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Module C5 Reorder Point/Service Levels

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Module C5. Reorder Point/Service Levels. DETERMINING A REORDER POINT, r* (Without Safety Stock). Suppose lead time is 8 working days The company operates 260 days per year r* = LD where L and D are in the same time units L = 8/260  .0308 yrs D = 6240 /year r* = .0308(6240)  192 - PowerPoint PPT Presentation

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Page 1: Module C5

Module C5

Reorder Point/Service Levels

Page 2: Module C5

DETERMINING A REORDER POINT, r* (Without Safety Stock)

• Suppose lead time is 8 working days

• The company operates 260 days per year

• r* = LD where L and D are in the same time units

• L = 8/260 .0308 yrs D = 6240 /year

r* = .0308(6240) 192

OR,

L = 8 days; D/day = 6240/260 = 24

r* = 8(24) = 192

Page 3: Module C5

DETERMINING A REORDER POINT, r* (With Safety Stock)

• Suppose lead time is 8 working days

• The company operates 260 days per year

• r* = LD + SS

• Suppose a safety stock of SS = 13 is desired

• L = 8/260 .0308 yrs D = 6240 /year

r* = .0308(6240) +13 192 +13 = 205

Page 4: Module C5

Actual Demand Distribution

• Suppose on a short term basis demand actually more closely follows a normal distribution with:– Weekly mean demand W

– Weekly variance 2W, Weekly St’d dev. W,

• Demand over an n-week period:– normal

– Mean nW _

– Variance = n2W, St’d Dev. = (n) W

Page 5: Module C5

Calculating Q*

• Over the course of a year, the standard deviation becomes small relative to the mean value -- hence a common practice is to ignore any variability and calculate Q* by the usual EOQ formula

Page 6: Module C5

Lead Time Demand• Lead times, however, tend to be short and hence

variability must be considered.

• A cycle service level is supplied to the modeler -- the probability of not running out of stock during the lead time period.

• Suppose lead time is L weeks – Demand during lead time is normal

– Mean demand = L = LW

– St’d dev. = L = L W

Page 7: Module C5

Example -- Allen Appliance

• Suppose we can assume that demand follows a normal distribution– This can be checked by a “goodness of fit” test

• From our data, over the course of a week, W, we can approximate W by (105 + … + 130)/10 = 120

W2 sW

2 = ((1052 +…+1302) - 10(120)2)/9 83.33

Page 8: Module C5

DEMAND DISTRIBUTION DURING 8 -DAY LEAD TIME

• Normal

• 8 days = 8/5 = 1.6 weeks, so

L = (1.6)(120) = 192

L2 (1.6)(83.33) = 133.33

_____ L 133.33 = 11.55

Page 9: Module C5

X

Z

SAFETY STOCK

• Suppose we wish a cycle service level of 99%– WE wish NOT to run out of stock in 99% of our

inventory cycles

0 Z.01 = 2.33

.01

L = 11.55

?192

Page 10: Module C5

Calculating r* and Safety Stock Costs

• Reorder point, r* = L + z.01 L =

192 + 2.33(11.55) 219

• Safety stock SS = 2.33(11.55) = 27

• Safety stock cost = ChSS = 1.40(27) = $37.80

This should be added to the TOTAL ANNUAL COST

Page 11: Module C5

Using the Template

EnterLead TimeInformation Select

Cycle Service LevelWorksheet

Reorder Point

Page 12: Module C5

Module C5 Review• In the short run, demand may seem to follow a

probability distribution (normal)

• In the long term, variability is relatively insignificant in magnitude compared to the mean value-- so calculate Q* in usual way.

• Determine a cycle service level = 1- • Determine the mean and st’d deviation for demand

during lead time

• SS = zL r* = L + SS

• Safety Stock Costs = ChSS -- add to total cost

• Use of Template