math%104%–calculus % 8.8%improper%integrals% · 2015. 3. 2. · • an integral can be called...
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Math 104 -‐ Yu
Math 104 – Calculus 8.8 Improper Integrals
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Math 104 -‐ Yu
Improper Integrals • Goal: To evaluate integrals of func?ons over infinite intervals or with an infinite discon?nuity.
• Method: We replace the “bad” endpoints with variables and take limits. Combines skills of integra?on and evalua?ng limits.
• Descrip2on: If the limit exists, we say the integral converges and if it fails to exist (this includes infinite limits), we say the integral diverges.
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Math 104 -‐ Yu
Types of Improper Integrals An integral can be called improper with one or any combina?on of the following: Type I: contains infinity • at upper limit
• lower limit
• or both
Nicolas Fraiman Math 104
Types of improper integrals• An integral can be called improper with one or any
combination of the following
• Type I: Infinite interval at upper limit, lower limit or both
Z 1
1
lnx
x
2dx
Nicolas Fraiman Math 104
Types of improper integrals• An integral can be called improper with one or any
combination of the following
• Type I: Infinite interval at upper limit, lower limit or both
Z 0
�1
1
1 + x2dx
Nicolas Fraiman Math 104
• An integral can be called improper with one or any combination of the following
• Type I: Infinite interval at upper limit, lower limit or both
Types of improper integrals
Z 1
�1
1
1 + x2dx
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Math 104 -‐ Yu
Types of Improper Integrals Type II Infinite discon?nuity • at lower limit
• upper limit
• so some value in between
Nicolas Fraiman Math 104
Types of improper integrals• An integral can be called improper with one or any
combination of the following
• Type I: Infinite interval at upper limit, lower limit or both
• Type II: Infinite discontinuity at upper limit, lower limit, or some value in between
Nicolas Fraiman Math 104
Types of improper integrals• An integral can be called improper with one or any
combination of the following
• Type I: Infinite interval at upper limit, lower limit or both
• Type II: Infinite discontinuity at upper limit, lower limit, or some value in between
Z 1
0
1
(x� 1)2/3dx
Nicolas Fraiman Math 104
Types of improper integrals• An integral can be called improper with one or any
combination of the following
• Type I: Infinite interval at upper limit, lower limit or both
• Type II: Infinite discontinuity at upper limit, lower limit, or some value in between
Z 3
1
1
(x� 1)2/3dx
Z 3
0
1
(x� 1)2/3dx
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Math 104 -‐ Yu
Type I Improper Integral
Both have to converge to ensure that the LHS converge
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Examples
Nicolas Fraiman Math 104
Examples 1. Compute if it exists. 2. Determine whether converges or diverges. 3. Evaluate if it converges.
Z 1
1e
�2xdx
Z 1
2
1px
dx
Z 1
�1
x
2
1 + x6dx
Nicolas Fraiman Math 104
Examples 1. Compute if it exists. 2. Determine whether converges or diverges. 3. Evaluate if it converges.
Z 1
1e
�2xdx
Z 1
2
1px
dx
Z 1
�1
x
2
1 + x6dx
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Math 104 -‐ Yu
Examples
Nicolas Fraiman Math 104
Examples 1. Compute if it exists. 2. Determine whether converges or diverges. 3. Evaluate if it converges.
Z 1
1e
�2xdx
Z 1
2
1px
dx
Z 1
�1
x
2
1 + x6dx
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Math 104 -‐ Yu
Type II Integrals
Nicolas Fraiman Math 104
Type II integrals
Both have to converge to ensure that the LHS converge
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Math 104 -‐ Yu
Examples
Nicolas Fraiman Math 104
Examples 4. Find 5. Classify 6. Double improper
Z 9
0
1px
dx.
Z 2
�1
1
x
4dx.
Z 1
0
e
�1/x
x
2dx.
5. Determine of what type is the integral
Z 2
�1
1
x
4dx. Does it converge? If
it converges, evaluate the integral.
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Math 104 -‐ Yu
Examples In general, we can have mixture of Type I and Type II integrals. 6. Determine the type(s) of the integral
Z 1
0
e
�1/x
x
2dx. Does it converge?
If it converges, evaluate the integral.
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Math 104 -‐ Yu
Improper Integral of 1/x^p For any c > 0,
•Z 1
c
1
x
pdx converges for p > 1, diverges for p 1.
•Z c
0
1
x
pdx converges for p < 1, diverges for p � 1.
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Direct Comparison
Nicolas Fraiman Math 104
Comparison theorems
Nicolas Fraiman Math 104
Comparison theorems
WARNING: Do NOT switch the conditionsand the implications.
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Math 104 -‐ Yu
Examples
Nicolas Fraiman Math 104
Examples 7. Does converge or diverge? 8. Same for
Z 1
1
2 + sinx
x
2dx
Z 4
0
x+ 3
x
2dx
8. Does
Z 4
0
x+ 3
x
2dx converge or diverge?
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Math 104 -‐ Yu
Limit Comparison
Nicolas Fraiman Math 104
Comparison theorems
Nicolas Fraiman Math 104
Comparison theorems
i.e., f ⇠ g, f is ofthe same order as g
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Math 104 -‐ Yu
Examples
Nicolas Fraiman Math 104
Examples 9. Does converge or diverge? 10. A harder example
Z 1
2
xpx
4 + 5dx
Z ⇡/2
0cot(x) dx.
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Math 104 -‐ Yu
Comparison Tests for Type II • Comparison Tests also work for improper integral of the second type by replacing in the limit with the point where the func?on goes to infinity.
1
10. Does
Z ⇡/2
0cot(x)dx converge or diverge?
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Math 104 -‐ Yu
p-‐test for type I integral • In many cases, we can compare the integrand f(x) with func?ons of the form 1/x^p.
Type I integral:
Z 1
cf(x)dx, where f(x) is a nonnegative function and
c > 0.
• If f(x) ⇠ 1x
pwhen x ! 1, then the integral converges if p > 1,
diverges if p 1.
• If f(x) Cx
pfor some constant C > 0 and p > 1, when x is large
enough, then the integral converges.
• If f(x) � Cx
pfor some constant C > 0 and p < 1, when x is large
enough, then the integral diverges.
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Math 104 -‐ Yu
p-‐test for type II integral Type II integral:
Zb
a
f(x)dx, where f(x) is a nonnegative function con-
tinuous over the interval (a, b] and lim
x!a+f(x) = 1,
• If f(x) ⇠ 1(x� a)p when x ! a
+,
i.e., lim
x!a+f(x)
1(x�a)p
= L where L is a finite positive number,
then the integral converges if p < 1, diverges if p � 1.
• If f(x) C(x� a)p for some constant C > 0 and p < 1, when x is
close to a, then the integral converges.
• If f(x) � C(x� a)p for some constant C > 0 and p � 1, when x is
close to a, then the integral diverges.