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    ENE 428

    MicrowaveEngineering

    Lecture 12 Power Dividers andDirectional Couplers

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    Power dividers and directional couplers

    Passive components that are used for power division orcombining.

    The coupler may be a three-port or a four-port component

    Three-port networks take the form of T-junctions

    Four-port networks take the form of directional couplers

    and hybrids.

    Hybrid junctions have equal power division and either 90or a 180 phase shift between the outport ports.

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    33

    Types of power dividers and directionalcouplersT-junction power divider Resistive divider

    Wilkinson power divider

    Bethe Hole Coupler

    Quadrature (90) hybrid and magic-T (180) hybrid

    Coupled line directional coupler

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    Basic properties of dividers and couplers

    The simplest type is a T-junction or a three-port networkwith two inputs and one output.

    The scattering matrix of an arbitrary three-port network

    has nine independent elements

    11 12 13

    21 22 23

    31 32 33

    S S S

    S S S S

    S S S

    Divider

    or

    couplerP1

    P2aP1

    P3(1-a)P1

    Divider

    or

    coupler

    P1=P2+P3P2

    P3

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    The scattering parameters losslessproperty

    The unitary matrix:

    This can be written in summation form as

    where ij= 1 ifi= jand ij= 0 ifijthusifi= j,

    while ifij,

    1

    tS S

    -*

    1, ,

    N

    ki kj ijk

    S S for all i j*

    1

    1,N

    ki kik

    S S*

    1

    0.N

    ki kj

    k

    S S*

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    It is impossible to construct a three-portlossless reciprocal network. (1)

    If all ports are matched, then Sii= 0, and if the network isreciprocal the scattering matrix reduces to

    If the network is lossless, the scattering matrix must be

    unitary that leads to

    12 13

    12 23

    13 23

    0

    0 .

    0

    S S

    S S S

    S S

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    It is impossible to construct a three-portlossless reciprocal network. (2)

    Two of the three parameters (S12, S13, S23) must be zeros

    but this will be inconsistent with one of eq. (1a-c), implying

    that a three-port network cannot be lossless, reciprocal, and

    matched at all ports.

    2 212 13

    2 2

    12 23

    2 2

    13 23

    13 23

    23 12

    12 13

    1, (1 )

    1, (1 )

    1, (1 )

    0, (1 )

    0, (1 )

    0. (1 )

    S S a

    S S b

    S S c

    S S d

    S S e

    S S f

    *

    *

    *

    +

    +

    +

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    Any matched lossless three-port networkmust be nonreciprocal. (1) The [S] matrix of a matched three-port network has thefollowing form:

    If the network is lossless, [S] must be unitary, which

    implies the following:

    12 13

    21 23

    31 32

    0

    0 .0

    S S

    S S SS S

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    Any matched lossless three-port networkmust be nonreciprocal. (3) This results show that SijSji forij, therefore the device

    must be nonreciprocal.

    These S matrices represent two possible types of

    circulators, forward and backward.

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    1111

    A lossless and reciprocal three-port network

    can be physically realized if only two of its

    ports are matched. (1) If ports 1 and 2 are matched ports, then

    To be lossless, the following unitary conditions must be

    satisfied:

    12 13

    12 23

    13 23 33

    0

    0 .

    S S

    S S S

    S S S

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    1212

    A lossless and reciprocal three-port network

    can be physically realized if only two of its

    ports are matched. (2)

    From (3a-b), , so (3d) shows that S13 = S23= 0.

    Then |S12|=|S33|=1.

    2 2

    12 13

    2 2

    12 23

    2 2 2

    13 23 33

    13 23

    12 13 23 33

    23 12 33 13

    1, (3 )

    1, (3 )

    1, (3 )

    0, (3 )

    0, (3 )

    0. (3 )

    S S a

    S S b

    S S S c

    S S d

    S S S S e

    S S S S f

    *

    * *

    * *

    +

    +

    + +

    +

    +

    13 23S S

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    1313

    A lossless and reciprocal three-port network

    can be physically realized if only two of its

    ports are matched. (3) The scattering matrix and signal flow graph are shown

    below.

    If a three-port network is lossy, it can be reciprocal and

    matched at all ports.

    21

    3

    S21=e

    jq

    S12=ejq

    S33=ejf

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    Four-port networks (Directional Couplers)

    Power supplied to port 1 is coupled to port 3 (the coupled

    port), while the remainder of the input power is delivered to

    port 2 (the through port)

    In an ideal directional coupler, no power is delivered to

    port 4 (the isolated port).

