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  • 7/30/2019 Lecture7 Series and Parallel

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    Online Resource for ETCH 213

    Faculty: B. Allen

    Introduction to Series-Parallel DC Circuits

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    Series-parallel circuit

    A network or circuit that contains components

    that are connected in both series and parallel.

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    Series-parallel resistive circuits

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    Tracking current through a

    series-parallel circuit

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    Total resistance in a series-

    parallel circuitStep 1: Determine the equivalent resistance of all

    branch series-connected resistors.

    Step 2: Determine the equivalent resistance of allparallel-connected combinations.

    Step 3: Determine the equivalent resistance of the

    remaining series-connected resistors.

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    Calculating total resistance

    Find the equivalent resistance for R5 and R6.

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    Find the equivalent resistance for R4

    and R5-6

    .

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    Find the equivalent resistance for R2, R3, and R4-5-6.

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    Find RT.

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    Voltage division in a series-

    parallel circuitFind:

    V1

    V2

    V3

    V4

    V5

    V6

    V7

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    R3-4 = R3 + R4 = 2kohm R 5-6-7 = 1kohm/3 = 333 ohm

    Find R 3-4 and R 5-6-7.

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    R2-3-4 = R2

    R3-4/(R2 + R3-4) = 1k

    2k/(1k + 2k) = 667ohm

    Find R2-3-4

    .

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    RT = 1k +667ohm +333ohm = 2kohm

    V1 = R1/RT VT = 1k/2k 12V = 6V

    V2-3-4 = R2-3-4/RT 12V = 667/2k 12V = 4V

    V5-6-7 = R5-6-7/RT 12V = 333/2k 12V = 2V

    Find RT, V1, V2-3-4, V5-6-7.

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    Voltage division in a series-

    parallel circuit. SummaryFind:

    V1 = 6V

    V2 = 4V

    V3 = 2V

    V4 = 2V

    V5 = 2V

    V6 = 2V

    V7 = 2V

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    Branch current in a series-

    parallel circuitFind:

    I1

    I2

    I3

    I4

    I5

    I6

    I7

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    Find total current

    Since RT = 2kohm,

    IT = VT/RT = 12V/2kohm = 6mA.

    I1 = 6mA.

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    Find I2

    , I3

    , I4

    I2 = R2-3-4/R2 IT = 667ohm/1k 6mA = 4 mA

    I3

    = I4

    = R2-3-4

    /R3-4

    IT

    = 667ohm/2kohm 6mA = 2mA

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    Find I5, I6, I7

    I5 = R5-6-7/R5 IT = 330ohm/1kohm 6mA = 2mA

    I6 = R5-6-7/R6 IT = 330ohm/1kohm 6mA = 2mA

    I7 = R5-6-7/R7

    IT = 330ohm/1kohm

    6mA = 2mA

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    Branch current in a series-

    parallel circuit: SummaryFind:

    I1 = 6mA

    I2 = 4mA

    I3 = 2mA

    I4 = 2mA

    I5 = 2mA

    I6 = 2mA

    I7 = 2mA

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    Power in a series-parallel

    circuitPT = P1 + P2 + P3 +

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    Five-step procedure for series-

    parallel circuit analysisStep 1: Determine the total resistance.

    Step 2: Determine the total current.

    Step 3: Determine the voltage across each series

    resistor and each parallel combination of resistors.

    Step 4: Determine the value of current through each

    parallel resistor in every parallel combination.Step 5: Determine the total and individual power

    dissipated by the circuit.

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    Loading of voltage-divider

    circuitsLoading The adding of a load to a source

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    The Wheatstone bridge

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    Balanced Wheatstone bridge

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    Unbalanced Wheatstone bridge

    When the voltmeter in a bridge circuit

    does not read zero, the bridge isunbalanced.

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    Determining an unknown

    resistor using a bridge circuit

    Using a bridge circuit with a variable

    resistor, force the voltmeter to read zero.

    This will balance the bridge and the value

    of the variable resistor will equal the

    value of the unknown resistor.

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    R-2R ladder circuits

    R-2R A network or circuit composed of a

    sequence of L networks connected in tandem.This R-2R circuit is used in digital-to-analog

    converters.

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    Simplification of R2R ladder

    circuit

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    Troubleshooting series-parallel

    circuitsAn open in a series component No current flow

    An open in a parallel component Current

    A short in a series component Current

    A short in a parallel component Current

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    Theorems for DC circuits

    Superposition Theorem

    Thevenins Theorem

    Nortons Theorem

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    Voltage and current sources

    Voltage Source The circuit or device that

    supplies voltage to a load circuit.

    Current Source The circuit or device thatsupplies current to a load circuit.

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    Superposition Theorem

    In a network or circuit containing two or more voltage

    sources, the current at any point is equal to the algebraic sumof the individual source currents produced by each source

    acting separately.

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    Thevenins Theorem

    Any network of voltage sources and resistors can be replaced

    by a single equivalent voltage source (VTH) in series with asingle equivalent resistance (RTH).

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    To Thevenize a circuit

    Identify the circuit to be Thevenized.

    Measure the voltage at the output. This is the VTH.

    Remove the sources and replace them with a short;

    measure the resistance at the output. This is the RTH.

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    Find the Thevenin equivalent

    circuit for:

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    Thevenin equivalent circuit

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    Find VTH

    .

    VTH = 1.33V

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    Find RTH

    .

    RTH = 2kohm

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    Nortons Theorem

    Any network of voltage sources and

    resistors can be replaced by a singleequivalent current source, IN, in parallel

    with a single equivalent resistance, RN.

    T fi d th i l t N t

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    To find the equivalent Norton

    circuitIdentify the circuit for a Norton equivalent circuit.

    Measure the the short circuit amperes. This is IN.

    Replace the sources with shorts and measure the

    resistance at the output. This is RN.

    Fi d th N t i l t

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    Find the Norton equivalent

    circuit for:

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    Norton equivalent circuit

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    Find IN

    .

    IN

    = -2.333mA

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    Find RN.

    RN = 2.0kohm

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    End ofIntroduction to Series-Parallel DC

    Circuits