management aptitude test 6 december

05/03/23 AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

1

MANAGEMENT APTITUDE TEST

AFTERSCHO☺OL – DEVELOPING CHANGE MAKERS

CENTRE FOR SOCIAL ENTREPRENEURSHIP PGPSE PROGRAMME –

World’ Most Comprehensive programme in social entrepreneurship & spiritual entrepreneurship

OPEN FOR ALL FREE FOR ALL


2

MANAGEMENT APTITUDE TEST

Dr. T.K. Jain.

AFTERSCHO☺OLCentre for social entrepreneurship

Bikaner M: [email protected]

www.afterschool.tk, www.afterschoool.tk

http://www.afterschool.tk/

http://www.afterschoool.tk/


3

The pth term of an AP is (3p — 1) /6. The sum of the first n terms

of the AP is

• Let us assume first term is 2/6 = 1/3• Let us assume that P is 3, thus the value

is : 8/6• Sum of first 3 terms : N/2 (frst term + 3rd

term). 3/2 (1/3 + 8/6) = 3/2 *(10/6) =5/2 answer. (compare with answers).


4

The first term of an A.P is 14 and the sums of the first five terms and

the first ten terms areequal in magnitude but opposite in

sign. The 3 term of the AP is

• Sum = n/2 (2a+ (n-1)d)• 5/2 (28 +4d) = - 5 (28 + 9d)• 70 + 4d + 200 +45 d=0• +49d = -270 or D = - 5.5 approx. • 3rd term is 14 + ( - 11) = 3 answer


5

Out of 8 persons in a group, find the number of ways of selecting 3 persons and also the number of

ways of arranging these 3 selected persons in a row.

• 8C 3 = (8! / (5! * 3!) • =56• Number of ways of arranging these

persons in a row: 3*2*1 = 6• Total number of ways : 56 *6 = 336.


6

There are 6 distinct letters of Englishalphabet and 4 distinct digits. All possible 6

character alpha — numero codes are generated using any 4 letters of the alphabet

and any 2available digits. If in any given code, the

characters are all distinct, then what is themaximum number of such codes that can be

generated?

• Here all these can be interchanged – so 6!, we select from groups so 6C4.

• 6C4 * 4C2 * 6!= 6! / (4!*2!) * 4/ (2!* 2!) *6!• = 15 * 6 * 720• =64800 answer.


7

In a cricket tournament, each participatingteam plays once against every other

and in all 36 matches are played. Find thenumber of teams that participated in the

tournament.

• N(N – 1) / 2 = 36• N (N – 1 ) = 72• N^2 –N – 72 =0 or N^2 -9N + 8N -72 =0• N (N – 9) +8(N – 9) or N = 9 or - 8• Thus N = 9. answer.


8

.The letters of the word ADROIT are permuted in all

possible ways to form 6! different words. How many words can be formed which neither begin

with T nor end in A?

• Total possibilities of permutations of ADROIT = 6! = 720. words starting with T = 5! = 120. words ending with A = 5! = 120. there are some words which have T as start and A as end, just remove them: 4! = 24. thus answer = 720 – (120+120-24)=504 answer


9

If the letters of the word ‘NUMBERS’ arepermuted in all possible ways, then in how

many of these permutations, are the vowels

never together i.e. vowels are separated?

• There are 7! digits in numbers. So we can make 7! Number of words from this.

• Let us consider all the vowels together, there are 2 vowels. Thus we have only 5 + 1 = 6! Options. Thus we can say that there are 5040 – 720 number of permutations. = 4320


10

ERROR SPOTTING


11

While (A) a strong defend (B) is important to any country it cannot

be more important than the livelihood (C) of its

(1) citizens.• Instead of defend, use defence (noun

should be used and not the verb).


12

It (A) can take hundreds (B) of different experiments to achieve

(C) a (D) ultimate solution.

• (d) use an or the instead of a.


13

Studying (A) the science of (B) logic is one way to (C) cultivate

one’s reason (D) skills.

• (d) it should be reasoning and not reason.


14

Every candidate under (A) considering (B) for a military

job must undergo (C) a thorough medical (0)

examination.

• (b) it should be consideration and not considering.


15

Drug abuse (A) become one of (B) our most (C)

serious social problems (D)

• It should be ‘ Drug abuse has become …”


16

Although (A) the advisory commission on Central America has completed its (B)

report that examines (C) the political tensions in that area, but, no easing (D) of

tensions hasresulted.

• (d) remove but. We don’t use but with although, we may use yet with although.


17

Hard work and self-discipline often result (A) in a rise (B)

not only in (C) salary but also in your self-esteem

• ( c) put your after in.• Or you may use one’s with another

replacement – instead of your – use one’s.


18

Caffeine (A) in coffee is relative (B) harmless if people drink (C) it

moderately (D)

• (b) use relatively and not relative (we should use adverb and not adjective).


19

When they have been (A) frightened (B) as for example,

by (C) an electrical storm, dairy cows may refuse giving

(D) milk.

• (d) it should be refuse to give and not refuse giving.


20

An unexpected raise (A) in the cost of living as well as (B) a decline in employment opportunities resulted (C) in the rapid implementation (0) of new Goveinment programmes

for the unemployed. • (a) use rise instead of raise.


21

It is (A) imperative that a management student maintains

(B) a grade point at (C) “B” in (D) major field.

• (c ) delete at.


22

If the ozone gases of the atmosphere did not filter out (A) the ultraviolet rays of the sun, life (B) we know (C) would not have evolved on

earth (D).

• ( a) it should be ‘had not filtered out ‘ instead of ‘did not filter out’


23

The baby was left (A) in charge (B) of (C) elderly lady

• (b) instead of ‘in charge’ use ‘in the charge’


24

More than (A) one scientists (B) have contributed (C) to the success of this venture (D)

• (b) instead of scientists use singular – scientist.


25

Smoking (A) is not allowed at petrol pumps because there is (B) too

many (C) easily ignited (D) material in the vicinity

• (c) use too much • Or • You may also correct (b) where you may

use there are .


26

Regardless of (A) your teaching method, the objective of any

conversation class should be (B) for the students practice (C)

speaking words (D)

• (c ) instead of the students practice, use ‘the students to practise’.


27

Atrophy (A) can affect a cell, organ (B) tissues (C) or(D) limb.

• Instead of tissues, use tissue, because we are using a with them.


28

The pleura that cover (A) the exterior(B)of the lungs (C) and

the inner walls of the chest cavity is (D) a thin elastic

membrane.

• (a) it should be covers.


