lesson 9

49
1 April 2012 2006 by Fabian Kung Wai Lee 1 10 - RF Oscillators The information in this work has been obtained from sources believed to be reliable. The author does not guarantee the accuracy or completeness of any information presented herein, and shall not be responsible for any errors, omissions or damages as a result of the use of this information. April 2012 2006 by Fabian Kung Wai Lee 2 Main References [1]* D.M. Pozar, “Microwave engineering”, 2nd Edition, 1998 John-Wiley & Sons. [2] J. Millman, C. C. Halkias, “Integrated electronics”, 1972, McGraw-Hill. [3] R. Ludwig, P. Bretchko, “RF circuit design - theory and applications”, 2000 Prentice-Hall. [4] B. Razavi, “RF microelectronics”, 1998 Prentice-Hall, TK6560. [5] J. R. Smith,”Modern communication circuits”,1998 McGraw-Hill. [6] P. H. Young, “Electronics communication techniques”, 5 th edition, 2004 Prentice-Hall. [7] Gilmore R., Besser L.,”Practical RF circuit design for modern wireless systems”, Vol. 1 & 2, 2003, Artech House. [8] Ogata K., “Modern control engineering”, 4 th edition, 2005, Prentice-Hall.

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Page 1: Lesson 9

1

April 2012 2006 by Fabian Kung Wai Lee 1

10 - RF Oscillators

The information in this work has been obtained from sources believed to be reliable.The author does not guarantee the accuracy or completeness of any informationpresented herein, and shall not be responsible for any errors, omissions or damagesas a result of the use of this information.

April 2012 2006 by Fabian Kung Wai Lee 2

Main References

• [1]* D.M. Pozar, “Microwave engineering”, 2nd Edition, 1998 John-Wiley & Sons.

• [2] J. Millman, C. C. Halkias, “Integrated electronics”, 1972, McGraw-Hill.

• [3] R. Ludwig, P. Bretchko, “RF circuit design - theory and applications”, 2000

Prentice-Hall.

• [4] B. Razavi, “RF microelectronics”, 1998 Prentice-Hall, TK6560.

• [5] J. R. Smith,”Modern communication circuits”,1998 McGraw-Hill.

• [6] P. H. Young, “Electronics communication techniques”, 5th edition, 2004

Prentice-Hall.

• [7] Gilmore R., Besser L.,”Practical RF circuit design for modern wireless

systems”, Vol. 1 & 2, 2003, Artech House.

• [8] Ogata K., “Modern control engineering”, 4th edition, 2005, Prentice-Hall.

Page 2: Lesson 9

2

April 2012 2006 by Fabian Kung Wai Lee 3

Agenda

• Positive feedback oscillator concepts.

• Negative resistance oscillator concepts (typically employed for RF oscillator).

• Equivalence between positive feedback and negative resistance oscillator theory.

• Oscillator start-up requirement and transient.

• Oscillator design - Making an amplifier circuit unstable.

• Constant |Γ1| circle.

• Fixed frequency oscillator design.

• Voltage-controlled oscillator design.

April 2012 2006 by Fabian Kung Wai Lee 4

1.0 Oscillation Concepts

Page 3: Lesson 9

3

Introduction

• Oscillators are a class of circuits with 1 terminal or port, which produce

a periodic electrical output upon power up.

• Most of us would have encountered oscillator circuits while studying for

our basic electronics classes.

• Oscillators can be classified into two types: (A) Relaxation and (B)

Harmonic oscillators.

• Relaxation oscillators (also called astable multivibrator), is a class of

circuits with two unstable states. The circuit switches back-and-forth

between these states. The output is generally square waves.

• Harmonic oscillators are capable of producing near sinusoidal output,

and is based on positive feedback approach.

• Here we will focus on Harmonic Oscillators for RF systems.

Harmonic oscillators are used as this class of circuits are capable of

producing stable sinusoidal waveform with low phase noise.

April 2012 2006 by Fabian Kung Wai Lee 5

April 2012 2006 by Fabian Kung Wai Lee 6

2.0 Overview of Feedback Oscillators

Page 4: Lesson 9

4

April 2012 2006 by Fabian Kung Wai Lee 7

Classical Positive Feedback Perspective on Oscillator (1)

• Consider the classical feedback system with non-inverting amplifier,

• Assuming the feedback network and amplifier do not load each other,

we can write the closed-loop transfer function as:

• Writing (2.1a) as:

• We see that we could get non-zero output at So, with Si = 0, provided

1-A(s)F(s) = 0. Thus the system oscillates!

+

+

E(s) So(s)Si(s)

A(s)

F(s)

( ) ( )( ) ( )sFsA

sA

iSoS

s−

=1

( ) ( ) ( )sFsAsT =Positive

Feedback Loop gain (the gain of the system

around the feedback loop)

Non-inverting amplifier

(2.1a)

(2.1b)

( ) ( )( ) ( ) ( )sSsS isFsA

sA

o −=

1

Feedback network

High impedance

High impedance

April 2012 2006 by Fabian Kung Wai Lee 8

Classical Positive Feedback Perspective on Oscillator (1)

• The condition for sustained oscillation, and for oscillation to startup from

positive feedback perspective can be summarized as:

• Take note that the oscillator is a non-linear circuit, initially upon power

up, the condition of (2.2b) will prevail. As the magnitudes of voltages

and currents in the circuit increase, the amplifier in the oscillator begins

to saturate, reducing the gain, until the loop gain A(s)F(s) becomes one.

• A steady-state condition is reached when A(s)F(s) = 1.

( ) ( ) 01 =− sFsA

( ) ( ) 1>sFsA ( ) ( )( ) 0arg =sFsA

For sustained oscillation

For oscillation to startup

Barkhausen Criterion (2.2a)

(2.2b)

Note that this is a very simplistic view of oscillators. In reality oscillatorsare non-linear systems. The steady-state oscillatory condition correspondsto what is called a Limit Cycle. See texts on non-linear dynamical systems.

Page 5: Lesson 9

5

April 2012 2006 by Fabian Kung Wai Lee 9

Classical Positive Feedback Perspective on Oscillator (2)

• Positive feedback system can also be achieved with inverting amplifier:

• To prevent multiple simultaneous oscillation, the Barkhausen criterion

(2.2a) should only be fulfilled at one frequency.

• Usually the amplifier A is wideband, and it is the function of the

feedback network F(s) to ‘select’ the oscillation frequency, thus the

feedback network is usually made of reactive components, such as

inductors and capacitors.

+

-

E(s) So(s)Si(s)

-A(s)

F(s)

( ) ( )( ) ( )sFsA

sA

iSoS

s−

=1

Inverting amplifier

Inversion

Classical Positive Feedback Perspective on Oscillator (3)

• In general the feedback network F(s) can be implemented as a Pi or T

network, in the form of a transformer, or a hybrid of these.

• Consider the Pi network with all reactive elements. A simple analysis in

[2] and [3] shows that to fulfill (2.2a), the reactance X1, X2 and X3 need to

meet the following condition:

April 2012 2006 by Fabian Kung Wai Lee 10

+

-

E(s) So(s)-A(s)

X1

X3

X2

( )213 XXX +−=

If X3 represents inductor, then

X1 and X2 should be capacitors.

(2.3)

Page 6: Lesson 9

6

Classical Feedback Oscillators

• The following are examples of oscillators, based on the original circuit

using vacuum tubes.

