mémoire r. denis (2014)
TRANSCRIPT
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𝐺
𝑡
𝑌0
𝐺 𝑡
𝒀 𝑩 𝒀𝒏𝒆𝒕
𝒀𝟎
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{𝐵 = 𝐺 − 𝑡𝑌 𝑠𝑖 0 ≤ 𝑌 ≤ 𝑌0
𝐵 = 𝑡(𝑌0 − 𝑌) 𝑠𝑖 𝑌 ≥ 𝑌0
𝑌0
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𝐺 𝑡
𝐺
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∞
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𝐺 𝑡 𝑌0
𝐺 𝑡
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𝑌0
𝑡
𝐺
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𝐺
𝑌0
𝑌0
𝑌0
𝐺
𝐵 = 𝐺 − 𝑡𝑌 ⇒ 0 = 𝐺 − 𝑡𝑌0 ⇒ 𝑌0 =𝐺
𝑡
𝑡 =1
3⇒ 𝑌0 = 3𝐺
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𝐺
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𝑡
𝐵 𝐺
𝑡
𝐵 = 𝐺 − 𝑡𝑌
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𝐺
𝑡
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𝜋𝐴 𝜋𝐵
(1 − 𝜋𝐴) (1 − 𝜋𝐵)
𝑃𝐴𝐺(𝜋𝐵) = 1 ∙ 𝜋𝐵 + 0 ∙ (1 − 𝜋𝐵) = 𝜋𝐵 (𝑠’il serre à gauche)
𝑃𝐴𝐷(𝜋𝐵) = 0 ∙ 𝜋𝐵 + 1 ∙ (1 − 𝜋𝐵) = 1 − 𝜋𝐵 (s’il serre à droite)
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𝜋𝐵 = 1 − 𝜋𝐵 ⇒ 2𝜋𝐵 = 1 ⇒ 𝜋𝐵 = 0.5
𝑃𝐵𝐺(𝜋𝐴) = 1 ∙ 𝜋𝐴 + 0 ∙ (1 − 𝜋𝐴) = 𝜋𝐴 (𝑠’il serre à gauche)
𝑃𝐵𝐷(𝜋𝐴) = 0 ∙ 𝜋𝐴 + 1 ∙ (1 − 𝜋𝐴) = 1 − 𝜋𝐴 (s’il serre à droite)
𝜋𝐴 = 1 − 𝜋𝐴 ⇒ 2𝜋𝐴 = 1 ⇒ 𝜋𝐴 = 0.5
𝑃𝑟(𝐺, 𝐷) + 𝑃𝑟(𝐷, 𝐺) = 𝑃𝑟𝐴(𝐺) ∙ 𝑃𝑟𝐵(𝐷) + 𝑃𝑟𝐴(𝐷) ∙ 𝑃𝑟𝐵(𝐺) = 0.25 + 0.25 = 0.5
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𝜀
(1 − 𝜀) 𝜀
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𝜀
𝜀𝑠
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0,75(1 − 𝜋) + 0 ∙ 𝜋 =
0,50(1 − 𝜋) + 0,50𝜋 ⇒ 𝜋 = 13⁄
0,50(1 − 𝜋) + 0 ∙ 𝜋 = 0,25 ∙
(1 − 𝜋) + 0,25𝜋 ⇒ 𝑥 = 12⁄
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𝜆 = 𝐸 𝑃𝑃∗⁄
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61
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𝒔
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𝑟𝑚 − 𝑟𝑓 = 𝑐�̅�𝜎𝑚2
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�̅� =1
𝑐∙
𝑟𝑚 − 𝑟𝑓
𝜎𝑚2
𝑟𝑚
𝑟𝑓
𝜎𝑚2
𝑐 = 100 �̅�
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𝐷𝐸𝑃𝑉 = 𝛽0 + 𝛽1𝐼𝐷𝐶 + 𝛽2𝐼𝐷𝐸 + 𝛽3𝑉𝐼𝑋 + 𝛽4𝐴𝑉𝐸𝑅 + 𝜀
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𝐷𝐸𝑃𝑉 = 𝛽0 + 𝛽1𝐼𝐷𝐶 + 𝛽2𝐼𝐷𝐸 + 𝛽3𝐴𝑉𝐸𝑅 + 𝛼1𝑀1 + 𝛼2𝑀2 + 𝛼3𝑀3 + 𝛼4𝑀4 + 𝛼5𝑀5 + 𝛼6𝑀6
+ 𝛼7𝑀7 + 𝛼8𝑀8 + 𝛼9𝑀9 + 𝛼10𝑀10 + 𝛼11𝑀11 + 𝛼12𝑀12 + 𝜀
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𝑴𝟏 𝑴𝟐 𝑴𝟑 𝑴𝟗 𝑴𝟏𝟎 𝑴𝟏𝟏 𝑴𝟏𝟐
𝑀𝑛 ∶ 𝑛 = 1. .12
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𝐻0: 𝛽1 = 𝛽2 = 0 𝐻1: 𝛽1 ≠ 0 𝑜𝑢 𝛽2 ≠ 0
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