mid term revision 2014

17
Chapter 10. 2 Find the instantaneous velocity of the particle described in Figure P2.3 at t = 7.5 s. a. 5.0 m/s b. 0.33 m/s c. -0.33 m/s d. -5.0 m/s 11. A 50.0 g superball traveling at 25.0 m/s bounces off a brick wall and rebounds at 22.0 m/s. A high- speed camera records this event. If the ball is in contact with the wall for 3.50 ms, what is the magnitude of the average acceleration of the ball in this time interval? (Note: 1 ms = 10 -3 s.) a. 857 m/s 2 b. 1.34 × 10 4 m/s 2 c. 0.857 m/s 2 d. 13.4 m/s 2 20. A particle moves along the x axis according to the equation x = 2.00 + 3.00t - 1.00t 2 , where x is in meters and t is in seconds. At t = 1.00 s, find (a) the position of the particle, (b) its velocity, and (c) its acceleration. a. (a) 4.00 m; (b) 3.17 m/s; (c) 1.42 m/s 2 b. (a) 6.00 m; (b) 5.00 m/s; (c) 2.00 m/s 2 c. (a) 4.00 m; (b) -1.00 m/s; (c) 2.00 m/s 2 d. (a) 4.00 m; (b) 1.00 m/s; (c) -2.00 m/s 2 21. A truck covers 40.0 m in 8.50 s while smoothly slowing down to a final speed of 2.80 m/s. (a) Find

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Page 1: Mid Term Revision 2014

Chapter

10.

2

Find the instantaneous velocity of the particle described in Figure P2.3

at t = 7.5 s.

a. 5.0 m/s

b. 0.33 m/s

c. -0.33 m/s

d. -5.0 m/s

11.

A 50.0 g superball traveling at 25.0 m/s bounces off a brick wall and rebounds at 22.0 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 3.50 ms, what is the magnitude of the average acceleration of the ball in this time interval? (Note: 1 ms = 10

-3 s.)

a. 857 m/s

2

b. 1.34 × 10

4 m/s

2

c. 0.857 m/s

2

d. 13.4 m/s

2

20.

A particle moves along the x axis according to the equation x = 2.00 + 3.00t - 1.00t2, where x is in

meters and t is in seconds. At t = 1.00 s, find (a) the position of the particle, (b) its velocity, and (c) its acceleration.

a. (a) 4.00 m; (b) 3.17 m/s; (c) 1.42 m/s

2

b. (a) 6.00 m; (b) 5.00 m/s; (c) 2.00 m/s

2

c. (a) 4.00 m; (b) -1.00 m/s; (c) 2.00 m/s

2

d. (a) 4.00 m; (b) 1.00 m/s; (c) -2.00 m/s

2

21.

A truck covers 40.0 m in 8.50 s while smoothly slowing down to a final speed of 2.80 m/s. (a) Find

Page 2: Mid Term Revision 2014

its original speed. (b) Find its acceleration.

a. (a) 6.61 m/s; (b) -0.448 m/s

2

b. (a) 12.2 m/s; (b) -1.76 m/s

2

c. (a) 6.61 m/s; (b) 0.448 m/s

2

d. (a) 17.8 m/s; (b) -1.76 m/s

2

The minimum distance required to stop a car moving at 35.0 mi/hr is 40.0 ft. What is the minimum stopping distance for the same car moving at 10.0 mi/hr, assuming the same rate of acceleration?

a. 140 ft

b. 11.4 ft

c. 490 ft

d. 3.27 ft

31.

The initial speed of a body is 5.20 m/s. What is its speed after 2.50 s, (a) if it accelerates uniformly at 3.00 m/s

2 and (b) if it accelerates uniformly at -3.00 m/s

2?

a. (a) 7.5 m/s; (b) -7.5 m/s

b. (a) 12.7 m/s; (b) 0 m/s

c. (a) -2.30 m/s; (b) 12.7 m/s

d. (a) 12.7 m/s; (b) -2.3 m/s

40.