April 2012 2006 by Fabian Kung Wai Lee 11

+

-

+

-

+

-Hartley

oscillator

Clapp

oscillator

Colpitt

oscillator

+

-

Armstrong

oscillator

April 2012 2006 by Fabian Kung Wai Lee 12

Example of Tuned Feedback Oscillator (1)

A 48 MHz Transistor Common

-Emitter Colpitt Oscillator

0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.80.0 2.0

-1.0

-0.5

0.0

0.5

1.0

1.5

-1.5

2.0

time, usec

VL

, V

VB

, V

+

-

E(s) So(s)Si(s)-A(s)

F(s)

VL

VB

VC

L

L1

R=

L=2.2 uH

V_DC

SRC1

Vdc=3.3 V

C

CD1

C=0.1 uF

C

Cc1

C=0.01 uF

C

Cc2

C=0.01 uF

C

CE

C=0.01 uF

C

C2

C=22.0 pF

C

C1

C=22.0 pF

R

RL

R=220 Ohmpb_mot_2N3904_19921211

Q1

R

RE

R=220 Ohm

R

RC

R=330 Ohm

R

RB2

R=10 kOhm

R

RB1

R=10 kOhm

( ) ( )ωω FA

t0

1

Page 7: Lesson 9

7

April 2012 2006 by Fabian Kung Wai Lee 13

Example of Tuned Feedback Oscillator (2)

A 27 MHz Transistor Common-Base

Colpitt Oscilator

0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.80.0 2.0

-400

-200

0

200

400

-600

600

time, usec

VL, m

VV

E, m

V

+

+

E(s) So(s)Si(s)

A(s)

F(s)

VL

VE

VB

VC

R

R1

R=1000 Ohm

C

C1

C=100.0 pF

C

C2

C=100.0 pF

L

L1

R=

L=1.0 uH C

C3

C=4.7 pF

R

RB2

R=4.7 kOhmR

RE

R=100 Ohm

R

RC

R=470 Ohm

V_DC

SRC1

Vdc=3.3 V

C

Cc1

C=0.1 uF

C

Cc2

C=0.1 uF

C

CD1

C=0.1 uF

pb_mot_2N3904_19921211

Q1

R

RB1

R=10 kOhm

April 2012 2006 by Fabian Kung Wai Lee 14

Example of Tuned Feedback Oscillator (3)

VLVC

VB

C

Cc2

C=0.1 uF

C

Cc1

C=0.1 uFC

CE

C=0.1 uF

sx_stk_CX-1HG-SM_A_19930601

XTL1

Fres=16 MHz

C

C2

C=22.0 pF

C

C1

C=22.0 pF

V_DC

SRC1

Vdc=3.3 V

C

CD1

C=0.1 uF

R

RL

R=220 Ohmpb_mot_2N3904_19921211

Q1

R

RE

R=220 Ohm

R

RC

R=330 Ohm

R

RB2

R=10 kOhm

R

RB1

R=10 kOhm

A 16 MHz Transistor Common-Emitter

Crystal Oscillator

Page 8: Lesson 9

8

Limitation of Feedback Oscillator

• At high frequency, the assumption that the amplifier and feedback

network do not load each other is not valid. In general the amplifier’s

input impedance decreases with frequency, and it’s output impedance

is not zero. Thus the actual loop gain is not A(s)F(s) and equation (2.2)

breakdowns.

• Determining the loop gain of the feedback oscillator is cumbersome at

high frequency. Moreover there could be multiple feedback paths due

to parasitic inductance and capacitance.

• It can be difficult to distinguish between the amplifier and the feedback

paths, owing to the coupling between components and conductive

structures on the printed circuit board (PCB) or substrate.

• Generally it is difficult to physically implement a feedback oscillator

once the operating frequency is higher than 500MHz.

April 2012 2006 by Fabian Kung Wai Lee 15

April 2012 2006 by Fabian Kung Wai Lee 16

3.0 Negative Resistance Oscillators

Page 9: Lesson 9

9

April 2012 2006 by Fabian Kung Wai Lee 17

Introduction (1)

• An alternative approach is needed to get a circuit to oscillate reliably.

• We can view an oscillator as an amplifier that produces an output

when there is no input.

• Thus it is an unstable amplifier that becomes an oscillator!

• For example let’s consider a conditionally stable amplifier.

• Here instead of choosing load or source impedance in the stable

regions of the Smith Chart, we purposely choose the load or source

impedance in the unstable impedance regions. This will result in

either |Γ1 | > 1 or |Γ2 | > 1.

• The resulting amplifier circuit will be called the Destabilized Amplifier.

• As seen in Chapter 7, having a reflection coefficient magnitude for Γ1

or Γ2 greater than one implies the corresponding port resistance R1 or

R2 is negative, hence the name for this type of oscillator.

April 2012 2006 by Fabian Kung Wai Lee 18

Introduction (2)

• For instance by choosing the load impedance ZL at the unstable region,

we could ensure that |Γ1 | > 1. We then choose the source impedance

properly so that |Γ1 Γs | > 1 and oscillation will start up (refer back to

Chapter 7 on stability theory).

• Once oscillation starts, an oscillating voltage will appear at both the

input and output ports of a 2-port network. So it does not matter

whether we enforce |Γ1 Γs | > 1 or |Γ2 ΓL | > 1, enforcing either one will

cause oscillation to occur (It can be shown later that when |Γ1 Γs | > 1

at the input port, |Γ2 ΓL | > 1 at the output port and vice versa).

• The key to fixed frequency oscillator design is ensuring that the criteria

|Γ1 Γs | > 1 only happens at one frequency (or a range of intended

frequencies), so that no simultaneous oscillations occur at other

frequencies.

Page 10: Lesson 9

10

April 2012 2006 by Fabian Kung Wai Lee 19

Recap - Wave Propagation Stability Perspective (1)

• From our discussion of stability from wave propagation in Chapter 7…

Z1 or Γ1

bs

bsΓ1

bsΓs Γ1

bsΓs Γ12

bsΓs 2Γ1

2

bsΓs 2Γ1

3

Source 2-port

Network

Zs or ΓsPort 1 Port 2

s

s

sssss

ba

bbba

ΓΓ−=⇒

+ΓΓ+ΓΓ+=

11

22111

1

...

bsΓs 3Γ1

3

bsΓs 3Γ1

4

a1b1

Compare with

equation (2.1a)

ssb

b

s

s

sssss

bb

bbbb

ΓΓ−

Γ=⇒

ΓΓ−

Γ=⇒

+ΓΓ+ΓΓ+Γ=

1

11

1

11

231

2111

1

1

...

( ) ( )( ) ( )sFsA

sA

iSoS

s−

=1

Similar mathematical

form

April 2012 2006 by Fabian Kung Wai Lee 20

Recap - Wave Propagation Stability Perspective (2)

• We see that the infinite series that constitute the steady-state incident

(a1) and reflected (b1) waves at Port 1 will only converge provided

|Γ sΓ1| < 1.

• These sinusoidal waves correspond to the voltage and current at the

Port 1. If the waves are unbounded it means the corresponding

sinusoidal voltage and current at the Port 1 will grow larger as time

progresses, indicating oscillation start-up condition.

• Therefore oscillation will occur when |Γ sΓ1 | > 1.

• Similar argument can be applied to port 2 since the signals at Port 1

and 2 are related to each other in a two-port network, and we see that

the condition for oscillation at Port 2 is |ΓLΓ2 | > 1.

Page 11: Lesson 9

11

Oscillation from Negative Resistance Perspective (1)

• Generally it is more useful to work with impedance (or admittance) when

designing actual circuit.

• Furthermore for practical purpose the transmission lines connecting ZL

and Zs to the destabilized amplifier are considered very short (length → 0).

• In this case the impedance Zo is ambiguous (since there is no

transmission line).

• To avoid this ambiguity, let us ignore the transmission line and examine

the condition for oscillation phenomena in terms of terminal impedance.

April 2012 2006 by Fabian Kung Wai Lee 21

1ZZ ≅

Zs ZoZ1

Destabilized

Amp. and

Load

sZZ ≅

Very short Tline

April 2012 2006 by Fabian Kung Wai Lee 22

Source

Network

Port 1

Zs Z1

( ) ss

sss

VZZ

ZV

XXjRR

jXRV

1

1

11

11

+=⋅

+++

+=

Oscillation from Negative Resistance Perspective (2)

• We consider Port 1 as shown, with the source network and input of the

amplifier being modeled by impedance or series networks.

• Using circuit theory the voltage at Port 1 can be written as:

(3.1)

jXs

Rs

jX1

R1

V ZL

Z2

Vamp

Port 2

Amplifier with load ZL

Page 12: Lesson 9

12

Oscillation from Negative Resistance Perspective (3)

• Furthermore we assume the source network Zs is a series RC network

and the equivalent circuit looking into the amplifier Port 1 is a series RL

network.

• Using Laplace Transform, (3.1) is written as:

April 2012 2006 by Fabian Kung Wai Lee 23

Rs

Cs

R1

L1

V ZL

Z2

Vamp

Vs

Zs Z1

( ) ( )sVsLRR

sLRsV s

sCs s

⋅+++

+=

111

11

ωσ js +=where

(3.2a)

(3.2b)

Oscillation from Negative Resistance Perspective (4)

• The expression for V(s) can be written in the “standard” form according

to Control Theory [8]:

• The transfer function V(s)/Vs(s) is thus a 2nd order system with two poles

p1, p2 given by:

• Observe that if (R1 + Rs) < 0 the damping factor δ is negative. This is

true if R1 is negative, and |R1| > Rs.

• R1 can be made negative by modifying the amplifier circuit (e.g. adding

local positive feedback), producing the sum R1 + Rs < 0.

