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  • 8/4/2019 Lime Dosing

    1/16

    Softening

    cations mg/l eq.wt mg/l as CaCO3 Anions mg/l eq.wt

    Ca2+

    1073 20 2682.5 CO32-

    0 30

    Mg2+

    574 12.2 2352.5 HCO3-

    46 61

    Na+

    10165 23 22097.8 Cl-

    16415 35.5

    Fe2+

    1.12 27.9225 2.0 SO42-

    3750 48

    Concentration

    H+

    1.94984E-08

    HCO3-

    0.0009

    Ka 4.46684E-07

    H2CO3 3.92864E-05

    Therefore CO2 = H2CO3

    Mol wt of CO2 44.0 g

    CO2 1.728602696 1000.0 mg

    CO2 3.92864249

    Mg2+ Fe+

    5038.9 27138.7

    37.7

    3.93 HCO3-

    CO2 3.93

    Ca carbonate

    hardness 37.7

    Mg Carbonate

    hardness 0

    excess lime 20

    Amount of lime

    (CaOH)2 required 61.63491803

    Mg2+ Fe+

    5001.2 27101.0

    After the Carbonate Hardness is removed

    CO2

    Ca2+ Na+

    2648.7 27099.0

    1) Note: Ca & Mg g

    2) first step to remove carbonate hardness

    association with Ca & Mg.

    alkalinity exist in the form of HCO3-& there w

    the alkalinty exist as OH-

    so either forms carbonic acid or HCo3- depen

    precipitate calcicum and Magnesium carbonat

    ness forms CaCO3 which precipitaes

    MgCO3 which is soluble and does'nt get rem

    convert MgCO3 to Mg(OH)2 which

    mg/l as CaCO3

    mg/l as CaCO3

    mg/l as CaCO3

    mg/l as CaCO3

    mg/l as CaCO3

    Cl- SO42-

    Amount of lime required = (CO2 + Ca carbonate hardness + Mg Carbonate hardness + excess Lime)

    Na+

    H2CO3 = [H+] x [HCO3

    -]/[Ka1], mol/l

    expressing CO2 in terms of mg/l

    CO2 2686.4 27136.7

    23157.4 27063.7

    Availability of CO2 @ Ph 7.7

    Assume all of H2CO3 forms CO2

    expressing CO2 in terms of mg/l as CaCO3

    mg/l as CaCO3

    Ca2+

  • 8/4/2019 Lime Dosing

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    3.93

    Ca Non

    carbonate

    hardness 2648.7

    Mg NonCarbonate

    hardness 2352.5

    Amount of Soda

    Ash required 5001.2

    Mg Non

    Carbonate

    hardness 2352.5

    Lime 2414.093934

    Soda Ash 4494.2

    After Ca & Mg being removed

    Fe+

    24182.3

    3.93 Cl- SO42-

    CO2

    Na+

    34748.9

    12584.5 17355.3

    Cl- SO42-

    Amount of Soda Ash required = (Ca Non carbonate hardness + Mg Non Carbonate hardness)

    1)Calcium Non Carbonate Hardne2)CaCl2 Or CaSO4 reacts with Na2CO3 and for

    dose

    3)Mg Non Carbonate Hardness could

    4)Firstly Mg Non Corbonate is added with

    contributes har

    5)secondly Lime is added which reacts with

    leaves behind Nacl and Na2SO4 which is

    mg/l as CaCO3

    mg/l as CaCO3

    mg/l as CaCO3

    23119.7 27026.0

    mg/l as CaCO3

    Amount of Lime required = ( Mg Non Carbonate hardness)

    Total Amount of dosage required

    mg/l as CaCO3

    mg/l as CaCO3

  • 8/4/2019 Lime Dosing

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    mg/l as CaCO3 pH 7.71

    0.0 pKa 6.35 at 25C

    37.7

    23119.7

    3906.3

    26630.8616380354

    27063.7

    t to be precipitated to remove hardness.