29

Many of us bemoan (A) our lack of foresight by

complaining that if we would have (B) bought property

twenty years ago, we could have (C) taken advantage of

the recent real estate (D) boom.

• (b) with if we cannot use models, so instead of ‘we would have’ use ‘we had’


30

After the absentee (A) ballots had been counted, the total of the

authorised votes cast (B) in the election were (C) one third (D) than

what had been predicted.

• (c ) the subject is total, so we should use the was instead of were (total is singular).


31

Organised (A) labour has fight (B) for and won protectionand benefits (C) for its (D)

workers.• (b ) instead of fight, we should use fought.


32

The book is well-printed (A) and attractively bound (B) making

altogether (C) an attractive volume (D).

• ( c) it should be making it altogether


33

He is one (A) of the shrewdest men (B) that is (C) in the

(D) administration.

• (c ) it should be are and not is.


34

No sooner had he (A) come from Mumbai when (B) he was asked

(C) to proceed to (D) Delhi.

• (b) no sooner is always followed by than and not when.


35

Drug abuse (A) become one of (B) our most (C)

serious social problems (D)

• (a) it should be drug abuse has become.


36

Alexander Calder, who was originally (A) interested j (B)

mechanical engineering later (C) became a sculpture (D)

• (d) use sculptor and not sculpture (which is an art).


37

ANALYTICAL ABILITY


38

Dhawal travels 900 kms. by train at an average speed of 60

km per hour; 3,000 kms. by steamship at an average of 25 kms. per hour; 400

kms. by aeroplane at 350 kms. per hour; and finally 15 kms. by bus at 25 kms.

per hour. Calculate his average speed for the entire journey. ( marks)

• Average speed = Total Distance / total time

• =(900+3000+400+15) / (15+120+1.14+.6)• =31.55 answer.


39

Average monthly income of all the workers of a company is Rs. 6,000.

Average monthly income of male and female workers of the company is Rs. 6,200 and Rs 5,200 respectively. Find

the percentage of maleand female workers in the company.

• Solve it by alligation method..


40

Solution ..

• Thus we can see the ratio between male and female is 800 : 200 or 4:1.

• Thus male workers are 80% and female workers are 20% of total number of workers.

6200

800 200

5200

Mix

6000


41

The salaries paid to the managers of a company had a mean of Rs. 20,000 with a standard deviation of Rs. 3000. What will be the mean and standard deviation if all the salaries are increased by (i) 10%, (ii)

10% of the existing mean?

• If salaries are increased by 10%, new mean and standard deviation both will increase by 10%. If salary is increased by 2000 in each case, only mean will increase, and standard deviation will remain same. Answer.


42

Puzzle test • Tata produces car components. The company has to

ensure that it does not supply defective parts. If a buyer receives a defective part, Tata has to pay a penalty of Rs 200 per component. It produces 1000 components at a time in a batch. It wants to test the quality of these before shipping them to its buyers. It can use two tests for quality control. Test 1 costs Rs 8per component but it identifies only 80% of all defective parts. Test 2 costs Rs 12 per component but it can detect all defective parts. Tata can rework defective parts at a cost of Rs 100 per part. Let ‘x’ be number of defective parts per batch. What should be the value of X if both the tests are equal for Tata ?


43

Solution..

• Test 2 cost : 12 *1000 = 12000• Test 1 cost (it is equal to test 2). = 12000• That means cost can be divided in two parts:

1000*8 = 8000• Due to defects : 4000• Differential cost (200 – 100) = 100• Thus number of defective parts: 4000/100 = 40• These are only 20%, so number of defective

items is 40 *100/20 =200 answer.


44

Data sufficiency question…

• c and d are positive integers. Is c even?• (I) c^2- 1 is odd• (II) ( c-3) (d + 2) is odd.• Only (1) can give you correct answer.


45

Goti and Jitu are two friends. If Goti tells the truth 40% of the time

and Jitu 30% of the time, the probability that they will contradict each other when they are narrating

the same incident is

• Goti speaks the truth but Jitu lies : (.4 * .7) = .28

• Goti lies, but Jitu speaks the truth :(.6*.3) =.18• Thus they will contradict = 46% answer.


46

if arithmetic mean of 17 15, 23, x and 19 be 20 then what is the value

of x

• There are 5 values so total 5*20 = `100• Total of 17,15,23,19 = 84. • Thus x is 100 – 84 = 16 answer.


47

The average of first 30 natural numbers is

• Let us add all the 30 numbers. The total is (30 *31 )/2 = 465 or (1 + 2+ 3 + …. 30)

• Or n/2 (first term + last term)• =30/2 (1 +30) = 30/2 *31 the total is 465. • Thus average is : 465/30 = 15.5 answer.


48

What is the average of all prime numbers between 30 and 50

• Let us count all prime numbers : • 31,37,41,43,47,• Let us add them : 199• Their average is 199/5 = 39.9 approx.

answer.


49

The average of first five multiples of 3 is

• List down first 5 multiples: • 3,6,9,12,15• The mid point is 9, therefore average is 9.

answer. • Or you may add them = 45 now divide it

by 5, we get 9 as answer.


50

The number of employees, average wages per employee W of the wage per employee for two factories are given below:

Factory A Factory BNumber of Employees 100 200Average Wage per Employee (Rs.) 120 200Variance of the Wages per Employee 16 25In which factory is there-greater variation in the distribution

of wages per employee?

• Coeffecient of variance = std. dev. / mean *100

• = 4/120 *100 = 3.33%. In factory B, it is 5/200 *100 = 2.5%. Thus there is greater variance in factory A.


51

if a, b, C, d, e are five consecutive odd integers, then what is their

arithmetic mean

• List down any consecutive odd integers: • 1,3,5,7,9• Add them up, we get : 25, divide it by 5,

we get 5, which is the middle figure. Thus their average is their middle point which is C. answer.


52

‘A’ sells a car to ‘B’ at 10% profit, ‘B’ sells it to ‘C at

20% loss If the cost of A is Rs.5000, then find

Cost of ‘C’.• A sells it for Rs. 5500. B sells it at 80% or

4400. thus cost of C is 4400 answer.


53

A man sold 250 chairs and had a gain equal to S P of

50 chairs. What is his profit in %?

• Let us assume selling price of 250 chairs was 2500 (10 per piece).

• Thus gain is 10 * 50 = 500• Thus cost is 2500 – 500 = 2000. • Thus profit in % is 500/2000 *100 = 25%

answer.


54

What is the loss percent if a man loses Rs. 10 on

selling an article for Rs.100?

• Sale price = 100• Loss = 10• Cost = 100 +10 = 110• Loss in % = 10/110 *100 = 9.9% answer.