April 2012 2006 by Fabian Kung Wai Lee 24

( ) ( )( )

( )22

2

11

12

11

1 2

1

11

1

nn

ns

CLL

RR

s ss

sLRsC

ss

sLRs

Ls

V

V

s

s ωδω

ω

++

+=

++

+⋅=

+

Frequency Natural Factor Damping11

1 1

2

====+

s

s

s

CLn

CL

RR ωδ

(3.3a)

where

12

2,1 −±−= δωδω nnp (3.4)

(3.3b)

Page 13: Lesson 9

13

Oscillation from Negative Resistance Perspective (5)

• Assuming |δ|<1 (under-damped), the poles as in (3.4) will be complex

and exist at the right-hand side of the complex plane.

• From Control Theory such a system is unstable. Any small perturbation

will result in a oscillating signal with frequency that grows

exponentially.

• Usually a transient or noise signal from the environment will contain a

small component at the oscillation frequency. This forms the ‘seed’ in

which the oscillation builts up.April 2012 2006 by Fabian Kung Wai Lee

25

0|1 <+o

RRs ω ×

×

Re

Im

0

Complex pole pair

Complex Plane

t

A small disturbance

or impulse ‘starts’ the

exponentially growing

sinusoid

Time

Domain

v(t)

12 −δωn

Oscillation from Negative Resistance Perspective (6)

• When the signal amplitude builds up, nonlinear effects such as

transistor saturation and cut-off will occur, this limits the β of the

transistor and finally limits the amplitude of the oscillating signal.

• The effect of decreasing β of the transistor is a reduction in the

magnitude of R1 (remember R1 is negative). Thus the damping factor δwill approach 0, since Rs+ R1 → 0.

• Steady-state sinusoidal oscillation is achieved when δ =0, or

equivalently the poles become

• The steady-state oscillation frequency ωo corresponds to ωn,

April 2012 2006 by Fabian Kung Wai Lee 26

sCnCLnXXL

sns=⇒=⇒= 1

11

12

1 ωωω

njp ωδ

±==02,1

01 =+⇒o

sXXω

Page 14: Lesson 9

14

Oscillation from Negative Resistance Perspective (7)

• From (3.3b), we observe that the steady-state oscillation frequency is

determined by L1 and Cs, in other words, X1 and Xs respectively.

• Since the voltages at Port 1 and Port 2 are related, if oscillation occur

at Port 1, then oscillation will also occur at Port 2.

• From this brief discussion, we use RC and RL networks for the source

and amplifier input respectively, however we can distill the more

general requirements for oscillation to start-up and achieve steady-

state operation for series representation in terms of resistance and

reactance:

April 2012 2006 by Fabian Kung Wai Lee 27

0|1 <+o

RRs ω

0|1 =+o

XX s ω

0|1 =+o

RRs ω

0|1 =+o

XX s ω

(3.6a)

(3.6b)

(3.5a)

(3.5b)

Steady-stateStart-up

Illustration of Oscillation Start-Up and Steady-State

• The oscillation start-up process and steady-state are illustrated.

April 2012 2006 by Fabian Kung Wai Lee 28

0 10 20 30 40 50 60 70 80 90 100 110 120

-0.8

-0.6

-0.4

-0.2

0.0

0.2

0.4

0.6

0.8

1.0

1.2

1.4

Destabilized

Amplifier

ZLZs

t

R1+Rs

0

Oscillation

start-upSteady-state

Z1Zs

We need to note that this is a very simplistic view of oscillators.

Oscillators are autonomous non-linear dynamical systems, and the steady-state

condition is a form of Limit Cycles.

Page 15: Lesson 9

15

April 2012 2006 by Fabian Kung Wai Lee 29

Source

Network

Port 1

Zs Z1

Summary of Oscillation Requirements Using Series Network

• By expressing Zs and Z1 in terms of resistance and reactance, we

conclude that the requirement for oscillation are.

• A similar expression for Z2 and ZL can also be obtained, but we shall not

be concerned with these here.

jXs

Rs

jX1

R1

V ZL

Z2

Vamp

Port 2

0|1 <+o

RRs ω

0|1 =+o

XX s ω

0|1

=+o

RRs ω

0|1 =+o

XX s ω

(3.6a)

(3.6b)

(3.5a)

(3.5b)

Steady-state Start-up

The Resonator

• The source network Zs is usually called the Resonator, as it is clear

that equations (3.5b) and (3.6b) represent the resonance condition

between the source network and the amplifier input.

• The design of the resonator is extremely important.

• We shall see later that an important parameter of the oscillator, the

Phase Noise is dependent on the quality of the resonator.

April 2012 2006 by Fabian Kung Wai Lee 30

Page 16: Lesson 9

16

Summary of Oscillation Requirements Using Parallel Network

• If we model the source network and input to the amplifier as parallel

networks, the following dual of equations (3.5) and (3.6) are obtained.

• The start-up and steady-state conditions are:

April 2012 2006 by Fabian Kung Wai Lee 31

jBsGs jB1G1

V ZL

Z2

Vamp

Port 1

0|1 =+o

GGs ω

0|1 =+o

BBs ω

0|1 <+o

GGs ω

0|1 =+o

BBs ω

Steady-state Start-up

(3.7a)

(3.7b)

(3.8a)

(3.8b)

Series or Parallel Representation? (1)

• The question is which to use? Series or parallel network

representation? This is not an easy question to answer as the

destabilized amplifier is operating in nonlinear region as oscillator.

• Concept of impedance is not valid and our discussion is only an

approximation at best.

• We can assume series representation, and worked out the

corresponding resonator impedance. If after computer simulation we

discover that the actual oscillating frequency is far from our prediction

(if there’s any oscillation at all!), then it probably means that the series

representation is incorrect, and we should try the parallel

representation.

• Another clue to whether series or parallel representation is more

accurate is to observe the current and voltage in the resonator. For

series circuit the current is near sinusoidal, where as for parallel circuit

it is the voltage that is sinusoidal.April 2012 2006 by Fabian Kung Wai Lee 32

Page 17: Lesson 9

17

Series or Parallel Representation? (2)

• Reference [7] illustrates another effective alternative, by computing the

large-signal S11 of Port 1 (with respect to Zo) using CAD software.

• 1/S11 is then plotted on a Smith Chart as a function of input signal

magnitude at the operating frequency.

• By comparing the locus of 1/S11 as input signal magnitude is gradually

increased with the coordinate of constant X or constant B circles on the

Smith Chart, we can decide whether series or parallel form

approximates Port 1 best.

• We will adopt this approach, but plot S11 instead of 1/S11. This will be

illustrated in the examples in next section.

• Do note that there are other reasons that can cause the actual

oscillation frequency to deviate a lot from prediction, such as frequency

stability issue (see [1] and [7]).

April 2012 2006 by Fabian Kung Wai Lee 33

April 2012 2006 by Fabian Kung Wai Lee 34

4.0 Fixed Frequency Negative Resistance

Oscillator Design

Page 18: Lesson 9

18

April 2012 2006 by Fabian Kung Wai Lee 35

Procedures of Designing Fixed Frequency Oscillator (1)

• Step 1 - Design a transistor/FET amplifier circuit.

• Step 2 - Make the circuit unstable by adding positive feedback at radio

frequency, for instance, adding series inductor at the base for common-

base configuration.

• Step 3 - Determine the frequency of oscillation ωo and extract S-

parameters at that frequency.

• Step 4 – With the aid of Smith Chart and Load Stability Circle, make R1

< 0 by selecting ΓL in the unstable region.

• Step 5 (Optional) – Perform a large-signal analysis (e.g. Harmonic

Balance analysis) and plot large-signal S11 versus input magnitude on

Smith Chart. Decide whether series or parallel form to use.

• Step 6 - Find Z1 = R1 + jX1 (Assuming series form).

April 2012 2006 by Fabian Kung Wai Lee 36

Procedures of Designing Fixed Frequency Oscillator (2)

• Step 7 – Find Rs and Xs so that R1 + Rs<0, X1 + Xs=0 at ωo. We can

use the rule of thumb Rs=(1/3)|R1| to control the harmonics content at

steady-state.

• Step 8 - Design the impedance transformation network for Zs and ZL.

• Step 9 - Built the circuit or run a computer simulation to verify that the

circuit can indeed starts oscillating when power is connected.

• Note: Alternatively we may begin Step 4 using Source Stability

Circle, select Γs in the unstable region so that R2 or G2 is negative at

ωo .