An electron in a cathode-ray-tube (CRT) accelerates uniformly from 6.00 × 104 m/s to 2.00 × 10

6

m/s over 1.00 cm. (a) How long does the electron take to travel this 1.00 cm? (b) What is its acceleration?

a. (a) 2.00 × 10

-2 s; (b) 9.70 × 10

7 m/s

2

b. (a) 9.71 × 10

-9 s; (b) 2.00 × 10

14 m/s

2

c. (a) 9.71 × 10

-7 s; (b) 2.00 × 10

12 m/s

2

d. (a) 1.03 × 10

6 s; (b) 2.00 × 10

12 m/s

2

41.

55.

A ball thrown vertically upward is caught by the thrower after 1.00 s. Find (a) the initial velocity

of the ball and (b) the maximum height it reaches.

Page 3: Mid Term Revision 2014

a. (a) 9.80 m/s; (b) 14.7 m

b. (a) 4.90 m/s; (b) 2.45 m

c. (a) 4.90 m/s; (b) 1.23 m

d. (a) 9.80 m/s; (b) 4.90 m

65.

Another scheme to catch the roadrunner has failed. A safe falls from rest from the top of a 15.0 m high cliff toward Wile E. Coyote, who is standing at the base. Wile first notices the safe after it has fallen 7.00 m. How long does he have to get out of the way?

a. 1.28 s

b. 1.20 s

c. 0.554 s

d. 1.75 s

66.

A motorist drives along a straight road at a constant speed of 15.0 m/s. Just as she passes a parked motorcycle police officer, the officer starts to accelerate at 2.00 m/s

2 to overtake her. Assuming the

officer maintains this acceleration, (a) determine the time it takes the police officer to reach the motorist. Also, find (b) the speed and (c) the total displacement of the officer as he overtakes the motorist.

a. (a) 15.0 s; (b) 30.0 m/s; (c) 225 m

b. (a) 7.50 s; (b) 30.0 m/s; (c) 169 m

c. (a) 3.75 s; (b) 7.50 m/s; (c) 56.3 m

d. (a) 7.50 s; (b) 15.0 m/s; (c) 113 m

Page 4: Mid Term Revision 2014

Chapter 3

5.

If the cartesian coordinates of a point are given by (6, y) and its polar coordinates are (r, 15° ), determine y and r .

a. y = 1.61, r = 38.6

b. y = 22.4, r = 23.2

c. y = 1.61, r = 6.21

d. y = 22.4, r = 538

6.

If the polar coordinates of the point (x, y) are (r, ), determine the polar coordinates for the point (-x, y).

a.

, 180° -

b. r, 180° -

c.

, 360° -

d. r, 360° -

15.

A pedestrian moves 10.00 km east and then 21.0 km north. Using the graphical method, find the magnitude and direction of the resultant displacement vector.

a. 18.5 km, 61.6° east of north

b. 18.5 km, 25.5° north of east

c. 23.3 km, 64.5° north of east

d. 23.3 km, 61.6° north of east

16. Vector has a magnitude of 8.00 units and makes an angle of 45.0° with the positive x axis. Vector

has a magnitude of 8.00 units and is directed along the negative x axis. Using graphical methods,

find (a) the vector sum of and (b) the vector difference .

a. (a) 14.8 @ 22°; (b) 6.1 @ 67°

b. (a) 14.8 @ 22°; (b) 6.1 @ 112°

c. (a) 6.1 @ 112°; (b) 14.8 @ 22°

d. (a) 16.0 @ 45°; (b) 0

Page 5: Mid Term Revision 2014

25.

Fox Mulder is trapped in a maze. To find his way out, he walks 6.00 m, makes a 90° left turn, walks 4.00 m, makes another 90° left turn and walks 2.00 m. What is his displacement from his initial position?

a. 5.66 m, 45.0° to the right of his original direction

b. 8.94 m, 26.6° to the left of his original direction

c. 5.66 m, 45.0° to the left of his original direction

d. 8.94 m, 26.6° to the right of his original direction

26.

A person walks 25.0° north of east for 3.10 km. How far would she have to walk due north and due east to arrive at the same location?

a. 2.81 km north and 1.31 km east

b. 1.45 km north and 2.74 km east

c. 2.74 km north and 1.45 km east

d. 1.31 km north and 2.81 km east

40.