55

What is the sum of the digits of the number : 10^560 -123456789?

• In this number, we have 551 times 9 and one time all the digits from 1 to 8.

• Thus the total of all the digits is : • (551*9) + 36 +1• =4996 answer.


56

Solve it

• 100 liters of a mixture of Boric Acid and water contains 80% Boric Acid. So what amount of water should be added to the mixture to reduce the strength of Boric Acid in the mixture to 50%?


57

Solution

• Total liquid = 100 liters• Boric acid = 80 liters• We have to make it 50%, so the total liquid

should be 160 (just double of it). That means we have to add 160-100 = 60 liters of water.

• Answer.


58

Solve it • If 7 men or 8 women or 10 boys can finish a

piece of work in 24.days each of 9 hours, then find how many men with the help of 4 women and 5 boys can finish the work in 18 days each of 6 hours.

• Solution : • 4 women = 5 boys, so 10 boys. • 10*24/18*9/6* = 20 boys, we already have 10

boys, we need additional 10 boys to complete the work. 10 boys are equal to 7 men, so we need 7 more men to complete the work. Ans.


59

They ought to be here before now.

• Change before to by.


60

He is known about charity.

• Instead of about, use for.


61

The man laboured to good results.

• Change to into for• Correct : • The man laboured for good results.


62

I was on bed when he telephoned me.

• Instead of on, use in• I was in bed when he telephoned me.


63

This work of art is worthy for praise.

• Instead of worthy for praise, use praise-worthy.

• OR • This work of art is worthy of praise.


64

Which newspaper do you subscribe for?

• Instead of for, use to.


65

He scoffed on the idea of revolution.

• Instead of on, use at.


66

Where have you been to?

• There is no need of to.• Where have you been?


67

He lives at Delhi in India.

• Correct sentence:• He lives in Delhi in India.


68

The man died from fever.

• Use of instead of from.


69

Sumit rushed at my room, panting for breath.

• Instead of at, use into.


70

The poor man is beset by difficulties.

• Correct : • The poor man is beset with difficulties.


71

Bitthal is distinguished in the cartoons for his sense of

humour• Instead of in, use for.


72

He is a descendant from the Mughal royalty.

• Instead of from, use of.


73

The river flows below the bridge.

• Correct : • The river flows under the bridge.


74

The weather was not very congenial for him.

• Correct sentence: • The weather was not very congenial to

him.


75

We are expecting the reply till evening.

• Correct sentence:• We are expecting the reply by evening.


76

He has not been cured for his disease.

• Correct sentence: • He has not been cured of his disease.


77

We must not carp with the errors of our ancestors.

• Correct sentence:• We must not carp at the errors of our

ancestors.


78

Patanjali is an authority for Sanskrit grammar.

• Correct sentence:• Patanjali is an authority on Sanskrit

grammar.


79

The shopkeeper deals with cotton and cloth.

• Correct :• The shopkeeper deals in cotton and cloth.


80

SOLVE IT

• A salesman has a 35 hours per week normal schedule. During normal hours he gets Rs.40. per hour and for overtime he gets 1.5 times his normal charges. What is his income if he works for 60 hours in a week?

• SOLUTION : • 35*40 + 25*60 =1400+1500 = 2900 ANS.


81

What is the cube root of 571787?

• Options : • 47• 73, • 83• 93• Answer : • 83.


82

3A+2B / 5A-3B =12/15 what is the ratio of A to B?

• 3A + 2B = 12 5A – 3B = 15• Multiply the first equation with 5 and 2nd

equation with 3, we get : • 15A + 10 B = 60 and • 15A -9 B = 45• 19 B = 15. thus B = 15/19


83

Solution …

• 3A + 2B = 12• B =15/19• Putting this value in the first equation. • 3A + 30/19 = 12• 3A = 12 -30/19 = 228 -30 / 19• 3A = 198/19• A = 198/57• A: B = 198/57 : 15/19 = 22: 5


84

if p/q 2/3, what is the value of p+q / p-q

• P = 2• Q =3• Answer : (2+3) / (2-3)• = - 5 answer.


85

Two dice are tossed simultaneously. What is the

probability of getting the sum as a prime number?

• Prime number : 2,3,5,7,11,• Total possibilities = 6* 6 = 36• Answer = 16 out of 36 or 16/36. ans.


86

Solution…

Total of 2 12

3 4 5 6 7 8 9

10 11

1 1 2 3 4 5 6 5 4

3 2


87


88

What is the value of * in the given equation….


89

Solution

• We know that (A –B)^2 = A^2 – 2AB+ B^2• A = 16/7• B= 9/7, solutoin is 1. (16 -7 = 7,so 7/7) • Thus the above equation is just expansion

of this equation. Thus the value of * is 2AB, out of which we already have B. thus the remaining number is 2A = 32/7, we already have 7, thus answer is 32.


90

There is a circular park of 20 meters diameter. Inside the circular

park is a path1 meter wide. Find

the area of the park.

• Area of circle = pi* radius * radius• = pi * 10^2 – 9^2 { A^2 – B^2=(A+B) (A-b)}• = pi * 19*1 = 19 pi. Answer.


91

A can do a piece of work in 8 days, B can do it in 9 days and C can do it in 6 days. On the first two days A & B work together and on the third day C joins them. What is the total number of days worked, needed to

complete the work?


92

Solution • For the first 2 days – A and B are working

together… (2*1/8) + (2* 1/9) = 34/72• Now A,B,C will work together: • 1/8 +1/9 + 1/6 = 29/72• They will complete the work in 72/29 • Now multiply this by (1- 34/72) * 72/29• (because 34/72 work is already complete, the

remaining work is 38/72) • =38/72 *72/29 = 38/29. • Thus total time required is 2 +38/29 answer.


93

Surface area of a cube is 150 cm^2 . What is the length of its edge?

• Surface area of cube : • Formula = 6 * Side * side• 6 * side * side = 150 • Side * side = 25• Side = 5 answer.


94

A circular cord of 35 cm is drawn into a rhombus. what is the length

of its edge?

• Length of cord = 35 Cm• Edge = 35/4 = 8.75 answer.


95

The age of the father is 4 times the son’s age. 5 years ago it was 7 times the son’s age. What is his

age now?• Let us assume father’s age = X , son’s age

is X /4 . • (X-5) / (X/4 – 5) =7 or (X-5)/ (X – 20)/4 =7Or 4X- 20 = 7X – 140 • - 3X = -120, or X = 40 Answer.


96


97

What is the difference between a discount of 40% on Rs. 1000 and two successive discounts of 35%

and 5% on the same amount?