Page 19: Lesson 9

19

April 2012 2006 by Fabian Kung Wai Lee 37

Making an Amplifier Unstable (1)

• An amplifier can be made unstable by providing some kind of local

positive feedback.

• Two favorite transistor amplifier configurations used for oscillator

design are the Common-Base configuration with Base feedback and

Common-Emitter configuration with Emitter degeneration.

April 2012 2006 by Fabian Kung Wai Lee 38

Making an Amplifier Unstable (2)

Vout

Vin

L_StabCircleL_StabCircle1

LSC=l_stab_circle(S,51)

LStabCircle

S_StabCircle

S_StabCircle1SSC=s_stab_circle(S,51)

SStabCircle

StabFactStabFact1

K=stab_fact(S)

StabFact

RRe

R=100 Ohm

S_Param

SP1

Step=2.0 MHz

Stop=410.0 MHzStart=410.0 MHz

S-PARAMETERS

DC

DC1

DC

CCLB

C=0.17 pF

C

CbC=10.0 nF

L

LB

R=L=22 nH

R

RLB

R=0.77 Ohm

C

Cc2C=10.0 nF

CCc1

C=10.0 nF TermTerm1

Z=50 Ohm

Num=1

L

LC

R=

L=330.0 nH

LLE

R=

L=330.0 nH

V_DC

SRC1Vdc=4.5 V

TermTerm2

Z=50 OhmNum=2

R

Rb1R=10 kOhm

R

Rb2R=4.7 kOhm

pb_phl_BFR92A_19921214Q1

Positive feedback

here

Common Base

Configuration

This is a practical model

of an inductor

An inductor is added

in series with the bypass

capacitor on the base

terminal of the BJT.

This is a form of positive

series feedback.

Base bypass

capacitor

At 410MHz

Page 20: Lesson 9

20

April 2012 2006 by Fabian Kung Wai Lee 39

Making an Amplifier Unstable (3)

freq410.0MHz

K-0.987

freq410.0MHz

S(1,1)1.118 / 165.6...

S(1,2)0.162 / 166.9...

S(2,1)2.068 / -12.723

S(2,2)1.154 / -3.535

Unstable Regions

s22 and s11 have magnitude > 1

ΓL PlaneΓs Plane

April 2012 2006 by Fabian Kung Wai Lee 40

Making an Amplifier Unstable (4)

Vout

pb_phl_BFR92A_19921214

Q1

C

Ce1

C=15.0 pF

C

Ce2

C=10.0 pF

R

Rb1

R=10 kOhm

R

Rb2

R=4.7 kOhm

Term

Term1

Z=50 Ohm

Num=1

C

Cc1

C=1.0 nF

R

Re

R=100 Ohm

C

Cc2

C=1.0 nF

L_StabCircle

L_StabCircle1

LSC=l_stab_circle(S,51)

LStabCircle

S_StabCircle

S_StabCircle1

SSC=s_stab_circle(S,51)

SStabCircle

StabFact

StabFact1

K=stab_fact(S)

StabFact

S_Param

SP1

Step=2.0 MHz

Stop=410.0 MHz

Start=410.0 MHz

S-PARAMETERS

DC

DC1

DC

L

LC

R=

L=330.0 nH

V_DC

SRC1

Vdc=4.5 V

Term

Term2

Z=50 Ohm

Num=2

Positive feedback here

Common Emitter

Configuration

Feedback

Page 21: Lesson 9

21

April 2012 2006 by Fabian Kung Wai Lee 41

Making an Amplifier Unstable (5)

freq410.0MHz

K-0.516

freq

410.0MHz

S(1,1)

3.067 / -47.641

S(1,2)

0.251 / 62.636

S(2,1)

6.149 / 176.803

S(2,2)

1.157 / -21.427

Unstable

Regions

S22 and S11 have magnitude > 1

ΓL Plane Γs Plane

April 2012 2006 by Fabian Kung Wai Lee 42

Precautions

• The requirement Rs= (1/3)|R1| is a rule of thumb to provide the excess gain to start up oscillation.

• Rs that is too large (near |R1| ) runs the risk of oscillator fails to start up due to component characteristic deviation.

• While Rs that is too small (smaller than (1/3)|R1|) causes too much non-linearity in the circuit, this will result in large harmonic distortion of the output waveform.

V2

Clipping, a sign of too much nonlinearity

t

Rs too small

t

V2

Rs too large

For more discussion about the Rs = (1/3)|R1| rule,

and on the sufficient condition for oscillation, see

[6], which list further requirements.

Page 22: Lesson 9

22

April 2012 2006 by Fabian Kung Wai Lee 43

Aid for Oscillator Design - Constant |ΓΓΓΓ1| Circle (1)

• In choosing a suitable ΓL to make |ΓL | > 1, we would like to know the

range of ΓL that would result in a specific |Γ1 |.

• It turns out that if we fix |Γ1 |, the range of load reflection coefficient that

result in this value falls on a circle in the Smith chart for ΓL .

• The radius and center of this circle can be derived from:

• Assuming ρ = |Γ1 |:

L

L

S

DS

Γ−

Γ−=Γ

22

111

1

222

2211

**22

2

centerTSD

SDS

ρ

ρ

+−=

222

22

2112Radius

SD

SS

ρρ

−=

By fixing |Γ1 | and changing ΓL .

(4.1a) (4.1b)

April 2012 2006 by Fabian Kung Wai Lee 44

Aid for Oscillator Design - Constant |ΓΓΓΓ1| Circle (2)

• The Constant |Γ1 | Circle is extremely useful in helping us to choose a

suitable load reflection coefficient. Usually we would choose ΓL that

would result in |Γ1 | = 1.5 or larger.

• Similarly Constant |Γ2 | Circle can also be plotted for the source

reflection coefficient. The expressions for center and radius is similar

to the case for Constant |Γ1 | Circle except we interchange s11 and s22,

ΓL and Γs . See Ref [1] and [2] for details of derivation.

Page 23: Lesson 9

23

April 2012 2006 by Fabian Kung Wai Lee 45

Example 4.1 – CB Fixed Frequency Oscillator Design

• In this example, the design of a fixed frequency oscillator operating at 410MHz will be demonstrated using BFR92A transistor in SOT23 package. The transistor will be biased in Common-Base configuration.

• It is assumed that a 50Ω load will be connected to the output of the oscillator. The schematic of the basic amplifier circuit is as shown in the following slide.

• The design is performed using Agilent’s ADS software, but the author would like to stress that virtually any RF CAD package is suitable for this exercise.

April 2012 2006 by Fabian Kung Wai Lee 46

Example 4.1 Cont...

• Step 1 and 2 - DC biasing circuit design and S-parameter extraction.

DC

DC1

DC

S_Param

SP1

Step=2.0 MH z

Stop=410.0 MHz

Start=410.0 MH z

S-PARAME TERS

StabFact

StabFact1

K=stab_f act (S )

S t abFac t

L

LC

R=

L=330.0 nH

L

LE

R=

L=220.0 nH

L

LB

R =

L=12.0 nH

S_StabCircle

S_StabCircle1

source_s tabc ir=s_stab_c irc le(S ,51)

SStabCircle

L_StabCircle

L_StabCircle1

load_s tabcir=l_s tab_c irc le(S,51)

LSt abCircle

Term

Term 1

Z=50 OhmNum=1

C

Cc1

C=1.0 nF

Term

Term 2

Z=50 Ohm

Num=2

C

Cc2

C=1.0 nF

R

R e

R =100 Ohm

C

C b

C =1.0 nF

V_DC

SRC1

Vdc=4.5 V R

Rb1

R=10 kO hm

R

Rb2

R=4.7 kOhm

pb_phl_BFR 92A_19921214Q1

Port 1 - Input

Port 2 - Output

AmplifierPort 1 Port 2

LB is chosen care-fully so that theunstable regionsin both ΓL and Γs

planes are largeenough.

Page 24: Lesson 9

24

April 2012 2006 by Fabian Kung Wai Lee 47

Example 4.1 Cont...

freq410.0MHz

K-0.987

freq410.0MHz

S(1,1)1.118 / 165.6...

S(1,2)0.162 / 166.9...

S(2,1)2.068 / -12.723

S(2,2)1.154 / -3.535

Unstable Regions

Load impedance here will result

in |Γ1| > 1

Source impedance here will result

in |Γ2| > 1

April 2012 2006 by Fabian Kung Wai Lee 48

Example 4.1 Cont...

• Step 3 and 4 - Choosing suitable ΓL that cause |Γ1 | > 1 at 410MHz. We

plot a few constant |Γ1 | circles on the ΓL plane to assist us in choosing

a suitable load reflection coefficient.