    hich is formed by (HCO3-,CO3

    2-,OH

    --Contributes to Alkalinity) in

    3) At pH < 8.3

    ould be presence of CO2 4) At pH > 8.3 all of

    5) CO32-

    is not stableing upon pH 6) Lime Ca(OH)2 is used to

    e hardness 7) Lime + calcium Carbonate hard

    8) Lime + Mg Carbonate Hardness forms

    oved 9) So further addition of lime is required to

    precipitaes 10) finally excess lime is added

  • 8/4/2019 Lime Dosing

    4/16

    Note:

    ss could be removed by addition of Soda Ash (Na2CO3)s CaCO3 which precipitaes and NaCl,Na2SO4 which dissolves and

    nt contribute to hardness

    be removed by addition of both Lime & Soda Ash (Na2CO3)

    CaCO3 ,here MgCO3 is formed which is a soluble product and

    dness along with this CaCl2 r CaSO4 .

    gCO3 and forms Mg(OH)2 & CaCO3 a product that precipitaes .and

    a soluble and non-hardness product, but contributes to TDS.

  • 8/4/2019 Lime Dosing

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    Softening

    cations mg/l eq.wt mg/l as CaCO3 Anions mg/l eq.wt

    Ca2+

    942 20 2355.0 CO32-

    0 30

    Mg2+

    530 12.2 2172.1 HCO3-

    45 61

    Na+

    5921 23 12871.7 Cl-

    8935 35.5

    Fe2+

    0.1 27.9225 0.2 SO42-

    4580 48

    Concentration

    H+

    1.94984E-08

    HCO3-

    0.0009

    Ka 4.46684E-07

    H2CO3 3.92864E-05

    Therefore CO2 = H2CO3

    Mol wt of CO2 44.0 g

    CO2 1.728602696 1000.0 mg

    CO2 3.92864249

    Mg2+ Fe+

    4531.1 17403.0

    36.9

    3.93 HCO3-

    CO2 3.93

    Ca carbonate

    hardness 36.9

    Mg Carbonate

    hardness 0

    excess lime 20Amount of lime

    (CaOH)2

    required 60.8152459

    Mg2+ Fe+

    4494.2 17366.12322.0 17365.9

    17392.2

    Ca2+ Na+

    1) Note: Ca & Mg g

    2) first step to remove carbonate hardness

    association with Ca & Mg.

    alkalinity exist in the form of HCO3-& there w

    the alkalinty exist as OH-

    so either forms carbonic acid or HCo3- depen

    precipitate calcicum and Magnesium carbonat

    ness forms CaCO3 which precipitaes

    forms MgCO3 which is soluble and does'nt get

    to convert MgCO3 to Mg(OH)2 whic

    mg/l as CaCO3

    mg/l as CaCO3

    mg/l as CaCO3

    Availability of CO2 @ Ph 7.7

    H2CO3 = [H+] x [HCO3

    -]/[Ka1], mol/l

    Assume all of H2CO3 forms CO2

    expressing CO2 in terms of mg/l

    expressing CO2 in terms of mg/l as CaCO3

    17402.8

    mg/l as CaCO3

    CO2

    CO2

    2358.9

    mg/l as CaCO3

    mg/l as CaCO3

    SO42-

    12621.4

    Cl-

    Amount of lime required = (CO2 + Ca carbonate hardness + Mg Carbonate hardness + excess Lime)

    After the Carbonate Hardness is removed

    Ca2+ Na+

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    3.93

    Ca Non

    carbonate

    hardness 2322.0Mg Non

    Carbonate

    hardness 2172.1

    Amount of Soda

    Ash required 4494.174544

    Mg Non

    Carbonate

    hardness 2172.1

    Lime 2232.946393

    Soda Ash 4494.174544

    After Ca & Mg being removed

    Fe+

    24182.3

    3.93

    mg/l as CaCO3

    Amount of Soda Ash required = (Ca Non carbonate hardness + Mg Non Carbonate hardness)