• =1000*.35*.05 = discount of 350+32.5• v/s discount of 400. the difference is : 17.5

answer.


98

A man sold a horse at a loss of 7%. Had he been able to sell it at a gain of 9%, it would have fetched Rs.64 more than it did. What is the cost

price of the horse?

• 64 *100/16 = 400 answer


99

Solve it ..

• On an article marked Rs.20000, a customer has a choice between three successive discounts of 20%, 2O% and l0% and three successive discounts of 40%, 5% and 5%. By choosing the better offer, determine the amount he can save.

• Solution : • 20000*.8*.8*.9 v/s 20000*.6*.95*.95 • =12000 v/s 10300. thus savings are 1700.


100

A manufacturer sells a vehicle to a dealer at a profit of

40%, the dealer sells it to a customer at a profit of 30% and the

customer sells it to a friend for Rs.7280 at a loss of 2O%. Find the

cost price of the vehicle for the manufacturer?

• 7280*100/80*100/130*100/140 = 5000. ans.


101

What profit percent is made by selling an article at a certain price, if by selling it at two-thirds of that

price, there would be a loss of 20%?

• 80 *3/2 = 120 thus there will be profit of 20%. Answer.


102

Two articles are sold at Rs.198 each such that a prof1t of 10% is made on the first while a loss of

10% is incurred on the other. What would be the net profit/loss on the

two transactions combined?


103

Solution

• Sold • Profit on first 198 *10/110 =18• Loss on 2nd = 198 * 10/90 =22• There is net loss of Rs. 4


104

.A person purchases 50 dozen toys at Rs.4 per dozen. Of these, 40

toys were found broken. At what price should he

sell the remaining toys in order to make a profit of 5%?


105

Solution

• No. toys : 50 * 12 = 600• Defective = 40 • Net = 560• Cost : 4 * 50 = 200• add profit = 5% = 10• Selling price = 210 • No. of dozens = 560/12 = 46.66 dozens• New sale price per dozen= 4.5 answwer.

DR. T.K. JAIN


106

.A fruit vendor sells apples at cost price but uses false weight

of 960 gm instead of 1 kg. Find the gain %.

• Profit = 1000 grams – 960 grams• = 40 • Cost = 960• Profit = 40/960 *100 = 4.16% answer.


107

• A engaged 40 labourers on a job. He was paid Rs.1,050 for the work. After retaining 20% of it, he distributed the remaining amount amongst the labourers. If the number of men to women labourers was as 5: 3 and their wages were as 3 : 2, then how much did a man get as wages?


108

Solution

• No . Of men = 5/ (5+3) *40 = 25• 25 men were working• Total payments to men: • 5*3 = 15, women : 3*2 = 6• Thus payment received was 15/21 *

(1050*.8) • =total payment received = 600• Payment per man – 600/25 = 24 answer.


109

arrange eight of the nine numbers 2,3,4,5, 7,10, 11,12,13 in the vacant squares of 3X4

array shown below so that the arithmetic average of the numbers in each row and

column is the same integer.What is their average?


110

Solution • Let us add these numbers: • Sum( 1,2,3,4,5, 7,9,10, 11,12,13,14,15, - X) • X = left out number• =106-X • Let us assume average = Y • The average is same, so total of columns

should be 4Y.• 3*(4Y) = 106-X• 12Y = 106 – X, by hit and trial, we know that X

should be 10. Thus Y = 8. • Thus average is 8 and left out number is 10. • Answer.


111

For how many integers N, N/(20—n) is the square of an

integer?

• (a) 0 (b) 1• (c) 2 (d) 3• (e) 4• Solution : square cannot be negative, so

20-N must be positive. Therefore N can be upto 19 only. By trial, we can see that when N = 16, this is square, there is no other option, Thus answer is B.


112

Puzzle • A truck tra veiled from town A to town B over several

days. During the first day, it covered 1/p of the total distance, where p is a natural number. During the second day, it travelled 1/q of the remaining distance, where q is a natural number. Duthig the third day, it travelled i/p of the distance remaining after the second day, and during the fourth day, l/q of the distance remaining after third day. By the end of the fourth day the truck had travelled 3/4 of the distance between A and B.

• The value of p+q is• (a) 4 0) 5• (c) 6 (d) 7• (e) 8


113

Solution • Try from options, it cannot be 5 or 6, it has to

be higher value 7 or 8. Let us try for 7.• Let us assume that the number is 144 (we

have assumed it because 4*3*4*3 = 144) • First day: 36 is used, left out is 108. 2nd day:

36 is used and left out is 72. 3rd day: 18 is used and left out is 54. 4th day 18 is used and left out is 36.

• We know that now 1/4 th is left out, so our condition is fulfilled. Thus this is the answer.

•


114

In a certain factoiy, each day the expected number of accidents is related to the number of

overtime hour by a linear equation. Suppose that on one day there were 1000 overtime

hours logged and 8 accidents reported, and on another day there were 400 overtime hours

logged and 5 accidents. What are the expected numbers of accidents when no overtime hours

are logged?• (a) 2 (b) 3• (c) 4 (d) 5


115

Solution

• Let us frame 2 equations and use them to solve this question:

• 8 = 1000X +Y• 5 = 400 X +Y• Solving these we get : 3 = 600X • X = 1/200; putting this value, we get Y. • Y = 3. • Thus when there is no overtime, the number of

accident is 3. Answer.


116

In which year did the firm pay maximum tax?


117

Solution

• Since all the figures are in %, we cannot calculate the value of taxes paid as absolute value. We are not aware of change in sales also. So answer : cannot be determined.


118

Solve it : • Seven integers A, B, C,D, E, Fand G arc to be

arranged in an increasiug order such that• i. First four numbers are in arithmetic progression.• ii. Last four numbers are in geometric progression.• iii. There exists one number between E and G.• iv. There exist no numbers between A and B.• v. D is the smallest number and E is the greatest.• Vi. A / D = G /C = F / A >1• vii. E= 960• What is E / A?


119

SOLUTION

• F is more than A and A is more than D and G is more than C.

• D is smallest :D - - - - - - E (G will come one less than E, A and B are close. C has to be near D.

• D C B A G F E• The last four are in GP. • Thus E = A *r^3 (because it is GP) and A

= D +3(common difference)


120

Continued…• E = 960• Let us find factors of 960• 2*2*2*2*2*2*3*5• Thus A must be 15 and ratio must be 4• The numbers will be : 15,60,240,960.• Or A may be 120 and ratio may be 2, the numbers

will be 120,240,480 and 960• Thus F/A = 240/15 = 16 or 480/120 = 2.• The 2nd option is better. Thus A/D = 2 and D = 60• We can write that A = D + (3*common difference)• =120=60 +(3*common difference).


