marking scheme for paper 1 2010
TRANSCRIPT
-
8/8/2019 Marking Scheme for Paper 1 2010
1/7
3472/1
Matematik
Tambahan
Kertas 1
2 jamSept 2010
SEKOLAH-SEKOLAH MENENGAH ZON A KUCHING
PEPERIKSAAN PERCUBAAN
SIJIL PELAJARAN MALAYSIA 2010
MATEMATIK TAMBAHAN
Kertas 1
Dua jam
JANGAN BUKA KERTAS SOALAN INI SEHINGGA DIBERITAHU
Skema Pemarkahan ini mengandungi 7 halaman bercetak
MARKING SCHEME
-
8/8/2019 Marking Scheme for Paper 1 2010
2/7
2
MARKING SCHEME FOR PAPER 1 -2010ZON A
No Solution and marking scheme Sub Marks Total Marks
1. (a) (i) 8, 8
(ii) 4
(b) 2 2( ) or :h x x h x x=
1
1
1
3
2.(a)
1 1( )2
xf x
+=
12
yx +=
(b) 2( ) 4 2 3gf x x x= + +
( ) ( )2
(2 1) 2 1 3 2 1 5g x x x = + +
2
B1
2
B1
4
3. (a)p = 2
q = 24
(b) ( 3) 736gh =
( 3) 30h =
1
1
2
B1 4
4.2 2 8 0x x+ =
SONR = 2 2 2( ) 2( 1) + = + =
PONR = 2 2 4 4( 2) = =
SOR = 1 + = POR = 2 =
3
B2
B13
-
8/8/2019 Marking Scheme for Paper 1 2010
3/7
3
No Solution and marking scheme Sub Marks Total Marks
5.
1p =
2(2) 4(1)( ) 0
or
4 4 0
p
p
=
+ =
2
B1 2
6.
2 3p
2 3( 2)( 3) 0p p
3
B2
B1 3
7.
56
x =
3(2x) = 5 or 5 + 3(2x) = 0 or IE
3(2 ) 52 2x = or 25(23)2
x= 20
3
B2
B1
3
8.
5x =
2 2
2log log 25x = or x2 = 25
22
2
log 25log 0
log 4x =
3
B2
B1
3
9.
4
ax =
222
8
ax=
22log log 2
8a a
ax=
22
2log @ log 2 @ log8
a a a
ax x
4
B3
B2
B1
4
-
8/8/2019 Marking Scheme for Paper 1 2010
4/7
4
No Solution and marking scheme Sub Marks Total Marks
10.
(a) 2x =
(b) 255
33011 =S or 756 =S or
[ ])7)(10()5(22
11+ or [ ])7)(5()5(2
2
6+
1
2
B1
3
11.
4920
( )44
6 9 1
9 1S
=
6 or 9a r= =
3
B2
B1
3
12.
15, 5a b= =
a = 15 or b = 5
15xy x= +
3
B2
B13
13.
P ( 3, 1)
( ) ( ) ( ) ( )
+
+
+
+=
32
3322,
32
7332P
SP : PT= 3 : 2 or
3
B2
B1
3
14.k= 2
2 26 30k =
1[0(3) 3 6( 1) 5( 1) 3( 1) 6(3) 5 0( 1)] 15
2k k+ + + =
3
B2
B13
TSP
23
-
8/8/2019 Marking Scheme for Paper 1 2010
5/7
5
No Solution and marking scheme Sub Marks Total Marks
15.
(a) 3 4i j
(b)
4 3 43@
5 5 5
j i ji
2 2
3 4
(3) ( 4)
i j
+
1
2
B1
3
16.
qp4
1
4
3+
( )qpp ++4
1
1
4OM OP PQ= +
3
B2
B1
3
17.
105 , 165 , 285 , 345x =
2x=210, 330, 570, 690
30
22sin
1=
xor
2
12sin =x
4
B3
B2
B1
4
18.
.
3
rad
=
12 6( ) =
4 2
3( ) 3
=
3
B2
B1
3
-
8/8/2019 Marking Scheme for Paper 1 2010
6/7
6
No Solution and marking scheme Sub Marks Total Marks
19.
0.4y =
(12 4)(0.05)y x =
12 4 or 1.05 1 0.05dy
x xdx
= = =
3
B2
B1
3
20.
9h =
2
22
[1 2(2)]
h=
2
2
(1 2 )
dy h
dx x=
or equivalent
3
B2
B1
3
21.
4
32
2
5 15
2
kx + =
=+2
1
3
2
5)()( dxxfdxxf
3
B2
B1
3
22.
18, 21m n= =
39m n+ =
4 5 8 9 10 15 1812
9
x m nx
N
+ + + + + + + += = =
3
B2
B1
3
-
8/8/2019 Marking Scheme for Paper 1 2010
7/7
7
No Solution and marking scheme Sub Marks Total Marks
23.
(a) 22275
10 12
2 4C C
(b) 240
5!2!
2
B1
2
B1
4
24.
(a)4 3 1
9 8 6 =
(b)5
9
4 5 5 4( ) ( )9 8 9 8
+
1
2
B1
3
25.
(a) k = 0.53
1 0.7019
(b) X= 47.65
450.53
5
X=
2
B1
2
B1
4