mat133y final 2010w
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NAME (PRINT):Last/Surname First /Given Name
STUDENT #: SIGNATURE:
UNIVERSITY OF TORONTO MISSISSAUGA
APRIL 2010 FINAL EXAMINATION-Version A
MAT133Y5YCalculus and Linear Algebra for Commerce
Any Wilk, Shay Fuchs, Ken GiulianiDuration - 3 hours
Aids: Formula sheet provided (last pages of this paper)Calculator Model(s): Only TI-30X, TI-30XIIB or TI-30XIIS(with no lids or inserts)
The University of Toronto Mississauga and you, as a student, share a commitment to academicintegrity. You are reminded that you may be charged with an academic offence for possessingany unauthorized aids during the writing of an exam, including but not limited to any electronic
devices with storage, such as cell phones, pagers, personal digital assistants (PDAs), iPods,and MP3 players. Unauthorized calculators and notes are also not permitted. Do not have anyof these items in your possession in the area of your desk. Please turn the electronics off andput all unauthorized aids with your belongings at the front of the room before the examinationbegins. If any of these items are kept with you during the writing of your exam, you may becharged with an academic offence. A typical penalty may cause you to fail the course.
Please note, you CANNOTpetition to RE-WRITEan examination once you have begun writing.
INSTRUCTIONS:1. There are two parts to this examination:
PART I: MULTIPLE CHOICE 15 questions of equal value (3 marks each).PART II: Questions of varying value. In each question, you must show your workand write a concludingstatement(in the box provided). A correct answer obtained with false reasoning (or no reasoning) will notreceive any marks.
2. This examination has 24 different pages including this page. Make sure your copy of the examination has 24different pages and sign it at the top.
3. Budget your time. Good Luck!
Continued on page 2
PART I ******************PART II******************
Q1- Q15 Q1 Q2 Q3 Q4 Q5 Q6
Value 45 7 10 10 8 10 10
Score
TOTAL:
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*******************************************************************************************
PART I:MULTIPLE CHOICE [Total: 45 marks, 3 marks for each part]
For each question clearly circle the letter corresponding to your answer,
in the MULTIPLE CHOICE ANSWER TABLEprovided BELOW .
(ONLY ONE LETTER should be circled for each question).
NO marksfor incorrect answers or answers indicated outside the MULTIPLE CHOICE ANSWER TABLE]
PART I: MULTIPLE CHOICE ANSWER TABLE
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
A A A A A A A A A A A A A A A
B B B B B B B B B B B B B B B
C C C C C C C C C C C C C C CD D D D D D D D D D D D D D D
E E E E E E E E E E E E E E E
NO marksfor incorrect answers or answers indicated outside the MULTIPLE CHOICE ANSWER TABLE]
********************************************************************************************
Continued on page 3
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MAT133Y5Y April 2010 Final examination-A Student number______________________________
PART I:MULTIPLE CHOICE (continued) [Total: 45 marks, 3 marks for each part]For each question clearly circle the letter corresponding to your answer, in the MULTIPLE CHOICE ANSWERTABLE provided on page 2.
1. The solution to the logarithmic equation given by log(2 11) log3 log( 4)x x+ = + is
A) 1 B) -4 C) -1 D) 3/7 E) none of these
2. Which of the following options has the highest effective rate?
A) 10.25% compounded annually
B) 10.10% compounded semi-annually
C) 9.8% compounded continuously
D) 10% compounded quarterly
E) An effective rate of 10.3%
Continued on page 4
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PART I: MULTIPLE CHOICE (continued) [Total: 45 marks, 3 marks for each part]For each question clearly circle the letter corresponding to your answer, in the MULTIPLE CHOICE ANSWERTABLE provided on page 2.
