load flow 1

30
POWER SYSTEM 2 - EPO 643 1 POWER (LOAD) FLOW STUDY INTRODUCTION BASIC TECHNIQUES TYPE OF BUSES Y BUS MATRIX POWER SYSTEM COMPONENTS BUS ADMITTANCE MATRIX

Upload: kinoki-watanabe

Post on 03-Dec-2014

3.379 views

Category:

Art & Photos


6 download

DESCRIPTION

 

TRANSCRIPT

Page 1: load flow 1

POWER SYSTEM 2 - EPO 643 1

POWER (LOAD) FLOW STUDY

INTRODUCTION

BASIC TECHNIQUES

TYPE OF BUSES

Y BUS MATRIX

POWER SYSTEM COMPONENTS

BUS ADMITTANCE MATRIX

Page 2: load flow 1

POWER SYSTEM 2 - EPO 643 2

INTRODUCTION

Power (Load) flow study is the analysis of a power system in normal steady-state operation

This study will determine: Voltages Currents Real power Reactive powerWhy we need load flow study?

In a power system under a given set of load conditions

Page 3: load flow 1

POWER SYSTEM 2 - EPO 643 3

The power flow problem was originally motivated within planning environments where engineers considered different network configurations necessary to serve an expected future load.

Later, it became an operational problem as operators and operating engineers were required to monitor the real-time status of the network in terms of voltage magnitudes and circuit flows.

Page 4: load flow 1

POWER SYSTEM 2 - EPO 643 4

A power flow solution procedure is a numerical method that is employed to solve the power flow problem.

A power flow program is a computer code that implements a power flow solution procedure.

The power flow solution contains the voltages and angles at all buses, and from this information, we may compute the real and reactive generation and load levels at all buses and the real and reactive flows across all circuits.

Page 5: load flow 1

POWER SYSTEM 2 - EPO 643 5

Terminology

The above terminology is often used with the word “load” substituted for “power,” i.e., load flow problem, load flow solution procedure, load flow program, and load flow solution.

However, the former terminology is preferred as one normally does not think of “load” as something that “flows.”

Page 6: load flow 1

POWER SYSTEM 2 - EPO 643 6

Power system components

Generator Transmission Lines Load

Figure 1

Page 7: load flow 1

POWER SYSTEM 2 - EPO 643 7

Generator Generators have maximum and minimum real and

reactive power capabilities. Maximum reactive power capability:

maximum reactive power that the generator may produce when operating with a lagging power factor.

minimum reactive power capability: maximum reactive power the generator may absorb when

operating with a leading power factor. These limitations are a function of the real power

output of the generator, as the real power increases, the reactive power limitations

move closer to zero.

Page 8: load flow 1

POWER SYSTEM 2 - EPO 643 8

Figure 2

Page 9: load flow 1

POWER SYSTEM 2 - EPO 643 9

Figure 2 illustrates several important elements of the power flow problem.

First, identify each bus depending on whether generation and/or load is connected to it.

A bus may have generation only (buses B1, B2, and B3), load only (buses B5, B7, and B9), neither generation or load (buses B4, B6, and B8). both generation and load (leads us to define “bus

injection”)

Page 10: load flow 1

POWER SYSTEM 2 - EPO 643 10

Basic Technique for Load Flow Studies

In a load flow study, assumptions are made about: Voltage at a bus or Power being supplied to the bus

For each bus in the system

Page 11: load flow 1

POWER SYSTEM 2 - EPO 643 11

Types of Buses

For each bus, there are four possible variables that characterize the buses electrical condition.

The four variables are real and reactive power injection, Pi and Qi,

voltage magnitude and angle, |Vi| and i , respectively

Page 12: load flow 1

POWER SYSTEM 2 - EPO 643 12

Types of Buses (cont..) Generation Bus

Also called the P-V bus or voltage-controlled buses Voltage magnitude |Vi| and real power Pi are specified Able to specify (and therefore to know) the voltage

magnitude of this bus. Most generator buses fall into this category, independent of

whether it also has load

Load Bus Also called the P-Q bus Real power Pi and Qi are specified All load buses fall into this category, including buses that

have not either load or generation.

Page 13: load flow 1

POWER SYSTEM 2 - EPO 643 13

Slack or Swing Bus Known as reference bus Voltage magnitude |Vi| and phase angle i are

specified There is only one swing bus, and it can be

designated by the engineer to be any generator bus in the system.

This generator “swings” to compensate for the network losses, or, one may say that it “takes up the slack.”

Page 14: load flow 1

POWER SYSTEM 2 - EPO 643 14

Bus types Quantities specified

Unknown values

Generator Bus |Vi| , Pi Qi , i

Load Bus Pi , Qi |Vi| , i

Slack Bus |Vi| , i Pi , Qi

Page 15: load flow 1

POWER SYSTEM 2 - EPO 643 15

Bus injection

An injection is the power (P or Q), that is being injected into or withdrawn from a bus by an element having its other terminal (in the per-phase equivalent circuit) connected to ground. Such an element would be either a generator or a load.

Positive injection is defined as one where power is flowing from the element into the bus.

Negative injection is then when power is flowing from the bus, into the element.

Page 16: load flow 1

POWER SYSTEM 2 - EPO 643 16

Bus injection (cont..)

