16 de agosto de 2012

Asignación II

Darvin Colón K00291438

Eric J. Burgos E00348857

Ejercicios 1

A = (2 34 −1) I = (0 0

0 0)a) I(A) b) A(I) c) A(I) = I(A)

a) (1(2) +0(4)0 (2) +1(4)) (1(3) +0(−1)

0 (3) +1(−1)) = (2 +00 +4) (3 +0

0 +0) = (2 34 −1)

b) (2(1) +3 (0)4(1) +−1(0)) (2(0) +3(1)

4(0) +−1(1)) = (2 +00 +4) (0 +3

0 +−1) = (2 34 −1)

c) I = A

Ejercicio 2

A = (−3 04 5) B = (7 −1

8 0 ) a) AB b) BA c) AB = BA

a) (−3 (7) +0 (8)4 (7) +5(8)) (−3 (−1) +0(8)

4 (−1) +5(0)) = (−21 +028 +40) ( 3 +0

−4 +0) = (−21 −368 −4 )

b) (7 (−3) +−1(4)8 (−3) +0(4) ) (7 (0) +−1(5)

8 (0) +0(5) ) = (−21 +−4−24 +0 ) (0 +−5

0 +0 ) =

(−25 +−5−24 +0 )

c) AB no = BA

Ejercicio 3

A = (7 25 4 ) B = ( 4 /18 −2/18

−5 /18 7 /18 ) Determinar si AB = A^-1