LSC

|Γ1 |=1.5

|Γ1 |=2.0

|Γ1 |=2.5

ΓL = 0.5<0

This point is chosen

because it is on

real line and easily

matched.

ΓL Plane

Note: More difficult

to implement load

impedance near

edges of Smith

Chart

ZL = 150+j0

Page 25: Lesson 9

25

Example 4.1 Cont...

• Step 5 – To check whether the input of the destabilized amplifier is

closer to series or parallel form. We perform large-signal analysis and

observe the S11 at the input of the destabilized amplifier.

April 2012 2006 by Fabian Kung Wai Lee 49

LSSP

HB1

Step=0.2Stop=-5

Start=-20

SweepVar="Poutv"LSSP_FreqAtPort[1]=

Order[1]=5

Freq[1]=410.0 MHz

LSSP

R

RLR=150 Ohm

VARVAR1

Poutv=-10.0

EqnVar

P_1Tone

PORT1

Freq=410 MHz

P=polar(dbmtow(Poutv),0)

Z=50 OhmNum=1

CCc2

C=1.0 nF

CCc1

C=1.0 nF

L

LB

R=

L=12.0 nH

C

CBC=1.0 nF

V_DC

SRC1Vdc=4.5 V

RRE

R=100 Ohm

L

LE

R=L=220.0 nH

R

RB2R=4.7 kOhm

RRB1

R=10 kOhm

L

LC

R=

L=330.0 nH

pb_phl_BFR92A_19921214

Q1

We are measuringlarge-signal S11 lookingtowards here

Large-signal S-parameterAnalysis controlin ADS software.

Example 4.1 Cont...

• Compare the locus of S11 and the constant X and constant B circles on

the Smith Chart, it is clear the locus is more parallel to the constant X

circle. Also the direction of S11 is moving from negative R to positive R

as input power level is increased. We conclude the Series form is more

appropriate.

April 2012 2006 by Fabian Kung Wai Lee 50

Region where R1 or G1 is negative

Poutv (-20.000 to -5.000)

S(1

,1)

Direction of S11 as magnitudeof P_1tone source is increased

Compare

Locus of S11 versus P_1tone power at 410MHz(from -20 to -5 dBm)

Boundary ofNormal Smith Chart

Region where R1 or G1 is positive

Page 26: Lesson 9

26

April 2012 2006 by Fabian Kung Wai Lee 51

Example 4.1 Cont...

• Step 6 – Using the series form, we find the small-signal input impedance

Z1 at 410MHz. So the resonator would also be a series network.

• For ZL = 150 or ΓL = 0.5<0:

• Step 7 - Finding the suitable source impedance to fulfill R1 + Rs<0, X1 +

Xs=0:

851.7257.101

1

479.0422.11

1

11

22

111

jZZ

jS

DS

o

L

L

+−=Γ−

Γ+=

+−=Γ−

Γ−=Γ

851.7

42.33

1

1

1

−≅−=

≅=

XX

RR

s

s

R1

X1

April 2012 2006 by Fabian Kung Wai Lee 52

Example 4.1 Cont...

Common-Base (CB)

Amplifier

with feedback

Port 1 Port 2Zs = 3.42-j7.851

ZL = 150

• The system block diagram:

Page 27: Lesson 9

27

April 2012 2006 by Fabian Kung Wai Lee 53

Example 4.1 Cont...

pFC

C

44.49851.7

1

1851.7

==

=

ω

ω

CB Amplifier3.42

27.27nH49.44pF

50

Zs= 3.42-j7.851 ZL=150

@ 410MHz3.49pF

• Step 5 - Realization of the source and load impedance at 410MHz.

Impedance transformation network

April 2012 2006 by Fabian Kung Wai Lee 54

Example 4.1 Cont... - Verification Thru Simulation

Vpp = 0.9V

V = 0.45V

Power dissipated in the load:

mW

R

VP

LL

025.250

45.05.0

2

1

2

2

==

=

BFR92A

Vpp

Page 28: Lesson 9

28

April 2012 2006 by Fabian Kung Wai Lee 55

Example 4.1 Cont... - Verification Thru Simulation

• Performing Fourier Analysis on the steady state wave form:

484 MHz

The waveform is very clean with

little harmonic distortion. Although

we may have to tune the capacitor

Cs to obtain oscillation at 410 MHz.

April 2012 2006 by Fabian Kung Wai Lee 56

Example 4.1 Cont... – The Prototype

0 10 20 30 40 50 60 70 80 90 100 110 120

-0.8

-0.6

-0.4

-0.2

0.0

0.2

0.4

0.6

0.8

1.0

1.2

1.4

Voltage at the base terminal and 50 Ohms load resistor of the

fixed frequency oscillator:

Output portVout

Vbb

V

nsStartup transient

Page 29: Lesson 9

29

Example 4.2 – 450 MHz CE Fixed Frequency Oscillator Design

• Small-signal AC or S-parameter analysis, to show that R1 or G1 is

negative at the intended oscillation frequency of 450 MHz.

April 2012 2006 by Fabian Kung Wai Lee 57

S_ParamSP1

Step=10.0 MHzStop=800.0 MHzStart=100.0 MHz

S-PARAMETERS

TermTerm1

Z=50 OhmNum=1

CC2C=4.7 pF

RRL

R=150 Ohm

C

Cc2C=330.0 pF

V_DCSRC1

Vdc=3.0 V

LLC

R=L=220.0 nH

RRER=220 Ohm

RRBR=47 kOhm

DC_BlockDC_Block1

CC1C=2.2 pF

pb_phl_BFR92A_19921214Q1

200 300 400 500 600 700100 800

-500

-400

-300

-200

-100

-600

0

-1500

-1000

-500

-2000

0

freq, MHz

rea

l(Z

(1,1

))

ima

g(Z

(1,1

))

200 300 400 500 600 700100 800

-0.010

-0.005

-0.015

0.000

0.005

0.010

0.015

0.000

0.020

freq, MHz

rea

l(Y

(1,1

))

ima

g(Y

(1,1

))

Selection of load

resistor as in

Example 4.1.

There are simplified

expressions to find C1

and C2, see reference [5].

Here we just trial and

error to get some

reasonable values.

Destabilized amplifier

Example 4.2 Cont…

• The large-signal analysis to check for suitable representation.

April 2012 2006 by Fabian Kung Wai Lee 58

Poutv (-5.000 to 15.000)

S(1

,1)

LSSPHB1

Step=0.2Stop=15Start=-5Sw eepVar="Poutv"

LSSP_FreqAtPort[1]=Order[1]=7Freq[1]=450.0 MHz

LSSP

CC2C=4.7 pF

P_1Tone

PORT1

Freq=450 MHzP=polar(dbmtow (Poutv),0)Z=50 OhmNum=1

RRL

R=150 Ohm

C

Cc2C=330.0 pF

V_DCSRC1

Vdc=3.0 V

LLC

R=L=220.0 nH

RRER=220 Ohm

RRBR=47 kOhm

DC_BlockDC_Block1 C

C1C=2.2 pF

VARVAR1Poutv=-10.0

EqnVar

pb_phl_BFR92A_19921214Q1

Direction of S11 as magnitude

of P_1tone source is increased

from -5 to +15 dBm

Compare

Since the locus of S11 is close in shape to

constant X circles, and it indicates R1 goes from

negative value to positive values as input power

is increased, we use series form to

represent the input network looking towards

the Base of the amplifier.

Boundary of

Normal Smith Chart

S11

Page 30: Lesson 9

30

Example 4.2 Cont…

• Using a series RL for the resonator, and performing time-domain

simulation to verify that the circuit will oscillate.

April 2012 2006 by Fabian Kung Wai Lee 590.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.50.0 5.0

0.2

0.4

0.6

0.0

0.8

freq, GHz

ma

g(V

fL)

m1

m1freq=mag(VfL)=0.733

450.0MHz

VLVC

VB

L

L1

R=10

L=39.0 nH

VtPWL

SRC2

V_Tran=pw l(time, 0ns,0V, 2ns,0.1V, 4ns,0V)

t

Tran

Tran1

MaxTimeStep=1.0 nsec

StopTime=100.0 nsec

TRANSIENT

C

Cc1C=1.0 nF

C

C2C=4.7 pF

R

RL

R=150 Ohm

C

Cc2C=330.0 pF

V_DC

SRC1Vdc=3.0 V

L

LC

R=

L=220.0 nH

R

RER=220 Ohm

RRBR=47 kOhm

C

C1C=2.2 pF

pb_phl_BFR92A_19921214Q1

20 40 60 800 100

-1.0

-0.5

0.0

0.5

-1.5

1.0

time, nsec

VL

, V

Eqn VfL=fs(VL)

vL(t)

|VL(f)|Large coupling

capacitor

Example 4.3 – Parallel Representation

• An example where the network looking into the Base of the destabilized

amplifier is more appropriate as parallel RC network.

