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ARCHN305 Building Construction III
BUILDING CONSTRUCTION III
ARCHN305
QUANTITIES CALCULATIONQUANTITIES CALCULATION
Lecture 4, 5 - CONSTRUCTION MANAGEMENT & BUILDING ECONOMICS 1
Sunday, March 21, 2010
QUANTITIES CALCULATIONQUANTITIES CALCULATION
HESHAM KHAIRY
Sunday, May 16, 2010 Lecture 10 – Quantities Calculation
ARCHN305 Building Construction III
Example in Quantities Calculation
Guard room
� Room 4.00 × 4.00 m Cl. To Cl.
� Room 4.25 × 4.25 m Total
� Total Height = 3.00 m W1
Lecture 4, 5 - CONSTRUCTION MANAGEMENT & BUILDING ECONOMICS 2
Sunday, March 21, 2010Sunday, May 16, 2010 Lecture 10 – Quantities Calculation
� Total Height = 3.00 m
� Wood Door 1.00 × 2.20 m
� Alum. Window 1.20 × 1.00 m
W1
D1
ARCHN305 Building Construction III
Example in Quantities Calculation
� Slab Thickness = 12 cm
� Beams = 25 × 60 cm
Guard room
Lecture 4, 5 - CONSTRUCTION MANAGEMENT & BUILDING ECONOMICS 3
Sunday, March 21, 2010Sunday, May 16, 2010 Lecture 10 – Quantities Calculation
� Beams = 25 × 60 cm
�Columns 25 × 25 cm
ARCHN305 Building Construction III
Example in Quantities Calculation
Guard room
Lecture 4, 5 - CONSTRUCTION MANAGEMENT & BUILDING ECONOMICS 4
Sunday, March 21, 2010Sunday, May 16, 2010 Lecture 10 – Quantities Calculation
ARCHN305 Building Construction III
Calculations
Excavation
Footing Excavation = 4 × 1.25 × 1.25 × 2.00 = 12.500 m³
Smells Excavation = 4 × 2.75 × 1.30 × 0.25 = 3.575 m³
Total Excavation = 16.075 m³
Plain Concrete
Lecture 4, 5 - CONSTRUCTION MANAGEMENT & BUILDING ECONOMICS 5
Sunday, March 21, 2010Sunday, May 16, 2010 Lecture 10 – Quantities Calculation
Footings = 4 × 1.25 × 1.25 × 0.40 = 2.500 m³
Total P.C.= 2.500 m³
Reinforced Concrete for Foundations
Footing = 4 × 0.75 × 0.75 × 0.30 = 0.675 m³
Smells = 4 × 0.25 × 0.40 × 3.75 = 1.500 m³
Total Foundation R.C. = 2.500 m³
Columns Necks = 4 × 0.25 × 0.25 × 1.30 = 0.325 m³
ARCHN305 Building Construction III
Calculations
Fill
Fill = 16.075 – 2.5 – 2.5 = 11.075 m³
Total Fill = 11.075 m³
Reinforced Concrete for Skelton
Columns = 4 × 0.25 × 0.25 × 2.40 = 0.600 m³
Beams = 4 × 3.75 × 0.25 × (0.60 – 0.12) = 1.800 m³
Lecture 4, 5 - CONSTRUCTION MANAGEMENT & BUILDING ECONOMICS 6
Sunday, March 21, 2010Sunday, May 16, 2010 Lecture 10 – Quantities Calculation
Beams = 4 × 3.75 × 0.25 × (0.60 – 0.12) = 1.800 m³
Total Skelton R.C. = 4.5675 m³
Slab = 4.25 × 4.25 × 0.12 = 2.1675 m³
Floor Tiles
Floor Tiles = (4 × 4) – (4 × 0.125 × 0.125) = 15.9375 m²
Total Floor Tiles = 15.9375 m²
Brick works
Brick = (4 × 3.75 × 2.40 ) – (1.00 × 1.20) – (1.00 × 2.20) = 32.600 m²
Total Brick works= 32.600 m²
ARCHN305 Building Construction III
Calculations
Plaster
Ceiling Plaster = (4 × 4) – (4 × 0.125 × 0.125) = 15.9375 m²
Total Plaster = 58.6175 m²
Walls Plaster = 4 × 4 × (3 – 0.12) – (1.20 × 1.00) – (2.20 × 1.00) = 42.68 m²
Painting
Ceiling Painting = (4 × 4) – (4 × 0.125 × 0.125) = 15.9375 m²
Lecture 4, 5 - CONSTRUCTION MANAGEMENT & BUILDING ECONOMICS 7
Sunday, March 21, 2010Sunday, May 16, 2010 Lecture 10 – Quantities Calculation
Corniche (الكورنيشه)
Corniche = 4 × 4 = 16.000 m
Corniche = 16.000 m
Ceiling Painting = (4 × 4) – (4 × 0.125 × 0.125) = 15.9375 m²
Total Painting = 58.6175 m²
Walls Painting = 4 × 4 × (3 – 0.12) – (1.20 × 1.00) – (2.20 × 1.00) = 42.68 m²
Cill (الوزره)
Cill = (4 × 4) – 1.00 = 15.000 m
Corniche = 15.000 m
ARCHN305 Building Construction III
Very important notes
In External work:
� Brick works:
� in case of flat openings……………....Deduct all openings.
� in case of Curved openings…………..Deduct half openings only.
Lecture 4, 5 - CONSTRUCTION MANAGEMENT & BUILDING ECONOMICS 8
Sunday, March 21, 2010Sunday, May 16, 2010 Lecture 10 – Quantities Calculation
� Plaster works:
� in case of openings less than 4m²……………......No Deduction.
� in case of openings more than 4m²……………....Deduct half openings only.