121

Continued…

• 120=60 +(3*common difference).• Common difference is 20• Thus the numbers are :• 60,80,100,120,240,480,960• Thus we can find answer to the question:

E/A• =960/120 = 8 answer.


122

Goti and Nitin could do a piece of work in 12 days. Nitin and Kap

togetherdo lt In 15 days. If Goti is twice as

good a workman as Kap, findin how many days Goti alone will

do it?


123

Solution

• G = 2K (now add the two equations) • 2K+N+N+K = 1/12+1/15 = 27/180, • K+N = 1/15 or 2 (K+N) = 2/15• 3K +2N = 3/20• K = 3/20 – 2/15 = 1/60• Thus Kap can do it in 60 days. • Goti being twice fast, can do it in 30 days

alone. Answer.


124

Goti car paint a fence 100 metres long in 6 days,

then how much time will both Goti and his friend Kap

take, if Kap is thrice as efficient as Goti?

• Goti’s one day work = 1/6, Kap=3*1/6• 1/6 + 3/6 = 4/6• Thus they will take 6/4 = 1.5 days to

complete the work.


125

Two pipes A and B can fill a cistern in 10 and 15 minutes

respectively. Both pipes are opened together but at the end of 3

minutes, ‘B’ is turned off. How much time will the cistern take to

fill?

• 3/10 +3/15 = 75/150 thus the remaining pipe A will take 5 minutes to fill up the tank. Total time: 2+5 = 7 minutes. Ans.


126

Explanation

• 75/150 = is half of the total pip3 thus the pipe is helf illed. Thus A can fill the remaining portion in 5 minutes (it takes 10 minutes to fill completely).


127

A is twice as good a workman as B; and together they finish

a work in 14 days. In how many days can it be done by each

separately?

• Let us assume that A takes X and B takes 2X days. 1/2x + 1/x = 1/14

• Let us assume 1/x = Y• Y/2 + Y = 1/14• 3/2Y = 1/14 or Y = 2/42 or 1/21• Thus A can do it in 21 days and B in 42 days.

Answer.


128

If 20 men complete one-third of a piece of work in 20 days, how many more men should be employed to

finish the rest of the work in 25 days?

• Total work left = 2*20 = 40 days. • Total mandays required = 40*20 = 800• Thus no. of persons required = 800/25=32• Additional persons required = 32-20=12

persons. Answer.


129

Goti can copy 75 pages in 25 hours Goti and Kap together can copy

135 pages in 27 hours In what time can Kap copy 42 pages?

• Goti copies 3 pages in one hour. Thus he copies 27*3 = 81 pages. Kap copies (135-81) = 54 pages in 27 hours, or 2 pages in one hour. Thus 42/2 = 21 hours will be taken by Kap Sa. Answer.


130

goti & Kap can do a piece of work in 4.8 days, Kap and

Jitu together can do it in 8 days and the three together in 4

days. How long would Goti & Jitu together take to do it’


131

Solution • (calculate for 1 day and add them to get the

ans.) • G+K +K +J= 1 / (4.8) + 1/8• GKKJ = 12.8 / 38.4• GKJ = ¼• K = 12.8 / 38.4 - ¼• = (12.8 – 9.6) / 38.4• = 3.2 / 38.4 = 1/12• Thus G+J = ¼ - 1/12 = 2/12 = 1/6 • G + J will do it in 6 days. Answer.


132

A person works twice as fast as a woman. A woman works twice as fast as a child. If 16 persons can complete a job in 12 days, then

how many days would be required for 32 women and 64 children

together to complete the same job?

• 32 women = 16 men• 64 children = 16 men.• Thus they will together do it in 6 days.

Ans.


133

3 pipes A, B and C can fill a cistern in 15, 20 and 30 min. respectively.

They were all turned on at the same time. After 5 minutes the first two pipes were turned off. In what

time will the cistern be filled?


134

Solution

• 5/15 + 5/20 5/30• = (20+15+10) / 60 = 45/60 or ¾• Thus remaining ¼ of the cistern can be

filled by C in 7.5 minutes only. • Thus total time taken is 5 + 7.5 =12.5

minutes


135

A certain number of men can finish a piece of work in 100

days. If, however, there are 10 men less, it would take 10

days more for the work to finish. How many men were there?

• Let the number of men = X • Total work = 100X • (X-10) 110 = 100X or 110X -1100 = 100X• 10X = 1100 or X = 110.


136

A, B and C can do a piece of work in 20, 20 and 40 days

respectively. They began the work together but C left 2

days before the completion of work. In how many days would

the work have been completed?


137

Solution

• For 2 days only A and B worked• 2/20 + 2/20 = 4/20 or 1/5• Together (all three) : • 1/20+1/20+1/40 = (2+2+1) / 40 = 1/8• Thus they take 8 days to complete the

work, but they completed only 4/5 work together, so 8*4/5 = 6.4 days were taken by them. Thus total days : 8.4 days. Answer.


138

ERROR SPOTTING Industrial accidents/(1)usually result into /(2) ignorance/(3)or carelessness/(4) No Error (5)

• The correct sentence should be : • Industrial accidents are caused by

ignorance or carelessness. • So answer is (2)


139

Some people are like (1)to do a lot of social work/(2)even though they

are poor(3)and lack resources

• Correct sentence should be : • Some people want / are likely to do a lot of

social work, even though they are poor and lack resources.

• So answer is (1) .


140

ERROR SPOTTING Some men (1)have conveniently

believe (2)that women are inferior to(3) men in respect of abilities.(4)

No Error (5)

• (2) = it should be : have conveniently believed.


141

ERROR SPOTTING His qualities include(1)the ability to

take/(2)right and/(3)quickly decisions.(4)/ No Error(5)

• ANSWER : (4) • It should be quick decisions.


142

ERROR SPOTTING If you want to (1)ensure prompt

service (2)please be contacted to us (3) at your earlier convenience.

(4) No Error (5)• Answer : (3) please contact us OR please

be in contact with us


143

They founded (1)this institution for/(2)the welfare of the poor (3)

and the disable people.(4) No Error (5)

• Answer (4) it should be : • For the disable (there is no need to put

people with disable).


144

He asked me/U) what had my total investrnents(2)during the (3) last

five years.(4) No Error. (5)

• Answer : (2) it should be : • What had my total investments been


145

He takes the(1) prescribed medicine regularly(2) and that is how(3) he has succeed to control

his ailment.(4) No Error (5)• Answer : (3) • It should be : this is how


146

We should take(1) regular exercises to keep ourself (2) fit and

active.(3) No Error (4)

• (2) it should be : regular exercises to keep • (there is no need of ourself).