3. Which set of constraints will determine a boundedfeasible region?
A)
2 4
4 4
0
x y
y x
x
B)
2 4
4 4
0
x y
y x
x
C)
2 4
4 4
0
x y
y x
x
D)
2 4
4 4
0
x y
y x
x
E) none of these
Continued on page 5
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MAT133Y5Y April 2010 Final examination-A Student number______________________________
PART I: MULTIPLE CHOICE (continued) [Total: 45 marks, 3 marks for each part]For each question clearly circle the letter corresponding to your answer, in the MULTIPLE CHOICE ANSWERTABLE provided on page 2.
4.A linear system is represented by the following augmented coefficient matrix
1 2 1 1
1 5 4 7
0 4 4 8
.
This linear system has
A) no solutions B) exactly one solution C) exactly two solutionsD) infinitely many solutions E) none of these
5.According to the matrix equation1
1 32
z y xe x
y k
+ =
, the value ofzis:
A) ln3 B) ln4 C) 3 D) e2 E) e
4
Continued on page 6
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PART I:MULTIPLE CHOICE (continued) [Total: 45 marks, 3 marks for each part]For each question clearly circle the letter corresponding to your answer, in the MULTIPLE CHOICE ANSWERTABLE provided on page 2.
6.
1 if 0
3( )1
if 05
x
xf x
xx
+= < +
is continuous on the intervals
A) ( ) ( ),0 0, B) ( ) ( ) ( ), 5 5, 3 3, C) ( ) ( ) ( ), 5 5,0 0,
D) ( ) ( ) ( ), 3 3,0 0, E) none of these
7. If 3 1( ) xy x x += then ( )y x =
A) ( ) 3 12 ln xx x x ++ B) 3 11
3 3ln xx xx
+ + +
C)
3 13ln
xx
x
++ D) ( ) 3ln xx x E) ( ) 33 1 xx x+
Continued on page 7
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PART I:MULTIPLE CHOICE (continued) [Total: 45 marks, 3 marks for each part]For each question clearly circle the letter corresponding to your answer, in the MULTIPLE CHOICE ANSWERTABLE provided on page 2.
8. Given the demand equation 21 2p q= for10 90q . For which value of qis the demand elastic?
A) 49.0 B) 51.5 C) 42.3 D) 64.5 E) 87.3
9. The minimum average cost for [10, 20]x , if total cost is given by 3( ) 40 686C x x x= + + , is
A) 473.3 B) 208.6 C) 1870 D) 187 E) 5036
Continued on page 8
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PART I:MULTIPLE CHOICE (continued) [Total: 45 marks, 3 marks for each part]For each question clearly circle the letter corresponding to your answer, in the MULTIPLE CHOICE ANSWERTABLE provided on page 2.
10. Suppose that r(q) is the total daily revenue (in $) at a fast food restaurant when qhamburgers are sold per day
If 310000
dr qdq
= + , find the pricepthat should be charged if q= 200 hamburgers are to be sold per day.
A) p= $5.98 B)p= $2.99 C)p= $3.01 D)p= $4.50 E) none of these
11.The average value of2
2( )
1 3
xf x
x=
+
on the interval [0, 1] is
A) 1 B)2
3
C)ln 2
3
D)1
3
E) none of these
Continued on page 9
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MAT133Y5Y April 2010 Final examination-A Student number______________________________
PART I:MULTIPLE CHOICE (continued) [Total: 45 marks, 3 marks for each part]For each question clearly circle the letter corresponding to your answer, in the MULTIPLE CHOICE ANSWERTABLE provided on page 2.
12.The improper integral0
x
x
e
edx
e
A) equals 1 B) equals e C) equals1
e D) diverges to E) none of these
13.The area of the region enclosed by the curve lny x= , 0y = and 4x= is
A) 4 ln 4 3 B) ln 4 C) 4 ln 4 4 D)3
4 E) none of these
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MAT133Y5Y April 2010 Final examination-A Student number______________________________
PART II: You must show your workand write a concluding statement(in the box provided).