A vector has an x component of -40.0 units and a y component of 60.0 units. Find the magnitude and direction of this vector.

a. 44.7 units at 56.3°

b. 72.1 units at 56.3°

c. 72.1 units at 124°

d. 44.7 units at 124°

41. Consider two vectors and . Calculate .

a.

2.00 + 6.00

b.

2.00 - 6.00

c.

2.00 - 2.00

d.

4.00 + 2.00

Page 6: Mid Term Revision 2014

50.

The helicopter view in Figure P3.37 shows two people pulling on a stubborn mule.

Find (a) the single force that is equivalent to the two forces shown and (b) the force that a third person would have to exert on the mule to make the resultant force equal to zero. The forces are measured in units of newtons.

a.

(a) 240 N @ 69.3° from the positive x axis; (b) (85.0 + 224 ) N

b.

(a) 225 N @ 84.9° from the positive x axis; (b) (-19.9 - 224 ) N

c.

(a) 92.0 N @ 22.5° from the positive x axis; (b) (-35.3 - 85.0 ) N

d.

(a) 225 N @ 84.9° from the positive x axis; (b) (19.9 + 224 ) N

51. Vectors and have equal magnitudes of 5.00. If the sum of and is the vector 6.00 ,

determine the angle between and .

a. 16.3?

b. 106?

c. 90.0?

d. 73.7?

Page 7: Mid Term Revision 2014

60.

Three vectors are oriented as shown in Figure P3.51, where = 100 units, = 120 units and = 110 units. Find (a) the x and y components of the resultant vector (expressed in unit-vector notation) and (b) the magnitude and direction of the resultant vector.

a.

(a) 163 + 263 ; (b) 309 units @ 58.2?

b.

(a) 163 + 107 ; (b) 195 units @ 33.4?

c.

(a) 233 + 233 ; (b) 330 units @ 45.0?

d.

(a) 263 + 7.07 ; (b) 263 units @ 1.54?

61. If = (6.00 - 8.00 ) units, = (-8.00 + 3.00 ) units, and = (26.0 + 19.0 ) units, determine

a and b such that a + b + = 0.

a. a = 5.00, b = 7.00

b. a = 5.76, b = 6.70

c. a = -5.00, b = -7.00

d. a = -5.76, b = -6.70

70. A vector is given by = 6.00 + 5.00 + 7.00 . Find (a) the magnitude of the x, y, and z

components; (b) the magnitude of and (c) the angles between and the x, y, and z axis.

a. (a) 6.00, 5.00, 7.00; (b) 18.0; (c) 70.5°, 73.9°, 67.1°

b. (a) 6.00, 5.00, 7.00; (b) 10.5; (c) 55.1°, 61.5°, 48.1°

c. (a) 6.00, 5.00, 7.00; (b) 10.5; (c) 34.9°, 28.5°, 41.9°

d. (a) 1.00, 1.00, 1.00; (b) 18.0; (c) 70.5°, 73.9°, 67.1°

Page 8: Mid Term Revision 2014

71.

A jet airliner, moving initially at 300 mi/h to the east, suddenly enters a region where the wind is blowing at 100 mi/h in a direction 30.0° north of east. What are the new speed and direction of the aircraft relative to the ground?

a. 219 mi/h at 13.2° south of east

b. 361 mi/h at 13.9° north of east

c. 390 mi/h at 7.37° north of east

d. 219 mi/h at 13.2° north of east

Page 9: Mid Term Revision 2014

Chapter 4

5.

Suppose that the position vector for a particle is given as = x + y , with x = at + b and y = ct2 + d,

where a = 5.00 m/s, b = 5.00 m, c = 0.525 m/s2, and d = 5.00 m. (a) Calculate the average velocity

during the time interval from t = 2.00 s to t = 4.00 s. (b) Determine the velocity and the speed at t = 2.00 s.

a.

(a) (7.50 + 3.55 ) m/s; (b) (7.50 + 3.55 ) m/s, 8.30 m/s

b.

(a) (7.50 + 3.55 ) m/s; (b) (5.00 + 2.10 ) m/s, 5.42 m/s

c.