April 2012 2006 by Fabian Kung Wai Lee 60

Poutv (-7.000 to 12.000)

S(1

,1)

V_DC

VCCVdc=3.3 V

R

RE

R=100 Ohm

LLC

R=0.2L=2 nH

R

RB1R=1000 Ohm

R

RL

R=50 Ohm

VAR

VAR5

fo=2300

Poutv=1.0

EqnVar

LSSP

HB1

Step=0.2

Stop=12

Start=-7

SweepVar="Poutv"

LSSP_FreqAtPort[1]=fo MHzOrder[1]=8

Freq[1]=fo MHz

LSSP

CCdec1

C=100.0 pF

P_1Tone

PORT1

Freq=fo MHzP=polar(dbmtow(Poutv),0)

Z=50 Ohm

Num=1

C

Cc1

C=1.2 pF

CCc2

C=1.0 pF

CC2

C=0.7 pF t

CC1

C=0.6 pF t

R

RB2

R=1000 Ohm

pb_phl_BFR92A_19921214

Q1

S11

Compare

Direction of S11 as magnitude

of P_1tone source is increased

from -7 to +12 dBm

S11 versus

Input power

Page 31: Lesson 9

31

Frequency Stability

• The process of oscillation depends on the non-linear behavior of the

negative-resistance network.

• The conditions discussed, e.g. equations (3.1), (3.8), (3.9), (3.10) and

(3.11) are not enough to guarantee a stable state of oscillation. In

particular, stability requires that any perturbation in current, voltage and

frequency will be damped out, allowing the oscillator to return to it’s

initial state.

• The stability of oscillation can be expressed in terms of the partial

derivative of the sum Zin + Zs or Yin + Ys of the input port (or output

port).

• The discussion is beyond the scope of this chapter for now, and the

reader should refer to [1] and [7] for the concepts.

April 2012 2006 by Fabian Kung Wai Lee 61

April 2012 2006 by Fabian Kung Wai Lee 62

Some Steps to Improve Oscillator Performance

• To improve the frequency stability of the oscillator, the following steps

can be taken.

• Use components with known temperature coefficients, especially

capacitors.

• Neutralize, or swamp-out with resistors, the effects of active device

variations due to temperature, power supply and circuit load changes.

• Operate the oscillator on lower power.

• Reduce noise, use shielding, AGC (automatic gain control) and bias-

line filtering.

• Use an oven or temperature compensating circuitry (such as

thermistor).

• Use differential oscillator architecture (see [4] and [7]).

Page 32: Lesson 9

32

Extra References for This Section

• Some recommended journal papers on frequency stability of oscillator:

• Kurokawa K., “Some basic characteristics of broadband negative

resistance oscillator circuits”, Bell System Technical Journal, pp. 1937-

1955, 1969.

• Nguyen N.M., Meyer R.G., “Start-up and frequency stability in high-

frequency oscillators”,IEEE journal of Solid-State Circuits, vol 27, no. 5

pp.810-819, 1992.

• Grebennikov A. V., “Stability of negative resistance oscillator circuits”,

International journal of Electronic Engineering Education, Vol. 36, pp.

242-254, 1999.

April 2012 2006 by Fabian Kung Wai Lee 63

Reconciliation Between Feedback and Negative Resistance Oscillator

Perspectives• It must be emphasized that the circuit we obtained using negative

resistance approach can be cast into the familiar feedback form. For

instance an oscillator circuit similar to Example 4.2 can be redrawn as:

April 2012 2006 by Fabian Kung Wai Lee 64

VL

C

Cc1

C=4.7 pF

R

RL

R=50 Ohm

C

Cc2

C=1.0 pF

L

L1

R=0.1

L=15.0 nH t

R

RB1

R=10000 Ohm t

L

LC

R=0.2

L=2.2 nH t

C

C1

C=1.0 pF t

C

C2

C=0.8 pF tR

RE

R=100 Ohm t

pb_phl_BFR92A_19921214

Q1

V_DC

VCC

Vdc=3.0 V

VL

R

RL

R=50 Ohm

R

RE

R=100 Ohm t

pb_phl_BFR92A_19921214Q1

C

C2

C=0.8 pF t

C

C1

C=1.0 pF t

L

L1

R=0.1

L=15.0 nH t

C

Cc1

C=4.7 pF

C

Cc2

C=1.0 pF

R

RB1

R=10000 Ohm t

L

LC

R=0.2L=2.2 nH t

V_DC

VCC

Vdc=3.0 V

Amplifier

Feedback

Network

Negative Resistance

Oscillator

Page 33: Lesson 9

33

April 2012 2006 by Fabian Kung Wai Lee 65

5.0 Voltage Controlled Oscillator

April 2012 2006 by Fabian Kung Wai Lee 66

About the Voltage Controlled Oscillator (VCO) (1)

• A simple transistor VCO using Clapp-Gouriet or CE configuration will be

designed to illustrate the principles of VCO.

• The transistor chosen for the job is BFR92A, a wide-band NPN

transistor which comes in SOT-23 package.

• Similar concepts as in the design of fixed-frequency oscillators are

employed. Where we design the biasing of the transistor, destabilize the

network and carefully choose a load so that from the input port (Port 1),

the oscillator circuit has an impedance (assuming series representation

is valid):

• Of which R1 is negative, for a range of frequencies from ω1 to ω2.

( ) ( ) ( )ωωω 111 jXRZ +=

Lower Upper

Page 34: Lesson 9

34

April 2012 2006 by Fabian Kung Wai Lee 67

About the Voltage Controlled Oscillator (VCO) (2)

Clapp-Gouriet

Oscillator Circuit

with LoadZs

Z1 = R1 + jX1

ZL

April 2012 2006 by Fabian Kung Wai Lee 68

About the Voltage Controlled Oscillator (VCO) (3)

• If we can connect a source impedance Zs to the input port, such that within a range of frequencies from ω1 to ω2:

• The circuit will oscillate within this range of frequencies. By changing the value of Xs, one can change the oscillation frequency.

• For example, if X1 is positive, then Xs must be negative, and it can be generated by a series capacitor. By changing the capacitance, one can change the oscillation frequency of the circuit.

• If X1 is negative, Xs must be positive. A variable capacitor in series with a suitable inductor will allow us to adjust the value of Xs.

( ) ( ) ( )ωωω sss jXRZ +=

( ) ( ) ( ) 0 11 << ωωω RRRs ( ) ( ) 1 ωω XX s =

The rationale is that only the initial spectral of the noise

signal fulfilling Xs = X1 will start the oscillation.

Page 35: Lesson 9

35

April 2012 2006 by Fabian Kung Wai Lee 69

Schematic of the VCO

R

RL

R=Rload

ParamSweep

Sweep1

St ep=100

St op=700

St art=100

SimIns tanceNam e[6]=

SimIns tanceNam e[5]=

SimIns tanceNam e[4]=

SimIns tanceNam e[3]=

SimIns tanceNam e[2]=

SimIns tanceNam e[1]="Tran1"

SweepVar="R load"

P ARAM ET ER SWEEP

VAR

VAR 1

R load=100

X=1.0

EqnVar

Tran

Tran1

MaxTimeS tep=1.2 nsec

StopTim e=100. 0 nsec

TRANS IE NT

D C

D C1

DC

C

C b4

C =4.7 pF

V _D C

S RC1

V dc=-1.5 V

C

Cb3

C=4. 7 pF

di_sms_bas40_19930908

D1

L

L2

R =

L=47.0 nH

C

Cb2

C=10. 0 pF

R

R1

R=4700 Ohm

C

Cb1

C=2. 2 pF

R

Rb

R=47 kOhm

pb_phl_BFR92A_19921214

Q1

R

Re

R=220 O hm

L

Lc

R=

L=220.0 nH

R

Rout

R=50 O hm

C

C c2

C =330. 0 pF

V_DC

Vcc

Vdc=3.0 V

VtP WL

Vtrig

V_Tran=pwl(t ime, 0ns , 0V, 1ns,0.01V, 2ns ,0V)t

2-port network

Variable

capacitance

tuning network

Initial noise

source to start

the oscillation

April 2012 2006 by Fabian Kung Wai Lee 70

More on the Schematic

• L2 together with Cb3, Cb4 and the junction capacitance of D1 can

produce a range of reactance value, from negative to positive.

