mais chak
TRANSCRIPT
-
7/28/2019 Mais Chak
1/27
Numerical simulation of electrostaticspray painting
Matthias Maischak
I AMf Institute for Applied Mathematics
Hannover University, Germany
BMBF-Projekt 03STM1HV
3D Adaptive Multilevel FEM-BEM Kopplung fur ein ElektrostatischesTeilproblem der Nasslackierung mit Aussenraumaufladung
Head: Prof. Stephan (Hannover)
Partners: Prof. Peukert, Dr. Schmid, Hr. Horn (Erlangen)
Hr. Sonnenschein, Hr. Poppner (DaimlerChrysler)
-
7/28/2019 Mais Chak
2/27
Overview
Physical/Engineering problem Model problem
Variational Formulation Method of Characteristics Least-Squares formulation Numerical examples
I AMf Overview 2
-
7/28/2019 Mais Chak
3/27
Electrostatic spray painting
I AMf Electrostatic spray painting 3
-
7/28/2019 Mais Chak
4/27
Target
Electrode
Outer boundary
T
E
A
u
uA
0
1
I AMf Model configuration (3D) 4
-
7/28/2019 Mais Chak
5/27
Electric corona discharge configuration
Applied Voltage between Target and Electrode(s) Electrical field (Poisson equation)
Ion transport (Convection), Space charge density Fluid (Moving Air, CFD) vAir
Particle tracking, Particle charge P
Corona discharge
Corona discharge: Locally high electric field strength leads to
ionization of air, ions are transported along field lines. Cloud of
space charge near electrode has influence on local field strength.
I AMf Electric corona discharge configuration 5
-
7/28/2019 Mais Chak
6/27
Distribution of scalar potential u
0u = + PElectric field
E = uDensity of ionic current
jIon = bE+ vAir
Charge conservation law
t+ div(jIon) = S
Source term S due to to charge transfer between and P.
0: 8.8542 1012
Electron mobility: 2 104 m2
V s
I AMf Electric corona discharge configuration 6
-
7/28/2019 Mais Chak
7/27
Electrostatic Model problem
Poisson equation
u = 0
in (1)
Electrical fieldE = u (2)
Boundary conditions (applied voltage)
u = u0 on T (Target) (3)
u = u1 on E (Electrode) (4)
I AMf Electrostatic Model problem 7
-
7/28/2019 Mais Chak
8/27
Artifical boundary conditions on
u
n| =
0 (Outflow b.c.)
Su (infinite domain)(5)
oru| = 0 (Faraday) (6)
Using the Poincare-Steklov operator
S := 12 (W + (I K
)V1
(I K)) we can describe a charge freeexterior domain as a boundary condition for the interior domain.
The symmetric fem-bem coupling formulation approximates the
Poincare-Steklov operator by the Schur-complement of Galerkin
matrices.
I AMf Artifical boundary conditions on 8
-
7/28/2019 Mais Chak
9/27
Linear transport equation Neglecting the air flow and the
particle charge we can describe the unipolar ion transport by the
linear transport equation
div(E) =0 in (7)
=A on E (Inflow-b.c.) (8)
Non-linear transport equation Inserting the Poisson equation
in the linear transport equation we eliminate div E and we obtain
E + 2
0=0 in (9)
=A on E (Inflow-b.c.) (10)
I AMf Transport equation 9
-
7/28/2019 Mais Chak
10/27
Kaptzovs assumption
Let Eonset be the field strength where corona emission starts. With
Kaptzovs assumption we obtain on E the boundary condition:
A 0, E n Eonset (11)A(E n + Eonset) = 0 (12)
Peek-field strength Eonset (argument r in cm, result in V/m)
Eonset =3.1 106(1 + 0.308r
) (Cylinder) (13)
Eonset =3.1 106(1 + 0.308r/2
) (Spherical) (14)
I AMf Kaptzovs assumption 10
-
7/28/2019 Mais Chak
11/27
Solve initial Laplace equation
?Adjust A on E
?Solve coupled differential equations
?
6
Solve non-linear transport equation
?
