lecture # 5 thermodynamics-ii
TRANSCRIPT
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SequenceSpecific heat capacities of a gas mixture
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Specific heat capacities of a gas mixtureAs a consequence of the Gibbs-Dalton law the internal energy of a mixture of gases is given by the Eq. 6.5
Also for a perfect gas from Eq. 2.14
Hence substituting we have
or
Eq.6.18
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Specific heat capacities of a gas mixture Contd.Similarly from Eq.6.6
And from Eq.2.18
Therefore
Or
Eq.6.19
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Specific heat capacities of a gas mixture Contd.From equations from 6.18 and 6.19
Using equation 2.17,
Also from equation 6.12
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Specific heat capacities of a gas mixture Contd.Therefore for the mixture
The equations 2.20, 2.21 and 2.22 can be applied to a mixture of gases
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Problem: The gas in an engine cylinder has a volumetric analysis of 12% CO2 , 11.5% O2 and 76.5% N2 . The temperature at the beginning of the expansion is 1000 C and the gas mixture expands reversibly through a volume ratio of 7 to 1, according to a law pv1.25=constant. Calculate the work done and the heat flow per unit mass of gas. The values of cp for the constituents averaged over the temperature are as follows: cp for CO2 = 1.271kJ/kgK; cp for O2 = 1.110 kJ/kgK; cp for N2 = 1.196 kJ/kgK.
Specific heat capacities of a gas mixture Contd.
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The End