(a) (5.00 + 3.15 ) m/s; (b) (5.00 + 2.10 ) m/s, 5.42 m/s

d.

(a) (5.00 + 3.15 ) m/s; (b) (7.50 + 3.55 ) m/s, 8.30 m/s

6. At t = 0, a particle moving in the xy plane with constant acceleration has a velocity = (3.00 - 2.00

) m/s when it is at the origin. At t = 3.00 s, the particle's velocity is = (9.00 + 7.00 ) m/s. Find (a) the acceleration of the particle and (b) its coordinates at any time t.

a.

(a) (6.00 + 9.00 ) m/s2; (b) x = (9.00t) m, y = (7.00t) m

b.

(a) (6.00 + 9.00 ) m/s2; (b) x = (6.00t) m, y = (9.00t) m

c.

(a) (2.00 + 3.00 ) m/s2; (b) x = (3.00t + t

2) m, y = (-2.00t + 1.50t

2) m

d.

(a) (6.00 + 5.00 ) m/s2; (b) x = (9.00t) m, y = (7.00t) m

10. At t = 0, a particle moving in the xy plane with constant acceleration has a velocity = (7.00 - 6.00

) m/s when it is at the origin. At t = 3.00 s, the particle's velocity is = (13.0 + 11.0 ) m/s. Find (a) the acceleration of the particle and (b) its coordinates at any time t.

a.

(a) (6.00 + 5.00 ) m/s2; (b) x = (13.0t) m, y = (11.0t) m

b.

(a) (2.00 + 5.66 ) m/s2; (b) x = (17.0t + t

2) m, y = (16.0t + 2.83t

2) m

c.

(a) (6.00 + 17.0 ) m/s2; (b) x = (6.00t) m, y = (17.0t) m

d.

(a) (6.00 + 17.0 ) m/s2; (b) x = (13.0t) m, y = (11.0t) m

Page 10: Mid Term Revision 2014

11.

An artillery shell is fired with an initial velocity of 300 m/s at 55.0° above the horizontal. It explodes on a mountainside 42.0 s after firing. What are the x and y components of the shell where it explodes, relative to its firing point?

a. x = 7.23 km, y = 1.68 km

b. x = 10.3 km, y = 1.42 km

c. x = 7.23 km, y = 10.3 km

d. x = 1.42 km, y = 1.68 km

20.

An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 17.0 m if her initial speed is 7.00 m/s. What is the free fall acceleration on the planet?

a. 0.412 m/s

2

b. 2.88 m/s

2

c. 5.77 m/s

2

d. 1.44 m/s

2

21.

A soccer player kicks a rock horizontally off a cliff 40.0 m high into a pool of water. If the player hears the sound of the splash 3.00 s later, what was the initial speed given to the rock° Assume the speed of sound in air to be 343 m/s.

a. 9.91 m/s

b. 22.1 m/s

c. 0 m/s

d. 17.2 m/s

30.

A tire 0.300 m in radius rotates at a constant rate of 400 rpm. Find the speed and acceleration of a small stone lodged in the tread of the tire (on its outer edge). (Hint: In one revolution, the stone

travels a distance equal to the circumference of its path, 2r.)

a. 0.283 m/s, 0.267 m/s

2

b. 0.283 m/s, 0.943 m/s

2

c. 12.6 m/s, 41.9 m/s

2

d. 12.6 m/s, 526 m/s

2

31.

A student attaches a ball to the end of a string 0.600 m in length and then swings the ball in a

Page 11: Mid Term Revision 2014

vertical circle. The speed of the ball is 4.30 m/s at its highest point and 6.50 m/s at its lowest point. Find the acceleration of the ball when the string is vertical and the ball is at (a) its highest point and (b) its lowest point.

a. (a) 10.8 m/s

2 downward; (b) 7.14 m/s

2 upward

b. (a) 7.14 m/s

2 downward; (b) 10.8 m/s

2 upward

c. (a) 70.4 m/s

2 downward; (b) 30.8 m/s

2 upward

d. (a) 30.8 m/s

2 downward; (b) 70.4 m/s

2 upward

36.