    1)Calcium Non Carbonate Hardne

    2)CaCl2 Or CaSO4 reacts with Na2CO3 and for

    dose

    3)Mg Non Carbonate Hardness could

    4)Firstly Mg Non Corbonate is added with

    contributes ha

    5)secondly Lime is added which reacts with

    leaves behind Nacl and Na2SO4 which is

    mg/l as CaCO3

    mg/l as CaCO3

    Amount of Lime required = ( Mg Non Carbonate hardness)

    12584.5 17355.3

    mg/l as CaCO3

    Cl- SO42-

    mg/l as CaCO3

    Total Amount of dosage required

    CO2

    12584.5 17355.3Cl- SO42-

    Na+

    24182.1

    mg/l as CaCO3

  • 8/4/2019 Lime Dosing

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    mg/l as CaCO3 pH 7.71

    0.0 pKa 6.35 at 25C

    36.9

    12584.5

    4770.8

    17402.9481974954

    17392.2

    t to be precipitated to remove hardness.

    hich is formed by (HCO3-,CO3

    2-,OH

    --Contributes to Alkalinity) in

    3) At pH < 8.3

    uld be presence of CO2 4) At pH > 8.3 all of

    5) CO3

    2-is not stable

    ing upon pH 6) Lime Ca(OH)2 is used to

    e hardness 7) Lime + calcium Carbonate hard

    8) Lime + Mg Carbonate Hardness

    removed 9) So further addition of lime is required

    precipitaes 10) finally excess lime is added

  • 8/4/2019 Lime Dosing

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    Note:

    ss could be removed by addition of Soda Ash (Na2CO3)

    s CaCO3 which precipitaes and NaCl,Na2SO4 which dissolves and

    nt contribute to hardness

    e removed by addition of both Lime & Soda Ash (Na2CO3)

    CaCO3 ,here MgCO3 is formed which is a soluble product and

    dness along with this CaCl2 r CaSO4 .

    gCO3 and forms Mg(OH)2 & CaCO3 a product that precipitaes .and

    a soluble and non-hardness product, but contributes to TDS.

  • 8/4/2019 Lime Dosing

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    Softening

    cations mg/l eq.wt mg/l as CaCO3 Anions mg/l eq.wt

    Ca2+

    319 20 797.5 CO32-

    0 30

    Mg2+

    177 12.2 725.4 HCO3-

    65 61

    Na+

    7311 23 15893.5 Cl-

    9928 35.5

    Fe2+

    0 27.9225 0.0 SO42-

    3235 48

    Concentration

    H+

    1.94984E-08

    HCO3-

    0.0013

    Ka 4.46684E-07

    H2CO3 5.67471E-05

    Therefore CO2 = H2CO3

    Mol wt of CO2 44.0 g

    CO2 2.49687056 1000.0 mg

    CO2 5.674705819

    Mg2+ Fe+

    1528.6 17422.1

    53.3

    5.67 HCO3-

    CO2 5.67

    Ca carbonate

    hardness 53.3

    Mg Carbonate

    hardness 0

    excess lime 20

    Amount of lime

    (CaOH)2 required 78.94868852

    Mg2+ Fe+

    1475.3 17368.8

    5.67

    mg/l as CaCO3

    Availability of CO2 @ Ph 7.7

    H2CO3 = [H+] x [HCO3

    -]/[Ka1], mol/l

    Assume all of H2CO3 forms CO2

    expressing CO2 in terms of mg/l

    expressing CO2 in terms of mg/l as CaCO3

    CO2

    Ca2+ Na+

    803.2 17422.1

    14036.4 17406.2

    Cl- SO42-

    Amount of lime required = (CO2 + Ca carbonate hardness + Mg Carbonate hardness + excess Lime)

    1) Note: Ca & Mg g

    2) first step to remove carbonate hardness

    association with Ca & Mg.

