linear programming feasible region

21
Topic: Linear Programming Problem Submitted To : Prof. Nilesh Coordinators : Zeel Mathkiya (19) Dharmik Mehta (20) Sejal Mehta (21) Hirni Mewada (22) Varun Modi (23) Siddhi Nalawade (24) OPERATIONAL RESEARCH

Upload: varun-modi

Post on 20-Jan-2015

1.997 views

Category:

Documents


5 download

DESCRIPTION

 

TRANSCRIPT

Page 1: Linear Programming Feasible Region

Topic: Linear Programming Problem

Submitted To : Prof. Nilesh

Coordinators : Zeel Mathkiya (19)

Dharmik Mehta (20)

Sejal Mehta (21)

Hirni Mewada (22)

Varun Modi (23)

Siddhi Nalawade (24)

OPERATIONAL RESEARCH

Page 2: Linear Programming Feasible Region

DEFINITION OF LINEAR PROGRAMMING

The Mathematical Definition of LP:

“It is the analysis of problem in which a linear function of a number of variables is to maximised (minimised), when those variables are subject to a number of restraints in the form of linear inequalities”.

Page 3: Linear Programming Feasible Region

TERMINOLOGY OF LINEAR PROGRAMMING

A typical linear program has the following components

An objective Function.Constraints or Restrictions.Non-negativity Restrictions.

Page 4: Linear Programming Feasible Region

TERMS USED TO DESCRIBE LINEAR PROGRAMMING PROBLEMS

Decision variables.Objective function.Constraints.Linear relationship.Equation and inequalities.Non-negative restriction.

Page 5: Linear Programming Feasible Region

FORMATION OF LPPObjective functionConstraintsNon-Negativity restrictionsSolutionFeasible SolutionOptimum Feasible Solution

Page 6: Linear Programming Feasible Region

SOLVED EXAMPLE -1A Company manufactures 2 types of product H₁ & H₂. Both the

product pass through 2 machines M₁,M₂.The time requires for processing each unit of product H₁,H₂.On each machine & the available capacity of each machine is given below:

Product Machine

M₁ M₂

H₁ 3 2

H₂ 2 7

Available Capacity(hrs) 1800 1400

The availability of materials is sufficient to product 350 unit of H₁ & 150 of H₂.Each unit of H₁ gives a profit of Rs.25,each unit of H₂ gives profit of Rs.20.Formulate the above problem as LPP.

Page 7: Linear Programming Feasible Region

SOLUTIONFrom manufactures point of view we need to maximise the profit.The

profit depend upon the number of unit of product H₁ &H₂ produced.

Let x₁= no of unit of H₁ produce

x₂=no of unit of H₂ produce

x₁ ≥ 0 1

x₂ ≥ 0 2

3x₁ + 2x₂ ≤ 1800 3

2x₁ + 7x₂ ≤ 1400 4

Z= 25x₁ + 20x₂

LPP is formed as follows:

Maximise Z= 25x₁ + 20x₂

Page 8: Linear Programming Feasible Region

CONTI…..Subject to:

x₁ ≥ 0 x₂ ≥ 0 3x₁ + 2x₂ ≤ 1800 2x₁ + 7x₂ ≤ 1400

Page 9: Linear Programming Feasible Region

CONTI…...A Manager of hotel dreamland plans and extancison

not more than 50 groups attleast 5 must be executive single rooms the number of executive double rooms should be atleast 3 times the number of executive single rooms. He charges Rs.3000 for executive double rooms and Rs.1800 executive single rooms per day.

Page 10: Linear Programming Feasible Region

CONTI…..

Formulate the above problume for LPP

SOLUTION →

The LPP is formulated as follows ;

Let X1 = Total No. of single executive rooms

Let X2 = Total No. of Double executive rooms

... X1 + x2 < 50

X1 > 5

x2 > 3 X1

Maximise ; Z = 1800 X1 + 3000 x2

Page 11: Linear Programming Feasible Region

The LPP is formulated as follows

Maximise ; Z = 1800 X1 + 3000 x

Subject to ; X1 + x2 < 50

X1 > 5

x2 > 3 X1

Page 12: Linear Programming Feasible Region

GRAPHICAL METHOD

1. Arrive at a graphical solution for the following LPP.Maximize Z = 40x1 + 35x2

Subject to : 2x1 + 3x2 < 60

4x1 + 3x2 < 96

x1 , x2 > 0

Page 13: Linear Programming Feasible Region

Solution : Let us consider the equation

1) 2x1 + 3x2 = 60

Put x2 = 0: 2x1 = 60

x1 = 30

A = (30 , 0)Put x1 = 0 : 3x2 = 60

x2 = 20

B = (0 , 20)

Page 14: Linear Programming Feasible Region

2) 4x1 + 3x2 < 96

Put x2 = 0 : 4x1 = 96

x1 = 24

C = (24 , 0)Put x1 = 0 : 3x2 = 96

x2 = 32

D = (0 , 32)

Page 15: Linear Programming Feasible Region

Y axis

Scale : Xaxis = 1 cm = 5 units Yaxis = 1 cm = 5 units D

B

p

C A X axis O

5 10 15 20 25 30 35 40

40

35

30

25

20

15

10

5

Page 16: Linear Programming Feasible Region

OBPC is the feasible regionPoints x1 x2 z

O 0 0 z = 0B 0 20 z = 40(0) + 35 (20) = 700P 18 8 z = 40(18) + 35(8) = 1000C 24 0 z = 40(24) + 35(0) = 960

Thus, the optimal feasible solution is x1 = 18 , x2 = 8 and z = 1000

Page 17: Linear Programming Feasible Region

CONTI…..Find the feasible solution to following LPPMinimize Z = 6x + 5ySubject to = x + y > 7

x < 3 , y < 4x < 0 , y > 0

Page 18: Linear Programming Feasible Region

Solution : Removing Inequality in given equation1. x + y > 7Put y = 0 : x = 7Put x = 0 : y = 7The two points are : A = (7 , 0) & B = (0 , 7)Further,X = 3 , y = 4

Page 19: Linear Programming Feasible Region

Y axis

B Scale : X axis = 1cm = 1 unit Y axis = 1cm = 1 unit

P

A X axis O

1 2 3 4 5 6 7 8

8

7 6

5 4

3

2

1

Page 20: Linear Programming Feasible Region

CONTI…..As all the 3 lines intersect each other at a

common point P( 3 , 4) it is the feasible solution to LPP

Z = 6(3) + 5(4) = 18 + 20 = 38

Page 21: Linear Programming Feasible Region

CONCLUSIONLinear programming is very important

mathematical technique which enables managers to arrive at proper decisions regarding his area of work. Thus it is very important part of operations research.