How long does it take an automobile traveling in the left lane at 60.0 km/h to pull alongside a car traveling in the right lane at 40.0 km/h if the cars' front bumpers are initially 100 m apart?

a. 3.60 s

b. ∞

c. 18.0 s

d. 5.00 s

45.

A science student is riding on a flatcar of a train traveling along a straight horizontal track at a constant speed of 18.0 m/s. The student throws a ball into the air along a path that he judges to make an initial angle of 40.0° with the horizontal and to be in line with the track. The student's professor, who is standing on the ground nearby, observes the ball to rise vertically. How high does she see the ball rise?

a. 23.5 m

b. 6.83 m

c. 11.6 m

d. 55.5 m

46.

A ball on the end of a string is whirled around in a horizontal circle of radius 0.300 m. The plane of the circle is 1.20 m above the ground. The string breaks and the ball lands 2.00 m (horizontally) away from the point on the ground directly beneath the ball's location when the string breaks. Find the radical acceleration of the ball during its circular motion.

a. 54.4 m/s

2

b. 13.5 m/s

2

c. 92.0 m/s

2

d. 11.8 m/s

2

Chapter 5

Page 12: Mid Term Revision 2014

5. A 5.00 kg mass undergoes an acceleration given by = (6.00 + 3.00 ) m/s

2. Find the resultant

force and its magnitude.

a.

1.67 + 0.833 N, 1.86 N

b.

0.833 + 1.67 N, 1.86 N

c.

15.0 + 30.0 N, 33.5 N

d.

30.0 + 15.0 N, 33.5 N

6.

A 5.00 g bullet leaves the muzzle of a rifle with a speed of 320 m/s. The expanding gases behind it exert what force on the bullet while it is traveling down the barrel of the rifle, 0.820 m long? Assume constant acceleration and negligible friction.

a. 195 N

b. 312 N

c. 3.12 N

d. 1.95 N

15.

If a man weighs 800 N on the Earth, what would he weigh on Jupiter, where the acceleration due to gravity is 25.9 m/s

2?

a. 0.303 kN

b. 2.11 kN

c. 0.800 kN

d. 0.473 kN

Page 13: Mid Term Revision 2014

16.

Two forces, F1 and F2, act on a 5.00 kg mass. If F1 = 20.0 N and F2 = 15.0 N, find the accelerations

in (a) and (b) of Figure P5.15.

a. (a) 2.65 m/s

2 at 36.9°; (b) 6.77 m/s

2 at 12.8°

b. (a) 5.00 m/s

2 at 36.9°; (b) 6.08 m/s

2 at 25.3°

c. (a) 5.00 m/s

2 at 53.1°; (b) 6.08 m/s

2 at 64.7°

d. (a) 5.00 m/s

2 at 53.1°; (b) 6.77 m/s

2 at 12.8°

25.

A 3.00 kg mass is moving in a plane, with its x and y coordinates given by x = 9t2 - 5 and y = t

2 + 6,

where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this mass at t = 2.00 s.

a. 54.3 N

b. 36.2 N

c. 53.7 N

d. 109 N

26.

A bag of cement of weight 325 N hangs from three wires as suggested in Figure P5.24.

Two of the wires make angles 1 = 60.0° and 2 = 25.0° with the horizontal. If the system is in equilibrium, find the tensions T1, T2, and T3 in the wires.

a. T1 = 296 N, T2 = 163 N, T3 = 134 N

b. T1 = 296 N, T2 = 163 N, T3 = 325 N

c. T1 = 138 N, T2 = 283 N, T3 = 96.0 N

d. T1 = 138 N, T2 = 283 N, T3 = 325 N

Page 14: Mid Term Revision 2014
Page 15: Mid Term Revision 2014

35.

A 3.00-kg mass is observed to accelerate at 20.0 m/s2 in a direction 42.0° north of east (Fig. P5.29).

The force F2 acting on the mass has a magnitude of 40.2 N and is directed north. Determine the magnitude and direction of the force F1 acting on the mass.

a. 54.0 N east

b. 44.6 N east

c. 54.0 N west

d. 40.2 N east

36.

A block is given an initial velocity of 5.00 m/s up a frictionless 20.0° incline (Fig. P5.32).