Generators normally have positive real power injections, although they may also be assigned negative real power injections when they are operating as a motor.

Generators may have either positive or negative reactive power injections: positive if the generator is operating lagging and delivering

reactive power to the bus, negative if the generator is operating leading and

absorbing reactive power from the bus, and zero if the generator is operating at unity power factor.

Page 17: load flow 1

POWER SYSTEM 2 - EPO 643 17

Loads

Loads normally have negative real and reactive power injections.

Figure 3: Illustration of (a) positive injection, (b) negative injection, and (c) net injection

Pk=100 Qk=30

(a)

Pk= - 40 Qk= -20

(b)

Pk=100+(-40)=60 Qk=30+(-20)=10

(c)

Page 18: load flow 1

POWER SYSTEM 2 - EPO 643 18

Figure 3 illustrates the net injection as the algebraic sum when a bus has both load and generation;

In this case, the net injection for both real and reactive power is positive (into the bus).

Thus, the net real power injection is Pk=Pgk-Pdk, and the net reactive power injection is Qk=Qgk-Qdk.

We may also refer to the net complex power injection as Sk=Sgk-Sdk, where Sk=Pk+jQk.

Page 19: load flow 1

POWER SYSTEM 2 - EPO 643 19

Power Flow solution Most common and important tool in power

system analysis also known as the “Load Flow” solution used for planning and controlling a system assumptions: balanced condition and single phase analysis

The utility wants to know the voltage profile the nodal voltages for a given load and generation

schedule From the load flow solution –

the voltage magnitude and phase angle at each bus could be determined and hence the active and reactive power flow in each line could be calculated

Page 20: load flow 1

POWER SYSTEM 2 - EPO 643 20

The currents and powers are expressed as going into the bus for generation the powers are positive for loads the powers are negative the scheduled power is the sum of the generation

and load powers

Page 21: load flow 1

POWER SYSTEM 2 - EPO 643 21

The Bus Admittance Matrix

The matrix equation for relating the nodal voltages to the currents that flow into and out of a network using the admittance values of circuit branches is given by :-

Page 22: load flow 1

POWER SYSTEM 2 - EPO 643 22

Forming the Admittance Matrix

y4 y3

y1 y2

I4

I3 I2

I1

4 3

2

1

y34

y23

y13

y12

Page 23: load flow 1

POWER SYSTEM 2 - EPO 643 23

From Kirchoff’s Current Law (KCL) – the current injections be equal to the sum of

the currents flowing out of the bus and into the lines connecting the bus to other buses,or to the ground.

Therefore, recalling Ohm’s Law, I=V/Z=VY, the current injected into bus 1 may be written as:

I1=(V1-V2)y12 + (V1-V3)y13 + V1y1

Page 24: load flow 1

POWER SYSTEM 2 - EPO 643 24

I2 = (V2 - V1)(y21) + V2 y2 + (V2 – V3)y23

I1= V1( y1 + y12 + y13) + V2(-y12) + V3(-y13)

I2= V1(-y21) + V2( y2 + y21 + y23) + V3(-y23)

I3= V1(-y31) + V2(-y32) + V3( y3 + y31 + y32+ y34) +

V4(-y34)

I4= V3(-y43) + V4( y4 + y43)

Page 25: load flow 1

POWER SYSTEM 2 - EPO 643 25

Admittance Matrix

)y y (y-00

y-)y yy y (y-y-

0y- )y y y (y-

0y-y- )y y y (

43 443

34343231 33231

232321 221

131213121

Page 26: load flow 1

POWER SYSTEM 2 - EPO 643 26

Matrix Equation

4

3

2

1

43 443

34343231 33231

232321 221

131213121

4

3

2

1

)y y (y-00

y-)y yy y (y-y-

0y- )y y y (y-

0y-y- )y y y (

V

V

V

V

I

I

I

I

Page 27: load flow 1

POWER SYSTEM 2 - EPO 643 27

Y-Bus Matrix Building Rules

The matrix is symmetric, i.e., Yij=Yji.

A diagonal element Yii = Self Admittance is obtained as the sum of admittances for all branches

connected to bus i, including the shunt branch

The off-diagonal elements are the negative of the admittances connecting buses i and j, i.e., Yij=-yji = mutual admittance.

N

ikkikiii yyY

,1

Page 28: load flow 1

POWER SYSTEM 2 - EPO 643 28

E.g. for a 4 bus system

44434241

34333231

24232221

14131211

YYYY

YYYY

YYYY

YYYY

Y

Page 29: load flow 1

POWER SYSTEM 2 - EPO 643 29

The power flow equations

The net complex power injection into a bus

Sk=Sgk-Sdk

Sk=VkIk*

Vk=| Vk|k

Ik = | Ykj|kj | Vj|j

Ik = | Ykj|| Vj| (kj + j)

Ik* = | Ykj|| Vj| -(kj + j)

Page 30: load flow 1

POWER SYSTEM 2 - EPO 643 30

Sk=VkIk*

Sk= | Vk|k x | Ykj|| Vj| -(kj + j)

Sk= | Ykj| | Vk|| Vj| (k - j - kj )

Pk= | Ykj| | Vk|| Vj|cos (k - j - kj )

Qk= | Ykj| | Vk|| Vj|sin (k - j - kj )