lesson 18: increasing efficiency with built · web viewlesson 29: moment distribution method...
TRANSCRIPT
AB C D E F
50 ft 25 ft 50 ft
25 ft EI = Constant
10 ft 10 ft
G H
2 kip/ft
AB C D E F
50 ft 25 ft 50 ft
25 ft EI = Constant
10 ft 10 ft
G H
2 kip/ft
AB C D E F
50 ft 25 ft 50 ft
25 ft EI = Constant
10 ft 10 ft
G H
10 k@ midheight
10 k@ mid
CE412 Spring 2016 Lesson 29: Moment Distribution III
“When I die, I want my remains scattered at Disneyland. Also, I don’t want to be cremated” ― Author UnknownLESSON 29: MOMENT DISTRIBUTION METHOD III
Wednesday, April 06, 2016LESSON OBJECTIVE
1. Use symmetry and anti-symmetry in non-sway moment distribution problems.
READING AND LESSON SCOPE: Hibbeler (8th edition) Sections 12-3, 12-4.
FIXED-END MOMENTS FOR TODAY (Complete Chart in the back of Hibbeler)
HOMEWORK ASSIGNMENTUse shortcuts to solve the problems as simply as possible. Connections are rigid unless a pin connection is indicated.
1. Use moment distribution and plot the moment diagram.
2. Use moment distribution and plot the moment diagram.
3. Use moment distribution and plot the moment diagram.