math2043answerkeytest1-2-3
DESCRIPTION
Temple Math 2043 Exam Review Answer KeyTRANSCRIPT
Math 2043 Answer Key to the even-numbered review problems for Test 1 Spring 2015
Section 12.1
4. The projection of (2, 3, 5) onto the xy-plane is (2, 3, 0),onto the yz-plane is (0, 3, 5), onto the xz-plane is (2, 0, 5).
The length of the diagonal is√38.
12. Intersection with
xy-plane: a circle with center (2,−6, 0) and radius 3;xz-plane: no intersection;yz-plane: a circle with center (0,−6, 4) and radius
√21
Section 12.2
4. (a)−→AC (b)
−→CB (c)
−→DA (d)
−→DB 8. |w | =
√
| − u |2 + | − v |2 =√2
26. 〈−√6, 2
√6,√6〉
Section 12.3
64. (u+v) · (u−v) = 0 ⇒ u ·u−u ·v+v ·u−v ·v = |u |2 − |v |2 = 0 ⇒ |u |2 = |v |2 ⇒ |u | = |v |
Section 12.5
4. Vector equation: r = (14j− 10k)+ t(2i− 3j+9k), parametric equations: x = 2t, y = 14− 3t, z = −10+9t
26. 3x− y + 4z = 10
Chapter 12 Review
6.
⟨
7
3√6, 2
3√6, − 1
3√6
⟩
and⟨
− 7
3√6,− 2
3√6, 1
3√6
⟩
Section 13.2
40. (12te2t − 1
4e2t) i + (−t− ln |1− t|) j + arcsin tk + C 42. (1
2t2 + 1) i+et j+(tet − et + 2)k
Section 13.3
2.7
3; 6. 15
Section 16.2
34. mass = 1
2ka3
Section 14.3
34.∂w
∂x= yz2exyz,
∂w
∂y= xz2exyz,
∂w
∂z= (xyz + 1)exyz
Section 14.4
20. L(x, y) = 2 + 1 · (x− 1) + 1 · (y − 1), f(1.02, 0.97) ≈ L(1.02, 0.97) = 1.99
A12
2. 2 4. x = 3
2, y = − 1
2or x = 1
2, y = − 3
2
7. (a) 〈1,−5, 3〉 (b) both vectors are 0 (c)⟨
−22√566
, 1√566
, 9√566
⟩
or⟨
22√566
, −1√566
, −9√566
⟩
10. y = −1, z = −1 or y = 7
5, z = 1
5
A13
1. r(t) =(
2
5(t− 1)5/2 + 2
3(t− 1)3/2 − 1
15
)
i+(− tπ cos(πt) + 1
π2 sin(πt) +2
π ) j+(t lnx− t+ 5− 2 ln 2)k
2.
√5− 1
4