    1 2

    34

    Input Through

    CoupledIsolated

    1 2

    34

    Input Through

    CoupledIsolated

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    Basic properties of directional couplers aredescribed by four-port networks.(1)

    12 13 14

    12 23 24

    13 23 34

    14 24 34

    0

    0.

    0

    0

    S S S

    S S SS

    S S S

    S S S

    The [ S ] matrix of a reciprocal four-port network matched

    at all ports has the above form.

    If the network is lossless, there will be 10 equations result

    from the unitary condition.

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    Conditions needed for a lossless reciprocalfour-port network (2) Then the self-products of the rows of the unitary [S] matrix

    yield the following equations:

    which imply that |S13|=|S24|and that |S12|=|S24|.

    2 2

    12 13

    2 2

    12 24

    2 2

    13 34

    2 2

    24 34

    1, (6 )

    1, (6 )

    1, (6 )

    1, (6 )

    S S a

    S S b

    S S c

    S S d

    +

    +

    +

    +

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    Symmetrical and Antisymmetrical coupler (2) If 2is ignored, we yield

    1. The symmetrical coupler: q= f= /2.

    2. The antisymmetrical coupler: q= 0, f= .

    0 0

    0 0.0 0

    0 0

    j

    jS j

    j

    a

    a

    a

    a

    0 0

    0 0.

    0 0

    0 0

    S

    a

    a

    a

    a

    -

    -

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    2020

    Symmetrical and Antisymmetrical coupler (3) The two couplers differ only in the choice of the reference

    planes. The amplitudes aand are not independent, eq

    (6a) requires that

    a2+ 2=1.

    Another way for eq. (4) and (5) to be satisfied is if|S13|=|S24| and |S12|=|S34|.

    If phase references are chosen such that S13=S24=aand

    S12=S34=j, two possible solutions are given. FirstS14=S23=0, same as above.

    The other solution is fora= =0, which implies

    S12=S13=S24=S34=0, the case of two decoupled two-port

    network.

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    Power supplied to port 1 is coupled to port 3 (the coupledport) with the coupling factor

    The remainder of the input power is delivered to port 2 (the

    through port) with the coefficient

    In an ideal coupler, no power is delivered to port 4 (the

    isolated port).

    Hybrid couplers have the coupling factor of 3 dB ora= = The quadrature hybrid coupler has a 90 phase shift

    between ports 2 and 3 (q= f= /2) when fed at port 1.

    21

    Directional couplers characterization (1)2 2

    13 .S

    2 2 2

    12 1 .S -a

    1/ 2.

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    Coupling = C= = -20log dB,

    Directivity = D = = 20log dB,

    Isolation = I= = -20log|S14

    | dB.

    The coupling factor indicates the fraction of the input

    power coupled to the output port.

    The directivity is a measure of the couplers ability toisolate forward and backward waves, as is the isolation.

    These quantities can be related as

    I= D + CdB. 22

    Directional couplers characterization(2)1

    310log

    P

    P

    3

    4

    10logP

    P

    1

    4

    10logP

    P

    14S

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    The ideal coupler would have infinite directivity andisolation (S14 = 0).

    23

    Ideal coupler

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    Lossless divider (1)

    A lumped susceptance, B, accounts for the storedenergy resulted from fringing fields and higher ordermodes associated with the discontinuity at the junction.

    In order for the divider to be matched to the input lineimpedance Z0, and assume a TL to be lossless, we willhave

    1 2 0

    1 1 1

    .inY Z Z Z +

    jB

    Z1

    Z2

    Z0

    +V0-

    Yin

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    Lossless divider (2)

    The output line impedances Z1 and Z2 can then beselected to provide various power division ratios.

    In order for the divider to be matched to the input line

    impedance Z0, and assume a TL to be lossless, we willhave

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    Ex1 A lossless T-junction power divider has a

    source impedance of 50 . Find the output

    characteristic impedances so that the input poweris divided in a 3:1 ratio. Compute the reflection

    coefficients seen looking into the output ports.

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    Resistive divider

    A lossy three-port divider can be made to matched at allports, although the two output ports may not be isolated.

    Z0/3

    Z0

    Z0

    +

    V

    -

    Zin

    Z

    Z0+

    V2-

    +V3-

    Z0/3

    Z0/3+

    V1-

    P1

    Port 1

    Port 2

    P2

    P3

    Port 3

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