution (normal)
• In the long term, variability is relatively insignificant in magnitude compared to the mean value-- so calculate Q* in usual way.
• Determine a cycle service level = 1- • Determine the mean and st’d deviation for demand
during lead time
• SS = zL r* = L + SS
• Safety Stock Costs = ChSS -- add to total cost
• Use of Template