Question 1 [Total: 7 marks]
Anna makes 5 payments into an annuity. Each payment is $1000, placed into the annuity at the beginning of each
year. For the first 3 years, interest is earned at 5% compounded annually. In the fourth and fifth years, however, thinterest rate goes up to 6% compounded annually. Determine the value of the annuity after 5 years.Round your answer to two decimals.
Conclusion for Question 1: Round your answer to two decimals.
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PART II: You must show your workand write a concluding statement(in the box provided).
Question 2 [Total: 10 marks]
From a 15 inch by 15 inch piece of cardboard, four congruent squares are to be cut out, one at each corner. The
remaining cross-like piece is then to be folded into an open-topped box. What size squares should be cut out tomaximize the volume of the resulting box?
15 in
15 in
x
x
x
x
x
x x
x
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MAT133Y5Y April 2010 Final examination-A Student number______________________________
PART II: You must show your workand write a concluding statement(in the box provided).
Question 2 (continued) [Total: 10 marks]
Conclusion for Question 2:
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PART II: You must show your workand write a concluding statement(in the box provided).
Question 3 [Total: 10 marks]
The demand function for a product is
210 800
30 200qp
q q+=
+ +.
Assume that the market equilibrium occurs when 10q= , and find the consumers surplus under market
equilibrium. Round your answer to one decimal.
Conclusion for Question 3: Round your answer to one decimal
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This page is intentionally left blank. Use it for rough work.
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Question 4 (continued)[Total: 8 marks]
For each part, clearly indicate your final short answer in the appropriate BOX provided.[8 marks, 1 mark for each part, with NO part marks for incorrect final answers.]
f) Does the given function have a horizontal asymptote, If so, where?
g) Does the given function have a vertical asymptote, If so, where?
h) Sketch the graph of the given function,on the co-ordinate system provided
5555 444 4 3 33 3 222 2 1111 1111 2222 3333 4444 5555 6666
2222
1111
1111
2222
3333
4444
5555
6666
x
y
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MAT133Y5Y April 2010 Final examination-A Student number______________________________
PART II: You must show your workand write a concluding statement(in the box provided).
Question 5 (continued) [Total:10 marks]
(b)What will be the temperature of the pot of soup after 10 minutes? [2 marks
Round your answer to the nearest degree (integer).
Conclusion for Question 5 (b):
(c)What will be the temperature of the soup after a long time (i.e. what is lim ( )t
T t
)? [2 marks
Conclusion for Question 5(c):
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PART II: You must show your workand write a concluding statement(in the box provided).
Question 6 [Total: 10 marks]
The revenue r(in dollars per square meter of ground) obtained from the sale of a crop of tomatoes grown in an
artificially heated greenhouse is given by
( )( , ) 5 1 xr x y y e= and the cost c(in dollars per square meter of ground) is given by
2( , ) 20 0.1c x y x y= +
wherexis the amount of fertilizer applied per square meter andyis the temperature (in C ) maintained in thegreenhouse.
(a)Write an expression, in terms ofxandy, for the profit Pper square meter obtained from the sale of the cro
of tomatoes. [2 marks
Conclusion for Question 6(a):
(b)Evaluate 5(ln ,5)4
xP and 5(ln ,5)
4y
P [2 marks
Conclusion for Question 6(b):
Continued on page 21
P(x,y) =
5(ln ,5)
4x
P =5
(ln ,5)4
yP =
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PART II: You must show your workand write a concluding statement(in the box provided).
Question 6(continued) [Total: 10 marks]
(c)Given that the pairs
( , ) (ln 5,20)x y = and 5( , ) (ln ,5)4
x y =
are the only critical points of the profit function in part (a), use the second derivative test to determinewhether either of these points corresponds to a relative maximum profit per square meter. [6 marks
Conclusion for Question 6(c):
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MAT133Y5Y April 2010 Final examinationFORMULA SHEET
Your name and student # MUST be written in INK on this page if you wish to separate it from the rest!
