limiting reactant

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LIMITING REACTANT

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Limiting reactant. Limiting Reactant. Limiting Reagent The reactant that is totally used up during the chemical reaction Limits the amount of product produced . Excess Reactant. Excess Reagent - PowerPoint PPT Presentation

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Page 1: Limiting reactant

LIMITING REACTANT

Page 2: Limiting reactant

LIMITING REACTANT• Limiting Reagent• The reactant that is totally

used up during the chemical reaction

• Limits the amount of product produced

Page 3: Limiting reactant

EXCESS REACTANT• Excess Reagent• The reactant present in a

quantity that is greater than what is needed to react with the limiting reactant

• Remains after the limiting reactant has been used up

Page 4: Limiting reactant

• What is the limiting reactant?• What are the excess

reactants?

Page 5: Limiting reactant

STEPS1. Balance the equation2. Identify the givens (there are

2!)3. Identify what you want to find4. Use stoichiometry to solve5. The reactant with a smaller

amount of product produced is the limiting reactant

6. The other reactant is in excess

Page 6: Limiting reactant

How many grams of silver bromide (AgBr) can be formed when solutions containing 50.0 g of MgBr2 and 100.0 g of AgNO3 are mixed together? What is the limiting reactant?

What is in excess?1 MgBr2 + 2 AgNO3 2 AgBr + 1 Mg(NO3)2

50.0 g MgBr2 1 mol MgBr2 2 mol AgBr 187.77 g AgBr

184.11 g MgBr2 1 mol MgBr2 1 mol AgBr

= 102 g AgBr

100.0 g AgNO3 1 mol AgNO3 2 mol AgBr 187.77 g AgBr

169.88 g AgNO3 2 mol AgNO3 1 mol AgBr

= 110.5 g AgBr

Limiting Reactant (LR) = MgBr2 Excess Reactant (ER) = AgNO3

Page 7: Limiting reactant

How many grams of hydrogen chloride can be produced from 1.00 g of hydrogen and 55.0 g of chlorine? What is

the limiting reactant? What is in excess?H2 + Cl2

HCl

1.00 g H2 1 mol H2 2 mol HCl 36.46 g HCl

2.02 g H2 1 mol H2 1 mol HCl= 36.1 g HCl

55.0 g Cl2 1 mol Cl2 2 mol HCl 36.46 g HCl

70.90 g Cl2 1 mol Cl2 1 mol HCl

= 56.6 g HCl

Limiting Reactant (LR) = H2 Excess Reactant (ER) = Cl2

Page 8: Limiting reactant

How many grams of barium sulfate (BaSO4) will be formed from 200.0 g of barium nitrate (Ba(NO3)2) and 150.0 g of

sodium sulfate (Na2SO4)? What is the limiting reactant? What is in excess?

Ba(NO3)2 + Na2SO4 BaSO4 + NaNO3

200.0 g Ba(NO3)2 1 mol Ba(NO3)2 1 mol BaSO4 233.40 g BaSO4

261.35 g Ba(NO3)2 1 mol Ba(NO3)2 1 mol BaSO4

= 178.6 g BaSO4

150.0 g Na2SO4 1 mol Na2SO4 2 mol BaSO4 233.40 g BaSO4

142.05 g Na2SO4 2 mol AgNO3 1 mol BaSO4

= 246.5 g BaSO4

Limiting Reactant (LR) = Ba(NO3)2 Excess Reactant (ER) = Na2SO4