147

Each time (1) you reached this spot (2) go back and(3) start your next (4) round again.(4) No Error (5)

• (2) it should be – you reach this spot.


148

SENTENCE IMPROVEMENT

• The honourable court had taken a leniency view because the accused had no previous criminal record.

• (1) had viewed leniency (2) had taken a leniency viewing

• (3) had taken a lenient view(4) Noae of these• (5) No correction required• Solution:• (3)


149

Sentence improvement

• Maintaining global peace is our self-made commitment to the word.

• (1) self-making commitment• (2) self-made committee• (3) made of self-connnitment• (4) None of these• (5) No correction required• Solution (5)


150

The dinner party hosted by the President at the club was shifted to

an undisclosed location.• (1) a locality undisciosing• (2) a undisc location• (3) an undisc location• (4) None of these• (5) No correction required• Solution • (5)


151

Sentence improvement

• The government should launch such projects which should reversible the destructive cycle of flood and drought.

• (1) should have reversible (2) should be reverse (3) should have been reverse

• (4) None of these• (5) No correction required• Solution : • (4) correct answer: should reverse


152

A comnilttee comprising eminent experts from various fields were

setting up.(1) was setup

(2) was setting up (3) were being set up

(4) None of these(5) No correction required

• Solution : (1)


153

Our foreign exchange reserves have been increased substantial.

(1) have been increased substantially

(2) have increased substantially(3) have substantially increasing


• Solution : (2)


154

The key to a competitive economy is its investment regime.

• (1) competition economy is• (2) competing economist lays• (3) economy competition was• (4) None of these• (5) No correction required• Solution• (5)


155

Driving a car in jammed traffic require extraordinary patience -

especially when other drivers are not disciplined.

(1) required extraordinary patient(2) requires extraordinary patience(3) requiring extraordinary patience


• Solution (2)


156

Chinese army possesses highly sophisticated simulotors on which

their soldiers are training.

• (1) which their soldiers training on• (2) on which their soldiers have trains• (3) which their soldiers do train• (4) None of these• (5) No correction required• Solution : last part : soldiers are getting training.

(so answer is (4))


157

Every novel activity will be likely to face resistance from vested

interests.

• (1) is likely to face• (2) would be like facing• (3) No correction required• (4) will be likely facing• (5) None of these• Solution : (1)


158

We observed that traders were not primarily dedicated with art of

selling.

• (1) dedicated to the art of(2) None• (3) dedicated in the art by• (4) dedicated by the art of• (5) No correction required• Solution (1) preposition error .


159


160


161


162

If expenses per participant during the meeting is Rs.200 in 1995, which keeps on increasing at the rate of 10% per year, then what are the total expenses (in Rs.thousand) in 1996. The graph below shows the number of participants coming from different regions?


163

Solution

• 200*1.1*360 = 79200 answer.


164

The following graph shows profits of 5 companies. What was the

average profit in 1979?


165

Solution :

• A =130• B = 40• C = 110• D = 60• E = 90 • Let us add them and divide by 5: • =430/5 = 86 answer.


166

Solve it

• A cube with edges equal to 8cm is painted on all the six faces and is subsequently cut into 64 identical cubes. The number ct smaller cubes painted on atleast two faces is

• (1) 24 (2) 16• (3) 36• (4) 32


167

Solution

• There are four on the top right side. There are 4 on the opposite side also (4*4*4 = 64).

• Thus we have 4+4+2+2 cubes in front, same 12 in the back side also. We have 8 in sides also. Thus we have 32 cubes.

• Ans.


168

Solve it • The perimeter of a regular hexagon is 36cm.

The area of the hexagon is• (1) 54*sqrt(3) sq cm (2) 108*3 sq cm• (3) 27*3 sq cm (4) 18*3 sq cm• Solution: • One side of hexagon = 6• One triagle = ((sqrt(3)/4 * side )^2 =1.7/4* 36 • Hexagon = 6* equilateral triangle =

6*sqrt(3)/4*36• =54* sqrt(3) ans


169

Solve it …

• How many patient does the doctor examine in a day, if he treats 5 patients in 3 hours with breaks of 10 minutes between two consecutive patients and works for 10 hours per day?

• (1) 16 (2) 15• (3) 12 (4) 20


170

Solution

• 3 hours = 180 minutes• Break = 4*10 = 40• Time per patient = 140 / 5 = 28 minutes• Total time : 10 hours *60 = 600 minutes• 600 – 28 = 572• Now dividing 572 / (28+10) = 15• Thus the doctor checks 15+1 = 16

patients.


171

If the interior angle of a regular polygon is twice its exterior angle

then the polygon is a(1) rhombus (2) pentagon(3) hexagon (4) heptagon

Interior angle = 2X and exterior angle = X3X = 180 or X = 60Thus one exterior angle is 60Thus 360/60 = 6Thus the shape is hexagon. Answer.


172

DATA SUFFICIENCY QUESTION.40 pens were distributed equally

amon all the participants, then how many participants were there?

(A) The number of participants was a prime number greater than 10.(B) The leftover pen was kept by

the Chairman.


173

Solution

• If we combine both the statements, we can get the answer. One pen was left (given to the chairman), so 39 pen were distributed.

• 39 = 3*13• Thus the number of participants must be

either 3 or 13. since it had to be above 10, therefore the answer is 13. (so answer can be drawn with the help of both the students together). Ans.


174

WHAT IS THE VALUE OF X


175

WHAT IS THE VALUE OF X


176

Data sufficiency question.

• Is the series a GP?• (A) If the third term is twice the second.• (B) The fourth term is eight times the first.• Solution • Let us start from 1• 1,2,4,8 = yes it is GP • Thus the answer can be drawn with the

help of both the statements. Ans.


177

The number of common terms in the two-seç 17, 21,

25,.. ., 417 and 16, 21, 26,. . ., 466

• Let us start from 21. In the first term the gap is of 4 and in second series the gap is of 5. their LCM is 20 so we have to find the gaps of 20 each.

• Last term is 417. let us deduct 21 from 417, we get 396. now let us divide it by 20. We get : 19. Thus we have 19+1 = 20 common terms. Answer.


178

Solution continued. .. .

• The final series is : • 21,41,61,81,101,121,141,161,181,201,221

,241,261,281,301,321,341,361,381,401,


179

What is the total production of machine no. 3?


180

Solution

• Production accepted : 100 – 27 = 73%. • Thus total production • 100/73 * 438 = 600 units answer.