-
-
Method of Characteristics or
Non-linear Least-Squares
?Solve Newton-steps
6
Solve Poisson equation
6
I AMf Flowchart of electro static subproblem 11
-
7/28/2019 Mais Chak
12/27
Poisson equation
Find u H1D := {v H1() : u|T = u0, u|E = u1}, such that:
(u, v)0 = 10
(, v)0 v H1D,0 (15)
Solver: diagonal preconditioned Conjugate Gradient
Overlaping domain decomposition as preconditioner for CG
Mixed formulation
Find (p, u) H(div; ) L2() such that(q, p)0 + (u, div q)0 = u0, q nT + u1, q nE q H(div; )
(v, divp)0 = 1
0 (, v)0 v L2() (16)
Solver: unpreconditioned GMRES
Overlapping domain decomposition as preconditioner for GMRES
I AMf Poisson equation 12
-
7/28/2019 Mais Chak
13/27
Symmetric FEM-BEM-coupling
Find (u, ) H1D() H1/2(), such that:
u = 0
in
=u
non
2 = W u + (I K) on
0 = (I K)u + V on Variational formulation:
Find (u, ) H1D() H1/2(), such that:
2(u, v)0 + W u ,v + (K I), v = 2
0v dx v H1D,0()
(K I)u, V , = 0 H1/2()
I AMf Symmetric FEM-BEM-coupling 13
-
7/28/2019 Mais Chak
14/27
V (x) := 12
1|x y|(y) dsy single layer potential
K(x) :=1
2
ny
1
|x
y
|
(y) dsy double layer potential
K(x) :=1
2
nx
1
|x y|(y) dsy adjoint double layer potential
W (x) :=
1
2
nx
ny
1
|x y|(y) dsy hypersingular operator
I AMf Symmetric FEM-BEM-coupling 14
-
7/28/2019 Mais Chak
15/27
Smoothing of electrical field
Let E = uhClement-Interpolation: Let x be a node of the mesh Th.Then we define
U(x) =
TTh,xT
T
i.e. U(x) is the union of all elements connected to the node x.
Then the value of Eh in the node x is given by
Eh(x) :=
U(x)
E(x) dyU(x)
1 dy
L2
-Projection: The L2
-Projection Eh of E is given by:Find Eh VEh := {Eh [H1()]3 : Eh|T ist linear , T Th}, suchthat:
(Eh, vh)L2() = (E, vh)L2()
vh
VE
h
. (17)
I AMf Smoothing of electrical field 15
-
7/28/2019 Mais Chak
16/27
Method of Characteristics
We compute (x) along a field line, i.e., along a characteristic line.
We write (s) = (x(s)). x(s) is determined by b E(x(s)) = dx(s)dsand x(0) = x0. Then there holds
0 = bE + b 2
0= (s) + b
2(s)
0(18)
For 0 = (x(0)) the solution reads
1
=
1
0+
bs
0(19)
resp.
(s) = 0 00 + b0s(20)
I AMf Method of Characteristics 16
-
7/28/2019 Mais Chak
17/27
The remaining problem is the determination
of the characteristic field line:
Find x(s), such that bE(x(s)) = dx(s)ds , i.e.
x(s) = x(0) + s
0
bE(x(t)) dt
On the finite element mesh follow the direction
of the electrical field. Efficient computation of
boundary crossing points is essential.
Computated values of space charge density are
averaged on each element. Resulting average
density is smoothed using Clement interpola-tion.
I AMf Method of Characteristics 17
-
7/28/2019 Mais Chak
18/27
Least-Squares Formulation
Find the minimum of the non-linear least squares functional
J(; f, D, N) =E + 2
0 S2L2( (21)
for functions VA withVA = {v H1() : v = A on E} (22)
The first and second Frechet-derivative of (21) read:
J(; ) =2
(E + 2
0 S)(E + 2
0) dx
J(; , ) =2
(E + 20
)(E + 20
) dx
+ 2
(E + 2
0 S) 2
0dx
I AMf Least-Squares Formulation 18
-
7/28/2019 Mais Chak
19/27
The Newton algorithm applied to (21) reads:
Find k+1 VA , such that
0 = J(k; ) + J(k; , k+1 k) V0 (23)
I AMf Least-Squares Formulation 19
-
7/28/2019 Mais Chak
20/27
Numerical Examples
Mesh Elements Nodes
Single electrode (tetrahedral,Horn) 347193 68647
Single electrode (tetrahedral,Sonnenschein) 1650233 281829
Six electrodes (tetrahedral,Sonnenschein) 3030803 545429
