lecture 23 10/28/05. 50 ml of 0.02 m koh with 0.1 m hbr construct curve from 4 points initial ph x =...
Post on 21-Dec-2015
221 views
TRANSCRIPT
50 mL of 0.02 M KOH with 0.1 M HBr Construct curve from 4 points
• Initial pH• X = 0 mL, Y = ?
• Equivalence point• X = Veq, Y = 7
• Before Equivalence point• X = ?, Y = ?
• After Equivalence point• X = ?, Y = ?
Titration of a weak acid with strong base
• 50 mL of 0.02 M MES• [2-(n-morpholino)ethanesulfonic acid]
• pKa = 6.15
• with 0.100 M NaOH.
50 mL of 0.02 M MES with 0.100 M NaOH.Construct curve from 4 points
• Initial pH• X = 0 mL, Y = ?
• Equivalence point• X = Veq, Y = ?
• Before Equivalence point• X = ½ Veq, Y = pKa
• After Equivalence point• X = ?, Y = ?