    alkalinity exist in the form of HCO3-& there w

    the alkalinty exist as OH-

    so either forms carbonic acid or HCo3- depen

    precipitate calcicum and Magnesium carbonat

    ness forms CaCO3 which precipitaes

    MgCO3 which is soluble and does'nt get remconvert MgCO3 to Mg(OH)2 which

    mg/l as CaCO3

    mg/l as CaCO3

    mg/l as CaCO3

    mg/l as CaCO3

    mg/l as CaCO3

    After the Carbonate Hardness is removed

    CO2

    Ca2+ Na+

    749.9 17368.8

    13983.1 17352.9

    Cl- SO42-

    Amount of Soda Ash required = (Ca Non carbonate hardness + Mg Non Carbonate hardness)

  • 8/4/2019 Lime Dosing

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    Ca Non

    carbonate

    hardness 749.9

    Mg Non

    Carbonate

    hardness 725.4

    Amount of SodaAsh required 1475.3

    Mg Non

    Carbonate

    hardness 725.4

    Lime 804.3585246

    Soda Ash 1475.3

    After Ca & Mg being removed

    Fe+

    24182.3

    3.93

    Na+

    19594.0

    1)Calcium Non Carbonate Hardne

    2)CaCl2 Or CaSO4 reacts with Na2CO3 and for

    dose

    3)Mg Non Carbonate Hardness could

    4)Firstly Mg Non Corbonate is added withcontributes har

    5)secondly Lime is added which reacts with

    leaves behind Nacl and Na2SO4 which is

    mg/l as CaCO3

    mg/l as CaCO3

    mg/l as CaCO3

    12584.5 17355.3

    Cl- SO42-

    Amount of Lime required = ( Mg Non Carbonate hardness)

    mg/l as CaCO3

    Total Amount of dosage required

    mg/l as CaCO3

    mg/l as CaCO3

    CO2

  • 8/4/2019 Lime Dosing

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    mg/l as CaCO3 pH 7.71

    0.0 pKa 6.35 at 25C

    53.3

    13983.1

    3369.8

    t to be precipitated to remove hardness.

    hich is formed by (HCO3-,CO3

    2-,OH

    --Contributes to Alkalinity) in

    3) At pH < 8.3

    ould be presence of CO2 4) At pH > 8.3 all of

    5) CO32-

    is not stable

    ing upon pH 6) Lime Ca(OH)2 is used to

    e hardness 7) Lime + calcium Carbonate hard

    8) Lime + Mg Carbonate Hardness forms

    oved 9) So further addition of lime is required toprecipitaes 10) finally excess lime is added

  • 8/4/2019 Lime Dosing

    12/16

    Note:

    ss could be removed by addition of Soda Ash (Na2CO3)

    s CaCO3 which precipitaes and NaCl,Na2SO4 which dissolves and

    nt contribute to hardness

    be removed by addition of both Lime & Soda Ash (Na2CO3)

    CaCO3 ,here MgCO3 is formed which is a soluble product anddness along with this CaCl2 r CaSO4 .

    gCO3 and forms Mg(OH)2 & CaCO3 a product that precipitaes .and

    a soluble and non-hardness product, but contributes to TDS.

  • 8/4/2019 Lime Dosing

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    Softening

    cations mg/l eq.wt mg/l as CaCO3 Anions mg/l eq.wt

    Ca2+

    699 20 1747.5 CO32-

    0 30

    Mg2+

    367 12.2 1504.1 HCO3-

    66 61

    Na+

    6204 23 13487.0 Cl-

    9325 35.5

    Fe2+

    0 27.9225 0.0 SO42-

    3400 48

    Concentration

    H+

    1.94984E-08

    HCO3-

    0.00132

    Ka 4.46684E-07

    H2CO3 5.76201E-05

    Therefore CO2 = H2CO3

    Mol wt of CO2 44.0 g

    CO2 2.535283954 1000.0 mg

    CO2 5.762008986

    Mg2+ Fe+

    3257.3 16744.2

    54.1

    5.67 HCO3-

    CO2 5.67

    Ca carbonate

    hardness 54.1

    Mg Carbonate

    hardness 0

    excess lime 20Amount of lime

    (CaOH)2

    required 79.76836066

    Mg2+ Fe+

    3203.2 16690.1

    After the Carbonate Hardness is removed

    CO2

    Ca2+ Na+

    1699.1 16690.1

    Cl-

    SO42-

    Amount of lime required = (CO2 + Ca carbonate hardness + Mg Carbonate hardness + excess Lime)