Together these components form the frequency determining network.

• Cb4 is optional, it is used to introduce a capacitive offset to the junction

capacitance of D1.

• R1 is used to isolate the control voltage Vdc from the frequency

determining network. It must be a high quality SMD resistor. The

effectiveness of isolation can be improved by adding a RF choke in

series with R1 and a shunt capacitor at the control voltage.

• Notice that the frequency determining network has no actual

resistance to counter the effect of |R1(ω)|. This is provided by the loss

resistance of L2 and the junction resistance of D1.

Page 36: Lesson 9

36

April 2012 2006 by Fabian Kung Wai Lee 71

Time Domain Result

0 10 20 30 40 50 60 70 80 90 100

-1.5

-1.0

-0.5

0.0

0.5

1.0

Vout when Vdc = -1.5V

April 2012 2006 by Fabian Kung Wai Lee 72

Load-Pull Experiment

100 200 300 400 500 600 700 800

1

2

3

4

5

• Peak-to-peak output voltage versus Rload for Vdc = -1.5V.

Vout(pp)

RLoad

Page 37: Lesson 9

37

April 2012 2006 by Fabian Kung Wai Lee 73

Vout

Controlling Harmonic Distortion (1)

• Since the resistance in the frequency determining network is too small,

large amount of non-linearity is needed to limit the output voltage

waveform, as shown below there is a lot of distortion.

April 2012 2006 by Fabian Kung Wai Lee 74

Controlling Harmonic Distortion (2)

• The distortion generates substantial amount of higher harmonics.

• This can be reduced by decreasing the positive feedback, by adding a

small capacitance across the collector and base of transistor Q1. This

is shown in the next slide.

Page 38: Lesson 9

38

April 2012 2006 by Fabian Kung Wai Lee 75

Controlling Harmonic Distortion (3)

Capacitor to control

positive feedback

CCcbC=1.0 pF

R

RLR=50 Ohm

R

RoutR=50 Ohm

R

ReR=220 Ohm

LLc

R=L=220.0 nH

I_ProbeIC

pb_phl_BFR92A_19921214Q1

TranTran1

MaxTimeStep=1.2 nsecStopTime=280.0 nsec

TRANSIENT

DCDC1

DC

I_Probe

Iload CCc2C=330.0 pF

LL2

R=L=47.0 nH

R

RbR=47 kOhm

CCb1C=6.8 pF

CCb2C=10.0 pF

V_DCSRC1

Vdc=0.5 V

C

Cb4C=0.7 pF

CCb3

C=4.7 pF

di_sms_bas40_19930908D1

RR1R=4700 Ohm

V_DCVccVdc=3.0 V

VtPWLVtrigV_Tran=pwl(time, 0ns,0V, 1ns,0.01V, 2ns,0V)

t

The observantperson wouldprobably noticethat we can alsoreduce the harmonicdistortion by introducinga series resistance inthe tuning network.However this is notadvisable as the phasenoise at the oscillator’soutput will increase (more about this later).

Control voltageVcontrol

April 2012 2006 by Fabian Kung Wai Lee 76

Controlling Harmonic Distortion (4)

• The output waveform Vout after this modification is shown below:

Vout

Page 39: Lesson 9

39

April 2012 2006 by Fabian Kung Wai Lee 77

Controlling Harmonic Distortion (5)

• Finally, it should be noted that we should also add a low-pass filter (LPF) at the output of the oscillator to suppress the higher harmonic components. Such LPF is usually called Harmonic Filter.

• Since the oscillator is operating in nonlinear mode, care must be taken in designing the LPF.

• Another practical design example will illustrate this approach.

April 2012 2006 by Fabian Kung Wai Lee 78

The Tuning Range

• Actual measurement is carried out, with the frequency measured using

a high bandwidth digital storage oscilloscope.

0 0.5 1 1.5 2 2.5395

400

405

410

f

Vdc

MHz

Volts

D1 is BB149A,

a varactor

manufactured by

Phillips

Semiconductor (Now

NXP).

Page 40: Lesson 9

40

Phase Noise in Oscillator (1)

• Since the oscillator output is periodic. In frequency domain we would

expect a series of harmonics.

• In a practical oscillation system, the instantaneous frequency and

magnitude of oscillation are not constant. These will fluctuate as a

function of time.

• These random fluctuations are noise, and in frequency domain the effect

of the spectra will ‘smear out’.

April 2012 2006 by Fabian Kung Wai Lee 79

( ) ( )( ) ( )( )tttmVtv noisenoiseoosc θθω +++= cos

ffo 2fo 3foIdeal oscillator output

ffo 2fo 3fo

t

t

Real oscillator output

Smearing

April 2012 2006 by Fabian Kung Wai Lee 80

Phase Noise in Oscillator (2)

• Mathematically, we can say that the instantaneous frequency and

magnitude of oscillation are not constant. These will fluctuate as a

function of time.

• As a result, the output in the frequency domain is ‘smeared’ out.

t

v(t)

t

v(t)

ffo

ffo

T = 1/fo

Contains both phaseand amplitude modulationof the sinusoidal waveformat frequency fo

( )[ ]2

81log10

offset

o

L f

f

QA

FkTPML ⋅⋅∝

Leeson’s expression

Large phase noise

Small phase noise

Page 41: Lesson 9

41

April 2012 2006 by Fabian Kung Wai Lee 81

Phase Noise in Oscillator (3)

• Typically the magnitude fluctuation is small (or can be minimized) due

to the oscillator nonlinear limiting process under steady-state.

• Thus the smearing is largely attributed to phase variation and is known

as Phase Noise.

• Phase noise is measured with respect to the signal level at various

offset frequencies.

• Phase noise is measured in dBc/Hz @ foffset. • dBc/Hz stands for dB downfrom the carrier (the ‘c’) in 1 Hz bandwidth.• For example -90dBc/Hz @ 100kHz offset from a CW sine wave at 2.4GHz.

- 90dBc/Hz

100kHz

ffo

t

v(t)

Signal level

Assume amplitude limiting effect

Of the oscillator reduces amplitude fluctuation

( ) ( )( )ttVtv noiseoosc θθω ++≅ cos

April 2012 2006 by Fabian Kung Wai Lee 82

Reducing Phase Noise (1)

• Requirement 1: The resonator network of an oscillator must have a high

Q factor. This is an indication of low dissipation loss in the tuning

network (See Chapter 3a – impedance transformation network on Q

factor).

X1

Xtune

-X1

∆f

f

2∆|X1|

Tuning

Network with

High QX1

Xtune

-X1

∆f

f

2∆|X1|

Tuning

Network with

Low Q

Ztune = Rtune +jXtune

Variation in Xtune

due to environmentcauses small changein instantaneousfrequency.

Page 42: Lesson 9

42

April 2012 2006 by Fabian Kung Wai Lee 83

Reducing Phase Noise (2)

• A Q factor in the tuning network of at least 20 is needed for medium

performance oscillator circuits at UHF. For highly stable oscillator, Q

factor of the tuning network must be in excess or 1000.

• We have looked at LC tuning networks, which can give Q factor of up

to 40. Ceramic resonator can provide Q factor greater than 500, while

piezoelectric crystal can provide Q factor > 10000.

• At microwave frequency, the LC tuning networks can be substituted

with transmission line sections.

• See R. W. Rhea, “Oscillator design & computer simulation”, 2nd edition

1995, McGraw-Hill, or the book by R.E. Collin for more discussions on

Q factor.

• Requirement 2: The power supply to the oscillator circuit should also

be very stable to prevent unwanted amplitude modulation at the

oscillator’s output.

Reducing Phase Noise (3)

• Requirement 3: The voltage level of Vcontrol should be stable.

• Requirement 4: The circuit has to be properly shielded from

electromagnetic interference from other modules.

• Requirement 5: Use low noise components in the construction of the

oscillator, e.g. small resistance values, low-loss capacitors and

inductors, low-loss PCB dielectric, use discrete components instead of

integrated circuits.

April 2012 2006 by Fabian Kung Wai Lee 84

Page 43: Lesson 9

43

Example of Phase Noise from VCOs

• Comparison of two VCO outputs on a spectrum analyzer*.

April 2012 2006 by Fabian Kung Wai Lee 85

*The spectrumanalyzer internaloscillator mustof course hasa phase noise ofan order of magnitudelower than our VCOunder test.

VCO output

with high

phase noise VCO output

with low

phase noise

More Materials

• This short discussion cannot do justice to the material on phase noise.