181

• The integers 1, 2,..., 40 are written on a blackboard. The following operation is then repeated 39 times: In each repetition, any two numbers, say a and b, currently on the blackboard are erased and a new number a + b —1 is written. What will be the number left on the board at the end?

• Options: (1) 820 (2) 821 (3) 781(4) 819 (5) 780


182

Solution ….

• In the first round, we add up 1 and 2 and get 2. now we take up 2 and 3, we get 4, now we take up 4 and 4 and get 7. now we take up 7 and 5 and get 11. Now we take up 11 and 6 and get 16. We can find that we have an increasing series :

• 2,4,7,11,16 …. … • Let us add 1 to 39. =39*40/2 = 780• Let us add 780 + 1= 781 answer.


183

What is the total sale (in no. of units) in the year 1991?


184

• = 82016 answer.


185

What is the % increase in the sale of VCR in 1993 against 1992?

• Sale in 1993 =6151• Sale in 1992 = 3006• Difference = 3145• Increase in % = 3145/3006 *100 • = 105% answer.


186

This graph shows price of 4 shares, what is the average price of these 4

shares?


187

Solution

• Let us add them: • (150+40+120+90)/4 = 100 answer


188

what is the production of food grains in 1991, expressed as a percentageof its production in 1989?


189

Solution

• 15/20 *100 = 75 % answer.


190

Which is the most logical idea?

• If an ant were as big as a horse, could it move mountains?

• No. A giant ant . . . . . (select from a,b,c,d)• (a) Would be a structural failure.• (b) Would never be able to move

mountains.• (c) Would be a mere curiosity.• (d) Would never be able to hunt for food.


191

Solution

• A giant Ant would not be able to move mountains because it is just a curoisity (we are not sure about what could it do). Other options are not logical – as logically we cannot say that it is structural failure or it cannot hunt for food or it cannot move mountains.


192

Puzzle test…• Nine cricket fans are watching a match in a

stadium. Seated in one row, they are J, K, L, M, N, 0, P, Q and R. L is at the right of M and at third place at the right of N. K is at one end of the row. Q is immediately next to 0 and P. 0 is at the third place at the left of K. J is right next to left of 0.

• Who is sitting in the centre of the row?• (a)L (b)O• (c)J (d)Q


193

Solution …

• NRMLJOPQK• J IS IN THE CENTRE


194

A and B start walking in opposite directions. A covers 3 km and B

covers 4 km. Then A turns right and walks 4 km while B turns left and walks 3 km. How far is each from

the starting point?• A is 3 KM in one direction and 4 KM in

right. Applying pythogorus, we find that A is 5 KM from the starting point. Similarly B is also 5 KM from the starting point. Ans.


195

Ram walks 10 m south from his house, turns left and walks

25 m, again turns left and walks 40 m, then turns right and. walks 5 m

to reach to school. In which direction the schoolis from his house?

• Draw a map and get the answer = north-east.


196

In a class of 35 students Kiran is placed 7th from the bottom

whereas Sohan is placed 9th from the top. Mohan is placed exactly in between the two. What is Kiran’s

position from Mohan?

• 10th

• From 9th to the top and 7th to the bottom, we have 21 candidates (35-(6+8) ). Mohan is just in the centre. So from Mohan, Kiran is at 10th place. Answer.


197

A watch reads 4 If the minute hand points towards the East, in which

direction does the hour hand point?

• The hour hand is towards South West.


198

Puzzle

• Goti and I started walking towards each other from two places lOO m apart. After walking 30m, Goti turns left and goes lO m, then he turns right and goes 20m then turns right again and comes back to the road and starts walking. If we walk with the same speed, what is the distance between us at this point of time


199

Solution

• (Goti walks 70 meters in all), so I walk 70 meters towards Goti’s starting point and now I am 30 meters from that. Goti takes only 30+20 meters on the road. Thus Goti is 50 meters from my starting point. Thus there is a gap of 20 meters between me and Goti. Answer.


200

Sum of 1st to 30th terms of a series in arithmetic

progèssion is 150. if the first term is A, what is 30th term of the series?

• Sum = 30/2 (2a + (29)D) = 150• 2a + 29d =150*2/30 = or 29 D = 10 – 2A • 30th term = A + 29D• 29 D = 10 – 2A, putting the value, we get the answer

= 10 – A answer


201

Question on number system

• Convert 252 into binary system • 252 / 2 = 126 / 2 = 63/2 = 31/2 = 15/2 =

7/2 = 3/2 =1 (starting from last remainder to the first)

• 11111100 answer. • Convert it again to decimal system: • 1*2^7+1*2^6+1*2^5+1*2^4+1*2^3+1*2^2+

0*2^1+0*2^0 = 128+64+32+16+8+4 = 252


202

Multiply 12 to 13 ( note - both are octal numbers, your outcomes must

also be in octal numbers)?

• Let us first convert them into decimal numbers: 12= 1*8^1 + 2*8^0 =10

• 13 = 1*8^1 + 3*8^0 =11• Now multiply 10 to 11 = 110• Now convert it into octal number: • 110/8 = 13 / 8 • =156 • Test = now convert 156 to decimal number


203

Convert 156 (octal) to decimal number …..

• 1*8^2 + 5*8^1 + 6*8^0• =64+40+6• =110 answer.


204

Multiply 5 (base 16) to 12 (base 7) and get the outcome in binary?

• (5*16^0 ) * (1*7^1 +2*7^0) • 5 *9 = 45• 45/2 = 22/2 = 11/2 = 5/2 =2/2 1• =101101 answer.


205

78.8% of a common medicine for stomach-upsets is absolute alcohol;

3.3% of it is mentha oil; 0.07% spear mint oil; and 0.177%

chloroform. How much of each of these compounds is there in a pack

of 30 ml?solution

alchol = 23.6 ml, 1 ml of menthol oil and so. On.


206

What is the sum of cubes of the first 5 natural numbers?

• Formula • = [N (N+1)/2 ]^2• = [5*6 / 2 ]^2• =225 answer.


207

What is the sum of squares of the first 13 natural numbers?

• Formula• =[n(n+1)(2n+1) ] /6• =(13*14*27)/6• =819 answer.


208

In a Class of 80 pupils, the number of boys is three-fifths the number of girls. Determine the number of girls

in the class.

• Let the number of girls be X• X + 3/5X = 80• 8/5 X = 80• X = 80 *5/8• X = 50 (the number of girls is 50, boys are

30) answer.


209

The difference between two numbers is 30. On dividing the

greater by the smller the quotient is 3. Find the numbers.