STUDENT NAME: ________________________________ Student number______________________________
FORMULA SHEET (1)
Some facts that may be useful:For discrete periodic compoundingwith periodic rate r(where r is theAPRdivided by the number of interest periods in onyear):
(1 )nS P r= + is the compound amount when a principal amount Pis invested for nperiods at a periodic rate of r.
(1 ) nP S r = + is the present value (or principal amount) that needs to be invested at the periodic rate of rfor n
interest periods so that the compound amount is S.The effective rate rethat is equivalent to anAPR(a nominal rate) compounded n times a year is given by:
1 1
n
e
APRr
n
= +
For continuous compounding:
rtS Pe= is the compound amount Sof a principal amount Pafter tyears at an annual interest rate rcompoundedcontinuously.
rtP Se= is the present value Pof a compound amount Sdue at the end of tyears at an annual interest rate rcompoundedcontinuously.
The effective rate recorresponding to an annual rate of rcompounded continuously is 1r
er e=
Annuities:
1 (1 ) nrA R
r
+
= is the present value of an
ordinary annuity
(1 ) 1
n
rS Rr
+ = is the future value of an
ordinary annuity
11 (1 )1
nrA R
r
+ += +
is the present value
of an annuity due
1(1 ) 11
nrS R
r
+ + =
is the future value of
an annuity due)
A= Present value of an annuityS= amount (future value) of an annuityR= amount of each paymentn= number of paymentsr= periodic rate of interest
For a LOAN amortized over nperiods at a periodic rate r, we have:
Principal outstanding at beginning of period k:
Ak=( )
11 1
n kr
Rr
+
+
The interest portion of the kth payment is:
Akr=R ( )1
1 1 n kr
+
+
The principal contained in the payment of the kth period is:
R-R ( )1
1 1 n kr
+
+ = ( )1
1 n k
R r +
+
Total finance charges (interest paid): nRA
****************************************************
For continuous annuities:
0
( )T
rtA f t e dt= 0
( )( )
T
r T tS f t e dt
=
With the annual rate being r(compounded continuously), for Tyears,and where the payment at time tis at a rate off(t) dollars per year.
A= Present value of the continuous annuityS= accumulated (future value) of the continuous annuity
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MAT133Y5Y April 2010 Final examinationFORMULA SHEET (2)
Derivatives:
1[ln ]'x
x= [ ] 'x xe e= 1[ ]'r rx rx =
[ ]' lnx xa a a= (for a> 0)
Some general rules for differentiation:
The Product Rule:[ ( ) ( )]' '( ) ( ) ( ) '( )f x g x f x g x f x g x= +
The Quotient Rule:
( )2
'( ) '( ) ( ) ( ) '( )
( ) ( )
f x f x g x f x g x
g x g x
=
The Chain Rule:
[ ]'( ) '( ( )) '( )f g x f g x g x=
Elasticity of Demand:
The point elasticity of demand , which is anegative
number, is given by
p
p dqq
dp q dp
dq
= =
Economics stuff some useful relations:c
cq
= ,
r pq= , P r c=
Here,cstands for cost (total),
cstands for averagecost,pstands for the demand (price per unit), qis the
number of units of a product, ris revenue, Pis profit.
Integrals:
11 lndx x dx x C
x
= = +
x xe dx e C = + ,kx
kx ee dx C
k= +
(for 0 1)ln
xx a
a dx C aa
= + <
1
(for 1)1
rr x
x dx C rr
+
= + +
Average value of a function on[a,b]:
The average (or mean) value of a functiony=f(x) over
the interval [a, b] is denoted by y (or) fand is given
by
1( )
b
a
f f x dxb a
=
Some general rules for integration:
( ) ( )cf x dx c f x dx=
[ ( ) ( )] ( ) ( )f x g x dx f x dx g x dx+ = +
[ ( ) ( )] ( ) ( )f x g x dx f x dx g x dx =
( ( )) ( ) ( )f g x g x dx f u du = when we let ( )u g x=
( ) '( ) ( ) ( ) ( ) '( )f x g x dx f x g x g x f x dx= OR udv uv v du= (Integration by parts)