    1) Note: Ca & Mg g

    2) first step to remove carbonate hardness

    association with Ca & Mg.

    alkalinity exist in the form of HCO3-& there w

    the alkalinty exist as OH-

    so either forms carbonic acid or HCo3- depen

    precipitate calcicum and Magnesium carbonat

    ness forms CaCO3 which precipitaes

    forms MgCO3 which is soluble and does'nt get

    to convert MgCO3 to Mg(OH)2 whic

    mg/l as CaCO3

    mg/l as CaCO3

    mg/l as CaCO3

    mg/l as CaCO3

    mg/l as CaCO3

    CO2

    Ca2+ Na+

    1753.2 16744.2

    13187.9 16729.6

    Availability of CO2 @ Ph 7.7

    H2CO3 = [H+] x [HCO3

    -]/[Ka1], mol/l

    Assume all of H2CO3 forms CO2

    expressing CO2 in terms of mg/l

    expressing CO2 in terms of mg/l as CaCO3

    mg/l as CaCO3

  • 8/4/2019 Lime Dosing

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    5.67

    Ca Non

    carbonate

    hardness 1699.1Mg Non

    Carbonate

    hardness 1504.1

    Amount of Soda

    Ash required 3203.2

    Mg Non

    Carbonate

    hardness 1504.1

    Lime 1583.866721

    Soda Ash 3203.2

    After Ca & Mg being removed

    Fe+

    24182.3

    3.93 Cl- SO42-

    Amount of Lime required = ( Mg Non Carbonate hardness)

    mg/l as CaCO3

    Total Amount of dosage required

    mg/l as CaCO3

    mg/l as CaCO3

    CO2

    Na+

    21592.4

    12584.5 17355.3

    Cl- SO42-

    Amount of Soda Ash required = (Ca Non carbonate hardness + Mg Non Carbonate hardness)

    1)Calcium Non Carbonate Hardne

    2)CaCl2 Or CaSO4 reacts with Na2CO3 and for

    dose

    3)Mg Non Carbonate Hardness could

    4)Firstly Mg Non Corbonate is added with

    contributes ha

    5)secondly Lime is added which reacts with

    leaves behind Nacl and Na2SO4 which is

    mg/l as CaCO3

    mg/l as CaCO3

    mg/l as CaCO3

    13133.8 16675.5

  • 8/4/2019 Lime Dosing

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    mg/l as CaCO3 pH 7.71

    0.0 pKa 6.35 at 25C

    54.1

    13133.8

    3541.7

    t to be precipitated to remove hardness.

    hich is formed by (HCO3-,CO3

    2-,OH

    --Contributes to Alkalinity) in

    3) At pH < 8.3

    uld be presence of CO2 4) At pH > 8.3 all of

    5) CO32-

    is not stable

    ing upon pH 6) Lime Ca(OH)2 is used to

    e hardness 7) Lime + calcium Carbonate hard

    8) Lime + Mg Carbonate Hardness

    removed 9) So further addition of lime is required

    precipitaes 10) finally excess lime is added

  • 8/4/2019 Lime Dosing

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    Note:

    ss could be removed by addition of Soda Ash (Na2CO3)

    s CaCO3 which precipitaes and NaCl,Na2SO4 which dissolves and

    nt contribute to hardness

    e removed by addition of both Lime & Soda Ash (Na2CO3)

    CaCO3 ,here MgCO3 is formed which is a soluble product and

    dness along with this CaCl2 r CaSO4 .

    gCO3 and forms Mg(OH)2 & CaCO3 a product that precipitaes .and

    a soluble and non-hardness product, but contributes to TDS.