• Let the smaller number be X. • 3X – X = 30• 2X =30; X = 15, • Thus 2 numbers are 15 and 45 answer.


210

Gunpowder contains 75% nitre and 10% sulphur. The rest of it is

charcoal. What is the amount of charcoal in 9 kg of gunpowder.

• Charcoal is (100 – 75 – 10) = 15% • 9 KG = 9000 Grams • 9000*15/100• =1350 grams answer.


211

Question on profit

• At what percentage alove the Cost price must an article be marked so as to gain 33% after allowing the customer a discount of 5%?

• (a) 48% (b) 43%• (c) 40% (d) 38%• (e) None of the above


212

Solution …

• Let the cost be 100• Final price being realised 133• It is after discount, so price before

discount (marked price) is : • 133*100/95 =140 , so 40 is the answer.


213

A vertical pole PO is standing at the centre 0 of a square ABCD. If AC

subtends an angle 90° at point P of the pole then the angle subtended

by a side of the squareat Pis

(a) 35° (b) 45°(c) 30° (d) 60°

(e) None of the above


214

Solution

• When diagonal (in a square) makes angle of 90 degree in a pyrimidical shape, then sides make angles of 60 degree. (rule).

• So answer is 60 degrees.


215

Find the per cent of pure gold in 22 carat gold, if 24 carat gold is cent

per cent pure gold.

• 22/24 *100• =91.67 % answer.


216

In the diagram the two circles pass through each other’s centre. If the radius of each circle is 2, what is

the perimeter of the region marked B?


217

Solution

• Permieter of one circle is 2/3 now because, it is being cut by other circle.

• Thus 2/3 + 2/3 of perimeters added : • 2 * 2/3 * (formula of perimeter = 2pi *r)• =(8 * pi * r) /3 answer.


218

What is angle C?


219

Solution

• Angle O is double the angle A. Thus it is 100 degree. Thus C is (180 -100)/2 = 40 degrees answer.


220

What is angle a?


221

Solution • Angles from D and C are equal . • 180 – 60 – 37 – x• =83 – x• Let us sum up for two angles: • (180+180 ) = 360• 83-x + 83 – x + 180+2X = 360• 2Y +2X = 180 let us assume Y = 53 • 2X = 72 or X = 36 answer (solve by options,

so angle A = 53 ) answer.


222

ABOUT AFTERSCHO☺OL

Afterschoool conducts three year integrated PGPSE (after class 12th along with IAS / CA / CS) and 18 month PGPSE (Post Graduate Programme in Social Entrepreneurship) along with preparation for CS / CFP / CFA /CMA / FRM. This course is also available online also. It also conducts workshops on social entrepreneurship in schools and colleges all over India – start social entrepreneurship club in your institution today with the help from afterschoool and help us in developing society.


223

Why such a programme?

• To promote people to take up entrepreneurship and help develop the society

• To enable people to take up franchising and other such options to start a business / social development project

• To enable people to take up social development as their mission

• To enable people to promote spirituality and positive thinking in the world


224

Who are our supporters?

• Afterschoolians, our past beneficiaries, entrepreneurs and social entrepreneurs are supporting us.

• You can also support us – not necessarily by money – but by being promotor of our concept and our ideas.


225

About AFTERSCHO☺OL PGPSE – the best programme for developing great

entrepreneurs• Most flexible, adaptive but rigorous programme• Available in distance learning mode• Case study focused- latest cases • Industry oriented practical curriculum• Designed to make you entrepreneurs – not just

an employee• Option to take up part time job – so earn while

you learn • The only absolutely free course on internet


226

Workshops from AFTERSCHO☺OL

• IIF, Delhi• CIPS, Jaipur• ICSI Hyderabad Branch• Gyan Vihar, Jaipur• Apex Institute of Management, Jaipur• Aravali Institute of Management, Jodhpur• Xavier Institute of Management, Bhubaneshwar • Pacific Institute, Udaipur• Engineering College, Hyderabad


227

Flexible Specialisations:• Spiritualising business and society• Rural development and transformation• HRD and Education, Social Development• NGO and voluntary work• Investment analysis,microfinance and inclusion • Retail sector, BPO, KPO• Accounting & Information system (with CA / CS /CMA)• Hospital management and Health care• Hospitality sector and culture and heritage• Other sectors of high growth, high technology and social

relevance


228

Salient features:• The only programme of its kind (in the whole world)• No publicity and low profile course• For those who want to achieve success in life – not just a

degree• Flexible – you may stay for a month and continue the rest of

the education by distance mode. / you may attend weekend classes

• Scholarships for those from poor economic background• Latest and constantly changing curriculum – keeping pace

with the time• Placement for those who are interested• Admissions open throughout the year • Latest and most advanced technologies, books and study

material


229

Components • Pedagogy curriculum and approach based on IIM Ahmedabad and ISB

Hyderabad (the founder is alumnus from IIMA & ISB Hyderabad)• Meditation, spiritualisation, and self development • EsGotitial softwares for business• Business plan, Research projects• Participation in conferences / seminars• Workshops on leadership, team building etc. • Written submissions of research projects/articles / papers• Interview of entrepreneurs, writing biographies of entrepreneurs• Editing of journals / newsletters• Consultancy / research projects • Assignments, communication skill workshops• Participation in conferences and seminars• Group discussions, mock interviews, self development diaryng • Mind Power Training & writing workshop (by Dr. T.K.Jain)


230

Pedagogy • Case analysis,• Articles from Harvard Business Review • Quiz, seminars, workshops, games, • Visits to entrepreneurs and industrial visits• PreGotitations, Latest audio-visuals• Group discussions and group projects• Periodic self assessment• Mentoring and counselling• Study exchange programme (with institutions out of

India)• Rural development / Social welfare projects


231

Branches

• AFTERSCHO☺OL will shortly open its branches in important cities in India including Delhi, Kota, Mumbai, Gurgaon and other important cities. Afterschooolians will be responsible for managing and developing these branches – and for promoting social entrepreneurs.


232

Case Studies

• We want to write case studies on social entrepreneurs, first generation entrepreneurs, ethical entrepreneurs. Please help us in this process. Help us to be in touch with entrepreneurs, so that we may develop entrepreneurs.


233

Basic values at AFTERSCHO☺OL

• Share to learn more• Interact to develop yourself• Fear is your worst enemy• Make mistakes to learn • Study & discuss in a group• Criticism is the healthy route to mutual support

and help • Ask fundamental questions : why, when, how &

where?• Embrace change – and compete with yourself

only


234

www.afterschoool.tk social entrepreneurship for better

society

http://www.afterschoool.tk/