How far up the incline does the block slide before coming to rest?

a. 0.436 m

b. 3.73 m

c. 3.50 m

d. 1.36 m

45.

Two masses of 2.00 kg and 7.00 kg are connected by a light string that passes over a frictionless pulley, as in Figure P5.15a.

Determine (a) the tension in the string, (b) the acceleration of each mass, and (c) the distance each mass will move in the first second of motion if they start from rest.

a. (a) 15.3 N; (b) 5.44 m/s

2; (c) 2.72 m

Page 16: Mid Term Revision 2014

b. (a) 30.5 N; (b) 9.80 m/s

2; (c) 4.90 m

c. (a) 5.44 N; (b) 30.5 m/s

2; (c) 15.3 m

d. (a) 30.5 N; (b) 5.44 m/s

2; (c) 2.72 m

46.

A 25.0 kg block is initially at rest on a horizontal surface. A horizontal force of 75.0 N is required to set the block in motion. After it is in motion, a horizontal force of 60.0 N is required to keep the block moving with constant speed. Find the coefficients of static and kinetic friction from this information.

a. s = 4.08, k = 3.27

b. s = 0.245, k = 0.306

c. s = 0.306, k = 0.245

d. s = 3.27, k = 4.08

55.

A 17.0 kg hanging weight is connected by a string over a pulley to a 9.00 kg block that is sliding on a flat table (Fig. P5.49).

If the coefficient of kinetic friction is 0.400, find the tension in the string.

a. 167 N

b. 34.6 N

c. 80.7 N

d. 66.6 N

56.

A high diver of mass 70.0 kg jumps off a board 10.0 m above the water. If his downward motion is stopped 2.00 s after he enters the water, what average upward force did the water exert him?

a. 0.686 kN

b. 1.18 kN

c. 0.490 kN

d. 0.196 kN

65.

Two forces, given by = (- 8.00 - 6.00 ) N and = (-5.00 + 9.00 ) N, act on a particle of mass 3.00 kg that is initially at rest at coordinates (-3.00 m, +5.00 m). (a) What are the components of the velocity at t = 10.0 s? (b) In what direction is the particle moving at t = 10.0 s? (c) How far from the

Page 17: Mid Term Revision 2014

origin does the particle move the first 10.0 s? (d) What are the coordinates of the particle at t = 10.0 s?

a.

(a) (-43.3 + 10.0 ) m/s; (b) 167° from the +x axis; (c) 227 m; (d) (-220, 50.0) m

b.

(a) (-43.3 + 10.0 ) m/s; (b) 167° from the +x axis; (c) 222 m; (d) (-217, 50.0) m

c.

(a) (-130 + 30.0 ) m/s; (b) 13.0° from the +x axis; (c) 667 m; (d) (-650, 150) m

d.

(a) (-130 + 30.0 ) m/s; (b) 167° from the +x axis; (c) 671 m; (d) (-653, 155) m

66.

A 2.00 kg block is placed on top of a 5.00 kg block as in Fig. P5.67.

The coefficient of kinetic friction between the 5.00 kg block and the surface is 0.200. A horizontal force, F, is applied to the 5.00 kg block. (a) What force accelerates the 2.00 kg block? (b) Calculate the magnitude of the force necessary to pull both blocks to the right with an acceleration of 3.00 m/s

2. (c) Find the minimum coefficient of static friction between the blocks such that the 2.00 kg

block does not slip under an acceleration of 3.00 m/s2.

a. (a) static friction between the blocks; (b) 30.8 N; (c) 0.306

b. (a) the horizontal force, F; (b) 34.7 N; (c) 1.77

c. (a) the horizontal force, F; (b) 30.8 N; (c) 0.200

d. (a) static friction between the blocks; (b) 34.7 N; (c) 0.306

71.

The system shown in Figure P5.72 has an acceleration of magnitude 1.50 m/s2.

Assume the coefficients of kinetic friction between block and incline are the same for both inclines. Find (a) the coefficient of kinetic friction and (b) the tension in the string.

a. (a) 0.746; (b) 18.7 N

b. (a) 0.0871; (b) 27.4 N

c. (a) 0.222; (b) 18.7 N

d. (a) 0.292; (b) 39.1 N