• For instance the mathematical model of phase noise in oscillator and

the famous Leeson’s equation is not shown here. You can find further

discussion in [4], and some material for further readings on this topic:

– D. Schere, “The art of phase noise measurement”, Hewlett Packard

RF & Microwave Measurement Symposium, 1985.

– T. Lee, A. Hajimiri, “The design of low noise oscillators”, Kluwer,

1999.

April 2012 2006 by Fabian Kung Wai Lee 86

Page 44: Lesson 9

44

April 2012 2006 by Fabian Kung Wai Lee 87

More on Varactor

• The varactor diode is basically a PN junction optimized for its linear

junction capacitance.

• It is always operated in the reverse-biased mode to prevent

nonlinearity, which generate harmonics.

• As we increase the negative

biasing voltage Vj , Cj decreases,

hence the oscillation frequency increases.

• The abrupt junction varactor has high

Q, but low sensitivity (e.g. Cj varies

little over large voltage change).

• The hyperabrupt junction varactor

has low Q, but higher sensitivity.

Vj

Vj0

Cj

Linear region

Reverse biased

Forward biasedCjo

April 2012 2006 by Fabian Kung Wai Lee 88

A Better Variable Capacitor Network

• The back-to-back varactors are commonly employed in a VCO circuit, so that at low Vcontrol, when one of the diode is being affected by the AC voltage, the other is still being reverse biased.

• When a diode is forward biased, the PN junction capacitance becomes nonlinear.

• The reverse biased diode has smaller junction capacitance, and this dominates the overall capacitance of the back-to-back varactor network.

• This configuration helps to decrease the harmonic distortion.

At any one time, at least one of

the diode will be reverse biased.

The junction capacitance of the

reverse biased diode will dominate

the overall capacitance of the

network.

Vcontrol

Symbol

for Varactor

To suppress

RF signals

To negativeresistanceamplifier

Vcontrol

Vcontrol

Page 45: Lesson 9

45

April 2012 2006 by Fabian Kung Wai Lee 89

Example 5.1 – VCO Design for Frequency Synthesizer

• To design a low power VCO that works from 810 MHz to 910 MHz.

• Power supply = 3.0V.

• Output power (into 50Ω load) minimum -3.0 dBm.

April 2012 2006 by Fabian Kung Wai Lee 90

Example 5.1 Cont…

• Checking the d.c. biasing and AC simulation.

S_ParamSP1

Step=1.0 MHz

Stop=1.0 GHz

Start=0.7 GHz

S-PARAMETERS

DC

DC1

DC

b82496c3120j000

LC

param=SIMID 0603-C (12 nH +-5%)

4_7pF_NPO_0603

Cc1

100pF_NPO_0603

Cc2

2_2pF_NPO_0603

C1

R

RER=100 Ohm

3_3pF_NPO_0603

C2

R

RL

R=100 Ohm

Term

Term1

Z=50 Ohm

Num=1

V_DC

SRC1

Vdc=3.3 V

R

RBR=33 kOhm

pb_phl_BFR92A_19921214

Q1

Z11

Page 46: Lesson 9

46

April 2012 2006 by Fabian Kung Wai Lee 91

Example 5.1 Cont…

• Checking the results – real and imaginary portion of Z1 when output is

terminated with ZL = 100Ω.

m2freq=m2=-84.412

809.0MHzm1freq=m1=-89.579

775.0MHz

0.72 0.74 0.76 0.78 0.80 0.82 0.84 0.86 0.88 0.90 0.92 0.94 0.96 0.980.70 1.00

-110

-100

-90

-80

-70

-60

-50

-120

-40

freq, GHz

real(Z

(1,1

))

m2

imag(Z

(1,1

))

m1

April 2012 2006 by Fabian Kung Wai Lee 92

Example 5.1 Cont…

• The resonator design.

Vvar

VAR

VAR1

Vcontrol=0.2

EqnVar

C

C3

C=0.68 pF

L

L1

R=

L=10.0 nH

ParamSweep

Sweep1

Step=0.5

Stop=3

Start=0.0

SimInstanceName[6]=

SimInstanceName[5]=

SimInstanceName[4]=

SimInstanceName[3]=SimInstanceName[2]=

SimInstanceName[1]="SP1"

SweepVar="Vcontrol"

PARAMETER SWEEP

L

L2

R=L=33.0 nH

100pF_NPO_0603

C2

V_DC

SRC1

Vdc=Vcontrol V

S_Param

SP1

Step=1.0 MHz

Stop=1.0 GHz

Start=0.7 GHz

S-PARAMETERS

BB833_SOD323

D1

Term

Term1

Z=50 Ohm

Num=1

Page 47: Lesson 9

47

April 2012 2006 by Fabian Kung Wai Lee 93

Example 5.1 Cont…

• The resonator reactance.

m1freq=m1=64.725Vcontrol=0.000000

882.0MHz

0.75 0.80 0.85 0.90 0.950.70 1.00

20

40

60

80

100

0

120

freq, GHz

ima

g(Z

(1,1

)) m1

-im

ag

(VC

O_

ac..

Z(1

,1))

Resonator

reactance

as a function of

control voltage

The theoretical tuning

range

-X1 of the destabilized amplifier

April 2012 2006 by Fabian Kung Wai Lee 94

Example 5.1 Cont…

• The complete schematic with the harmonic suppression filter.

Vvar

b82496c3120j000L3param=SIMID 0603-C (12 nH +-5%)

b82496c3100j000L1param=SIMID 0603-C (10 nH +-5%)

b82496c3330j000L2

param=SIMID 0603-C (33 nH +-5%)

RR1

R=100 Ohm

100pF_NPO_0603C4

b82496c3150j000L4param=SIMID 0603-C (15 nH +-5%)

0_47pF_NPO_0603C9

RRLR=100 Ohm2_7pF_NPO_0603

C8

100pF_NPO_0603Cc2

pb_phl_BFR92A_19921214Q1

TranTran1

MaxTimeStep=1.0 nsec

StopT ime=1000.0 nsec

TRANSIENT

DCDC1

DC

CC7

C=3.3 pF

CC6C=2.2 pF

V_DCSRC2Vdc=1.2 V

C

C5C=0.68 pF

BB833_SOD323D1

VtPWLSrc_triggerV_Tran=pwl(time, 0ns,0V, 1ns,0.1V, 2ns,0V)

t

4_7pF_NPO_0603Cc1

RRER=100 Ohm

V_DCSRC1Vdc=3.3 V

R

RBR=33 kOhm

Low-pass filter

Page 48: Lesson 9

48

April 2012 2006 by Fabian Kung Wai Lee 95

Example 5.1 Cont…

• The prototype and the result captured from a spectrum analyzer (9 kHz

to 3 GHz).

VCOHarmonic

suppression filterFundamental

-1.5 dBm- 30 dBm

April 2012 2006 by Fabian Kung Wai Lee 96

Example 5.1 Cont…

• Examining the phase noise of the oscillator (of course the accuracy is

limited by the stability of the spectrum analyzer used).

300Hz

Span = 500 kHz

RBW = 300 Hz

VBW = 300 Hz-0.42 dBm

Page 49: Lesson 9

49

April 2012 2006 by Fabian Kung Wai Lee 97

Example 5.1 Cont…

• VCO gain (ko) measurement setup:

Spectrum

Analyzer

Vvar

PortVout

Num=2

PortVcontrol

Num=1

RRcontrolR=1000 Ohm

RRattnR=50 Ohm

b82496c3120j000L3

param=SIMID 0603-C (12 nH +-5%)

b82496c3100j000

L1param=SIMID 0603-C (10 nH +-5%)

b82496c3150j000L4param=SIMID 0603-C (15 nH +-5%)

0_47pF_NPO_0603

C92_7pF_NPO_0603

C8

100pF_NPO_0603

Cc2

pb_phl_BFR92A_19921214

Q1

C

C7C=3.3 pF

C

C6C=2.2 pF

CC5

C=0.68 pF

BB833_SOD323D1

4_7pF_NPO_0603

Cc1

RRER=100 Ohm

V_DC

SRC1Vdc=3.3 V

R

RBR=33 kOhm

Variable

power

supply

April 2012 2006 by Fabian Kung Wai Lee 98

Example 5.1 Cont…

• Measured results:

0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0

750

800

850

900

950

fVCO / MHz

Vcontrol/Volts

MHz/Volt 74.40Volt 35.1

MHz 55 =≅ok MHz/Volt 74.40Volt 35.1

MHz 55 =≅ok