mektan i 2 flow nets
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1.
Permeabil ity coefficient in stratified soil
2. Permeability test in the field
3. Seepage and Flow-net
4. Uplift pressure on hydraulic structure
5. Seepage through an earth dam on impervious base
6.
Soil compaction
Soil Mechanics I(T. Faisal Fathani)
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SeepageFlow nets:To calculate the flow of water through soil which is not in one direction
only, nor is it uniform over the area perpendicular to the flow.
The concept of flow nets Laplace’s equation of continuity
H1
H2
h
dz
dx
Impermeable layer
Sheet pile
A Single-row sheet piledriven into permeable
layer
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Flow at A:
dx
dz
dy
vz dx dy
vx dz dy
Laju perubahan
kecepatan aliran
Assuming the water is incompressible
and that no volume change in soil
mass:
2D seepage continuity equation:
If the volume change:(1)
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With Darcy’s Law, discharge velocities:
kx = hydraulic conductivity in horizontal direction
kz = hydraulic conductivity in vertical direction (2)
From Eq (1) and (2):
If the soil is isotropic, kx = kz ; continuity equation for 2D flow:
(1)
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Flow nets:- Flow lines: a water particle will travel from upstream
to downstream side in permeable soil medium- Equipotential lines: potential head at all points is
equal.
H1
H2
Impervious layer
Sheet pile
Flow line
Equipotential
line
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- Equipotential lines intersect the flow lines at right angles
- The flow elements formed are approximate squares
H1
H2
Impervious layer
Sheet pile
a b
c
d e
f g
Nf = 4Nd = 6
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H1
H2
Impervious layer
a d
Nf = 4Nd = 8
H
Flow net under a dam
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The rate of seepage through the flow channel per unit length.
Because no flow across the flow lines:
From Darcy’s Law:
Seepage calculation from a Flow Net
(flow channel
square elements)
q
q
h1
h2h3
h4l 1
l 2
l 3
l 1
l 2
l 3
q1q2
q3
h1, h2, h3, hn = piezometric
levels corresponding to the
equipotential lines
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H = head difference between upstream and downstream sidesNd = Number of potential drops
Nf = Number of flow channels
Total rate of flow through all the channels per unit length:
Flow elements are drawn as approximate potential drop between
any 2 adjacent equipotential line is the same
The rate of flow through a flow channel per unit length:
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The rate of flow through the channel:
q
q
h1h2
h3h4
b1
b2
b3
l 1
l 2l 3
Seepage calculation from a Flow Net
(flow channel
rectangular elements)
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H1
H2
Impervious layer
Sheet pile
Channel-1Channel-2
Channel-3
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15 m
5 m
Impervious layer
Sheet pile
I II
III
30 m a
b
c
d 1 2 3 4 5
Example-1
(a)
How high (above the ground surface) the water will rise if
piezometers are placed at points a, b, c dan d
From the figure : Nf = 3 dan Nd = 6
Potential drop between 2 equipotential lines: H/Nd = 10/6 = 1,667 m
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Point a is located on equipotential line 1
Potential drop at a = 1 x 1,667 m
• Water in piezometer at point a will rise to an elevation of
(15-1,667) = 13,333 m above the ground surface.
Similary, the piezometer levels for:
• Point b = (15 - 2 x 1,667) = 11,67 m above the ground surface
• Point c = (15 - 5 x 1,667) = 6,67 m above the ground surface
•
Point d = (15 - 5 x 1,667) = 6,67 m above the ground surface
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(b) The rate of flow through flow channel II per unit length:
(c) Total rate of flow through all the channels per unit length
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4,5 m
0,5 m
Impervious layer
Sheet pile
6 m
8,6 m
Datum
h = 4 m h = 0
A
B C
E
D
2. Draw flow nets of the following case:
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•
From flow nets:
•
Potential drop between 2 adjacent equipotential lines:
•
Total volume of flow under the sheet pile per length of sheetpile :
•
Total head at every points on the same equipotential line
with number (n
d) =• A piezometer at point P on equipotential line : nd=10. Total
head at point P:
Nf = 4,3
Nd = 12
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4 m
Impermeable layer
Sheet pile
4,8 m
Datum
3. Draw net water pressure distribution at the sheet pile.
4,7 m
2,5 m
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Total head at the water table (upstream) = 2,5 m
(pressure head = 0; elevation head +2,50 m)
Total heal at the ground surface in front of sheet pile(downstream equipotential) =0 (pressure head = 4,00 m; elevation head = -4,00m)
Nd = 12
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Water pressure at both sides of sheet pile no. 1-7
example, at Surface 4, Total head behind the sheet pile:
Total heat in front of sheet pile:
Elevation heat at the surface 4 = -5,5 m
Net pressure behind the sheet pile :
Similar calculation for the other point
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Example 4
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q = 0,25 m3/hour
per length
Nf = 6,0Nd = 11
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• Hydraulic conductivity of sand:
•
Hydraulic gradient below the excavated surface :
Distance (s) between 2 last equipotential line = 0,9 m.
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