Using single electrode mesh created by Erlangen-group (Horn)
Applied Voltage: 26300 V
Electrode radius: 0.0075 cm
Distance Electrode-Target: 0.32 m
Measured Ion flow density (central target): 1.4mA/m2
Computed Eonset: 1.4 107 Vm (Cylinder),1.86 107 Vm (Spherical)
Charge injection law: |A = 0 max(0, (E n Eonset)/(Emax Eonset))I AMf Numerical Examples 20
-
7/28/2019 Mais Chak
21/27
I AMf Numerical Examples 21
-
7/28/2019 Mais Chak
22/27
-
7/28/2019 Mais Chak
23/27
0.1000E11
0.4663E11
0.2175E10
0.1014E09
0.4729E09
0.2205E08
0.1028E07
0.4795E07
0.2236E06
0.1043E05
0.4862E05
0.2267E04
0.1057E03
0.4931E03
0.2299E02
0.1072E01
0.5000E01
0.1000E11
0.4663E11
0.2175E10
0.1014E09
0.4729E09
0.2205E08
0.1028E07
0.4795E07
0.2236E06
0.1043E05
0.4862E05
0.2267E04
0.1057E03
0.4931E03
0.2299E02
0.1072E01
0.5000E01
Space charge density (MOC), full injection law (Eonset = 0)
Piecewise linear E-Field (left), piecewise constant u (right)I AMf Numerical Examples 23
-
7/28/2019 Mais Chak
24/27
0.7883E+02
0.1893E+03
0.4547E+03
0.1092E+04
0.2622E+04
0.6298E+04
0.1512E+05
0.3632E+05
0.8723E+05
0.2095E+06
0.5031E+06
0.1208E+07
0.2902E+07
0.6969E+07
0.1674E+08
0.4019E+08
0.9653E+08
absolute value
0.8214E+02
0.1938E+03
0.4574E+03
0.1080E+04
0.2548E+04
0.6012E+04
0.1419E+05
0.3348E+05
0.7901E+05
0.1865E+06
0.4400E+06
0.1038E+07
0.2451E+07
0.5783E+07
0.1365E+08
0.3221E+08
0.7601E+08
absolute value
Electric field strength (MOC), first and 7th iteration
I AMf Numerical Examples 24
-
7/28/2019 Mais Chak
25/27
0.1000E11
0.4663E11
0.2175E10
0.1014E09
0.4729E09
0.2205E08
0.1028E07
0.4795E07
0.2236E06
0.1043E05
0.4862E05
0.2267E04
0.1057E03
0.4931E03
0.2299E02
0.1072E01
0.5000E01
absolute value
0.1000E11
0.4663E11
0.2175E10
0.1014E09
0.4729E09
0.2205E08
0.1028E07
0.4795E07
0.2236E06
0.1043E05
0.4862E05
0.2267E04
0.1057E03
0.4931E03
0.2299E02
0.1072E01
0.5000E01
absolute value
Space charge density near tip (MOC), first and 7th iteration
0.1915E+06
0.2825E+06
0.4168E+06
0.6149E+06
0.9072E+06
0.1339E+07
0.1975E+07
0.2914E+07
0.4299E+07
0.6343E+07
0.9358E+07
0.1381E+08
0.2037E+08
0.3006E+08
0.4434E+08
0.6543E+08
0.9653E+08
absolute value
0.1975E+06
0.2865E+06
0.4156E+06
0.6030E+06
0.8747E+06
0.1269E+07
0.1841E+07
0.2671E+07
0.3874E+07
0.5621E+07
0.8154E+07
0.1183E+08
0.1716E+08
0.2490E+08
0.3612E+08
0.5239E+08
0.7601E+08
absolute value
Electric field strength near tip, first and 7th iteration
I AMf Numerical Examples 25
-
7/28/2019 Mais Chak
26/27
0.0000E+00
0.1058E+03
0.2117E+03
0.3175E+03
0.4233E+03
0.5292E+03
0.6350E+03
0.7408E+03
0.8467E+03
0.9525E+03
0.1058E+04
0.1164E+04
0.1270E+04
0.1376E+04
0.1482E+04
0.1588E+04
0.1693E+04
0.0000E+00
0.8859E+02
0.1772E+03
0.2658E+03
0.3544E+03
0.4429E+03
0.5315E+03
0.6201E+03
0.7087E+03
0.7973E+03
0.8859E+03
0.9745E+03
0.1063E+04
0.1152E+04
0.1240E+04
0.1329E+04
0.1417E+04
n E L2() 2/0L2() E + 2/0L2() Emax1 1.2160E+04 1.2068E+03 1.1657E+04 1.0297E+08
2 1.0299E+04 1.1297E+03 9.8192E+03 8.2916E+07
3 1.0067E+04 1.1132E+03 9.5929E+03 8.0682E+07
4 1.0117E+04 1.1163E+03 9.6416E+03 8.1190E+07
5 1.0095E+04 1.1141E+03 9.6202E+03 8.0963E+07
I AMf Least-Squares error indicator 26
-
7/28/2019 Mais Chak
27/27
Conclusion/ to do
Method of Characteristics gives space charge distribution
Need better E-field (with mixed formulation?)
Initial mesh should be better adjusted to field lines Use Least squares functional of transport problem for adaptive
scheme
I AMf Conclusion/ to do 27